# ar25-0c556536 · pasada 0 · log de pensamiento

## Paso 1 · nivel 1 · acción 1

**Pensamiento:**

Let me inspect the board structure first.

```python
print(current_frame.shape, current_frame.level, current_frame.step)
print(valid_actions)
seg = current_frame.segmentation
for n in seg['nodes']:
    print(n['id'], n['color'], n['pixels'], n['boundary'], n['rotation'], n['children'])
print('adj', seg['adjacency_list'])
```

```text
(64, 64) 1 0
['UP', 'DOWN', 'LEFT', 'RIGHT', 'SPACE', 'MOUSE', 'UNDO']
0 b 1845 [[0, 0], [0, 29], [62, 29], [62, 0]] 270 [4]
1 S 189 [[0, 30], [0, 32], [62, 32], [62, 30]] 90 []
2 b 1800 [[0, 33], [0, 62], [62, 62], [62, 33]] 0 [5, 11]
3 Y 64 [[0, 63], [63, 63]] 90 []
4 B 40 [[15, 18], [15, 26], [23
… [528 caracteres más]
```

**Pensamiento:**

Let me understand the board. There's a blue background split by a light-blue vertical line at columns 30-32. There's a yellow vertical bar at column 63 (right edge, full height) — possibly a timer bar. Bottom row 63 is black (63 pixels wide) — could be another bar.
Objects:
- Node 4: black L-shape at rows 15-23, cols 18-26, with white dots inside (children 6-10). Actually the black shape is like a "7" shape: horizontal bar row 15-17 cols 18-26, plus vertical col 24-26 rows 17-23. Hmm.
- Node 5: dark gray (charcoal) L-shape at rows 15-23, cols 36-44.
- Node 11: yellow L-shape at rows 45-53, cols 51-59.
The white dots inside the black shape look like a pattern of dots — maybe indicating something.
Let me look at the ASCII for the shapes to get exact forms.
The idea may be: the black shape (with dots) is a "target pattern" and the other shapes must be moved/rotated to match? Or the yellow shape is a player to move?
Let me print small crops.

```python
a = current_frame.ascii.split('\n')
def crop(r0,r1,c0,c1):
    for r in range(r0,r1+1):
        print(r, a[r][c0:c1+1])
print('--- black shape + dots region')
crop(14,24,17,27)
print('--- charcoal shape')
crop(14,24,35,45)
print('--- yellow shape')
crop(44,54,50,60)
print('--- right edge col 60-63 rows 0-10')
crop(0,10,60,63)
print('--- bottom rows 60-63 cols 0-10')
crop(60,63,0,10)
```

```text
--- black shape + dots region
14 bbbbbbbbbbb
15 bBBBBBBBBBb
16 bBWBBWBBWBb
17 bBBBBBBBBBb
18 bbbbbbbBBBb
19 bbbbbbbBWBb
20 bbbbbbbBBBb
21 bbbbbbbBBBb
22 bbbbbbbBWBb
23 bbbbbbbBBBb
24 bbbbbbbbbbb
--- charcoal shape
14 bbbbbbbbbbb
15 bcccccccccb
16 bcccccccccb
17 bcccccccccb
18 bcccbbbbbbb
19 bcccbbbb
… [465 caracteres más]
```

**Pensamiento:**

So we have:
- Charcoal L-shape: 3x9? Actually rows 15-23, cols 36-44: horizontal bar rows 15-17 cols 36-44 (9 wide, 3 tall), plus vertical bar cols 36-38 rows 17-23 (3 wide, 7 tall). It's an "L" shape (corner) with thickness 3.
- Yellow shape: same shape (rows 45-53, cols 51-59): horizontal rows 45-47 cols 51-59, vertical cols 51-53 rows 47-53. Same shape as charcoal.
- Black shape: rows 15-23, cols 18-26: horizontal rows 15-17 cols 18-26, vertical cols 24-26 rows 17-23. That's a mirrored/rotated version. Black shape has white dots along its centerline: at (16,19),(16,22),(16,25),(19,25),(22,25) — dots along the middle row of the horizontal bar and middle column of the vertical bar. So the black shape is like a "path" template with dots showing the path.
So it seems the puzzle: black shape is a "hole"/target with a dotted path; we need to move the yellow (or charcoal) shape to fit into the black shape? Hmm.
Actually, maybe the black shape is a "pipe" that the shape must fit into. The black shape's orientation is mirrored relative to charcoal/yellow: black's vertical leg is at the right end of the horizontal leg and goes down; charcoal's vertical leg is at the left end going down; yellow's same as charcoal.
Black: horizontal bar at top spanning cols 18-26, vertical leg at cols 24-26 going down to row 23. Charcoal: horizontal bar at top cols 36-44, vertical leg at cols 36-38 going down. So black is a mirror of charcoal (horizontal flip). Yellow is same orientation as charcoal.

… [1240 caracteres más]

```python
r = action([{'action':'DOWN'}])
print({k:v for k,v in r.items() if k!='frames'})
d = frame_diff()
import json
print(json.dumps({k:d[k] for k in d if k!='changed_cell_count'}, default=str)[:1500])
print('changed', d['changed_cell_count'])
```

```text
[action] DOWN -> effect
{'executed': True, 'action_num': 1, 'level': 1, 'score': 0, 'state': 'NOT_FINISHED', 'valid_actions': ['UP', 'DOWN', 'LEFT', 'RIGHT', 'SPACE', 'MOUSE', 'UNDO'], 'board_changed': True, 'done': False, 'level_completed': False, 'game_over': False, 'run_complete': False, 'action_
… [1377 caracteres más]
```

## Paso 2 · nivel 1 · acción 2

**Pensamiento:**

Interesting: DOWN moved the black shape and the charcoal shape down by 3 rows? Wait, the diff says B moved from [15,18] to [18,18] and c moved from [15,36] to [18,36]. But the yellow shape didn't move. Hmm, but the current image shows shapes at the same positions... Let me re-check. Actually the image shows the shapes at rows ~15-23 still. Hmm, but the diff says they moved down 3.
Wait — the diff image shows changes: blue appearing at top of shapes (they moved down), and dark gray moved. So both black and charcoal moved down by 3 rows. Yellow didn't move.
Hmm, so DOWN moves... both black and charcoal? Or maybe all "L" shapes except yellow? Or maybe the yellow is the "player"?
Wait, but the yellow bar at col 63 shrank from 64 to 63 pixels — that's the timer/step bar. So the yellow full-height bar is HUD.
So DOWN moved black shape and charcoal shape down by 3. Interesting. Actually maybe the whole left panel and right panel shift? No, only the shapes moved.
Hmm, wait. Maybe the shapes wrap around? Let me check current positions of the shapes now.
Actually let me re-inspect: the black shape at [18,18] and charcoal at [18,36]. Yellow at [45,51] presumably unchanged.
So DOWN moves black and charcoal down by 3 rows, but not yellow? That's weird. Unless yellow moved too but diff didn't detect... no, diff would show.
Hmm, maybe the movement is not "down 3" but the shapes are being "drawn" progressively? Like the black shape with dots is a path being traced?
Alternative interpretation
… [823 caracteres más]

```python
def pos():
    seg = current_frame.segmentation
    out=[]
    for n in seg['nodes']:
        if n['pixels']>=1 and n['color'] in 'BYcW' and n['pixels']<200:
            b=n['boundary']
            out.append((n['color'],n['pixels'],b[0]))
    return out

print('after DOWN', pos())
r=action(['UNDO'])
print('undo ok', r['executed'], r.get('board_changed'))
print('after UNDO', pos())
```

```text
after DOWN [('B', 1, [0, 63]), ('Y', 63, [1, 63]), ('B', 40, [18, 18]), ('c', 45, [18, 36]), ('W', 1, [19, 19]), ('W', 1, [19, 22]), ('W', 1, [19, 25]), ('W', 1, [22, 25]), ('W', 1, [25, 25]), ('Y', 45, [45, 51]), ('B', 63, [63, 0])]
[action] UNDO -> effect
undo ok True True
after UNDO [('B', 1, [0,
… [209 caracteres más]
```

## Paso 3 · nivel 1 · acción 8

**Pensamiento:**

UNDO restored positions. Now probe: RIGHT, SPACE, etc. Note the yellow bar (col 63) didn't restore? It shows Y 63 at [1,63] after undo... initially it was 64 at [0,63]. So the bar didn't restore on UNDO — it's a step budget that decreases each action regardless. So budget ~63 actions. Careful.
Let me probe RIGHT, then UNDO, then SPACE, then UNDO, then UP, etc. Each probe costs 2 actions (probe + undo), and possibly the undo costs budget too. Budget ~63, fine.
Let me do RIGHT probe.

```python
for act in ['RIGHT','UP','SPACE']:
    before = pos()
    r = action([act])
    after = pos()
    d = frame_diff()
    print('===',act,'exec',r['executed'],'board_changed',r.get('board_changed'),'gameplay',r.get('gameplay_changed'),'level_completed',r.get('level_completed'))
    print('  moved', [(m['color'],m['from'],m['to']) for m in d['moved']])
    print('  rotated', d['rotated'], 'appear', [(x['color'],x['bbox']) for x in d['appeared']], 'disappear',[(x['color'],x['bbox']) for x in d['disappeared']])
    print('  resized', [(x['color'],x['before_pixels'],x['after_pixels']) for x in d['resized']])
    u = action(['UNDO'])
    print('  undo board_changed', u.get('board_changed'), u.get('gameplay_changed'), 'pos now', pos()==before)
```

```text
[action] RIGHT -> effect
=== RIGHT exec True board_changed True gameplay True level_completed False
  moved [('B', [15, 18], [15, 21]), ('c', [15, 36], [15, 33]), ('W', [16, 19], [16, 28]), ('W', [19, 25], [19, 28]), ('W', [22, 25], [22, 28])]
  rotated [] appear [] disappear []
  resized [('b', 184
… [889 caracteres más]
```

## Paso 4 · nivel 1 · acción 13

**Pensamiento:**

Interesting findings:
- RIGHT: black shape moved right by 3 (from col 18 to 21), charcoal moved LEFT by 3 (from col 36 to 33). So the two shapes move in opposite directions?! Hmm, black moved right (+3 cols), charcoal moved left (-3 cols). They're approaching each other (moving toward the center line? or away?).
Wait, black is left of the divider (cols 30-32), charcoal is right of it. RIGHT moves black right (toward divider) and charcoal left (toward divider). Hmm, both toward the middle. Or perhaps the movement is relative to each panel: the left panel scrolls right, and the right panel scrolls left? That would be weird.
Hmm, another interpretation: both shapes move in the direction of... hmm. Actually maybe the black shape moves in the pressed direction and the charcoal moves opposite. Or maybe the shapes on the left half move with the input and shapes on right half move opposite.
But yellow didn't move at all! Yellow is on the right half. Hmm, yellow is a different color — maybe yellow is a "goal/locked" object.
Also, the dots (W) moved oddly: after RIGHT, W at [16,19] -> [16,28], [19,25]->[19,28], [22,25]->[22,28]. That's the diff matcher being confused (dots are identical, matcher matched wrong). Actually the black shape moved +3 cols, so dots should move +3 as well: (16,19)->(16,22), (16,22)->(16,25), (16,25)->(16,28), (19,25)->(19,28), (22,25)->(22,28). The diff just matched some to different targets. So dots move with the black shape.
Now the "pos now False" after UND
… [6993 caracteres más]

```python
def shapes():
    seg = current_frame.segmentation
    out=[]
    for n in seg['nodes']:
        if n['pixels'] in (40,45) and n['color'] in 'BcY':
            b=n['boundary'][0]
            out.append((n['color'],b))
    return out
for i in range(5):
    r = action(['LEFT'])
    print('LEFT',i+1, shapes(), 'lc',r.get('level_completed'),'go',r.get('game_over'))
```

```text
[action] LEFT -> effect
LEFT 1 [('B', [15, 15]), ('c', [15, 39]), ('Y', [45, 51])] lc False go False
[action] LEFT -> effect
LEFT 2 [('B', [15, 12]), ('c', [15, 42]), ('Y', [45, 51])] lc False go False
[action] LEFT -> effect
LEFT 3 [('B', [15, 9]), ('c', [15, 45]), ('Y', [45, 51])] lc False go Fals
… [201 caracteres más]
```

**Nivel 1 completado → nivel 2 (acción 23)**

## Paso 5 · nivel 2 · acción 23

**Pensamiento:**

Confirmed: LEFT moves black left and charcoal right. Now charcoal is at cols 51-59, matching yellow's cols. Now press DOWN 10 times to align rows 45-53.
Let me do it in steps and watch for level completion.

```python
for i in range(10):
    r = action(['DOWN'])
    print('DOWN',i+1, shapes(), 'lc',r.get('level_completed'),'go',r.get('game_over'))
    if r.get('level_completed') or r.get('game_over') or r.get('done'): break
```

```text
[action] DOWN -> effect
DOWN 1 [('B', [18, 3]), ('c', [18, 51]), ('Y', [45, 51])] lc False go False
[action] DOWN -> effect
DOWN 2 [('B', [21, 3]), ('c', [21, 51]), ('Y', [45, 51])] lc False go False
[action] DOWN -> effect
DOWN 3 [('B', [24, 3]), ('c', [24, 51]), ('Y', [45, 51])] lc False go False

… [592 caracteres más]
```

## Paso 6 · nivel 2 · acción 26

**Pensamiento:**

Level 1 solved by moving the mirrored shape pair so the charcoal shape lands on the yellow target.
Level 2: New board. There's a vertical light-blue divider with white dots (dashed). Left panel has a charcoal Z/S-shape and a yellow Z-shape. Right panel has a black shape with dots (Z-shape).
Let me inspect the segmentation.

```python
seg = current_frame.segmentation
for n in seg['nodes']:
    print(n['id'], n['color'], n['pixels'], n['boundary'][0], n['rotation'], n['children'])
print('adj', seg['adjacency_list'])
a=current_frame.ascii.split('\n')
def crop(r0,r1,c0,c1):
    for r in range(r0,r1+1): print(r, a[r][c0:c1+1])
print('--- right black shape')
crop(17,31,44,62)
print('--- left charcoal')
crop(17,31,10,32)
print('--- left yellow')
crop(40,56,0,22)
print('--- divider sample')
crop(0,12,35,39)
```

```text
0 b 2124 [0, 0] 0 [10, 28]
1 S 168 [0, 36] 90 [4, 5, 6, 7, 8, 9, 12, 16, 18, 20, 24, 25, 26, 27, 29, 30, 31, 32, 33, 34, 35]
2 b 1440 [0, 39] 0 [11]
3 Y 64 [0, 63] 90 []
4 W 1 [1, 37] None []
5 W 1 [4, 37] None []
6 W 1 [7, 37] None []
7 W 1 [10, 37] None []
8 W 1 [13, 37] None []
9 W 1 [16, 37] Non
… [2422 caracteres más]
```

**Pensamiento:**

Level 2 layout:
- Divider at cols 36-38 (light blue S) with white dots every 3 rows.
- Left panel: charcoal Z-shape at rows 18-29, cols 11-19 (top bar cols 11-19 rows 18-20, vertical leg at cols 11-13 rows 20-29... wait let me re-read.
Charcoal crop cols 10-32 shown with offset: at row 18-20, 'ccccccccc' starting at index 11 → col 10+11=21? Let me recompute: crop printed a[r][10:33], so index 0 = col 10. Row 18: "bbbbbbbbbbbcccccccccbbb" → c at indices 11-19 → cols 21-29. Hmm, but boundary says [18,21]. Yes: cols 21-29.
Row 21-26: c at indices 11-13 → cols 21-23.
Row 27-29: c at indices 5-13 → cols 15-23.
So charcoal Z: top bar rows 18-20 cols 21-29, vertical leg cols 21-23 rows 21-26, bottom bar rows 27-29 cols 15-23.
It's a Z/S shape (7 blocks of 3x3? pixels 72 = 8 blocks of 9). Let's count: top bar 3x3=3 blocks (cols 21-23,24-26,27-29), vertical leg 2 blocks (rows 21-23, 24-26), bottom bar 3 blocks (cols 15-17,18-20,21-23). Total 3+2+3 = 8 blocks = 72 pixels. ✓.
Yellow at rows 42-53: top bar rows 42-44 cols 9-17, vertical leg cols 9-11 rows 45-50, bottom bar rows 51-53 cols 3-11. Same Z shape, 72 pixels.
Black shape on right: rows 18-29, cols 45-59. From crop (index 0 = col 44): row 18-20: B at indices 1-9 → cols 45-53. Row 21-26: B at indices 7-9 → cols 51-53. Rows 27-29: B at indices 7-15 → cols 51-59.
So black: top bar cols 45-53 rows 18-20, vertical leg cols 51-53 rows 21-26, bottom bar cols 51-59 rows 27-29. That's a Z/S shape mirrored: it's the mirror image of the ch
… [1476 caracteres más]

```python
def snap():
    seg=current_frame.segmentation
    out={}
    for n in seg['nodes']:
        if n['pixels']>=40 and n['color'] in 'BcY' and n['pixels']<200:
            b=n['boundary']
            rs=[p[0] for p in b]; cs=[p[1] for p in b]
            out[(n['color'],n['pixels'])]=(min(rs),min(cs),max(rs),max(cs))
    return out
print(snap())
r=action(['LEFT'])
print('LEFT ->',snap())
r=action(['UNDO'])
print('undo ->',snap())
r=action(['UP'])
print('UP ->',snap())
r=action(['UNDO'])
print('undo ->',snap())
```

```text
{('Y', 64): (0, 63, 63, 63), ('c', 72): (18, 15, 29, 29), ('B', 64): (18, 45, 29, 59), ('Y', 72): (42, 3, 53, 17), ('B', 63): (63, 0, 63, 62)}
[action] LEFT -> effect
LEFT -> {('Y', 63): (1, 63, 63, 63), ('c', 72): (18, 9, 29, 23), ('B', 64): (18, 45, 29, 59), ('Y', 72): (42, 3, 53, 17), ('B', 63): 
… [943 caracteres más]
```

## Paso 7 · nivel 2 · acción 27

**Pensamiento:**

Key observations from level 2:
- LEFT moved the charcoal (left panel) from cols 15-29 to cols 9-23 (left by 6? wait: 15→9 is -6, and 29→23 is -6). Hmm, that's 6 columns, not 3! Let me check: before (18,15,29,29), after (18,9,29,23). So it moved left by 6. Hmm, that's odd. Wait, maybe the move step is 3 but the diff... no, bbox changed by 6.
Hmm interesting. Actually in level 1, the moves were 3 per press. Here the charcoal moved 6 per press? Let me double check: maybe the bbox min/max... bbox from boundary points. The boundary is the outer perimeter corner points. min cs 15 → 9. That's a 6 shift.
Hmm, or maybe the black shape didn't move at all! Black stayed at (18,45,29,59) both before and after. So in level 2, only the charcoal moved, and the black dotted shape is a static reference (a "legend" showing the shape, since the divider has dots too... hmm).
Wait, actually maybe the black shape is now a legend showing "the shape you control" — and the dots inside indicate it's the reference. And in level 1, the black shape was the one that moved along with the charcoal mirrored... Hmm, in level 1 the black shape moved.
Interesting: In level 2 the black shape is on the right panel and static; the charcoal on the left panel moves. And UP was a NO-OP! That's important: UP did nothing — meaning the charcoal can't move up (blocked?). It's at rows 18-29; there's nothing above it. Unless the movement is constrained to only certain axes?
Hmm, maybe the charcoal only moves along its "path
… [1107 caracteres más]

```python
import sys
base = snap()
print('base', base)
for act in ['DOWN','DOWN','RIGHT','LEFT']:
    try:
        r=action([act])
        s=snap()
        ch = {k:(base.get(k),s.get(k)) for k in s if base.get(k)!=s.get(k)}
        print(act,'no-op' if r.get('no_op') else 'moved', ch)
        base = s
    except Exception as e:
        print(act,'ERR',type(e).__name__)
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 1, in <module>
ImportError: Module 'sys' is not allowed in the sandbox.
```

**Pensamiento:**

Remove import. Also `snap` and `action` etc are available.

```python
base = snap()
print('base', base)
for act in ['DOWN','DOWN','RIGHT','LEFT']:
    try:
        r=action([act])
        s=snap()
        ch = {k:(base.get(k),s.get(k)) for k in s if base.get(k)!=s.get(k)}
        print(act,'no-op' if r.get('no_op') else 'moved', ch)
        base = s
    except Exception as e:
        print(act,'ERR',type(e).__name__, str(e)[:120])
```

```text
base {('Y', 63): (1, 63, 63, 63), ('c', 72): (18, 15, 29, 29), ('B', 64): (18, 45, 29, 59), ('Y', 72): (42, 3, 53, 17), ('B', 63): (63, 0, 63, 62)}
[action] DOWN -> NO-OP (executed, no change inside the board area)
DOWN no-op {}
DOWN ERR StaleStateActionError DOWN was not executed. The action immedi
… [385 caracteres más]
```

## Paso 8 · nivel 2 · acción 30

**Pensamiento:**

Both UP and DOWN are no-ops; only LEFT moved the charcoal (by 6 cols). Hmm. So the charcoal moves only horizontally? And it moved 6 columns per press.
Wait — maybe the movement is a "slide along a groove": the shape can only move in directions where it doesn't collide? No, UP/DOWN clearly have free space.
Alternative theory: the shape moves by one "block" (3 cells) per press... but LEFT moved 6. Hmm.
Wait, maybe I misread. Let me recheck: initial charcoal bbox (18,15)-(29,29). After LEFT: (18,9)-(29,23). Delta col = -6. Hmm, definitely 6.
Hmm, but hold on: maybe the charcoal moved -3 and the bbox also changed? No, the shape is rigid (72 pixels).
Hmm, maybe the shape slides 6 because the "grid" here is 6-wide? No, blocks are 3x3.
Let me reconsider: maybe the shape isn't moving freely; maybe it's like a "pipe" puzzle where the shape slides along its own axis... 
Another thought: maybe the no-ops are because the shape can only move in the direction that keeps it within a "lane"? Or maybe movement is only allowed along the direction where the shape is "long"?
Hmm, let me test RIGHT and see if it moves right. And test whether repeated LEFT moves by 6 each time or whether it stops at a boundary. Let me test RIGHT first (from base at cols 15-29).
Actually, another idea: maybe the charcoal shape moves only along the axis of its "legs"? The Z shape has horizontal bars at top-right and bottom-left plus a vertical middle. Hmm.
Let me just test RIGHT and multiple LEFTs to map the reachab
… [462 caracteres más]

```python
def try_act(a):
    try:
        r = action([a])
        return ('ok', r.get('no_op'), snap())
    except Exception as e:
        return ('err', type(e).__name__, snap())
print('base', snap()[('c',72)])
for a in ['RIGHT','RIGHT','UP','DOWN']:
    res = try_act(a)
    print(a, res[0], res[1], 'charcoal', res[2][('c',72)], 'black', res[2].get(('B',64)))
```

```text
base (18, 15, 29, 29)
[action] RIGHT -> effect
RIGHT ok False charcoal (18, 21, 29, 35) black (18, 45, 29, 59)
[action] RIGHT -> effect
RIGHT ok False charcoal (18, 27, 29, 41) black (18, 45, 29, 59)
[action] UP -> NO-OP (executed, no change inside the board area)
UP ok True charcoal (18, 27, 29, 41
… [104 caracteres más]
```

## Paso 9 · nivel 2 · acción 31

**Pensamiento:**

Now the charcoal shape has moved right and is overlapping the divider (cols 27-41, crossing the divider at cols 36-38). Interesting — the shape can pass over/through the divider? Looking at the image, the charcoal is drawn on top of the divider partially. Hmm, actually looking at the image, the charcoal's top bar extends to col 41 which is past the divider (36-38). The divider appears still visible... Actually the charcoal top bar row 18-20 goes to col 41, and the divider is at 36-38. In the image the divider looks continuous, so maybe the charcoal is drawn under the divider and clipped? Let's check the actual ascii at rows 18-20 cols 34-42.
Also important: the charcoal moved right by 6 each press, and it crossed the divider. Hmm.
Key question: why are UP/DOWN no-ops? Maybe because the shape only moves horizontally... but the target yellow is BELOW. So how do we get down there? Maybe the shape must move horizontally until it aligns and then something happens (like it falls)? Or maybe the divider moves? Hmm.
Wait — reconsider. Maybe the actual mechanic: the shape slides horizontally, and the "world" wraps or the shape falls down when... Hmm.
Alternatively, maybe the goal is different in level 2: maybe the goal is to make the charcoal shape overlap/align with the black dotted shape (mirror image) — i.e., "complete the picture"? Hmm, but the black is on the right panel; the charcoal moving right can reach the black shape's position? Black at rows 18-29, cols 45-59. Charcoal is a
… [2626 caracteres más]

```python
for i in range(4):
    res = try_act('RIGHT')
    print('RIGHT',i+1,res[0],res[1],'c',res[2][('c',72)],'Y',res[2][('Y',72)],'B',res[2].get(('B',64)))
res = try_act('SPACE')
print('SPACE',res[0],res[1],'c',res[2][('c',72)],'Y',res[2][('Y',72)],'B',res[2].get(('B',64)))
```

```text
[action] RIGHT -> effect

error:
Traceback (most recent call last):
  File "<python_tool>", line 3, in <module>
KeyError: ('c', 72)
```

## Paso 10 · nivel 2 · acción 34

**Pensamiento:**

The charcoal shape now touches/overlaps the black shape region. The KeyError for ('c',72) means the charcoal component is no longer 72 pixels — it merged or was clipped. Let me look at the full segmentation now.
Note: the charcoal moved right to cols 33-47 maybe, overlapping the divider and the black shape. When overlapping, the components might merge (same color? no, different colors) — but the charcoal pixels might be partially hidden behind the black shape (z-order), reducing visible charcoal pixels.
Let me inspect current segmentation.

```python
seg=current_frame.segmentation
for n in seg['nodes']:
    if n['pixels']>8:
        b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
        print(n['id'],n['color'],n['pixels'],(min(rs),min(cs),max(rs),max(cs)))
a=current_frame.ascii.split('\n')
print('--- overlap region rows 17-31 cols 30-60')
for r in range(17,31): print(r, a[r][30:61])
```

```text
0 b 2700 (0, 0, 62, 44)
1 S 48 (0, 45, 17, 47)
2 b 882 (0, 48, 62, 62)
6 Y 60 (4, 63, 63, 63)
11 c 63 (18, 33, 29, 44)
12 B 64 (18, 45, 29, 59)
16 S 112 (21, 45, 62, 47)
29 Y 72 (42, 3, 53, 17)
37 B 63 (63, 0, 63, 62)
--- overlap region rows 17-31 cols 30-60
17 bbbbbbbbbbbbbbbSSSbbbbbbbbbbbbb
18 bbb
… [448 caracteres más]
```

**Pensamiento:**

Wait, this is confusing. Let me re-read. Current ascii rows 18-20: 'c' at cols 39-44 (index 9-14 + 30 = 39-44), then 'B' at cols 45-53.
Hmm, so the charcoal is at cols 33-47 originally (after moving right 6 from 27-41 → 33-47), but the visible charcoal is only cols 33-44 in some rows... Let me look again:
Row 18: cols 39-44 are 'c', cols 45-53 'B'. Where are cols 33-38 in row 18? They show 'b' (background). Hmm! That means the divider region (cols 45-47 now?) — wait the divider moved!
Look: node 1 is S 48 at (0,45)-(17,47) and node 16 is S 112 at (21,45)-(62,47). So the divider is now at cols 45-47! Previously at 36-38. So the DIVIDER MOVED right by 9?? Hmm.
Hold on. Let me reconsider: maybe the whole mechanic is that the LEFT panel scrolls and the divider stays... no.
Let me recompute. Actually maybe I mis-attributed. Let me re-derive: after the previous RIGHT presses, the charcoal was at cols 27-41 and the divider at 36-38 (from the image at step 31, the divider looked like it was around col 45?). In the last image, the divider appears at about x=460/704*64 ≈ 42... and the black shape at ~x=590/704*64 ≈ 53.
Hmm, so in the current frame, the divider is at cols 45-47. But earlier it was at 36-38! Did the divider move? Or did the divider get covered by the charcoal, making the S segment split?
Wait, the S nodes: node 1 = S 48 spanning rows 0-17 at cols 45-47, node 16 = S 112 spanning rows 21-62 cols 45-47. Together they're the vertical strip at cols 45-47 (rows 0-62 minus rows
… [1842 caracteres más]

```python
def divider(fr):
    seg=fr.segmentation
    cols=set()
    for n in seg['nodes']:
        if n['color']=='S' and n['pixels']>20:
            b=n['boundary']; cs=[p[1] for p in b]
            cols.add((min(cs),max(cs)))
    return sorted(cols)
def cbox(fr):
    seg=fr.segmentation
    out={}
    for n in seg['nodes']:
        if n['color'] in 'cB' and n['pixels']>=40 and n['pixels']<100:
            b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
            out[n['color']+'%d'%n['pixels']]=(min(rs),min(cs),max(rs),max(cs))
    return out
for t in transitions[-8:]:
    print(t.action, 'div', divider(t.before_frame), '->', divider(t.after_frame), '| c/B', cbox(t.after_frame))
```

```text
LEFT div [(36, 38)] -> [(33, 35)] | c/B {'c72': (18, 9, 29, 23), 'B64': (18, 45, 29, 59), 'B63': (63, 0, 63, 62)}
UNDO div [(33, 35)] -> [(36, 38)] | c/B {'c72': (18, 15, 29, 29), 'B64': (18, 45, 29, 59), 'B63': (63, 0, 63, 62)}
UP div [(36, 38)] -> [(36, 38)] | c/B {'c72': (18, 15, 29, 29), 'B64': 
… [617 caracteres más]
```

**Pensamiento:**

Now it's clear: the DIVIDER moves with the charcoal shape! The divider moves +3 per RIGHT press while the charcoal moves +6. Hmm:
- Start: divider 36-38, charcoal 15-29.
- LEFT: divider 33-35 (-3), charcoal 9-23 (-6).
- RIGHT: divider 39-41 (+3), charcoal 21-35 (+6).
So the divider moves at half the speed of the charcoal, in the same direction.
Interesting! So the divider is a "half-speed" element. Hmm, why? Maybe the divider is a "mirror" that reflects... Actually maybe the divider position = charcoal center? Let's check: charcoal center col = (15+29)/2 = 22; divider center = 37. Hmm, 37 = 22 + 15? After RIGHT: charcoal center 28, divider center 40 → 28+12. Not constant.
Hmm, so what's the relationship? Maybe the divider moves at half the rate because the divider is "the mirror plane" between the charcoal and its reflection... no.
Hmm wait. What if the divider is not moving per se, but the two panels scroll at different rates (like a parallax)? Let's think: maybe the whole board is like two layers sliding.
Alternatively: maybe the divider moves by 3 for each press because it's affected by the shape's movement at half rate... Actually maybe the mechanic is: pressing RIGHT shifts the charcoal +6 and everything else (divider) +3? Let's check the black shape: it stayed at 45-59 in all these. And the yellow target stayed at 3-17. So no, only the divider moves at half speed.
Hmm, that's an odd mechanic. Maybe the divider is a "cursor" whose position matters for the win condition? 
… [14200 caracteres más]

```python
print('start c', cbox(current_frame))
for i in range(2):
    r=try_act('LEFT'); print('LEFT',r[1], r[2].get('c63') or r[2].get('c72'))
s=snap()
print('c now', [ (k,v) for k,v in s.items() if k[0]=='c'])
r=try_act('DOWN'); print('DOWN', r[0], r[1], [ (k,v) for k,v in r[2].items() if k[0]=='c'])
```

```text
start c {'c63': (18, 33, 29, 44), 'B64': (18, 45, 29, 59), 'B63': (63, 0, 63, 62)}
[action] LEFT -> effect
LEFT False None
[action] LEFT -> effect
LEFT False None
c now [(('c', 72), (18, 21, 29, 35))]
[action] DOWN -> NO-OP (executed, no change inside the board area)
DOWN ok True [(('c', 72), (18, 2
… [12 caracteres más]
```

## Paso 11 · nivel 2 · acción 35

**Pensamiento:**

DOWN still a no-op even when aligned. So vertical movement is not possible via arrows. 
New hypothesis: maybe the charcoal shape's vertical position changes when it crosses the mirror? Or maybe the mirror reflection means: the black shape is the charcoal's reflection, and the yellow target is the reflection of something? Let's check: mirror of the yellow target (rows 42-53, cols 3-17) about the divider center... currently divider center = (21+35)/2 = 28... hmm, the divider is at 36-38 again (center 37) since we moved back. Mirror of yellow about 37: cols 57-71 → out of bounds. So no.
Alternative hypothesis: maybe the goal is to make the black shape and charcoal overlap into a complete picture, or the goal is for the charcoal to reach the position where its mirror image coincides with... hmm.
Let me reconsider: maybe SPACE does something here (in level 1 it was a no-op). Let's test SPACE, and MOUSE clicks. Also, maybe the shape can be rotated with SPACE, and the target requires... but the target has the same orientation, so no rotation needed.
Wait. Maybe I should reconsider the level-1 win condition. In level 1, the win happened when the charcoal landed exactly on the yellow. But maybe the real win condition was something else that coincided — e.g., the black dotted shape's mirror... hmm, in level 1 the black moved to rows 45-53 cols 3-11, and the mirror of the charcoal (about the fixed divider 30-32) was... let me check: level 1's divider — did it move? Let me check with div
… [5169 caracteres más]

```python
r=try_act('SPACE'); print('SPACE',r[0],r[1],r[2])
```

```text
[action] SPACE -> effect
SPACE ok False {('Y', 57): (7, 63, 63, 63), ('c', 72): (18, 21, 29, 35), ('B', 64): (18, 45, 29, 59), ('Y', 72): (42, 3, 53, 17), ('B', 63): (63, 0, 63, 62)}
```

## Paso 12 · nivel 2 · acción 40

**Pensamiento:**

Very interesting! SPACE changed the dots: the black shape's dots turned from blue (b) to white (W), and the divider's dots turned from white to blue! Look at the diff image: the divider dots are now blue (changed from white), and the black shape's dots are now white (changed from blue).
So SPACE swaps the dot colors between the divider and the black shape! Hmm, that's a toggle. So the divider has dots (white) and the black shape has dots (blue = background color showing through holes?). Wait, initially the black shape had 'b' (blue) dots — i.e., holes in the black shape showing the background. And the divider had white dots.
After SPACE: the black shape's holes became white, and the divider's dots became blue.
Hmm, so SPACE toggles/rotates the "dot phase"? Maybe the dots are like a "lock combination"? Or maybe the dots represent "sockets" and "pegs" — the divider has white pegs, and the shape has holes; when the shape is placed on the divider, the pegs fill the holes?
Interesting! Maybe the mechanic: the divider is a "comb" with white dots at rows 1,4,7,...,61 (every 3 rows, at col 37). The black shape has holes at its block centers. When the shape overlaps the divider, the holes must align with the pegs?
Hmm, what about the yellow target? It has no dots.
Let me check the current state precisely: which cells are white vs blue now.
Let me diff the SPACE transition in detail.

```python
t = transitions[-1]
b=t.before_frame.ascii.split('\n'); af=t.after_frame.ascii.split('\n')
ch=[]
for r in range(64):
    for c in range(64):
        if b[r][c]!=af[r][c]: ch.append((b[r][c]+'>'+af[r][c], r, c))
from collections import Counter
cnt = Counter(x[0] for x in ch)
print('SPACE changes', cnt)
print('sample', ch[:12])
# divider dot rows before/after
for lbl,fr in (('before',b),('after',af)):
    rows=[r for r in range(64) if fr[r][37]=='W']
    print(lbl,'W in col37 rows', rows[:5], '...', rows[-5:], 'count', len(rows))
    rowsB=[r for r in range(64) if fr[r][37]=='b']
    print(lbl,'b in col37 count', len(rowsB))
```

```text
SPACE changes Counter({'W>b': 21, 'b>W': 8, 'Y>B': 1})
sample [('W>b', 1, 40), ('W>b', 4, 40), ('Y>B', 6, 63), ('W>b', 7, 40), ('W>b', 10, 40), ('W>b', 13, 40), ('W>b', 16, 40), ('W>b', 19, 40), ('b>W', 19, 46), ('b>W', 19, 49), ('b>W', 19, 52), ('W>b', 22, 40)]
before W in col37 rows [] ... [] coun
… [96 caracteres más]
```

**Pensamiento:**

The divider is now at col 40 (since the charcoal moved left, the divider moved with it). The changes: 21 W>b at col 40 (divider dots turned blue) and 8 b>W at the black shape's dot positions (holes turned white).
So SPACE swaps: divider dots white→blue, shape holes blue→white. That's a color toggle. What does it mean? Maybe it's a "phase" toggle: the dots on the divider are at rows 1,4,7,... (offset 1 mod 3), and the shape's holes are at its block centers. Hmm.
Hmm, maybe SPACE toggles which of the two is "male/female" (pegs vs holes). Or maybe SPACE is a "commit/lock" action.
Actually, maybe the important thing: maybe SPACE doesn't matter for the goal. Let me reconsider.
Let me reconsider the whole game concept. Two panels separated by a mirror line. Left panel: a plain (charcoal) shape and a yellow target shape. Right panel: a dotted black shape which is the mirror image of the charcoal shape.
In level 1: dotted black on the LEFT, plain charcoal on the RIGHT, yellow target on the right. Both shapes moved with arrows (mirror-linked), and the goal was to land the plain shape on the yellow target.
Hmm wait, actually! Maybe in level 1 the dotted black shape is the "player" and the plain one is its reflection. In level 2 the dotted black is on the right and the plain is on the left. And when I press LEFT in level 2, the plain one moves left by 6 and the dotted one doesn't move.
Hmm, so in level 1 both moved; in level 2 only one moves. What if in level 2 the dotted shape CAN'T mo
… [1510 caracteres más]

```python
for i in range(5):
    r=try_act('LEFT')
    s=r[2]
    c=[v for k,v in s.items() if k[0]=='c']
    print('LEFT',i+1,r[0],'noop' if r[1] else '', 'c',c, 'div', divider(current_frame))
```

```text
[action] LEFT -> effect
LEFT 1 ok  c [(18, 24, 29, 38)] div [(39, 41)]
[action] LEFT -> effect
LEFT 2 ok  c [(18, 27, 29, 38)] div [(39, 41)]
[action] LEFT -> effect
LEFT 3 ok  c [(21, 30, 29, 38)] div [(39, 41)]
[action] LEFT -> effect
LEFT 4 ok  c [] div [(39, 41)]
[action] LEFT -> effect
LEFT 5 o
… [38 caracteres más]
```

## Paso 13 · nivel 2 · acción 40

**Pensamiento:**

WOW, big change! The charcoal shape is now at (18,42)-(26,50) — it moved to the RIGHT side of the divider and its shape changed?! Let me look at the image: the black dotted shape is now at cols ~360-450 px (cols 33-45?) and the charcoal is to the right of the divider at cols ~430-560px.
Wait, the current frame shows: divider at cols 39-41 with blue dots. The black dotted shape is at cols ~30-41 (left of divider, partially?) and the charcoal shape appears at cols 42-50, rows 18-26 — and the charcoal shape looks DIFFERENT now: it looks like a mirrored/rotated Z?
Hmm, and the previous LEFT presses: the charcoal moved right (from 21-35 to 24-38, 27-38, 30-38, then disappeared, then appeared at 42-50)! That's bizarre. It looks like the shape is being CLIPPED by the divider as it passes: at (18,24,29,38) visible, then (18,27,29,38) — clipped at col 38 (the divider starts at 39), then (21,30,29,38), then nothing visible (fully hidden behind the divider? no...), then (18,42,26,50) — appeared on the right side of the divider with a smaller bbox (rows 18-26, 9 rows instead of 12).
Hmm, this suggests the shape WRAPPED around: as it moved left, parts went off... no wait.
Hold on. The LEFT presses moved the shape RIGHT? Let me recheck: before these presses, c was at (18,21,29,35). After LEFT 1: (18,24,29,38). That's +3 right? And the divider stayed at 39-41 (it was 39-41 before? Earlier after SPACE, divider... let me think: the divider was at 40 center. Yes div [(39,41)] throughout these 
… [2388 caracteres más]

```python
seg=current_frame.segmentation
for n in seg['nodes']:
    if n['pixels']>8:
        b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
        print(n['id'],n['color'],n['pixels'],(min(rs),min(cs),max(rs),max(cs)))
a=current_frame.ascii.split('\n')
print('--- rows 16-32 cols 20-62')
for r in range(16,33): print(r, a[r][20:63])
```

```text
0 b 2331 (0, 0, 62, 38)
1 S 72 (0, 39, 26, 41)
2 b 1269 (0, 42, 62, 62)
3 B 12 (0, 63, 11, 63)
8 Y 52 (12, 63, 63, 63)
11 B 64 (18, 30, 29, 44)
12 c 45 (18, 42, 26, 50)
24 S 88 (30, 39, 62, 41)
29 Y 72 (42, 3, 53, 17)
37 B 63 (63, 0, 63, 62)
--- rows 16-32 cols 20-62
16 bbbbbbbbbbbbbbbbbbbSbSbbbbbbb
… [766 caracteres más]
```

**Pensamiento:**

Now I see! The black dotted shape is now at cols 30-44 (bbox), i.e., it MOVED LEFT! And the charcoal is at cols 42-50, rows 18-26 — a smaller shape (45 px = 5 blocks).
So what happened: the black dotted shape moved left (in the direction of the presses), and the charcoal is its mirror image, partially clipped by the divider!
Let me verify: the black shape (dotted, now the "player") is at rows 18-29, cols 30-44 (bbox 15 wide = 5 blocks). Wait, the original black shape was 5 blocks wide? Original black: rows 18-29, cols 45-59 (15 wide, 12 tall) = 8 blocks. Now it's at (18,30)-(29,44): 15 wide, 12 tall ✓ same size, 64 pixels ✓ (same as before).
And the charcoal is at (18,42)-(26,50): 9 wide, 9 tall, 45 px = 5 blocks. Hmm, the charcoal was 72 px = 8 blocks. Now only 45 px visible. So the charcoal is partly hidden — hidden behind the divider? The divider is at cols 39-41. The charcoal bbox 42-50 doesn't include the divider... 
Hmm! Unless the charcoal is hidden behind the black shape! The black shape is at cols 30-44, and the charcoal at 42-50 → overlap at cols 42-44. The charcoal's left part (cols 36-41) is hidden behind the black shape (which spans up to col 44) and the divider.
So the charcoal (mirror image) is at cols 36-50 in full, with cols 36-41 hidden behind the black shape/divider.
Let's verify the mirror relation: mirror line center = 40. Charcoal full bbox [36,50] → mirror = [30,44] ✓ = black's bbox. 
So the black dotted shape is the PLAYER (moves with arrows), and the 
… [5769 caracteres más]

```python
def boxes(fr):
    seg=fr.segmentation; out={}
    for n in seg['nodes']:
        if n['pixels']>=9 and n['color'] in 'cB' and n['pixels']<100:
            b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
            out.setdefault(n['color'],[]).append((n['pixels'],min(rs),min(cs),max(rs),max(cs)))
    return out
for t in transitions[-9:]:
    print(t.action, 'before', boxes(t.before_frame), 'after', boxes(t.after_frame), 'div', divider(t.before_frame),'->',divider(t.after_frame))
```

```text
LEFT before {'c': [(63, 18, 33, 29, 44)], 'B': [(64, 18, 45, 29, 59), (63, 63, 0, 63, 62)]} after {'c': [(72, 18, 27, 29, 41)], 'B': [(64, 18, 45, 29, 59), (63, 63, 0, 63, 62)]} div [(45, 47)] -> [(42, 44)]
LEFT before {'c': [(72, 18, 27, 29, 41)], 'B': [(64, 18, 45, 29, 59), (63, 63, 0, 63, 62)]} a
… [1748 caracteres más]
```

## Paso 13 · nivel 2 · acción 41

**Pensamiento:**

Now the transitions are clearer. Let me carefully re-read the last 9 transitions:
1. LEFT: before c63 at (18,33,29,44) [clipped by divider at 45-47], B64 at (18,45,29,59), div 45-47 → after c72 at (18,27,29,41), B unchanged, div 42-44.
2. LEFT: c 27-41 → 21-35, B unchanged 45-59, div 42-44 → 39-41.
3. DOWN: no-op.
4. SPACE: dots swapped (c and B bboxes unchanged).
5. LEFT: c 21-35 → 24-38 (72 px, so NOT clipped... hmm, 24-38 is 15 wide = full width, and 72 px = full), B 45-59 → 42-56, div stays 39-41.
   So now: c moved +3, B moved -3, symmetric about div center 40. Mirror of [24,38] about 40 = [42,56] ✓.
6. LEFT: c 24-38 → 63px at 27-38 (clipped: full would be 27-41, but 39-41 is the divider strip, so 3 blocks... wait, clipping by the divider removes cols 39-41 → 63 px if a block is there). B 42-56 → 39-53.
7. LEFT: c → 45px at (21,30,29,38); B 39-53 → 36-50.
8. LEFT: c → two components (18,42,20,47) and (18,27,33,29,38)... this is the c being split by the black shape overlapping. B 36-50 → 33-47.
9. LEFT: c → 45px at (18,42,26,50); B 33-47 → 30-44.
So after SPACE, the behavior changed! Before SPACE: LEFT moved the c by -6 and the div by -3, with B fixed. After SPACE: LEFT moves the B by -3 and the c by +3, with the div fixed.
Interesting — so SPACE swapped which shape is the "player"! Before SPACE, the plain charcoal was the player (moving -6 per press?!) and after SPACE the black dotted one is the player (moving -3 per press).
Hmm, that -6 vs -3 is strange. Unless... befor
… [15026 caracteres más]

```python
r=try_act('DOWN'); print('DOWN',r[0],'noop' if r[1] else 'moved', boxes(current_frame), divider(current_frame))
```

```text
[action] DOWN -> effect
DOWN ok moved {'B': [(13, 0, 63, 12, 63), (64, 21, 30, 32, 44), (63, 63, 0, 63, 62)], 'c': [(45, 21, 42, 29, 50)]} [(39, 41)]
```

## Paso 14 · nivel 2 · acción 41

**Pensamiento:**

DOWN worked: the black shape moved from rows 18-29 to rows 21-32 (down 3). The charcoal is still visible at (21,42,29,50) — hmm, its bbox min row is 21, but it should also move down 3 → rows 21-32. The visible charcoal bbox is (21,42,29,50) = 45 px. Hmm, it says rows 21-29, 9 rows, 45 px = 5 blocks. Before DOWN the visible charcoal was (18,42,26,50) = rows 18-26. So after DOWN it's rows 21-29 → moved down 3 ✓ (the visible portion is 5 blocks; the hidden part is behind the divider/black).
So in the current mode (post-SPACE), DOWN moves both shapes down 3 ✓. Vertical mirror symmetry preserved.
So the model is confirmed: mode (a) = shape control; both shapes move together vertically.
Now I need:
- Vertical: charcoal rows 18-29 → need 42-53: +24 → 8 DOWN presses ✓ (currently rows 21-32 after 1 DOWN, so 7 more).
- Horizontal: charcoal cols 36-50 → need 3-17: -33.
With mode (a): RIGHT moves charcoal -3, black +3. Black center currently 37 → after a presses: 37+3a ≤ 55 → a ≤ 6.
With mode (b) (after SPACE): LEFT moves charcoal -6, d -3.
Plan: a=5, b=3: 5 RIGHT (mode a) then SPACE then 3 LEFT (mode b)? Let's verify the order matters for intermediate bounds. Let's compute:
Current: x=43 (charcoal center), y=37 (black center), d=40.
5× RIGHT (mode a): x=43-15=28, y=37+15=52, d=40. Check black bbox [45,59] ⊆ board ✓.
SPACE → mode (b). 3× LEFT (mode b): x=28-18=10 ✓, y=52 (fixed), d=40-9=31 ✓. Charcoal cols [3,17] ✓. Black [45,59] ✓ (mirror of [3,17] about 31 ✓).
Total horizontal: 8 press
… [1470 caracteres más]

```python
def pixset(fr, color, minpx=9):
    seg=fr.segmentation; out=set()
    a=fr.ascii.split('\n')
    for r in range(64):
        for c in range(64):
            if a[r][c]==color: out.add((r,c))
    return out
fr=current_frame
B=pixset(fr,'B')
B={(r,c) for r,c in B if r<60}  # exclude bottom bar
Y=pixset(fr,'Y')
Y={(r,c) for r,c in Y if c<60}  # exclude right bar
# mirror about d=40 (cols 39-41 center 40)
mir={(r, 80-c) for r,c in B}
# translation to align mir -> Y
minr_m=min(r for r,c in mir); minc_m=min(c for r,c in mir)
minr_y=min(r for r,c in Y); minc_y=min(c for r,c in Y)
dr=minr_y-minr_m; dc=minc_y-minc_m
moved={(r+dr,c+dc) for r,c in mir}
print('mirrored charcoal bbox', (minr_m,minc_m,max(r for r,c in mir),max(c for r,c in mir)))
print('yellow bbox', (minr_y,minc_y,max(r for r,c in Y),
… [127 caracteres más]
```

```text
mirrored charcoal bbox (0, 17, 32, 50)
yellow bbox (42, 3, 53, 17)
shape match after translate 42 -14 False
mir size 77 yellow size 72
```

**Pensamiento:**

The mirrored black has 77 pixels — that's more than 72 because the black shape includes the dots? No wait, after SPACE the black shape's holes are WHITE, so the black shape is a full solid 8-block shape? Hmm, 8 blocks × 9 = 72. But we got 77. Hmm, because the black shape now has white dots inside (8 dots) → black pixels = 72 - 8 = 64 (matches B64). And the mirrored set from B (64 px) should be 64, but I computed 77?
Oh! I mirrored B which is 64 px... let me recount: I filtered r<60 to exclude the bottom bar (63 px at row 63). So B = 64 px. mir should be 64. But len(mir)=77? That can't be unless B had 77 pixels. Hmm, maybe there are other 'B' cells: the top-right HUD bar is 'B' at col 63 rows 0-13 (13 px) — I filtered c<60 only for Y, not for B! So B included 13 HUD pixels → 64+13=77. Yes.
Let me redo with proper filtering.

```python
fr=current_frame
B={(r,c) for r,c in pixset(fr,'B') if r<60 and c<60}
Y={(r,c) for r,c in pixset(fr,'Y') if r<60 and c<60}
mir={(r, 80-c) for r,c in B}
mr=min(r for r,c in mir); mc=min(c for r,c in mir)
yr=min(r for r,c in Y); yc=min(c for r,c in Y)
dr=yr-mr; dc=yc-mc
moved={(r+dr,c+dc) for r,c in mir}
print('sizes', len(B), len(mir), len(Y))
print('mir bbox', (mr,mc,max(r for r,c in mir),max(c for r,c in mir)), 'yellow bbox',(yr,yc,max(r for r,c in Y),max(c for r,c in Y)))
print('match', moved==Y, 'delta', dr, dc)
print('diff cells', sorted(moved ^ Y)[:20])
```

```text
sizes 64 64 72
mir bbox (21, 36, 32, 50) yellow bbox (42, 3, 53, 17)
match False delta 21 -33
diff cells [(43, 10), (43, 13), (43, 16), (46, 10), (49, 10), (52, 4), (52, 7), (52, 10)]
```

**Pensamiento:**

The mirrored black (with white dots as holes) has 64 px; the yellow has 72 (solid). The 8 differing cells are exactly the dot positions — so the shapes match except the black has 8 holes (dots). So the charcoal (mirror of black) is the black shape with 8 holes, while the yellow target is solid.
Hmm! That's the key: the dots! In level 1, the dotted black shape had 5 white dots inside a 40-px shape (the shape had 45 cells minus 5 dots = 40 ✓). The plain charcoal was solid 45 px. And the yellow target was solid 45 px. So in level 1, the plain shape was solid and matched the yellow.
So here the CHARCOAL (mirror image) is drawn as solid charcoal (72 px when unoccluded) — the mirror image doesn't inherit the holes! Right: the charcoal was 72 px = 8 blocks solid, while the black has 64 px (8 blocks minus 8 dot cells). So the mirror image is the "filled" version.
So the mirror of the black's outer shape (filled) = 72 px = matches the yellow's 72 px. My comparison used the dotted black. Let me compare the FILLED black (black + its dot holes) mirrored vs yellow.
Filled black = B ∪ {(19,46),(19,49),(19,52),(22,52),(25,52),(28,52),(28,55),(28,58)} (the white dots inside the black).
Let me verify: filled black mirrored + translated == yellow?
Also important: the delta needed is dr=21 (rows) and dc=-33 (cols) from the current position. Rows: the charcoal is at rows 21-32 (after 1 DOWN); the target rows are 42-53 → +21 = 7 DOWN presses ✓. Cols: -33 ✓ as computed.
Let me verify the shape mat
… [3637 caracteres más]

```python
fr=current_frame
a=fr.ascii.split('\n')
B={(r,c) for r in range(60) for c in range(60) if a[r][c]=='B'}
W={(r,c) for r in range(60) for c in range(60) if a[r][c]=='W'}
Y={(r,c) for r in range(60) for c in range(60) if a[r][c]=='Y'}
# dots inside black = white cells within black bbox rows 21-32 cols 30-44
dots={p for p in W if 21<=p[0]<=32 and 30<=p[1]<=44}
filledB = B | dots
print('B',len(B),'dots',len(dots),'filled',len(filledB),'Y',len(Y))
mir={(r,80-c) for r,c in filledB}
mr=min(r for r,c in mir); mc=min(c for r,c in mir)
yr=min(r for r,c in Y); yc=min(c for r,c in Y)
dr=yr-mr; dc=yc-mc
moved={(r+dr,c+dc) for r,c in mir}
print('mir bbox',(mr,mc,max(r for r,c in mir),max(c for r,c in mir)),'need delta',dr,dc)
print('FILLED SHAPE MATCH:', moved==Y)
```

```text
B 64 dots 8 filled 72 Y 72
mir bbox (21, 36, 32, 50) need delta 21 -33
FILLED SHAPE MATCH: True
```

**Nivel 2 completado → nivel 3 (acción 57)**

## Paso 14 · nivel 3 · acción 57

**Pensamiento:**

Confirmed: the filled mirror shape matches the yellow target exactly; needed delta = (+21 rows, -33 cols).
Plan: 7 DOWN (mode A), 5 RIGHT (mode A), SPACE (→ mode B), 3 LEFT (mode B).
Let me execute step by step with checks, stopping on level completion. I'll use try_act to avoid stale-state errors, checking after each action.
Careful: in mode A, RIGHT moves the black +3 and the charcoal -3. Let me verify after the first RIGHT that the charcoal moves -3 as expected (to catch sign errors early).
Let me execute: 7 DOWN, then check; then 1 RIGHT, check; then 4 more RIGHT if the direction is right; then SPACE, then 1 LEFT, check; then 2 more LEFT.
I'll write a loop that executes the plan but verifies after each action and aborts if the charcoal moves the wrong way. Let me define a helper that returns the charcoal's full center (using the mirror relation: charcoal center = 2*d - black center, robust to occlusion).
Compute: black center from B64 bbox; d from divider. Then x = 2d - y.
Let me write it.

```python
def state(fr):
    a=fr.ascii.split('\n')
    B={(r,c) for r in range(60) for c in range(60) if a[r][c]=='B'}
    S=[c for c in range(64) if a[30][c]=='S']
    d=(min(S)+max(S))/2 if S else None
    ys=[c for r,c in B]; yc=(min(ys)+max(ys))/2
    return {'d':d,'black_c':yc,'char_c':2*d-yc,'black_rows':(min(r for r,c in B),max(r for r,c in B)),'Y':None}
def goal_ok(fr):
    a=fr.ascii.split('\n')
    Y={(r,c) for r in range(60) for c in range(60) if a[r][c]=='Y'}
    if len(Y)<72: return False
    yr=min(r for r,c in Y); yc=min(c for r,c in Y)
    return (yr,yc)==(42,3)
s=state(current_frame); print('start',s)
plan = ['DOWN']*7 + ['RIGHT']*5 + ['SPACE'] + ['LEFT']*3
for i,act in enumerate(plan):
    r=try_act(act)
    st=state(current_frame)
    print(i,act,r[0],'noop' if r[1] else '', 'cha
… [441 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 14, in <module>
  File "<python_tool>", line 7, in state
TypeError: unsupported operand type(s) for *: 'int' and 'NoneType'
```

**Pensamiento:**

The divider detection failed: at row 30 there may be no 'S' cells (the divider might be occluded by the shape at that row, or the divider is elsewhere). Let me make state() more robust: find S cells across all rows in a column-wise manner: find columns where the count of 'S' cells is high.
Also the error occurred at i=0? No—the error occurred in the initial `state(current_frame)` call before the loop (line 14 = the `s=state(...)` line). So no actions were executed. Good.
Let me fix state().

```python
def state2(fr):
    a=fr.ascii.split('\n')
    B={(r,c) for r in range(60) for c in range(60) if a[r][c]=='B'}
    colS={}
    for c in range(64):
        n=sum(1 for r in range(63) if a[r][c]=='S')
        if n>10: colS[c]=n
    d=(min(colS)+max(colS))/2 if colS else None
    ys=[c for r,c in B]; yc=(min(ys)+max(ys))/2
    Y={(r,c) for r in range(60) for c in range(60) if a[r][c]=='Y'}
    yt=(min(r for r,c in Y),min(c for r,c in Y)) if Y else None
    return (d, yc, (2*d-yc) if d is not None else None, (min(r for r,c in B),max(r for r,c in B)), yt)
print(state2(current_frame))
```

```text
(40.0, 37.0, 43.0, (21, 32), (42, 3))
```

**Pensamiento:**

State confirmed: d=40, black center 37, charcoal center 43, black rows 21-32, yellow at (42,3).
Needed: charcoal center 10 (cols 3-17), rows 42-53.
Plan: 7 DOWN, 5 RIGHT, SPACE, 3 LEFT.
Let me execute with verification after each step.

```python
plan = ['DOWN']*7 + ['RIGHT']*5 + ['SPACE'] + ['LEFT']*3
for i,act in enumerate(plan):
    r=try_act(act)
    st=state2(current_frame)
    res=last_action_call_result
    print(i,act,r[0],'noop' if r[1] else '','d',st[0],'blk_c',st[1],'chr_c',st[2],'rows',st[3],'Ytl',st[4],'lc',res.get('level_completed'),'go',res.get('game_over'))
    if res.get('level_completed') or res.get('game_over'): print('STOP'); break
```

```text
[action] DOWN -> effect
0 DOWN ok  d 40.0 blk_c 37.0 chr_c 43.0 rows (24, 35) Ytl (42, 3) lc False go False
[action] DOWN -> effect
1 DOWN ok  d 40.0 blk_c 37.0 chr_c 43.0 rows (27, 38) Ytl (42, 3) lc False go False
[action] DOWN -> effect
2 DOWN ok  d 40.0 blk_c 37.0 chr_c 43.0 rows (30, 41) Ytl (4
… [1457 caracteres más]
```

## Paso 15 · nivel 3 · acción 59

**Pensamiento:**

Level 3! New layout: the mirror line is now HORIZONTAL (at rows ~49-51, a horizontal divider with white dots). Multiple shapes: yellow shapes and black dotted shapes.
Let me inspect the board.
Objects visible:
- Yellow "T"-ish shape at top-left (~rows 8-15, cols 8-20).
- Yellow "L"/corner shape at top-middle (~rows 3-15, cols 33-44).
- Black dotted "L" at left-middle (rows 21-33, cols 12-23).
- Black dotted shape at right-middle (rows 27-33, cols 45-57).
- Yellow "T" at rows 42-49, cols 8-20.
- Yellow "L" at rows 42-55, cols 33-44.
- Horizontal divider at rows 49-51 with white dots.
So now the mirror is horizontal: the shapes above the line reflect below. The yellow shapes below the line are the mirror images (reflections) of the shapes above? Let's check: the top-left yellow T at rows 8-15 vs the bottom yellow T at rows 42-49: mirror about row 50: row r → 100-r. Rows 8-15 → 85-92, no. So not a mirror of the top one.
Hmm. Let me look at the segmentation carefully.
Note: the mirror line is horizontal, so the reflection flips vertically. The two black dotted shapes: left one is an L (vertical bar + horizontal foot), the right one is a T-ish shape.
Let me get the data.

```python
fr=current_frame
seg=fr.segmentation
for n in seg['nodes']:
    if n['pixels']>6:
        b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
        print(n['id'],n['color'],n['pixels'],(min(rs),min(cs),max(rs),max(cs)))
a=fr.ascii.split('\n')
print('--- top-left yellow')
for r in range(6,18): print(r,a[r][6:24])
print('--- top-mid yellow')
for r in range(2,17): print(r,a[r][31:46])
print('--- black L mid-left')
for r in range(20,34): print(r,a[r][10:26])
print('--- black right')
for r in range(26,34): print(r,a[r][43:59])
```

```text
0 b 2718 (0, 0, 47, 62)
1 Y 64 (0, 63, 63, 63)
2 Y 63 (3, 33, 14, 44)
3 Y 54 (9, 9, 14, 20)
4 B 56 (21, 12, 32, 23)
7 B 48 (27, 45, 32, 56)
19 Y 54 (42, 9, 47, 20)
20 Y 63 (42, 33, 53, 44)
21 S 88 (48, 0, 50, 32)
22 S 72 (48, 36, 50, 62)
43 b 720 (51, 0, 62, 62)
44 B 63 (63, 0, 63, 62)
--- top-left 
… [1039 caracteres más]
```

**Pensamiento:**

Level 3 layout:
- Mirror line: horizontal at rows 48-50 (S), with white dots at row 49.
- Above the line: 
  - Yellow T-shape (node 3): rows 9-14, cols 9-20: a "T" (top stem rows 9-11 cols 12-17... let me see: rows 9-11: cols 12-17 (6 wide = 2 blocks); rows 12-14: cols 9-20 (12 wide = 4 blocks). So a T shape: 2+4 = 6 blocks = 54 px ✓.
  - Yellow corner (node 2): rows 3-14, cols 33-44: rows 3-5 cols 33-44 (4 blocks), rows 6-14 cols 33-35 (3 blocks). L-shape, 7 blocks = 63 ✓.
  - Black dotted L (node 4): rows 21-32, cols 12-23: vertical bar rows 21-29 cols 12-14 (3 blocks), horizontal rows 30-32 cols 12-23 (4 blocks) = 7 blocks = 63-7 dots = 56 ✓.
  - Black dotted T (node 7): rows 27-32, cols 45-56: rows 27-29 cols 45-56 (4 blocks), rows 30-32 cols 48-53 (2 blocks) = 6 blocks = 54-6=48 ✓.
- Below the line:
  - Yellow T (node 19): rows 42-47, cols 9-20 — wait, rows 42-47 is ABOVE the line (48-50). Hmm, node 19 at (42,9)-(47,20): that's above the line.
  - Yellow L (node 20): rows 42-53, cols 33-44 — crosses the line!
Let me re-look at the image: the yellow T at rows 42-47 (above the line) and the yellow L from rows 42 to 53 crossing the line.
So objects:
1. Yellow T at rows 9-14, cols 9-20 (top-left).
2. Yellow T at rows 42-47, cols 9-20 (mid-left, just above the line).
3. Yellow L at rows 3-14, cols 33-44 (top-middle).
4. Yellow L at rows 42-53, cols 33-44 (crossing the line).
5. Black dotted L at rows 21-32, cols 12-23.
6. Black dotted T at rows 27-32, cols 45-56.
Hmm, interes
… [549 caracteres más]

```python
a=current_frame.ascii.split('\n')
print('--- node19 yellow T rows 40-49 cols 6-23')
for r in range(40,50): print(r,a[r][6:24])
print('--- node20 yellow L rows 40-56 cols 31-46')
for r in range(40,57): print(r,a[r][31:47])
print('--- line rows 47-52 cols 0-20')
for r in range(47,53): print(r,a[r][0:20])
```

```text
--- node19 yellow T rows 40-49 cols 6-23
40 bbbbbbbbbbbbbbbbbb
41 bbbbbbbbbbbbbbbbbb
42 bbbYYYYYYYYYYYYbbb
43 bbbYYYYYYYYYYYYbbb
44 bbbYYYYYYYYYYYYbbb
45 bbbbbbYYYYYYbbbbbb
46 bbbbbbYYYYYYbbbbbb
47 bbbbbbYYYYYYbbbbbb
48 SSSSSSSSSSSSSSSSSS
49 SWSSWSSWSSWSSWSSWS
--- node20 yellow L rows 40-56 cols 31-
… [516 caracteres más]
```

**Pensamiento:**

Now I see:
- Node 19 (yellow T at rows 42-47, cols 9-20): bar on top (rows 42-44 cols 9-20), stem below (rows 45-47 cols 12-17) = a "T" shape (normal T).
- Node 3 (yellow T at rows 9-14, cols 9-20): stem on top (rows 9-11), bar below (rows 12-14) = inverted T (⊥).
These two are vertical mirrors of each other! Mirror about the horizontal line at row 49: node 19 rows 42-47 → mirror rows 51-56. Not node 3's rows. So they're not positioned as mirror images, but their SHAPES are vertical mirrors of each other.
- Node 20 (yellow L crossing the line): rows 42-47 stem cols 33-35, rows 51-53 bar cols 33-44. So it's an L with a vertical stem going up and a horizontal bar at the bottom going right.
- Node 2 (yellow L at rows 3-14, cols 33-44): bar on top rows 3-5 cols 33-44, stem rows 6-14 cols 33-35 (going down from the left end).
Node 2's shape: bar at top, stem going down at the left. Node 20: stem going up at the left, bar at bottom. These are vertical mirrors of each other ✓ (flipping node 2 vertically: bar at bottom, stem going up at the left = node 20 ✓).
So: the yellow shapes above the line are vertical mirrors of the shapes below... but they're at different positions.
Hmm, wait. Now the key insight: the mirror line is horizontal, so the reflection of a shape above the line appears below the line, flipped vertically. The plain yellow shapes are the reflections of the black dotted shapes? Let's check: 
- Black dotted L (node 4): vertical bar rows 21-29 cols 12-14 (stem going down
… [7797 caracteres más]

```python
def comp(fr):
    seg=fr.segmentation; out={}
    for n in seg['nodes']:
        if n['pixels']>=20 and n['pixels']<400:
            b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
            out[(n['color'],n['pixels'])]=(min(rs),min(cs),max(rs),max(cs))
    return out
print('init', comp(current_frame))
for act in ['DOWN','LEFT','UP','RIGHT']:
    r=try_act(act)
    b=comp(previous_frame); a2=comp(current_frame)
    ch={k:(b.get(k),a2.get(k)) for k in set(b)|set(a2) if b.get(k)!=a2.get(k)}
    print(act,'noop' if r[1] else ch)
    if r[0]!='ok': break
```

```text
init {('Y', 64): (0, 63, 63, 63), ('Y', 63): (42, 33, 53, 44), ('Y', 54): (42, 9, 47, 20), ('B', 56): (21, 12, 32, 23), ('B', 48): (27, 45, 32, 56), ('S', 88): (48, 0, 50, 32), ('S', 72): (48, 36, 50, 62), ('B', 63): (63, 0, 63, 62)}
[action] DOWN -> effect
DOWN {('S', 48): (None, (51, 45, 53, 62)),
… [205 caracteres más]
```

## Paso 16 · nivel 3 · acción 62

**Pensamiento:**

DOWN moved the mirror line down by 3 (rows 48-50 → 51-53)! And LEFT was a no-op. So the mirror line moves (like the mode-B control in level 2), and the yellow L (node 20) which crossed the line is now... let me check: the diff shows the line moved down 3 and the yellow L is no longer crossing (its bbox?). The comp diff didn't show the Y63 changing... hmm, it shows only S changes. Let me look at the image: the yellow L (stem up, bar at bottom) is now fully above the line? In the image, the yellow L's bar is at rows 51-53... hmm, the image shows the yellow L with its bar at the same place as the line.
Wait, the comp diff showed no change for ('Y',63) — meaning the yellow L stayed at rows 42-53. And the line moved from rows 48-50 to rows 51-53. Now the yellow L's bar (rows 51-53) coincides with the line's rows.
Hmm, so the line moved down 3 and the yellow L stayed. LEFT was a no-op — so the line only moves vertically (it's a horizontal line; moving it left/right makes no sense).
So the mechanic: the mirror line moves in the arrow direction (vertical here). And the yellow shapes... are they reflections of the black shapes? If the line moves, the reflections move!
Hmm, but the yellow shapes didn't move when the line moved. Hmm.
Let me reconsider: maybe the yellow shapes are independent objects (not reflections), and the mirror line is the controllable object (mode B). In level 2 mode B, moving the line made the reflection move by 2x. Here, moving the line down 3 didn't move any ye
… [2401 caracteres más]

```python
for i in range(3):
    r=try_act('UP')
    b=comp(previous_frame); a2=comp(current_frame)
    ch={k:(b.get(k),a2.get(k)) for k in set(b)|set(a2) if b.get(k)!=a2.get(k)}
    print('UP',i,'noop' if r[1] else ch)
```

```text
[action] UP -> effect
UP 0 {('S', 48): ((51, 45, 53, 62), None), ('Y', 62): (None, (2, 63, 63, 63)), ('S', 72): (None, (48, 36, 50, 62)), ('S', 88): ((51, 0, 53, 32), (48, 0, 50, 32))}
[action] UP -> effect
UP 1 {('Y', 62): ((2, 63, 63, 63), None), ('S', 72): ((48, 36, 50, 62), (45, 36, 47, 62)), ('
… [522 caracteres más]
```

## Paso 17 · nivel 3 · acción 65

**Pensamiento:**

Now we see reflections appearing! After moving the line up (from rows 48-50 to rows 42-44), new CHARCOAL ('c') shapes appeared below the line: c36 at (60,12)-(62,23) earlier and now c54 at (54,45)-(59,56), c36 at (60,12,62,23).
These are the reflections of the black shapes: the black L (rows 21-32, cols 12-23) reflected about line center d=43: rows 2*43-32=54 to 2*43-21=65 → clipped at 62. So the reflection is partially visible at rows 54-65 (only 54-62 visible), and it's drawn in CHARCOAL (the reflection color, as in level 2 where the reflection was charcoal).
And the black T (rows 27-32, cols 45-56) → reflection rows 54-59, cols 45-56 = c54 ✓.
So the reflections appear as charcoal. Good — the mirror line is the controllable object (mode B in level-2 terms).
So the yellow shapes are static targets (or maybe they're also objects?). Note: the yellow shapes didn't move when the line moved ✓ static.
Now the goal: presumably to make the charcoal reflections land exactly on the yellow targets!
Let's check: yellow targets:
- T-shape (bar top, stem below) at rows 42-47, cols 9-20 [node 19]
- ⊥-shape (stem top, bar bottom) at rows 9-14, cols 9-20 [node 3]
- Γ-shape (bar top, stem down-left) at rows 3-14, cols 33-44 [node 2]
- L-shape (stem up-left, bar bottom) at rows 42-53, cols 33-44 [node 20]
Reflections:
- Black L (node 4, rows 21-32 cols 12-23) reflects to a shape at cols 12-23 (cols unchanged since the mirror is horizontal) with flipped vertical orientation (stem up... let me c
… [1800 caracteres más]

```python
r=try_act('SPACE'); print('SPACE', 'noop' if r[1] else comp(current_frame))
for act in ['LEFT','DOWN']:
    r=try_act(act)
    b=comp(previous_frame); a2=comp(current_frame)
    ch={k:(b.get(k),a2.get(k)) for k in set(b)|set(a2) if b.get(k)!=a2.get(k)}
    print(act,'noop' if r[1] else ch)
```

```text
[action] SPACE -> effect
SPACE {('Y', 63): (42, 33, 53, 44), ('Y', 59): (5, 63, 63, 63), ('Y', 54): (42, 9, 47, 20), ('B', 56): (21, 12, 32, 23), ('B', 48): (27, 45, 32, 56), ('S', 24): (42, 0, 44, 8), ('S', 32): (42, 21, 44, 32), ('S', 72): (42, 36, 44, 62), ('c', 54): (54, 45, 59, 56), ('B', 63): 
… [351 caracteres más]
```

## Paso 18 · nivel 3 · acción 69

**Pensamiento:**

Now in mode A (after SPACE):
- LEFT moved the black L (node 4) from cols 12-23 to cols 9-20 (-3) ✓. The black T (node 7) did NOT move.
- DOWN moved the black L down 3 (rows 21→24) and its reflection appeared as c63 at (51,9)-(62,20).
So in mode A, only ONE black shape moves (the "selected" one?). The black T didn't move. Interesting — so there's a selection. Maybe SPACE toggles which shape is selected? In the level-2 case, SPACE switched between the line and the shape... Hmm, in level 2 the "line" mode was mode B. Here mode B = line control, mode A = shape control (of the selected shape).
Maybe SPACE cycles: line → shape1 → shape2 → ... → line?
Let me press SPACE again and see whether the selection changes (test by pressing LEFT and seeing which object moves).
Also note the dots in the black L changed from blue to white? In the image, the black L now has white dots. The black T still has blue dots. Hmm, in level 2, SPACE swapped the dot colors (the divider's dots and the shape's dots). Here after SPACE, the selected shape's dots became white (and the line's dots became blue). Interesting: in the current image, the line's dots are blue and the L's dots are white.
So SPACE selects a "grabbed" object: the grabbed object's dots turn white and the line's dots turn blue? Hmm.
Let me test: press SPACE, then check the dot colors and which object moves with LEFT.

```python
def dots(fr):
    a=fr.ascii.split('\n')
    W=sum(1 for r in range(63) for c in range(63) if a[r][c]=='W')
    return W
for i in range(4):
    r=try_act('SPACE')
    b=comp(previous_frame); a2=comp(current_frame)
    ch={k:(b.get(k),a2.get(k)) for k in set(b)|set(a2) if b.get(k)!=a2.get(k)}
    print('SPACE',i,'noop' if r[1] else ch, 'Wcount',dots(current_frame))
    r=try_act('RIGHT')
    b=comp(previous_frame); a2=comp(current_frame)
    ch={k:(b.get(k),a2.get(k)) for k in set(b)|set(a2) if b.get(k)!=a2.get(k)}
    print('  RIGHT','noop' if r[1] else ch,'Wcount',dots(current_frame))
```

```text
[action] SPACE -> effect
SPACE 0 {('Y', 56): (None, (8, 63, 63, 63)), ('Y', 57): ((7, 63, 63, 63), None)} Wcount 6
[action] RIGHT -> effect
  RIGHT {('Y', 55): (None, (9, 63, 63, 63)), ('c', 54): ((54, 45, 59, 56), (54, 48, 59, 59)), ('B', 48): ((27, 45, 32, 56), (27, 48, 32, 59)), ('Y', 56): ((8, 6
… [290 caracteres más]
```

## Paso 19 · nivel 3 · acción 69

**Pensamiento:**

Interesting. Let me piece together the mode/selection model:
- Initially (level 3 start): mode B (line control). W count = ? (line dots white = 21, shapes' dots blue).
- SPACE #1 → mode A: the L-shape became selected (its dots white, line dots blue). Wcount = 6? Hmm, the L has 7 dots... Let me not worry.
- Then LEFT/DOWN moved the L.
- SPACE #2 (the first in the last test): Wcount went 6 → 6? Hmm, the printout shows after SPACE 0: Wcount 6, then after RIGHT: 6, then SPACE 1: Wcount 16, then RIGHT no-op.
Hmm, confusing. Let me carefully track the state now:
Current frame: the L black shape at rows 24-35, cols 9-20 (moved left 3, down 3). The black T moved right 3 (cols 48-59). Both black shapes have blue dots now? The image shows the L with blue dots and the T with blue dots, and the line with white dots.
So we're back in mode B (line control)? The last successful SPACE (SPACE 1) set Wcount to 16 and then RIGHT was a no-op → consistent with mode B (line control: LEFT/RIGHT are no-ops for a horizontal line).
Hmm, so: SPACE toggles mode A/B. In mode A, which shape moves? The L moved with LEFT/DOWN (before), then after another SPACE the T moved with RIGHT. So mode A might have a selection that cycles... or maybe mode A moves BOTH shapes? Earlier when I pressed LEFT in mode A, only the L moved (the T stayed). Then after SPACE (to mode B) and SPACE (back to mode A?), RIGHT moved the T only.
Hmm, so maybe in mode A, the arrow moves the shape(s) that "align" with the direction? Or ma
… [25606 caracteres más]

```python
def bar(fr):
    a=fr.ascii.split('\n')
    return sum(1 for r in range(64) if a[r][63]=='Y')
print('budget', bar(current_frame), comp(current_frame))
```

```text
budget 54 {('Y', 63): (42, 33, 53, 44), ('Y', 54): (42, 9, 47, 20), ('B', 56): (24, 9, 35, 20), ('B', 48): (27, 48, 32, 59), ('S', 24): (42, 0, 44, 8), ('S', 32): (42, 21, 44, 32), ('S', 72): (42, 36, 44, 62), ('c', 63): (51, 9, 62, 20), ('c', 54): (54, 48, 59, 59), ('B', 63): (63, 0, 63, 62)}
```

**Nivel 3 completado → nivel 4 (acción 108)**

## Paso 19 · nivel 4 · acción 108

**Pensamiento:**

Budget 54 remaining. Current state confirmed:
- L (B56) at rows 24-35, cols 9-20
- T (B48) at rows 27-32, cols 48-59
- Line at rows 42-44 (d=43)
- Reflections: c63 at (51,9)-(62,20) [L's reflection, clipped], c54 at (54,48)-(59,59) [T's reflection]
- Yellow targets: (42,33)-(53,44) 63px, (42,9)-(47,20) 54px, plus the two at the top (nodes 2 and 3) which are... hmm, wait! The comp shows only 2 yellow components: (42,33,53,44) and (42,9,47,20). Where are the top yellow shapes (nodes 2 and 3)?!
The comp filter was pixels 20..400 and the top shapes are 63 and 54 px... they should appear. Unless the top yellow shapes are now MERGED with something? Hmm, comp shows ('Y',63): (42,33,53,44) and ('Y',54): (42,9,47,20). The image clearly shows yellow shapes at the top (⊥ at rows 9-14 cols 9-20 and Γ at rows 3-14 cols 33-44).
OH! The dict key is (color, pixels) — the top Γ (63 px) and the bottom Γ-ish (63 px) have the SAME key ('Y',63) → the dict entry got overwritten! Same for the 54-px ones. So the comp dict is lossy. I need to use a list instead of a dict.
Let me write a better snapshot function returning a sorted list of (color, pixels, bbox) for all components.
Then let me verify the 4 yellow targets' positions.
Then execute the plan.

```python
def comps(fr):
    seg=fr.segmentation; out=[]
    for n in seg['nodes']:
        if n['pixels']>=20 and n['pixels']<400:
            b=n['boundary']; rs=[p[0] for p in b]; cs=[p[1] for p in b]
            out.append((n['color'],n['pixels'],min(rs),min(cs),max(rs),max(cs)))
    return sorted(out)
for x in comps(current_frame): print(x)
```

```text
('B', 48, 27, 48, 32, 59)
('B', 56, 24, 9, 35, 20)
('B', 63, 63, 0, 63, 62)
('S', 24, 42, 0, 44, 8)
('S', 32, 42, 21, 44, 32)
('S', 72, 42, 36, 44, 62)
('Y', 54, 9, 9, 14, 20)
('Y', 54, 10, 63, 63, 63)
('Y', 54, 42, 9, 47, 20)
('Y', 63, 3, 33, 14, 44)
('Y', 63, 42, 33, 53, 44)
('c', 54, 54, 48, 59, 
… [28 caracteres más]
```

**Pensamiento:**

Confirmed 4 yellow targets (excluding the HUD bar at col 63):
- ('Y',54) at (9,9)-(14,20) = ⊥ target
- ('Y',54) at (42,9)-(47,20) = T target
- ('Y',63) at (3,33)-(14,44) = Γ target
- ('Y',63) at (42,33)-(53,44) = A target
Plan:
1. Mode B (line): 5 UP → line to rows 27-29 (d=28).
2. SPACE → select L. 8 RIGHT (cols 9-20 → 33-44), 6 DOWN (rows 24-35 → 42-53).
3. SPACE → select T. 13 LEFT (cols 48-59 → 9-20), 5 DOWN (rows 27-32 → 42-47).
Total 39 actions; budget 54 → 15 spare.
Let me execute with a trace, stopping on level_completed or a no-op.

```python
plan = ['UP']*5 + ['SPACE'] + ['RIGHT']*8 + ['DOWN']*6 + ['SPACE'] + ['LEFT']*13 + ['DOWN']*5
for i,act in enumerate(plan):
    r=try_act(act)
    res=last_action_call_result
    if r[0]!='ok' or r[1]:
        print('PROBLEM at',i,act,r[0],'noop' if r[1] else '')
        print(comps(current_frame)); break
    if res.get('level_completed') or res.get('game_over'):
        print('END at',i,act,'lc',res.get('level_completed'),'go',res.get('game_over'))
        print(comps(current_frame)); break
else:
    print('plan done')
print('budget',bar(current_frame))
for x in comps(current_frame): print(x)
```

```text
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] SPACE -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT 
… [1105 caracteres más]
```

## Paso 20 · nivel 4 · acción 108

**Pensamiento:**

Level 4! New layout:
- Horizontal mirror line near the top (rows ~9-11 with white dots).
- Two yellow shapes: a "cross/plus-like" shape crossing the line (rows 9-27ish, cols 33-47) and another yellow cross below (rows 30-48, cols 33-47).
- Black dotted shapes: a "U/cup" shape (rows 18-24, cols 12-26) and a vertical bar (rows 30-48, cols 18-20).
- At the very top: two charcoal squares at rows 0-2, cols 12-14 and 24-26 (partially visible at the top edge!). Those are the reflections of the black U's two top prongs? Interesting — the reflection of the U-shape about the line at rows 9-11 (d=10): the U at rows 18-24 → reflection rows -4..2 → partially visible at rows 0-2 ✓ (the two charcoal blocks at cols 12-14 and 24-26 = the U's prongs reflected ✓).
So the mechanic is the same: a horizontal mirror line, black dotted players, charcoal reflections, yellow targets.
Let me inspect the segmentation to get exact shapes.

```python
fr=current_frame
for x in comps(fr): print(x)
a=fr.ascii.split('\n')
print('--- black U')
for r in range(16,26): print(r,a[r][10:28])
print('--- black bar')
for r in range(29,49): print(r,a[r][16:22])
print('--- yellow cross top (crossing line)')
for r in range(8,28): print(r,a[r][31:50])
print('--- yellow cross bottom')
for r in range(29,49): print(r,a[r][31:50])
```

```text
('B', 48, 30, 18, 47, 20)
('B', 56, 18, 12, 23, 26)
('B', 63, 63, 0, 63, 62)
('S', 56, 9, 42, 11, 62)
('S', 104, 9, 0, 11, 38)
('Y', 64, 0, 63, 63, 63)
('Y', 108, 9, 33, 26, 47)
('Y', 108, 30, 33, 47, 47)
--- black U
16 bbbbbbbbbbbbbbbbbb
17 bbbbbbbbbbbbbbbbbb
18 bbBBBbbbbbbbbbBBBb
19 bbBbBbbbbbbbbb
… [1329 caracteres más]
```

**Pensamiento:**

Level 4 state:
- Mirror line at rows 9-11 (d=10), horizontal, with white dots → mode B initially (line control).
- Black U-shape (B56): rows 18-23, cols 12-26: two prongs (cols 12-14 rows 18-20 and cols 24-26 rows 18-20) + a bar (rows 21-23, cols 12-26). Total blocks: 1+1+5 = 7 blocks = 63 - 7 dots = 56 ✓.
- Black vertical bar (B48): rows 30-47, cols 18-20: 6 blocks = 54 - 6 dots = 48 ✓.
- Yellow shape 1 (Y108): rows 9-26, cols 33-47: a "cross" with a long stem going up (rows 9-20, cols 39-41), a wide bar (rows 18-23: prongs at cols 33-35, 39-41, 45-47 rows 18-20, plus the full bar rows 21-23 cols 33-47), and a stem going down (rows 24-26 cols 39-41).
  Interesting: this yellow shape = the mirror image of the black U (the U part at rows 18-26: prongs going up + bar) PLUS an extra stem. Hmm, let me decompose.
  Yellow 1 blocks: stem rows 9-17 (cols 39-41) [3 blocks], then rows 18-20: cols 33-35, 39-41, 45-47 [3 blocks], rows 21-23: cols 33-47 [5 blocks], rows 24-26: cols 39-41 [1 block]. Total = 3+3+5+1 = 12 blocks = 108 ✓.
- Yellow shape 2 (Y108): rows 30-47, cols 33-47: stem rows 30-32 cols 39-41 [3 blocks], rows 33-35 full bar [5], rows 36-38: 3 prongs [3], rows 39-47: stem [3 blocks]. Total 3+5+3+3 = 14 blocks = 126 ≠ 108. Hmm, let me recount: rows 39-47 is 9 rows = 3 blocks. 3+5+3+3 = 14 blocks = 126. But the comp says 108 px = 12 blocks. Let me recount the ascii: rows 30,31,32: stem (3 rows = 1 block). Rows 33,34,35: bar (1 block-row of 5 = 5 blocks). Rows 36,37,38: 3 pr
… [20106 caracteres más]

```python
def info(fr):
    a=fr.ascii.split('\n')
    Brows=[r for r in range(63) for c in range(63) if a[r][c]=='B']
    Scols=[r for r in range(63) for c in range(63) if a[r][c]=='S']
    line=None
    if Scols:
        # line rows = rows with many S
        rows=sorted(set(Scols))
        line=(min(rows),max(rows))
    # find the two black shapes by bbox clustering
    compsB=[]
    pts={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
    seen=set()
    for p in sorted(pts):
        if p in seen: continue
        stack=[p]; comp=set()
        while stack:
            r,c=stack.pop()
            if (r,c) in comp: continue
            comp.add((r,c))
            for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
                q=(r+dr,c+dc)
                if q in pts and q not in comp: stack
… [256 caracteres más]
```

```text
((9, 11), [(56, 18, 12, 23, 26), (48, 30, 18, 47, 20)]) 64
```

## Paso 20 · nivel 4 · acción 116

**Pensamiento:**

Level 4 confirmed: line at rows 9-11 (d=10), U at (18,12)-(23,26), bar at (30,18)-(47,20). Budget 64.
Target: line at rows 27-29 (d=28) → 6 DOWN.
U → rows 18-23, cols 33-47 → 7 RIGHT.
Bar → rows 9-26, cols 39-41 → 7 UP + 7 RIGHT.
Let me execute: 6 DOWN first, then SPACE, then probe RIGHT to detect the selection.

```python
for i in range(6):
    r=try_act('DOWN')
    if r[0]!='ok' or r[1]: print('problem',i,r[0],r[1]); break
print('after line moves', info(current_frame))
r=try_act('SPACE'); print('SPACE',r[0],'noop' if r[1] else 'ok')
r=try_act('RIGHT'); print('RIGHT',r[0],'noop' if r[1] else info(current_frame))
```

```text
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
after line moves ((27, 29), [(56, 18, 12, 23, 26), (48, 30, 18, 47, 20)])
[action] SPACE -> effect
SPACE ok ok
[action] RIGHT -> effect
RIGHT ok ((27, 29), 
… [45 caracteres más]
```

## Paso 21 · nivel 4 · acción 122

**Pensamiento:**

The line is now at rows 27-29 (d=28) ✓. SPACE selected the U (the RIGHT press moved the U from cols 12-26 to 15-29 ✓). The U's dots are now white (selected).
Also I can see the reflections: the U's reflection (charcoal) appears above/below, and the bar's reflection too.
Now: continue the U's moves: 6 more RIGHT (to cols 33-47). Then SPACE → the bar: 7 UP + 7 RIGHT.
Note: the U's reflection is now at rows 33-38 (mirror about 28: rows 2*28-23=33 to 2*28-18=38) — visible as the charcoal U-shape below the line at rows 33-38 ✓ (in the image, the charcoal shape below the line looks like a flipped U ✓).
Let me continue: 6 RIGHT for the U, then check.

```python
for i in range(6):
    r=try_act('RIGHT')
    if r[0]!='ok' or r[1]: print('problem',i,r[0],r[1],info(current_frame)); break
print(info(current_frame), 'lc',last_action_call_result.get('level_completed'))
```

```text
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
((27, 29), [(56, 18, 33, 23, 47), (48, 30, 18, 47, 20)]) lc False
```

## Paso 22 · nivel 4 · acción 124

**Pensamiento:**

The U is now at rows 18-23, cols 33-47 ✓ (matching yellow 1's U-part). Its reflection is at rows 33-38 cols 33-47 ✓ (matching yellow 2's U-part).
Now: SPACE → select the bar, then 7 UP and 7 RIGHT (target rows 9-26, cols 39-41).
Current bar: rows 30-47, cols 18-20.
Order: Let me do 7 RIGHT first (cols 18-20 → 39-41, at rows 30-47): does it collide with anything? The U is at rows 18-23 → no overlap ✓. The yellow shapes are not obstacles (the bar will pass over/under yellow 2 — in level 2 the shape passed under the divider, and yellow shapes are probably just background targets, not obstacles).
Then 7 UP: the bar goes from rows 30-47 to 9-26 at cols 39-41 → passing through the U's bar (rows 21-23 cols 39-41) → overlap test at the end.
Let me do: SPACE, 7 RIGHT, then 7 UP, checking each step. If a no-op occurs (blocked), I'll switch to the detour route.

```python
r=try_act('SPACE'); print('SPACE',r[0],'noop' if r[1] else 'ok')
r=try_act('RIGHT'); print('probe RIGHT',r[0],'noop' if r[1] else info(current_frame))
```

```text
[action] SPACE -> effect
SPACE ok ok
[action] RIGHT -> effect
probe RIGHT ok ((27, 29), [(56, 18, 33, 23, 47), (48, 30, 21, 47, 23)])
```

**Nivel 4 completado → nivel 5 (acción 130)**

## Paso 23 · nivel 5 · acción 130

**Pensamiento:**

The bar is now selected (white dots) and moved right to cols 21-23 (rows 30-47). Continue: 6 more RIGHT (to cols 39-41), then 7 UP (to rows 9-26).
Let me execute 6 RIGHT then 7 UP with checks.

```python
for i in range(6):
    r=try_act('RIGHT')
    if r[0]!='ok' or r[1]: print('problem R',i,r[0],r[1]); break
print(info(current_frame))
for i in range(7):
    r=try_act('UP')
    if r[0]!='ok' or r[1]:
        print('problem U',i,r[0],r[1],info(current_frame)); break
    if last_action_call_result.get('level_completed') or last_action_call_result.get('game_over'):
        print('END',i,last_action_call_result.get('level_completed'),last_action_call_result.get('game_over')); break
print(info(current_frame),'budget',bar(current_frame))
```

```text
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> LEVEL COMPLETED
((0, 62), [(88, 36, 42, 50, 56)])

error:
Traceback (most recent call last):
  File "<python_tool>", line 6, in <module>
TerminalStateActionE
… [196 caracteres más]
```

## Paso 24 · nivel 5 · acción 133

**Pensamiento:**

Level 5! Now there are TWO mirror lines: a vertical line at cols ~9-11 and a horizontal line at rows ~15-17. So the reflection is 2D (both axes) — possibly producing up to 3 reflections (or a 4-fold symmetric pattern).
Objects:
- Yellow shape (large, irregular) at rows ~15-42, cols 12-39 (crossing the horizontal line? and there's a yellow bit at cols 0-14 row 15 and cols 36-38 row 15).
- Black dotted shape at rows ~36-51, cols 42-57.
Let me inspect the segmentation carefully.

```python
fr=current_frame
for x in comps(fr): print(x)
a=fr.ascii.split('\n')
print('--- lines')
Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('S rows',Srows,'S cols',Scols)
print('--- black')
for r in range(35,53): print(r,a[r][40:60])
```

```text
('B', 63, 63, 0, 63, 62)
('B', 88, 36, 42, 50, 56)
('S', 32, 15, 24, 17, 35)
('S', 64, 15, 39, 17, 62)
('S', 192, 0, 0, 62, 11)
('Y', 64, 0, 63, 63, 63)
('Y', 189, 15, 12, 41, 38)
('b', 135, 0, 0, 14, 8)
--- lines
S rows [15, 16, 17] S cols [9, 10, 11]
--- black
35 bbbbbbbbbbbbbbbbbbbb
36 bbBBBBBBBB
… [394 caracteres más]
```

**Pensamiento:**

Level 5:
- Horizontal line at rows 15-17 (d_h = 16), vertical line at cols 9-11 (d_v = 10).
- Black shape (88 px = 88 + dots... let me count blocks: the shape spans rows 36-50, cols 42-56. Blocks: rows 36-38: cols 42-53 (4 blocks); rows 39-41: cols 51-53 (1); rows 42-44: cols 51-56 (2); rows 45-47: cols 54-56 (1); rows 48-50: cols 48-56 (3). Total = 4+1+2+1+3 = 11 blocks = 99 px - 11 dots = 88 ✓.
- Yellow shape (189 px = 21 blocks) at rows 15-41, cols 12-38.
- 'b' 135 px at (0,0)-(14,8): that's the blue background region (top-left quadrant separated by the lines) — actually 'b' is the blue background; the component (0,0)-(14,8) is the top-left corner region of the background, split by the lines. So the background is blue.
So there's ONE black shape and ONE yellow shape, and two mirror lines (horizontal + vertical).
The reflections: with 2 lines, the black shape reflects into up to 3 images (horizontal mirror, vertical mirror, both).
Let me check the current reflection positions: the black is at rows 36-50, cols 42-56 (bottom-right quadrant relative to the lines: rows > 17, cols > 11).
- Horizontal mirror (about row 16): rows 2-16, cols 42-56.
- Vertical mirror (about col 10): cols -36..-20 → off-screen.
- Both: rows 2-16, cols off-screen.
Hmm, so the horizontal reflection should be visible at rows 2-16 cols 42-56 — but the comps show no 'c' component! Let me check for charcoal cells. The comps filter was pixels 20..400 — a reflection at rows 2-16 would be 88 px → should appea
… [749 caracteres más]

```python
a=current_frame.ascii.split('\n')
cnt={}
for r in range(64):
    for c in range(64):
        ch=a[r][c]
        cnt[ch]=cnt.get(ch,0)+1
print(cnt)
print('--- yellow region rows 14-42 cols 10-40')
for r in range(14,43): print(r,a[r][10:40])
```

```text
{'b': 3370, 'S': 288, 'Y': 271, 'W': 16, 'B': 151}
--- yellow region rows 14-42 cols 10-40
14 SSbbbbbbbbbbbbbbbbbbbbbbbbbbbb
15 SSYYYYYYYYYYYYSSSSSSSSSSSSYYYS
16 WSYYYYYYYYYYYYSWSSWSSWSSWSYYYS
17 SSYYYYYYYYYYYYSSSSSSSSSSSSYYYS
18 SSbbbbbbbbbYYYbbbbbbbbbbbbbbbb
19 bSbbbbbbbbbYYYbbbbbbbbbbbbbbbb
20 SS
… [776 caracteres más]
```

**Pensamiento:**

Interesting! There's no 'c' (charcoal) on the board — no reflection is drawn at all.
Yellow shape: 271 px total (189 for the main + 81 for the part at rows 15-17 cols 36-38? Let me see: the comps showed ('Y',189) at (15,12)-(41,38) and the HUD bar at col 63 (64 px). 189+64 = 253 ≠ 271. Hmm, the count says 271 yellow cells. 271-64 = 207 in the play area. The comps listed only one Y component of 189 px in that bbox. Hmm, maybe there's another yellow component < 20 px that comps filtered out. 207-189 = 18 px. Hmm, the yellow at rows 39-41 cols 12-14 (9 px)... and rows 15-17 cols 36-38 (9 px) = 18 ✓. So there are small yellow pieces: 
- rows 15-17 cols 36-38 (9 px) — separated from the main yellow body by the horizontal line's S cells? Looking at row 15: 'SSYYYYYYYYYYYYSSSSSSSSSSSSYYYS' → cols 12-23 yellow, cols 24-35 S, cols 36-38 yellow. So the yellow at cols 36-38 rows 15-17 is a separate component (it's separated by the line's S cells... wait, no, the line is at rows 15-17, so at rows 15-17 the cells are S except where the yellow overlaps).
Hmm, actually the yellow shape at rows 15-17 spans cols 12-23 and 36-38 — the S cells between them are at cols 24-35 in rows 15-17. But at rows 18-20 the yellow is only at cols 21-23. So the yellow at rows 15-17 cols 36-38 is a separate component only if it's not connected elsewhere. Row 18: 'SSbbbbbbbbbYYYbbb...' → yellow at cols 21-23 only. So yes, the yellow piece at rows 15-17 cols 36-38 is separate (18 px? no, 3 rows × 3 cols = 9 px).
… [8077 caracteres más]

```python
def snap5(fr):
    a=fr.ascii.split('\n')
    Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
    Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
    B=[(r,c) for r in range(63) for c in range(63) if a[r][c]=='B']
    bb=(min(r for r,c in B),min(c for r,c in B),max(r for r,c in B),max(c for r,c in B)) if B else None
    C=[(r,c) for r in range(63) for c in range(63) if a[r][c]=='c']
    cb=(min(r for r,c in C),min(c for r,c in C),max(r for r,c in C),max(c for r,c in C)) if C else None
    return (Srows[0] if Srows else None, Scols[0] if Scols else None, bb, len(B), len(C), cb)
print('start',snap5(current_frame))
for act,back in [('DOWN','UP'),('LEFT','RIGHT')]:
    r=try_act(act); print(act,'noop' if r[1] else snap5(current_frame))

… [73 caracteres más]
```

```text
start (15, 9, (36, 42, 50, 56), 88, 0, None)
[action] DOWN -> effect
DOWN (18, 9, (36, 42, 50, 56), 88, 36, (0, 42, 2, 53))
[action] UP -> effect
UP (15, 9, (36, 42, 50, 56), 88, 0, None)
[action] LEFT -> NO-OP (executed, no change inside the board area)
LEFT noop
RIGHT noop
```

## Paso 25 · nivel 5 · acción 136

**Pensamiento:**

Key finding: DOWN moved the h-line from row 15 to row 18, and a charcoal reflection appeared at (0,42)-(2,53) = the h-mirror of the black shape's top bar ✓. So the h-line is controllable (mode B) and moving it by +3 moved the reflection by +6.
LEFT/RIGHT are no-ops → the v-line does NOT move?! Hmm. Or maybe the v-line moves only in a different mode. Let me test SPACE then LEFT/RIGHT.
Interesting: the v-line is at cols 9-11. Maybe it's fixed (a permanent mirror) and only the h-line moves. Then the reflections: the v-mirror of the black shape (cols 42-56 about col 10) is off-screen; the h-mirror is visible when the line is close enough.
Hmm, but wait: maybe the v-line matters for the yellow shape: the yellow is at cols 12-38, and the v-line at cols 9-11 is just to its left. The yellow piece at rows 39-41 cols 12-14 and the piece at rows 15-17 cols 36-38 look like "leftovers".
Let me now test SPACE and see what becomes controllable.

```python
r=try_act('SPACE'); print('SPACE','noop' if r[1] else 'ok', snap5(current_frame))
for act in ['LEFT','DOWN']:
    r=try_act(act)
    print(act,'noop' if r[1] else snap5(current_frame))
    if r[0]!='ok' or r[1]: break
```

```text
[action] SPACE -> effect
SPACE ok (15, 9, (36, 42, 50, 56), 88, 0, None)
[action] LEFT -> effect
LEFT (15, 6, (36, 42, 50, 56), 88, 0, None)
[action] DOWN -> NO-OP (executed, no change inside the board area)
DOWN noop
```

## Paso 26 · nivel 5 · acción 139

**Pensamiento:**

After SPACE, LEFT moved the VERTICAL line from cols 9-11 to cols 6-8 ✓ (the black shape didn't move). And DOWN was a no-op (in this mode? hmm).
Hmm wait: snap5 after SPACE showed (15, 9, ...) — the same as before, but the dot colors swapped (the v-line's dots are now white, the h-line's dots blue). So SPACE selects the v-line! And LEFT moved the v-line -3 ✓. DOWN was a no-op → the v-line only moves horizontally ✓.
So the SPACE cycle: h-line (moves vertically) → v-line (moves horizontally) → shape? → back.
Let me press SPACE again and test all 4 arrows.
Note: currently the v-line is at cols 6-8 (I moved it -3; I'll need to move it back or find the right target).
Let me press SPACE and probe.

```python
r=try_act('SPACE'); print('SPACE','noop' if r[1] else 'ok')
for act in ['LEFT','DOWN']:
    r=try_act(act); print(act,'noop' if r[1] else snap5(current_frame))
    if r[0]!='ok' or r[1]: break
```

```text
[action] SPACE -> effect
SPACE ok
[action] LEFT -> effect
LEFT (15, 6, (36, 39, 50, 53), 88, 0, None)
[action] DOWN -> effect
DOWN (15, 6, (39, 39, 53, 53), 88, 0, None)
```

## Paso 27 · nivel 5 · acción 139

**Pensamiento:**

Now the shape is selected (white dots) and moves with LEFT/DOWN. Current: the shape at rows 39-53, cols 39-53 (moved LEFT 3 and DOWN 3 from the start).
The lines are at row 15 (h) and col 6 (v).
Note: no charcoal reflection is visible now (the h-line at row 15 with the shape at rows 39-53 → the mirror is off-screen).
Now I need to figure out the goal. The yellow shape (23 blocks) must be covered by the black shape + its reflections.
Let me carefully derive the yellow shape's block set and the black shape's block set, then search for a placement (shape position + line positions) such that the union of {shape, h-mirror, v-mirror, both-mirror} equals the yellow set exactly.
Let me set up coordinates in blocks (3x3 cells per block). But careful: the lines are 3 cells wide, so the mirror center is at the line's middle row/col. Let me work in cell coordinates to avoid confusion, using sets of cells.
Mirror about the h-line center row dh (the middle of the 3 line rows): row r → 2*dh - r. Since the shape's cells are in blocks of 3 and the line is 3 rows, if dh is the middle row of the line, the mirror maps block-aligned cells to block-aligned cells ✓ (as observed in levels 3-4).
Let me now extract:
- Y = set of yellow cells (in the play area, excluding the HUD col 63 and excluding cells covered by S? hmm, the yellow may be hidden under the line's S cells).
Careful: the yellow at rows 15-17 is partially covered by S cells (the h-line drawn over it). When the line moves away, more yell
… [11289 caracteres más]

```python
def blocks(fr, colors):
    a=fr.ascii.split('\n')
    out=set()
    for r in range(63):
        for c in range(63):
            if a[r][c] in colors: out.add((r//3,c//3))
    return out
Y=blocks(current_frame,'Y')
Y={b for b in Y if b[1]<21}  # drop HUD col 63 -> block col 21
print('Y blocks',len(Y),sorted(Y))
Bk=blocks(current_frame,'B')
Bk={b for b in Bk if b[0]<21}
print('B blocks',len(Bk),sorted(Bk))
```

```text
Y blocks 23 [(5, 4), (5, 5), (5, 6), (5, 7), (5, 12), (6, 7), (7, 7), (7, 8), (8, 8), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10), (10, 8), (11, 8), (11, 9), (12, 9), (13, 4), (13, 9), (13, 10), (13, 11), (13, 12)]
B blocks 11 [(13, 13), (13, 14), (13, 15), (13, 16), (14, 16), (15, 16), (15, 17), (16, 1
… [33 caracteres más]
```

## Paso 27 · nivel 5 · acción 139

**Pensamiento:**

Now I have exact block sets (block = 3x3 cells; note the shape's dots mean some blocks of the black shape are "dot" cells but the block occupancy is what matters).
Y (23 blocks):
(5,4),(5,5),(5,6),(5,7),(5,12)
(6,7)
(7,7),(7,8)
(8,8)
(9,6),(9,7),(9,8),(9,9),(9,10)
(10,8)
(11,8),(11,9)
(12,9)
(13,4),(13,9),(13,10),(13,11),(13,12)
B (11 blocks, current): (13,13),(13,14),(13,15),(13,16),(14,16),(15,16),(15,17),(16,17),(17,15),(17,16),(17,17)
Note: the black shape's blocks — hmm, the black shape's dots are at the center of some blocks; the shape's blocks are fully occupied. But careful: the black shape's cells include 'B' and the dots are 'b'/'W' — my blocks() only counted 'B' cells. A block with a dot in the center still has B cells around it → counted ✓. But a block that's entirely... no, each block has a border of B. Fine.
Hmm, but the black shape's block set here (11 blocks) matches my earlier manual reading ✓.
Now: Y has 23 blocks, B has 11. Let me search for (pose, Lh, Lv) with the union of 4 images == Y.
Let me define the shape's relative block set: subtract (13,13): 
(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4).
Search: for pose (r0,c0) in a range, for Lh in range, Lv in range: images = A, hA = {(2Lh-r, c)}, vA = {(r, 2Lv-c)}, hvA. Union == Y?
Prune: require A ⊆ Y. Enumerate translations of A ⊆ Y: A has 11 blocks; Y has 23. Let me find all translations where A ⊆ Y.
Then for each such translation, search Lh, Lv ∈ [-5..25] such that the union == Y.
Let 
… [760 caracteres más]

```python
Y={(5,4),(5,5),(5,6),(5,7),(5,12),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8),(9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,4),(13,9),(13,10),(13,11),(13,12)}
A={(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4)}
Ys=sorted(Y)
sols=[]
poses=[]
for r0 in range(-5,20):
    for c0 in range(-5,20):
        At={(r0+r,c0+c) for r,c in A}
        if At<=Y: poses.append((r0,c0))
print('poses with A subset Y:',len(poses),poses[:20])
for (r0,c0) in poses:
    At={(r0+r,c0+c) for r,c in A}
    for Lh in range(-5,25):
        hAt={(2*Lh-r,c) for r,c in At}
        if not (hAt|At)<=Y: continue
        for Lv in range(-5,25):
            vAt={(r,2*Lv-c) for r,c in At}
            hvAt={(2*Lh-r,2*Lv-c) for r,c in At}
            if At|hAt|vAt|hvAt==Y:
                sols.append((r0,c0,Lh,Lv)
… [40 caracteres más]
```

```text
poses with A subset Y: 1 [(5, 4)]
solutions 0 []
```

**Pensamiento:**

Only one pose where A ⊆ Y: the shape at (5,4) → blocks (5,4),(5,5),(5,6),(5,7),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8) — let me verify: A + (5,4) = (5,4),(5,5),(5,6),(5,7),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8) ✓ all in Y!
And with that pose, no (Lh,Lv) gives the exact union. Let me relax: maybe the union only needs to COVER Y (⊇ Y), or maybe only 2 images are involved (e.g., only the h-mirror, or only the v-mirror), or the shape's cells can be outside Y (i.e., the union ⊇ Y with the extras allowed? unlikely).
Let me explore the pose (5,4) with all (Lh,Lv) and see the best coverage: how many Y blocks are covered and how many extra blocks. Also try 2-image unions (A ∪ hA) and (A ∪ vA).
Also consider: maybe the shape's pose isn't required to be a subset of Y — maybe the win condition is "the yellow is fully covered by the shape + reflections" (extras allowed). Let me search for solutions with union ⊇ Y and minimize extras, allowing any pose.
Let me do the relaxed search: for poses in a range (the shape's bbox must intersect Y), for Lh, Lv: check union ⊇ Y, score = |union \ Y| (want 0 → same as before). Since exact equality failed, find the min extras.
Hmm, but the extras might be allowed only if they're off-screen? Hmm.
Wait — maybe I should reconsider. Maybe the reflection rendering has a rule: the reflection is only drawn for the part of the shape on the opposite side of the line? In level 2, when the shape crossed the divider, the reflection appeared... Let me recall: i
… [1631 caracteres más]

```python
Y={(5,4),(5,5),(5,6),(5,7),(5,12),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8),(9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,4),(13,9),(13,10),(13,11),(13,12)}
A={(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4)}
best=[]
for r0 in range(0,18):
    for c0 in range(0,18):
        At={(r0+r,c0+c) for r,c in A}
        if not (At & Y): continue
        for Lh in range(-3,22):
            hAt={(2*Lh-r,c) for r,c in At}
            for Lv in range(-3,22):
                vAt={(r,2*Lv-c) for r,c in At}
                hvAt={(2*Lh-r,2*Lv-c) for r,c in At}
                for variant,img in (('4',At|hAt|vAt|hvAt),('3h',At|hAt|vAt),('3v',At|hAt|hvAt),('h',At|hAt),('v',At|vAt)):
                    if img>=Y:
                        best.append((len(img-Y),variant,r0,c0,Lh,Lv))
best.sort
… [48 caracteres más]
```

```text
1
(10, '4', 5, 4, 9, 8)
```

## Paso 27 · nivel 5 · acción 139

**Pensamiento:**

Only 1 solution found and it has 10 extra blocks — so my hypothesis (the shape+4 mirrors covering the yellow exactly) is wrong, or the yellow I read is incomplete (some yellow hidden under the shape itself! The black shape currently overlaps part of the yellow — look at the image: the black shape's top bar is ON the yellow row at rows 39-41! So the yellow under the black shape is hidden!).
Yes! The black shape currently covers some yellow blocks. So my Y set is missing the yellow blocks hidden under the black shape.
Also the charcoal reflections could hide yellow (none visible now).
Let me move the black shape away (e.g., UP/RIGHT a few) to reveal the full yellow, read it, then plan.
Current shape at block rows 13-17, cols 13-17 (after LEFT 3, DOWN 3 from the start). The yellow's bottom row is at block row 13 (cols 9-12 and col 4) and the shape's top bar is at block row 13, cols 13-16 → overlapping the yellow at (13,13)? The yellow's bottom row is (13,9),(13,10),(13,11),(13,12) and the shape's bar is at (13,13)-(13,16) → adjacent, not overlapping. Hmm, but in the image the black bar appears to touch/overlap the yellow's right end at cols ~36-38 (block col 12) ✓ adjacent.
Hmm, so maybe no yellow is hidden. But wait, the yellow count: 207 px = 23 blocks ✓ matches my 23-block Y. So nothing hidden.
Hmm. So the exact-tiling hypothesis fails.
Let me reconsider the puzzle. Maybe the yellow shape is a "path" and the goal is to move the shape so that it lands on a specific part? Or ma
… [2005 caracteres más]

```python
Y={(5,4),(5,5),(5,6),(5,7),(5,12),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8),(9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,4),(13,9),(13,10),(13,11),(13,12)}
A={(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4)}
def clip(S): return {p for p in S if 0<=p[0]<=20 and 0<=p[1]<=20}
sols=[]
for r0 in range(0,18):
    for c0 in range(0,18):
        At=clip({(r0+r,c0+c) for r,c in A})
        for Lh in range(-3,24):
            hAt=clip({(2*Lh-r,c) for r,c in At})
            for Lv in range(-3,24):
                vAt=clip({(r,2*Lv-c) for r,c in At})
                hvAt=clip({(2*Lh-r,2*Lv-c) for r,c in At})
                if At|hAt|vAt|hvAt==Y: sols.append((r0,c0,Lh,Lv,'4'))
                elif hAt|vAt|hvAt==Y: sols.append((r0,c0,Lh,Lv,'3mirrors'))
                elif hAt|vAt==Y
… [79 caracteres más]
```

```text
0
```

**Pensamiento:**

No solution. So the "cover the yellow with mirror images" hypothesis fails for level 5.
Let me step back and think about what else the yellow shape could mean.
Observation: the yellow shape's structure (23 blocks):
(5,4),(5,5),(5,6),(5,7) — a horizontal bar of 4 at the top-left
(5,12) — an isolated block at the top-right
(6,7),(7,7),(7,8),(8,8) — a staircase going down-right
(9,6)..(9,10) — a horizontal bar of 5 in the middle
(10,8),(11,8),(11,9),(12,9) — a staircase down-right
(13,4) — isolated block at the bottom-left
(13,9),(13,10),(13,11),(13,12) — a horizontal bar of 4 at the bottom
This looks like a "path" — like a snake. And the black shape (11 blocks) is a "staircase piece": a bar of 4, then a step, then a bar of 3.
Hmm! Look: the yellow contains: a bar of 4 at the top-left (row 5, cols 4-7), then a staircase down to a bar of 5 at row 9 (cols 6-10), then a staircase down to a bar of 4 at row 13 (cols 9-12).
And the black shape = a bar of 4 (top), a staircase (2 steps), a bar of 3 (bottom). Hmm, similar structure!
Maybe the yellow shape is the "trail" of the shape's movement — i.e., the goal is to move the shape along a path so that its trajectory covers the yellow? That seems odd.
Alternative: maybe the yellow shape is the target for the shape's SWEEP including reflections... 
Hmm, let me think about the isolated blocks: (5,12) and (13,4). These are "single blocks" far from the rest. Interesting: (5,12) is at the top-right and (13,4) at the bottom-left. If the yellow 
… [5362 caracteres más]

```text
python requires a non-empty `code` string.
```

## Paso 27 · nivel 5 · acción 139

**Pensamiento:**

Let me run the search with general mirror constants K (b → K-b), allowing half-integer axes.
Also, importantly: maybe the yellow shape isn't meant to be exactly covered. Let me look at the yellow shape's relationship to the black shape once more:
Yellow contains a copy of the shape at (5,4). The remaining 12 blocks: (5,12), (9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,4),(13,9),(13,10),(13,11),(13,12).
Hmm, what if the remaining is a copy of the shape's ROTATION/FLIP plus the two isolated blocks are separate "dot markers"? The 10 connected blocks: (9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,9),(13,10),(13,11),(13,12). A copy of the shape flipped... the shape's v-flip (horizontal flip): {(0,0),(0,1),(0,2),(0,3),(1,0),(2,0),(2,-1),(3,-1),(4,1),(4,0),(4,-1)} normalized... let me just search for flipped copies of A inside Y in code.
Let me run a comprehensive search: for each of the 4 orientations of A (identity, hflip, vflip, rot180) and each translation, check if the oriented copy ⊆ Y. Report all. That tells me how the yellow decomposes into shape copies.

```python
Y={(5,4),(5,5),(5,6),(5,7),(5,12),(6,7),(7,7),(7,8),(8,8),(9,6),(9,7),(9,8),(9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,4),(13,9),(13,10),(13,11),(13,12)}
A={(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4)}
def norm(S):
    r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
orients={'id':A,'hflip':{(4-r,c) for r,c in A},'vflip':{(r,-c) for r,c in A},'rot':{(4-r,-c) for r,c in A}}
orients={k:norm(v) for k,v in orients.items()}
for k,O in orients.items():
    found=[]
    for r0 in range(0,20):
        for c0 in range(0,20):
            T={(r0+r,c0+c) for r,c in O}
            if T<=Y: found.append((r0,c0))
    print(k,len(found),found[:8])
```

```text
id 1 [(5, 4)]
hflip 0 []
vflip 0 []
rot 1 [(9, 8)]
```

**Pensamiento:**

Excellent! The yellow contains:
- the identity copy of the shape at (5,4)
- a ROT180 copy at (9,8): rot180 of A + (9,8) = let me verify: rot(A) normalized = {(0,0),(0,1),(0,2),(1,0),(1,1),(2,1),(3,1),(3,2),(4,1),(4,2),(4,3)}? Let me compute: A = {(0,0),(0,1),(0,2),(0,3),(1,3),(2,3),(2,4),(3,4),(4,2),(4,3),(4,4)}; rot180 → {(4-r, -c)} = {(4,0),(4,-1),(4,-2),(4,-3),(3,-3),(2,-3),(2,-4),(1,-4),(0,-2),(0,-3),(0,-4)} → normalize (add 4 to cols): {(4,4),(4,3),(4,2),(4,1),(3,1),(2,1),(2,0),(1,0),(0,2),(0,1),(0,0)} → sorted: (0,0),(0,1),(0,2),(1,0),(2,0),(2,1),(3,1),(4,1),(4,2),(4,3),(4,4).
+ (9,8) = (9,8),(9,9),(9,10),(10,8),(11,8),(11,9),(12,9),(13,9),(13,10),(13,11),(13,12) ✓ all in Y!
So Y = shape@(5,4) ∪ rot180shape@(9,8) ∪ {(5,12),(13,4)}.
The union of the two copies: 11 + 11 = 22, but they share (9,8) → 21 blocks. Plus (5,12) and (13,4) = 23 ✓ 
So the yellow = the shape's identity copy + the shape's 180° rotation copy + two isolated blocks at (5,12) and (13,4).
Interesting! And a 180° rotation = the h-mirror followed by the v-mirror (both mirrors). So the "rot" copy = hvA ✓.
So the target: the shape at (5,4) AND its double-mirror image at (9,8). For the double-mirror of the shape (at pose P) to be at (9,8): rot180 about the point (Lh, Lv)... The composition of the h-mirror (about block row Lh) and the v-mirror (about block col Lv) = a 180° rotation about the point (Lh, Lv).
If the shape is at pose (5,4) (its bbox top-left in block coords), then the shape's blocks are A+(5,4). 
… [7033 caracteres más]

```python
print('budget',bar(current_frame),'snap',snap5(current_frame))
# verify plan arithmetic
print('shape needs', 13-5,'UP blocks,',13-4,'LEFT blocks; hline',9-5,'DOWN; vline',8-2,'RIGHT')
```

```text
budget 57 snap (15, 6, (39, 39, 53, 53), 88, 0, None)
shape needs 8 UP blocks, 9 LEFT blocks; hline 4 DOWN; vline 6 RIGHT
```

## Paso 27 · nivel 5 · acción 156

**Pensamiento:**

Budget 57, plan needs 29 ✓ comfortable.
Wait — one consideration on the order: if I move the shape first (8 UP, 9 LEFT) while the h-line is at block row 5 and the v-line at block col 2, the shape's final position is block (5,4) — the h-line at block row 5 currently passes through the shape's final top bar. That's fine (the shape can overlap the line).
But hmm, one thing to check: does the game allow the shape to be placed such that the h-line crosses it? In level 3, the yellow crossed the line; in level 2, the shape crossed the divider ✓ yes.
Also: does the win check happen continuously (i.e., as soon as the configuration is right)? Presumably yes, on the last move.
Order: shape moves first (17), then SPACE → h-line? I need to know the cycle order. Let me handle it adaptively: after the shape's moves, press SPACE and probe with a harmless move... risky. Better: determine the cycle by probing cheaply BEFORE committing: but each probe costs actions.
Alternative robust approach: after the shape's moves, press SPACE and then check the dot colors to identify the selected object:
- If the h-line's dots are white → h-line selected (it moves vertically).
- If the v-line's dots are white → v-line selected.
From the current frame: the shape has white dots (selected), the lines have blue dots. Let me write a detector: count 'W' cells on the h-line row region vs the v-line col region vs the shape's bbox.
The white dots: the line's dots are along its length (the h-line's dots at its middl
… [818 caracteres más]

```python
def selected(fr):
    a=fr.ascii.split('\n')
    Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
    Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
    hr=Srows[len(Srows)//2] if Srows else None; vc=Scols[len(Scols)//2] if Scols else None
    W={(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'}
    if hr is not None and sum(1 for c in range(63) if (hr,c) in W)>5: return 'hline'
    if vc is not None and sum(1 for r in range(63) if (r,vc) in W)>5: return 'vline'
    return 'shape'
def run(acts):
    for a in acts:
        r=try_act(a)
        res=last_action_call_result
        if res.get('level_completed') or res.get('game_over'):
            return 'END:'+str(res.get('level_completed'))+'/'+str(res.get('game_over'))+' a
… [232 caracteres más]
```

```text
selected now shape
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] UP -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] 
… [169 caracteres más]
```

## Paso 28 · nivel 5 · acción 157

**Pensamiento:**

The shape is now at bbox (15,12)-(29,26) = block rows 5-9, cols 4-8 ✓ exactly the target pose (5,4) ✓.
The reflections appeared (charcoal at (3,0)-(17,26)) — the h-mirror and v-mirror and double-mirror are visible.
Now: move the h-line to block row 9 (4 DOWN) and the v-line to block col 8 (6 RIGHT).
Note: the shape's dots are now yellow-ish? The image shows the shape's dots as yellow/orange. Interesting: the shape is over the yellow target now, so its dots appear yellow? Whatever.
The `selected` detector returned 'shape' — hmm, but the dots now look yellow (not white), meaning... hmm. My detector returned 'shape' because neither line had >5 W cells. The shape's dots are now 'Y'-colored? That's odd. Maybe the dot color indicates "correctly placed"! Like the shape's dots turn yellow when the shape is on the yellow target ✓ (a nice feedback signal!).
Anyway, the shape is still selected presumably (the selection didn't change). Now press SPACE and check the selection, then move the lines.
Let me do: SPACE → selected? → then the appropriate moves.
Careful: my `selected` function may mis-detect now. Let me look at the dot colors more carefully: I'll print the count of W cells and their locations (lines vs shape).

```python
a=current_frame.ascii.split('\n')
Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
hr=Srows[len(Srows)//2]; vc=Scols[len(Scols)//2]
W={(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'}
print('hline row',hr,'W on it',sum(1 for c in range(63) if (hr,c) in W))
print('vline col',vc,'W on it',sum(1 for r in range(63) if (r,vc) in W))
print('W in shape bbox',sum(1 for (r,c) in W if 15<=r<=29 and 12<=c<=26))
print('dot colors in shape bbox', {a[r][c] for (r,c) in [(rr,cc) for rr in range(15,30) for cc in range(12,27)] if a[r][c] in 'WYb'})
r=try_act('SPACE'); print('SPACE',r[0],'noop' if r[1] else 'ok')
a=current_frame.ascii.split('\n')
Srows=[r for r in range(63) if sum(1 for c in 
… [423 caracteres más]
```

```text
hline row 16 W on it 0
vline col 7 W on it 0
W in shape bbox 0
dot colors in shape bbox {'b', 'Y'}
[action] SPACE -> effect
SPACE ok ok
after SPACE: hline row 16 W 16 | vline col 7 W 1 | shape W 1
```

**Nivel 5 completado → nivel 6 (acción 168)**

## Paso 29 · nivel 6 · acción 168

**Pensamiento:**

After SPACE, the h-line has 16 W dots → the h-line is selected ✓. So the cycle is shape → hline (i.e., the order is hline → vline → shape → hline...).
Now: 4 DOWN (h-line from block row 5 → 9), then SPACE → vline, 6 RIGHT (block col 2 → 8).
Let me execute.

```python
print(run(['DOWN']*4), snap5(current_frame))
r=try_act('SPACE'); print('SPACE',r[0],'noop' if r[1] else 'ok', selected(current_frame))
print(run(['RIGHT']*6), snap5(current_frame), 'budget',bar(current_frame))
```

```text
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
ok (27, 6, (15, 12, 29, 26), 88, 87, (15, 0, 41, 26))
[action] SPACE -> effect
SPACE ok ok vline
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action
… [138 caracteres más]
```

## Paso 30 · nivel 6 · acción 168

**Pensamiento:**

Level 6! The board shows:
- A vertical mirror line at cols ~21-23 (with blue dots).
- A horizontal mirror line at the top (rows 0-2, with white dots).
- A large yellow pattern (symmetric about the vertical line) spanning most of the board.
- A black dotted shape at the top-right (rows ~9-24, cols ~42-63).
- A charcoal piece at the left edge (rows 12-21, cols 0-3?) — a reflection.
Let me inspect the segmentation.

```python
fr=current_frame
for x in comps(fr): print(x)
a=fr.ascii.split('\n')
Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('Srows',Srows,'Scols',Scols)
print('counts',{ch:sum(a[r][c]==ch for r in range(64) for c in range(64)) for ch in 'bSYWcG'})
print('budget',bar(fr))
```

```text
('B', 24, 9, 45, 11, 53)
('B', 24, 12, 42, 20, 44)
('B', 40, 24, 51, 29, 62)
('B', 63, 63, 0, 63, 62)
('S', 24, 30, 21, 38, 23)
('S', 192, 0, 0, 11, 62)
('Y', 27, 12, 15, 20, 17)
('Y', 27, 12, 21, 20, 23)
('Y', 27, 21, 6, 23, 14)
('Y', 27, 21, 24, 23, 32)
('Y', 27, 45, 6, 47, 14)
('Y', 27, 45, 24, 4
… [319 caracteres más]
```

**Pensamiento:**

Level 6 layout:
- Vertical mirror line at cols 21-23 (block col 7), with blue dots (the S component at rows 30-38 is a fragment; the main S component (0,0)-(11,62) is the horizontal line at rows 0-2 with white dots).
- Horizontal mirror line at rows 0-2 (block row 0) with WHITE dots → the h-line is currently "selected" (mode B?).
- The yellow pattern: many components, symmetric about the vertical line (block col 7). Total yellow 532 px (incl. 64 HUD) = 468 = 52 blocks.
- Black shape: 3 components (B24 at (9,45)-(11,53), B24 at (12,42)-(20,44), B40 at (24,51)-(29,62)) — hmm, 3 separate components! Probably ONE object (a chiral path) whose blocks touch only diagonally → rendered as 3 components. Total = 24+24+40 = 88 px = 8 blocks (with dots) → 8 blocks + 8 dots = 88 px ✓ (8*9 - 8 = 64? no: 8 blocks = 72 cells; minus 8 dot cells = 64 ≠ 88). Hmm: 88 px means 88 B cells. If a block has a dot in the center, it contributes 8 B cells. 88/8 = 11 blocks with dots ✓. So the black object has 11 blocks (each with a dot) = 99 cells, of which 11 are dots → 88 B ✓.
- Charcoal (c): 27 px at (12,0)-(20,2) = 3 blocks (27 = 3*9) — the reflection of part of the black shape (clipped by the left edge).
So the same mechanic: a black shape with 2 mirror lines (v at block col 7, h at block row 0). The yellow is the target to be covered by the shape + its 3 mirror images.
Note: the yellow pattern is symmetric about the vertical line (block col 7) — pairs of components at cols 6-17/21-32 etc. Hmm, inte
… [800 caracteres más]

```python
Y={b for b in blocks(current_frame,'Y') if b[1]<21}
Bk={b for b in blocks(current_frame,'B') if b[0]<21}
print('Y',len(Y),sorted(Y))
print('B',len(Bk),sorted(Bk))
```

```text
Y 52 [(3, 4), (3, 8), (4, 5), (4, 7), (5, 5), (5, 7), (6, 1), (6, 5), (6, 7), (6, 11), (7, 2), (7, 3), (7, 4), (7, 8), (7, 9), (7, 10), (9, 2), (9, 3), (9, 4), (9, 5), (9, 7), (9, 8), (9, 9), (9, 10), (10, 3), (10, 9), (12, 3), (12, 9), (13, 2), (13, 3), (13, 4), (13, 5), (13, 7), (13, 8), (13, 9), 
… [278 caracteres más]
```

**Pensamiento:**

Hmm, the B block set has 13 blocks but I estimated 11 (88 B cells / 8 per dotted block). Let me check: maybe some blocks have no dots (solid) → 9 cells each. 11 dotted (88) + 2 solid (18) = 106 ≠ 88. Hmm. Let me count differently: if x blocks have dots and y don't: 8x + 9y = 88, x+y = 13 → 8x + 9(13-x) = 88 → 117 - x = 88 → x = 29?? No.
Hmm, maybe the block extraction is wrong: the black shape's blocks might not be aligned to the 3x3 grid starting at 0! Let me check: the black shape's components: (9,45)-(11,53) → rows 9-11 (block row 3 ✓ aligned), cols 45-53 → block cols 15,16,17 (45/3=15 ✓, 53/3=17, so cols 45-53 = 3 blocks: 45-47, 48-50, 51-53 ✓).
(12,42)-(20,44): rows 12-20 = block rows 4,5,6 ✓; cols 42-44 = block col 14 ✓. So 3 blocks.
(24,51)-(29,62): rows 24-29 = block rows 8,9 ✓; cols 51-62 = block cols 17,18,19,20 ✓ → 2 rows × 4 cols = 8 blocks? But the shape's actual cells: from the level-6 image, the bottom-right component is an L/T shape.
So the total block count from my extraction = 13, but the actual shape may have fewer blocks if some blocks are partially covered... My blocks() function counts a block if ANY cell in it is 'B'. Hmm, that's the issue: the shape's blocks are 3x3 aligned, so any B cell in a block means the block is (at least mostly) B ✓. Unless the shape's blocks are NOT 3-aligned.
Wait: (24,51)-(29,62) spans rows 24-29 (block rows 8,9) and cols 51-62 (block cols 17-20). My extraction gave (8,18),(9,17),(9,18),(9,19),(9,20) for that region — 5 block
… [2575 caracteres más]

```python
a=current_frame.ascii.split('\n')
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
print('B cells',len(B))
# components
seen=set(); out=[]
for p in sorted(B):
    if p in seen: continue
    st=[p]; comp=set()
    while st:
        r,c=st.pop()
        if (r,c) in comp: continue
        comp.add((r,c))
        for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
            q=(r+dr,c+dc)
            if q in B and q not in comp: st.append(q)
    seen|=comp
    rs=[x for x,y in comp]; cs=[y for x,y in comp]
    out.append((len(comp),min(rs),min(cs),max(rs),max(cs)))
for o in sorted(out,key=lambda t:(t[1],t[2])): print(o)
print('--- ascii rows 8-31 cols 41-63')
for r in range(8,32): print(r,a[r][41:63])
```

```text
B cells 104
(24, 9, 45, 11, 53)
(24, 12, 42, 20, 44)
(8, 12, 54, 14, 56)
(8, 21, 45, 23, 47)
(40, 24, 51, 29, 62)
--- ascii rows 8-31 cols 41-63
8 bbbbbbbbbbbbbbbbbbbbbb
9 bbbbBBBBBBBBBbbbbbbbbb
10 bbbbBbBBbBBbBbbbbbbbbb
11 bbbbBBBBBBBBBbbbbbbbbb
12 bBBBbbbbbbbbbBBBbbbbbb
13 bBbBbbbbbbbbbBbBbbbbbb
1
… [466 caracteres más]
```

## Paso 30 · nivel 6 · acción 168

**Pensamiento:**

The black object has 13 blocks (104 B cells = 13 dotted blocks × 8 ✓).
Black blocks (absolute): (3,15),(3,16),(3,17),(4,14),(4,18),(5,14),(6,14),(7,15),(8,18),(9,17),(9,18),(9,19),(9,20).
Wait, from the ascii: 
rows 9-11 (block row 3): cols 45-53 (block cols 15,16,17) ✓
rows 12-14 (br 4): cols 42-44 (bc 14) and cols 54-56 (bc 18) ✓
rows 15-17 (br 5): cols 42-44 (bc 14)
rows 18-20 (br 6): cols 42-44 (bc 14)
rows 21-23 (br 7): cols 45-47 (bc 15)
rows 24-26 (br 8): cols 54-56 (bc 18)
rows 27-29 (br 9): cols 51-62 (bc 17,18,19,20)
Total = 3+2+1+1+1+1+4 = 13 ✓
So the shape (relative, subtract (3,14)):
(0,1),(0,2),(0,3),(1,0),(1,4),(2,0),(3,0),(4,1),(5,4),(6,3),(6,4),(6,5),(6,6)
13 blocks.
Y has 52 blocks. 4 copies of 13 = 52 ✓✓ EXACTLY! So the yellow = the union of the 4 mirror images (disjoint), and the shape itself is one of them.
So the search: find (pose, Kh, Kv) such that the 4 images (clipped) union == Y exactly. Since 4*13 = 52 = |Y|, the images must be disjoint and all inside Y.
Mirror axes: the v-line at block col 7 (cols 21-23 ✓), the h-line at block row 0 (rows 0-2 ✓).
Note: the h-line at block row 0 means the h-mirror maps block row r → -r... wait: 2*0 - r = -r → all negative → off-board except row 0. Hmm! That's why only a small charcoal piece appears (the shape's blocks at block row 0 would map to row 0).
Hmm, but the charcoal piece at (12,0)-(20,2) = block rows 4-6, block col 0. That's the v-mirror of the shape's blocks (4,14),(5,14),(6,14) → mirror about col 7: 14-
… [840 caracteres más]

```python
Y={(3,4),(3,8),(4,5),(4,7),(5,5),(5,7),(6,1),(6,5),(6,7),(6,11),(7,2),(7,3),(7,4),(7,8),(7,9),(7,10),(9,2),(9,3),(9,4),(9,5),(9,7),(9,8),(9,9),(9,10),(10,3),(10,9),(12,3),(12,9),(13,2),(13,3),(13,4),(13,5),(13,7),(13,8),(13,9),(13,10),(15,2),(15,3),(15,4),(15,8),(15,9),(15,10),(16,1),(16,5),(16,7),(16,11),(17,5),(17,7),(18,5),(18,7),(19,4),(19,8)}
A={(0,1),(0,2),(0,3),(1,0),(1,4),(2,0),(3,0),(4,1),(5,4),(6,3),(6,4),(6,5),(6,6)}
print(len(Y),len(A))
def clip(S): return {p for p in S if 0<=p[0]<=20 and 0<=p[1]<=20}
poses=[]
for r0 in range(0,21):
    for c0 in range(0,21):
        At={(r0+r,c0+c) for r,c in A}
        if At<=Y: poses.append((r0,c0))
print('poses',len(poses),poses)
sols=[]
for (r0,c0) in poses:
    At={(r0+r,c0+c) for r,c in A}
    for Lh in range(0,21):
        hAt={(2*Lh-r,
… [275 caracteres más]
```

```text
52 13
poses 0 []
sols 0 []
```

**Pensamiento:**

No pose of the shape (as-is) fits inside Y. So the shape's own image need not be inside Y — maybe the shape itself is NOT one of the 4 images covering the yellow? Hmm, but the shape IS one of the 4 (the identity image). Unless the yellow is covered by the 3 mirror images only and the shape stays outside... but 3*13 = 39 < 52. So we need all 4 → the shape must be inside Y.
Unless the shape's blocks as I extracted them are wrong! Maybe the shape's blocks are not aligned to the global 3-grid. Let me check the shape's own block alignment: the components' rows: 9-11, 12-14, ..., 27-29 → all 3-aligned with rows ≡ 0 mod 3 (9,12,...,27 ✓ all ≡ 0 mod 3 ✓). Cols: 42-44 (42 ≡ 0 ✓), 45-53 ✓, 51-62 ✓, 54-56 ✓. So the shape is aligned to the 3-grid ✓.
And the yellow: the yellow components' rows: 12-14? Let me check the yellow block extraction: I used r//3, c//3 which assumes 3-alignment. The yellow components: (12,15)-(20,17) → rows 12-20 (3 block rows ✓), cols 15-17 (1 block col ✓). (21,6)-(23,14) → rows 21-23 ✓, cols 6-14 = 3 block cols ✓. So the yellow is 3-aligned ✓.
So the shape's 13 blocks can't be placed inside Y at all. Hmm.
Wait — maybe the mirror images are not just mirrors of the shape; maybe the shape can also ROTATE? Hmm.
Or maybe the shape's blocks include the "dot" pattern such that the shape's silhouette differs... no.
Let me reconsider: maybe the yellow pattern isn't a target for the shape at all. Let me look at the yellow pattern's structure: it's symmetric about the vert
… [2576 caracteres más]

```python
Y={(3,4),(3,8),(4,5),(4,7),(5,5),(5,7),(6,1),(6,5),(6,7),(6,11),(7,2),(7,3),(7,4),(7,8),(7,9),(7,10),(9,2),(9,3),(9,4),(9,5),(9,7),(9,8),(9,9),(9,10),(10,3),(10,9),(12,3),(12,9),(13,2),(13,3),(13,4),(13,5),(13,7),(13,8),(13,9),(13,10),(15,2),(15,3),(15,4),(15,8),(15,9),(15,10),(16,1),(16,5),(16,7),(16,11),(17,5),(17,7),(18,5),(18,7),(19,4),(19,8)}
A={(0,1),(0,2),(0,3),(1,0),(1,4),(2,0),(3,0),(4,1),(5,4),(6,3),(6,4),(6,5),(6,6)}
print('    '+''.join(str(c%10) for c in range(14)))
for r in range(0,21):
    row=''
    for c in range(0,14):
        ch='.'
        if (r,c) in Y: ch='#'
        if (r,c) in A: ch='@'
        if (r,c) in Y and (r,c) in A: ch='%'
        row+=ch
    print(f'{r:3d} '+row)
```

```text
01234567890123
  0 .@@@..........
  1 @...@.........
  2 @.............
  3 @...#...#.....
  4 .@...#.#......
  5 ....@#.#......
  6 .#.@@%@#...#..
  7 ..###...###...
  8 ..............
  9 ..####.####...
 10 ...#.....#....
 11 ..............
 12 ...#.....#....
 13 ..####.####...
 14 ..............

… [113 caracteres más]
```

## Paso 30 · nivel 6 · acción 174

**Pensamiento:**

Now I can see the structure! The block grid (cols 0-13 shown):
Row 3: Y at 4, 8
Row 4: Y at 5, 7
Row 5: Y at 5, 7
Row 6: Y at 1, 5, 7, 11  (and the shape A occupies (6,2),(6,3),(6,4),(6,5)... wait the '@' marks are the shape's current position which is at block rows 0-6, cols 14-20 — hmm, the printout shows '@' in cols 0-6?! 
Oh no, I printed A's absolute blocks but A is the RELATIVE shape set (I subtracted (3,14) mentally but actually I defined A = {(0,1),(0,2),(0,3),(1,0),(1,4),(2,0),(3,0),(4,1),(5,4),(6,3),(6,4),(6,5),(6,6)} which is relative). So the '@' overlay in the grid is the relative shape drawn at the origin — not its actual position. Ignore the @ overlay except that the '%' at (6,4) shows an overlap of the relative shape with Y at that spot (meaningless).
The Y pattern (block coords):
```
 3  ....#...#.....
 4  ....#.#.......   -> actually row4: 5,7
 5  ....#.#.......
 6  .#..#.#...#...   -> 1,5,7,11  hmm my print showed row6: .#.@@%@#...#..  → Y at 1, 5, 7, 11 (the @ are the shape overlay)
 7  ..###...###...   -> 2,3,4, 8,9,10
 9  ..####.####...   -> 2,3,4,5, 7,8,9,10
10  ...#.....#....   -> 3, 9
12  ...#.....#....
13  ..####.####...
15  ..###...###...
16  .#...#.#...#..
17  .....#.#......
18  .....#.#......
19  ....#...#.....
```
Interesting: the pattern from rows 3-7 is the vertical mirror of the pattern from rows 15-19 (flipped): row 3 ↔ row 19? row 3: {4,8}; row 19: {4,8} ✓. row 4: {5,7} ↔ row 18: {5,7} ✓. row 5: {5,7} ↔ row 17: {5,7} ✓. row 6: {1,5,7,11} ↔ r
… [5637 caracteres más]

```python
def sel6(fr):
    a=fr.ascii.split('\n')
    W={(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'}
    h=sum(1 for c in range(63) if (1,c) in W); v=sum(1 for r in range(63) if (r,22) in W)
    if h>5: return 'hline'
    if v>5: return 'vline'
    blk=sorted({(r//3,c//3) for (r,c) in W})
    return 'blk:'+','.join(f'{r},{c}' for r,c in blk)
print('start',sel6(current_frame))
for i in range(6):
    r=try_act('SPACE')
    if r[0]!='ok' or r[1]: print('SPACE stop',r[0],r[1]); break
    print(i,'SPACE ->',sel6(current_frame))
```

```text
start hline
[action] SPACE -> effect
0 SPACE -> vline
[action] SPACE -> effect
1 SPACE -> blk:8,18,9,17,9,18,9,19,9,20
[action] SPACE -> effect
2 SPACE -> blk:3,15,3,16,3,17,4,14,4,18,5,14,6,14,7,15
[action] SPACE -> effect
3 SPACE -> hline
[action] SPACE -> effect
4 SPACE -> vline
[action] SPACE ->
… [47 caracteres más]
```

## Paso 31 · nivel 6 · acción 193

**Pensamiento:**

There are 4 selectable objects in the cycle: hline → vline → objA → objB → hline → ...
- objA = blocks (8,18),(9,17),(9,18),(9,19),(9,20) — the bottom-right T-piece (5 blocks).
- objB = blocks (3,15),(3,16),(3,17),(4,14),(4,18),(5,14),(6,14),(7,15) — the top hook (8 blocks).
Total 13 ✓ but they're TWO separate objects (5 + 8 blocks).
So the yellow (52 blocks) = 4 images of... hmm, now with 2 objects: each object has 4 images → 8 images total: 4*5 + 4*8 = 20 + 32 = 52 ✓✓ PERFECT! The yellow = the union of the 4 mirror images of each of the two objects.
So the target: the two objects + their mirrors tile the yellow.
Now let me search: the v-line at block col Lv, the h-line at block row Lh, and each object's pose. Since the yellow is symmetric about col 6 and row 11, likely Lv=6, Lh=11.
Let me set up the search: unknowns: Lh, Lv, objA pose (ra,ca), objB pose (rb,cb). Constraint: the 8 images (clipped) union == Y exactly.
Search space: Lh, Lv ∈ [0,20] (441); objB pose: 13... objB has 8 blocks; the poses where objB ⊆ Y: enumerate; then for each, objA's pose where objA ⊆ Y and disjoint... Let me do it smartly:
1. Enumerate all poses of objB that are ⊆ Y (call PB).
2. Enumerate all poses of objA that are ⊆ Y (PA).
3. For each (Lh,Lv) and each pb ∈ PB: the images of objB = 4 sets, all ⊆ Y, disjoint. Then the remaining Y \ (union of objB images) must equal the union of objA's 4 images for some pa ∈ PA.
To reduce: given (Lh,Lv), the mirror constraint ties the pose: the images are deter
… [409 caracteres más]

```python
Y={(3,4),(3,8),(4,5),(4,7),(5,5),(5,7),(6,1),(6,5),(6,7),(6,11),(7,2),(7,3),(7,4),(7,8),(7,9),(7,10),(9,2),(9,3),(9,4),(9,5),(9,7),(9,8),(9,9),(9,10),(10,3),(10,9),(12,3),(12,9),(13,2),(13,3),(13,4),(13,5),(13,7),(13,8),(13,9),(13,10),(15,2),(15,3),(15,4),(15,8),(15,9),(15,10),(16,1),(16,5),(16,7),(16,11),(17,5),(17,7),(18,5),(18,7),(19,4),(19,8)}
OB={(3,15),(3,16),(3,17),(4,14),(4,18),(5,14),(6,14),(7,15)}
OA={(8,18),(9,17),(9,18),(9,19),(9,20)}
def norm(S):
    r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
OBn=norm(OB); OAn=norm(OA)
def poses(O):
    out=[]
    for r0 in range(0,21):
        for c0 in range(0,21):
            T={(r0+r,c0+c) for r,c in O}
            if T<=Y: out.append((r0,c0))
    return out
PB=poses(OBn); PA=poses(OAn)
print
… [50 caracteres más]
```

```text
PB 1 [(15, 7)]
PA 1 [(12, 2)]
```

**Pensamiento:**

Each object fits inside Y in exactly ONE pose:
- objB (8 blocks) at pose (15,7) → its blocks: (15,8),(15,9),(15,10),(16,7),(16,11),(17,7),(18,7),(19,8)
- objA (5 blocks) at pose (12,2) → blocks: (12,3),(13,2),(13,3),(13,4),(13,5)
Now find (Lh,Lv) such that the 8 images (identity + 3 mirrors of each) tile Y exactly.
objB identity at (15,7): {(15,8),(15,9),(15,10),(16,7),(16,11),(17,7),(18,7),(19,8)}
objA identity at (12,2): {(12,3),(13,2),(13,3),(13,4),(13,5)}
Let me compute the required mirrors:
The h-mirror of objB's identity about Lh: rows → 2Lh - r. The yellow's structure: objB's identity is in rows 15-19 (the bottom part). The h-mirror should be in rows 3-7: 2Lh - 19 = 3 → Lh = 11 ✓ and 2Lh-15 = 7 ✓.
Check: the h-mirror of objB = {(3,8),(3,9),(3,10),(4,7),(4,11),(5,7),(6,7),(7,8)}. Is that ⊆ Y? Y has (3,4),(3,8) — (3,9) and (3,10) are NOT in Y ✗.
Hmm! So objB's h-mirror isn't in Y. So maybe objB's identity is NOT at (15,7); maybe objB's identity is somewhere else and only its mirrors are inside Y... but then objB's identity wouldn't be ⊆ Y — but it must be, since the union must equal Y (any image outside Y would add extras).
Unless the extras are allowed... Hmm.
Hold on. Maybe the objects' poses in the SOLUTION don't need the identity image ⊆ Y — maybe the identity image can be anywhere, and the yellow is covered by the union of the images of BOTH objects... but then the identity images must also be within Y (else extras).
Unless the win condition is only about the REFLEC
… [7206 caracteres más]

```python
print('budget',bar(current_frame),'sel',sel6(current_frame))
# stage 1: objA 4 DOWN, 15 LEFT
res=run(['DOWN']*4+['LEFT']*15)
a=current_frame.ascii.split('\n')
Bk={b for b in blocks(current_frame,'B') if b[0]<21}
print(res,'B blocks',sorted(Bk),'budget',bar(current_frame),'lc',last_action_call_result.get('level_completed'))
```

```text
budget 58 sel blk:8,18,9,17,9,18,9,19,9,20
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> 
… [347 caracteres más]
```

## Paso 32 · nivel 6 · acción 213

**Pensamiento:**

objA is now at (12,3),(13,2),(13,3),(13,4),(13,5) ✓ exactly the target pose ✓. Its mirror images (charcoal) appeared at the right places ✓ (I can see the charcoal T at cols ~18-21 and the yellow-covered ones).
Budget 39. Remaining plan: SPACE → objB: 12 DOWN + 7 LEFT (19), SPACE → hline: 11 DOWN (11), SPACE → vline: 1 LEFT (1) = 1+19+1+11+1+1 = 34 ≤ 39 ✓ (5 spare).
Wait: after objA, the next SPACE gives objB ✓ (cycle hline→vline→objA→objB). Then SPACE → hline, then SPACE → vline ✓.
Let me execute stage 2 (objB) now, then verify, then stage 3+4.

```python
r=try_act('SPACE'); print('SPACE',r[0],sel6(current_frame))
res=run(['DOWN']*12+['LEFT']*7)
Bk={b for b in blocks(current_frame,'B') if b[0]<21}
print(res,sorted(Bk),'budget',bar(current_frame),'lc',last_action_call_result.get('level_completed'))
```

```text
[action] SPACE -> effect
SPACE ok blk:3,15,3,16,3,17,4,14,4,18,5,14,6,14,7,15
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[actio
… [375 caracteres más]
```

## Paso 33 · nivel 6 · acción 214

**Pensamiento:**

Both objects are now at their target poses ✓ (B blocks = objA (12,3),(13,2..5) and objB (15,8),(15,9),(15,10),(16,7),(16,11),(17,7),(18,7),(19,8) ✓).
Budget 19. Remaining: SPACE → hline: 11 DOWN; SPACE → vline: 1 LEFT = 1+11+1+1 = 14 ≤ 19 ✓ (5 spare).
Let me execute. The h-line is currently at block row 0 → 11 DOWN. Then the v-line from col 7 → 6: 1 LEFT.
Note: I should double check the direction of the v-line's LEFT (col decreases ✓ as in level 5).
Execute stage 3: SPACE, then 11 DOWN, verify the h-line's row; then SPACE, 1 LEFT, and check for level completion.

```python
r=try_act('SPACE'); print('SPACE',r[0],sel6(current_frame))
res=run(['DOWN']*11)
a=current_frame.ascii.split('\n')
Srows=[rr for rr in range(63) if sum(1 for c in range(63) if a[rr][c]=='S')>20]
print(res,'Srows',Srows,'budget',bar(current_frame),'lc',last_action_call_result.get('level_completed'))
```

```text
[action] SPACE -> NO-OP (executed, no change inside the board area)
SPACE ok hline
FAIL:DOWN err noop Srows [0, 1, 2] budget 18 lc False
```

## Paso 34 · nivel 6 · acción 215

**Pensamiento:**

The h-line is selected (white dots) but DOWN was a NO-OP! The h-line is at rows 0-2 (block row 0) — it can't move DOWN?? That's odd. Unless the h-line at block row 0 is at its top limit and DOWN is blocked... but it should be able to move down.
Hmm! Maybe the h-line here doesn't move at all (fixed)? Or maybe the h-line moves with UP/DOWN only in some other mode. Let me test: press UP (should be a no-op at the top edge), then DOWN again... DOWN was a no-op.
Hmm, wait. Maybe the horizontal line moves only when... hmm. In level 5, the h-line moved with UP/DOWN ✓ (it was at block row 5 and moved down 4 fine).
Here the h-line is at block row 0 (rows 0-2). Maybe the line can't move because the HUD is at row 0? Hmm, but DOWN should move it to rows 3-5.
Alternatively, maybe the "hline" detection is wrong: the white dots are on row 1 (the h-line) ✓. Hmm.
Or maybe the h-line moves DOWN but the move is blocked because... the yellow? No, in level 5 the lines crossed everything.
Let me test UP/DOWN on the h-line again and check for ANY change (board_changed). Also maybe the h-line here is at the top EDGE and can't move down because the game restricts lines to the playfield minus something? Let me just probe: DOWN, then check; if no-op, try UP (no-op expected), then LEFT/RIGHT (maybe the h-line moves horizontally?? no).
Wait — maybe I misidentified: maybe the object with white dots on row 1 is not a movable line but a FIXED border, and the actual "h-line" is elsewhere? The white dots on ro
… [1266 caracteres más]

```python
print('prev result',last_action_call_result)
r=try_act('DOWN')
print('DOWN ->',r[0],'noop',r[1])
res=last_action_call_result
print({k:res.get(k) for k in ('board_changed','gameplay_changed','executed','skipped','stop','level_completed','game_over')})
a=current_frame.ascii.split('\n')
Srows=[rr for rr in range(63) if sum(1 for c in range(63) if a[rr][c]=='S')>20]
print('Srows',Srows)
print('row0..8 cols 0..30')
for rr in range(0,9): print(rr,a[rr][0:30])
```

```text
prev result {'executed': False, 'action_num': None, 'level': None, 'score': None, 'state': None, 'valid_actions': ['UP', 'DOWN', 'LEFT', 'RIGHT', 'SPACE', 'MOUSE', 'UNDO'], 'board_changed': False, 'done': False, 'level_completed': False, 'game_over': False, 'run_complete': False, 'action_display': N
… [1649 caracteres más]
```

## Paso 35 · nivel 6 · acción 225

**Pensamiento:**

The DOWN worked this time: the h-line moved from rows 0-2 to rows 3-5 ✓ (Srows now [3,4,5]) ✓. The earlier "no-op" was a harness artifact: the SPACE press (which only changed dot colors, all within rows 0-2 = near the edge) was flagged as a no-op → my run() aborted. My try_act's no-op detection is too strict for dot-only changes.
Note: the h-line's dots are now on row 4 (white) ✓.
Budget: 17 now (18 - 1). The h-line is at block row 1 → needs 10 more DOWN to reach block row 11. Then SPACE → vline, 1 LEFT. Total 12 ≤ 17 ✓ (5 spare).
Let me be careful with the no-op detection: I'll use direct action() calls in a loop with explicit checks, avoiding try_act's stale-state halt. Better: batch the 10 DOWNs in one action() call, then check.

```python
res=action(['DOWN']*10)
a=current_frame.ascii.split('\n')
Srows=[rr for rr in range(63) if sum(1 for c in range(63) if a[rr][c]=='S')>20]
print('Srows',Srows,'lc',res.get('level_completed'),'go',res.get('game_over'),'budget',bar(current_frame))
```

```text
[action] batch of 10 actions, 10 executed: DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN
Srows [33, 34, 35] lc False go False budget 7
```

**Nivel 6 completado → nivel 7 (acción 227)**

## Paso 36 · nivel 7 · acción 227

**Pensamiento:**

The h-line is now at rows 33-35 = block row 11 ✓. The reflections now cover much of the yellow (the charcoal pieces appear in the upper half, mirroring the objects) ✓.
Budget 7. Remaining: SPACE (1) + LEFT (1) = 2 → 5 spare ✓.
Let me do it: SPACE then LEFT, checking completion.

```python
res=action(['SPACE','LEFT'])
print(res.get('executed_count'),res.get('stopped_early'),res.get('skipped_actions'))
print('lc',res.get('level_completed'),'go',res.get('game_over'),'done',res.get('run_complete'),'budget',bar(current_frame),'level',current_frame.level)
a=current_frame.ascii.split('\n')
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('Scols',Scols)
```

```text
[action] batch of 2 actions, 2 executed: SPACE, LEFT | stop_reason: level_completed
2 False None
lc True go False done False budget 64 level 7
Scols [9, 10, 11]
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

Level 7! The board:
- Vertical mirror line at cols 9-11 (block col 3), blue dots.
- Horizontal mirror line at rows 15-17 (block row 5), WHITE dots → selected.
- Yellow pattern: scattered blocks (dotted/checkerboard-like!) in two bands: rows 3-11 (above the h-line) and rows 21-41 (below).
- Three black objects: one at the left edge (charcoal? no — the charcoal at rows 48-60 cols 0-6 is a reflection), a black "thick plus" at rows 48-60 cols 15-30, and a black zigzag at rows 39-60 cols 51-57.
Let me analyze the blocks and run the same tiling search.
Note: the yellow pattern here is sparse (individual blocks with gaps) — that's fine, the same model should apply.
Let me extract: Y blocks, B blocks (grouped into objects), the line positions, and the selection cycle.
Then search: for the line positions (Lh, Lv) and each object's pose, the 4 images of each object must cover Y exactly (or ⊇ with minimal extras).
Let me first get the data.

```python
fr=current_frame
a=fr.ascii.split('\n')
Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('Srows',Srows,'Scols',Scols,'budget',bar(fr),'sel',sel6(fr))
Y={b for b in blocks(fr,'Y') if b[1]<21}
print('Y',len(Y),sorted(Y))
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
seen=set(); objs=[]
for p in sorted(B):
    if p in seen: continue
    st=[p]; comp=set()
    while st:
        r,c=st.pop()
        if (r,c) in comp: continue
        comp.add((r,c))
        for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
            q=(r+dr,c+dc)
            if q in B and q not in comp: st.append(q)
    seen|=comp; objs.append(comp)
for o in objs:
    bl=sorted({(r//3,c//3) for r,c in o})
 
… [45 caracteres más]
```

```text
Srows [15, 16, 17] Scols [9, 10, 11] budget 64 sel blk:5,0,5,1,5,2,5,3,5,4,5,5,5,6,5,7,5,9,5,10,5,11,5,12,5,13,5,14,5,15,5,17,5,18,5,19,5,20
Y 42 [(1, 7), (1, 9), (1, 11), (1, 13), (1, 15), (1, 17), (2, 13), (2, 14), (2, 15), (3, 7), (3, 13), (3, 14), (3, 15), (3, 17), (4, 9), (4, 11), (4, 13), (4, 
… [487 caracteres más]
```

**Pensamiento:**

Interesting: the yellow has 42 blocks. Also note the yellow extraction EXCLUDES yellow hidden under the objects, and the yellow blocks listed are in the region cols 0-20 only... wait, I filtered b[1]<21 which excludes block col 21 (the HUD at col 63). But the yellow in the image extends to block cols up to ~19 ✓.
Hmm wait, there's a problem: the yellow pattern in the image spans block cols 2-19 and rows 1-13. And the objects are at block rows 13-19 (two objects: 9 blocks and 14 blocks). Also the sel6 output shows white dots at block row 5 (the h-line) ✓ selected = hline.
Total object blocks = 9 + 14 = 23. Four images each: 4*23 = 92 > 42. So the yellow is NOT a full tiling by 4 images. Hmm.
But wait — maybe the yellow pattern is partially hidden under the objects! The objects are at block rows 13-19, cols 5-9 and 17-19. The visible yellow goes up to row 13. Hmm, the yellow at rows 13 (13,7),(13,9),(13,11),... overlaps the objects' rows 16-19? No, the objects are at rows 16-19 and there's no yellow visible there (rows 14-19 have no yellow). So maybe the yellow is entirely visible.
Hmm, so 42 yellow blocks vs 92 image blocks. So the coverage model must allow overlap, or the yellow is covered by only SOME images.
Hmm, let me think about the yellow pattern's structure: it looks like a grid/dither pattern. Let me print it as a block grid.
Also, maybe this level's goal is different: maybe the yellow blocks are "targets" to be covered by the shape's reflections, where overlapping is
… [765 caracteres más]

```python
Y={(1,7),(1,9),(1,11),(1,13),(1,15),(1,17),(2,13),(2,14),(2,15),(3,7),(3,13),(3,14),(3,15),(3,17),(4,9),(4,11),(4,13),(4,15),(5,8),(5,16),(7,9),(7,15),(9,8),(9,16),(10,9),(10,11),(10,13),(10,15),(11,7),(11,9),(11,10),(11,11),(11,17),(12,9),(12,10),(12,11),(13,7),(13,9),(13,11),(13,13),(13,15),(13,17)}
print('    '+''.join(str(c%10) for c in range(21)))
for r in range(0,21):
    print(f'{r:3d} '+''.join('#' if (r,c) in Y else '.' for c in range(21)))
```

```text
012345678901234567890
  0 .....................
  1 .......#.#.#.#.#.#...
  2 .............###.....
  3 .......#.....###.#...
  4 .........#.#.#.#.....
  5 ........#.......#....
  6 .....................
  7 .........#.....#.....
  8 .....................
  9 ........#.......#....
 10 .........#.#.#
… [267 caracteres más]
```

**Pensamiento:**

The yellow pattern (rows 1-13, cols 7-17) is symmetric under the 180° rotation about the point (7,12): let me check: (1,7) → (13,17) ✓ in Y; (2,13),(2,14),(2,15) → (12,11),(12,10),(12,9) ✓; (5,8) → (9,16) ✓; (7,9) → (7,15) ✓. Yes, it's 180°-symmetric about (7,12).
It's also symmetric under the mirror c → 24-c? (1,7)→(1,17) ✓; (2,13),(2,14),(2,15) → (2,11),(2,10),(2,9) ✗ not in Y. Hmm, no.
Mirror r → 14-r: (1,7)→(13,7) ✓; (2,13)→(12,13)? not in Y ✗.
So only the 180° rotational symmetry (and maybe a mirror about the row axis combined with something).
Hmm. Let me think about the objects:
obj1 (9 blocks): (13,19),(14,19),(15,18),(15,19),(16,18),(17,17),(17,18),(18,17),(19,17) — a staircase.
obj2 (14 blocks): (16,6),(16,8),(17,5),(17,6),(17,7),(17,8),(17,9),(18,5),(18,6),(18,7),(18,8),(18,9),(19,6),(19,8) — a thick plus/cross.
Total 23 blocks. The yellow has 42 blocks.
Hmm, 42 = 23 + 19? or 42 = 2*23 - 4?
If the two objects and their images cover the yellow with the objects themselves also on the yellow: e.g., if the two lines are placed such that the objects' images overlap... 
Let me think: with 2 objects and 2 lines, there are 8 images = 92 block-instances. To cover 42 yellow blocks exactly, we'd need lots of overlap (50 overlaps). Unlikely.
Alternatively, maybe the mirror images can be clipped by the board edges? The board is 21x21 blocks. Hmm, the objects are at rows 13-19 and cols 5-19, so the mirrors would be within the board mostly.
Hmm, maybe the goal here is different! L
… [2856 caracteres más]

```python
Y={(1,7),(1,9),(1,11),(1,13),(1,15),(1,17),(2,13),(2,14),(2,15),(3,7),(3,13),(3,14),(3,15),(3,17),(4,9),(4,11),(4,13),(4,15),(5,8),(5,16),(7,9),(7,15),(9,8),(9,16),(10,9),(10,11),(10,13),(10,15),(11,7),(11,9),(11,10),(11,11),(11,17),(12,9),(12,10),(12,11),(13,7),(13,9),(13,11),(13,13),(13,15),(13,17)}
O1={(13,19),(14,19),(15,18),(15,19),(16,18),(17,17),(17,18),(18,17),(19,17)}
O2={(16,6),(16,8),(17,5),(17,6),(17,7),(17,8),(17,9),(18,5),(18,6),(18,7),(18,8),(18,9),(19,6),(19,8)}
def norm(S):
    r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
n1=norm(O1); n2=norm(O2)
def poses_in(O):
    out=[]
    for r0 in range(0,21):
        for c0 in range(0,21):
            T={(r0+r,c0+c) for r,c in O}
            if T<=Y: out.append((r0,c0))
    return out
P
… [87 caracteres más]
```

```text
P1 0 []
P2 0 []
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

Neither object fits inside the yellow (in the identity orientation). So the objects themselves are NOT on the yellow — only their reflections must cover it (like levels 1-2!).
Hmm, but 3 mirror images of 2 objects = 69 instances vs 42 yellow blocks — with overlaps that's plausible if the images overlap each other.
Hmm, wait. Maybe the yellow pattern is covered by the reflections of the objects where the reflections overlap each other. Let's think: the cross (14 blocks) mirrored... 
Alternatively, maybe the yellow pattern is the "shadow" of the objects' 4 images but the yellow cells are only where an ODD number of images cover (XOR / parity)! Look at the pattern: it's dithered/checkerboard-like — very reminiscent of a parity/XOR pattern!
Hmm, that's exotic. Let me think differently.
Look at the yellow pattern again:
```
 1  .......#.#.#.#.#.#...
 2  .............###.....
 3  .......#.....###.#...
 4  .........#.#.#.#.....
 5  ........#.......#....
 7  .........#.....#.....
 9  ........#.......#....
10  .........#.#.#.#.....
11  .......#.###.....#...
12  .........###.........
13  .......#.#.#.#.#.#...
```
And the cross object (14 blocks):
```
row0: .#.#.#.#.#   -> (16,6),(16,8) hmm let me draw it:
(16,6),(16,8)
(17,5),(17,6),(17,7),(17,8),(17,9)
(18,5),(18,6),(18,7),(18,8),(18,9)
(19,6),(19,8)
```
As a grid (rows 16-19, cols 5-9):
```
.#.#.
#####
#####
.#.#.
```
Interesting! And the yellow pattern has rows like ".........#.#.#.#....." (row 4: cols 9,11,13,15) and "........#....
… [19204 caracteres más]

```python
a=current_frame.ascii.split('\n')
print('cross region rows 45-62, cols 12-32')
for r in range(45,63): print(r,a[r][12:32])
print('charcoal blocks:',sorted({(r//3,c//3) for r in range(63) for c in range(63) if a[r][c]=='c'}))
```

```text
cross region rows 45-62, cols 12-32
45 bbbbbbbbbbbbbbbbbbbb
46 bbbbbbbbbbbbbbbbbbbb
47 bbbbbbbbbbbbbbbbbbbb
48 bbbbbbBBBbbbBBBbbbbb
49 bbbbbbBbBbbbBbBbbbbb
50 bbbbbbBBBbbbBBBbbbbb
51 bbbBBBBBBBBBBBBBBBbb
52 bbbBbBBbBBbBBbBBbBbb
53 bbbBBBBBBBBBBBBBBBbb
54 bbbBBBBBBBBBBBBBBBbb
55 bbbBbBBbBBbBBbBBbBbb

… [239 caracteres más]
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

The cross is confirmed: 14 blocks in a 4x5 pattern (rows 48-59 = block rows 16-19, cols 18-29 = block cols 6-9... wait: from the ascii, rows 48-50 have B at cols 18-20 and 24-26 → block cols 6 and 8 ✓; rows 51-56 have B at cols 15-29 → block cols 5-9 ✓; rows 57-59: block cols 6, 8 ✓. So the cross pattern:
row0 (br16): .#.#.  (cols 6,8)
row1 (br17): #####
row2 (br18): #####
row3 (br19): .#.#.
✓ 14 blocks.
Charcoal blocks: (16,0),(17,0),(17,1),(18,0),(18,1),(19,0) = 6 blocks. The cross's v-mirror about col 3: (r,c) → (r, 6-c): the cross's cols 5..9 → 1, 0, -1, -2, -3; and cols 6,8 → 0, -2. So the visible mirrored blocks: from (17,5)→(17,1) ✓, (17,6)→(17,0) ✓, (18,5)→(18,1) ✓, (18,6)→(18,0) ✓, (16,6)→(16,0) ✓, (19,6)→(19,0) ✓. Total 6 ✓✓ matches exactly! Great — the mirror model is confirmed (full mirror, clipped at the board edge).
Now, the yellow pattern (42 blocks) can't contain the cross. So the cross's image must overlap the yellow partially with extras.
Hmm, let me reconsider the whole thing. What if the yellow pattern is not a "cover target" but rather a pattern that must be REPRODUCED by the reflections? I.e., the goal: the reflections (charcoal) must cover the yellow... same thing.
Alternatively, maybe this level's yellow pattern is a "dithered" version of a solid region because the reflections of the two objects, when overlapping, produce a XOR-like pattern... 
Hmm, hold on! What if the yellow pattern = the XOR (parity) of the objects' images? Let's test: the cross's 4
… [11021 caracteres más]

```python
Yl=[(1,7),(1,9),(1,11),(1,13),(1,15),(1,17),(2,13),(2,14),(2,15),(3,7),(3,13),(3,14),(3,15),(3,17),(4,9),(4,11),(4,13),(4,15),(5,8),(5,16),(7,9),(7,15),(9,8),(9,16),(10,9),(10,11),(10,13),(10,15),(11,7),(11,9),(11,10),(11,11),(11,17),(12,9),(12,10),(12,11),(13,7),(13,9),(13,11),(13,13),(13,15),(13,17)]
Yset=set(Yl); idx={b:i for i,b in enumerate(Yl)}
O1={(0,2),(1,2),(2,1),(2,2),(3,1),(4,0),(4,1),(5,0),(6,0)}
O2={(0,1),(0,3),(1,0),(1,1),(1,2),(1,3),(1,4),(2,0),(2,1),(2,2),(2,3),(2,4),(3,1),(3,3)}
def onb(S): return {p for p in S if 0<=p[0]<=20 and 0<=p[1]<=20}
def cover(O,r0,c0,Lh):
    At={(r0+r,c0+c) for r,c in O}
    Ht={(2*Lh-r-c*0, c) for r,c in At}
    Ht={(2*Lh-r,c) for r,c in At}
    U=onb(At)|onb(Ht)
    m=0
    for p in U:
        if p in idx: m|=1<<idx[p]
    return m, len(U-Yset
… [476 caracteres más]
```

```text
tool: python
function_retention: |
  Retained your function onb(S) for later Python calls in this game.
  Your function cover was not retained: unavailable dependencies: Yset, idx. Pass snippet-specific data as arguments or redefine it if needed.
returncode: 0
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

The search printed nothing → no solution with the identity + h-mirror only (with the v-mirrors ignored) covering all 42 yellow cells. Hmm, wait, it printed nothing at all, meaning `best` was empty → for no Lh did any pair cover FULL.
Hmm, but I ignored the v/hv mirrors in the coverage (I only used identity + h-mirror), while the actual game would also draw the v/hv mirrors (which could cover yellow cells if the objects are placed left of the v-line... but the yellow is at cols 7-17 and the v-line at col 3 → the objects would need to be at cols ≤ -1 to mirror into 7-17. Not possible with Lv=3.
So with Lv=3, the identity+h-mirror can't cover Y. Therefore the v-line must move (right) so that the v-mirrors can cover the yellow.
Let me redo the search including all 4 images, with Lv as a variable. To keep it fast, I'll parametrize differently:
For each (Lh, Lv) and each object and pose: compute the mask over Y and extras. Then find pairs covering FULL.
Cost: 441 (Lh,Lv) × 2 objects × 441 poses = 388K cover computations, each building 4 sets of ≤14 cells → ~50M ops. Too slow.
Reduce the pose range: the objects' poses must be such that their images overlap the yellow significantly. The yellow spans rows 1-13, cols 7-17. The images (identity, h-mirror about Lh, v-mirror about Lv, hv) — the identity pose range: rows 0..20, cols 0..20 (441). Hmm.
Alternative: think about it as covering the yellow with 8 images where each image is a transformed copy. Let me instead search image-by-image
… [5165 caracteres más]

```python
a=current_frame.ascii.split('\n')
for r in range(3,15): print(r,a[r][21:54])
```

```text
3 YYYbbbYYYbbbYYYbbbYYYbbbYYYbbbYYY
4 YYYbbbYYYbbbYYYbbbYYYbbbYYYbbbYYY
5 YYYbbbYYYbbbYYYbbbYYYbbbYYYbbbYYY
6 bbbbbbbbbbbbbbbbbbYYYYYYYYYbbbbbb
7 bbbbbbbbbbbbbbbbbbYYYYYYYYYbbbbbb
8 bbbbbbbbbbbbbbbbbbYYYYYYYYYbbbbbb
9 YYYbbbbbbbbbbbbbbbYYYYYYYYYbbbYYY
10 YYYbbbbbbbbbbbbbbbYYYYYYYYYbbbYYY
11 YYYbbbbb
… [136 caracteres más]
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

Wait, this crop (rows 3-14, cols 21-53) shows yellow at block cols 7,9,11,13,15,17 in rows 3-5 (block row 1)... and a solid yellow region at rows 6-11 (block rows 2,3) cols 39-47 (block cols 13,14,15) — that's a 3x3-block solid area = rows 6-11, cols 39-47. But my block extraction said Y has (2,13),(2,14),(2,15),(3,13),(3,14),(3,15) ✓ = a 2x3 solid ✓ consistent.
Hmm OK. So the yellow is block-aligned ✓.
Let me now think about the yellow pattern as a "picture" — maybe it's two overlapping "H" glyphs and the objects are the letter pieces? Hmm.
Let me try yet another interpretation of the game: maybe the yellow pattern is the target for the objects + reflections, and the reflections of the objects are drawn in YELLOW (not charcoal) when they land on the yellow? No...
Let me revisit: in level 5, the yellow was exactly covered by the 4 images with 10 extras. So the rule "union of 4 images ⊇ Y" is confirmed. Here, the union of 8 images (2 objects × 4) ⊇ Y, extras allowed.
My earlier search (identity + h-mirror only, Lv=3) found NO solution. So the v-line must move.
Let me now run the full search over (Lh, Lv) with both objects' 4 images, but smartly:
For each (Lh, Lv):
  - For obj2 (the cross, 14 blocks): for each pose (441), compute mask2 and extras2.
  - For obj1: same.
  - Find pairs with mask1|mask2 == FULL minimizing extras.
The inner pair loop is the expensive part (441² = 194K per (Lh,Lv) → ×441 = 86M). Too slow.
Optimization: for each (Lh,Lv), instead of all pairs, note tha
… [5712 caracteres más]

```python
import time
Yl=[(1,7),(1,9),(1,11),(1,13),(1,15),(1,17),(2,13),(2,14),(2,15),(3,7),(3,13),(3,14),(3,15),(3,17),(4,9),(4,11),(4,13),(4,15),(5,8),(5,16),(7,9),(7,15),(9,8),(9,16),(10,9),(10,11),(10,13),(10,15),(11,7),(11,9),(11,10),(11,11),(11,17),(12,9),(12,10),(12,11),(13,7),(13,9),(13,11),(13,13),(13,15),(13,17)]
Yset=set(Yl); idx={b:i for i,b in enumerate(Yl)}
O1={(0,2),(1,2),(2,1),(2,2),(3,1),(4,0),(4,1),(5,0),(6,0)}
O2={(0,1),(0,3),(1,0),(1,1),(1,2),(1,3),(1,4),(2,0),(2,1),(2,2),(2,3),(2,4),(3,1),(3,3)}
def norm(S):
    r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
def hflip(S): return norm({(-r,c) for r,c in S})
def vflip(S): return norm({(r,-c) for r,c in S})
def both(S): return norm({(-r,-c) for r,c in S})
FULL=(1<<len(Yl))-1
def table(O)
… [1550 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 1, in <module>
ImportError: Module 'time' is not allowed in the sandbox.
```

## Paso 37 · nivel 7 · acción 227

**Pensamiento:**

`time` isn't importable. Let me restructure: build the tables in one call (they're cheap) and store them... but Python variables reset between calls! Only retained functions persist. So I need to do the whole search in ONE call (or have a retained function that recomputes).
Let me write a single self-contained snippet that:
1. Builds the tables.
2. Runs the search with pruning.
3. Prints the best solutions.
And keep it under 30s. I'll define a retained function `solve7(...)` that takes the data as arguments so I can call it repeatedly with different parameters.
For the pair search, I'll filter poses by popcount ≥ threshold. Let me pick thresholds: the cross's 4 images have up to 56 cells; to cover a good chunk of the 42 yellow cells, popcount ≥ 14. The staircase: up to 36 cells; popcount ≥ 10.
Actually, let me first check the maximum achievable coverage per object per (Lh,Lv) — a quick diagnostic to see whether covering all 42 is even plausible, and for which (Lh,Lv).
Plan for the snippet:
- Build tables (4 orientations × 2 objects × 441 poses) — fast.
- For each (Lh,Lv): compute the lists; record max popcount per object; if max1+max2 >= 42, do the pair search with filtered lists (popcount ≥ 60% of max maybe).
- Collect solutions with total extras; print the top 10.
To keep the runtime manageable, I'll first do a diagnostic pass over all (Lh,Lv) computing max popcounts (441*441*2 lookups = 388K → fine), then only for the promising (Lh,Lv) do the pair search.
Let me write it a
… [85 caracteres más]

```python
def build7(Yl,O1,O2):
    Yset=set(Yl); idx={b:i for i,b in enumerate(Yl)}
    def norm(S):
        r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
    def hf(S): return norm({(-r,c) for r,c in S})
    def vf(S): return norm({(r,-c) for r,c in S})
    def bf(S): return norm({(-r,-c) for r,c in S})
    def table(O):
        h=max(r for r,c in O)+1; w=max(c for r,c in O)+1
        T=[]
        for r0 in range(21):
            row=[]
            for c0 in range(21):
                S={(r0+r,c0+c) for r,c in O}
                S={p for p in S if p[0]<=20 and p[1]<=20}
                m=0
                for p in S:
                    if p in idx: m|=1<<idx[p]
                row.append((m,len(S-Yset)))
            T.append(row)
        return T,h,w
 
… [1568 caracteres más]
```

```text
top (sum,maxO1,maxO2,Lh,Lv):
(42, 14, 28, 7, 12)
(38, 12, 26, 7, 14)
(38, 12, 26, 7, 13)
(38, 12, 26, 7, 11)
(38, 12, 26, 7, 10)
(36, 14, 22, 8, 12)
(35, 13, 22, 6, 12)
(34, 13, 21, 8, 13)
(33, 13, 20, 8, 11)
(33, 13, 20, 8, 10)
(33, 12, 21, 6, 11)
(32, 12, 20, 7, 15)
```

**Pensamiento:**

The maximum possible coverage is 42 = |Y| exactly, achieved ONLY at (Lh=7, Lv=12) with maxO1=14 and maxO2=28 ✓✓. That's the unique candidate! And it means both objects must be at their best poses and their coverages must be disjoint and together cover all 42 ✓.
This strongly suggests the solution: Lh=7, Lv=12.
Now find the poses: for (Lh=7, Lv=12), find pose1 with popcount 14 and pose2 with popcount 28 such that mask1|mask2 == FULL.
Let me also compute the extras for those. Then compute the moves needed:
- h-line: currently block row 5 → 7: 2 DOWN.
- v-line: currently block col 3 → 12: 9 RIGHT.
- O1 (staircase) currently at pose (13,17) [bbox top-left block: rows 13-19, cols 17-19] → target pose.
- O2 (cross) currently at pose (16,5) → target pose.
Let me find the poses.

```python
Yl=[(1,7),(1,9),(1,11),(1,13),(1,15),(1,17),(2,13),(2,14),(2,15),(3,7),(3,13),(3,14),(3,15),(3,17),(4,9),(4,11),(4,13),(4,15),(5,8),(5,16),(7,9),(7,15),(9,8),(9,16),(10,9),(10,11),(10,13),(10,15),(11,7),(11,9),(11,10),(11,11),(11,17),(12,9),(12,10),(12,11),(13,7),(13,9),(13,11),(13,13),(13,15),(13,17)]
O1={(0,2),(1,2),(2,1),(2,2),(3,1),(4,0),(4,1),(5,0),(6,0)}
O2={(0,1),(0,3),(1,0),(1,1),(1,2),(1,3),(1,4),(2,0),(2,1),(2,2),(2,3),(2,4),(3,1),(3,3)}
tabs,FULL=build7(Yl,O1,O2)
Lh,Lv=7,12
L1=lists7(tabs,FULL,Lh,Lv,'O1'); L2=lists7(tabs,FULL,Lh,Lv,'O2')
L1b=[x for x in L1 if bin(x[0]).count('1')>=13]
L2b=[x for x in L2 if bin(x[0]).count('1')>=27]
print('cands',len(L1b),len(L2b))
sols=[]
for m1,e1,r1,c1 in L1b:
    for m2,e2,r2,c2 in L2b:
        if (m1|m2)==FULL: sols.append((e1+e2,e1,(r1,c1),
… [53 caracteres más]
```

```text
cands 10 4
(48, 20, (1, 15), 28, (1, 8))
(48, 20, (1, 15), 28, (1, 12))
(48, 20, (1, 15), 28, (10, 8))
(48, 20, (1, 15), 28, (10, 12))
(48, 20, (7, 7), 28, (1, 8))
(48, 20, (7, 7), 28, (1, 12))
(48, 20, (7, 7), 28, (10, 8))
(48, 20, (7, 7), 28, (10, 12))
```

## Paso 37 · nivel 7 · acción 231

**Pensamiento:**

Solutions found at (Lh=7, Lv=12):
- O1 (staircase) at pose (1,15) or (7,7); O2 (cross) at pose (1,8), (1,12), (10,8), or (10,12).
All with 48 extras total (20 for O1, 28 for O2). Hmm, 48 extras is a lot (the union = 42 covered + 48 extras = 90 cells ≈ the full 8 images = 92 with 2 overlaps). So the coverage is "sparse dithered" — the images cover the yellow plus lots of blue. That's consistent with the yellow being a sparse subset of the images.
Hmm, 48 extras is suspicious. In level 5 the extras were 10, in level 6 zero. Here 48?! That means the yellow is a sparse subset of the images — i.e., the yellow pattern marks only some of the image cells. That seems like a strange puzzle design... 
Hmm wait. Maybe the rule isn't "cover the yellow" but something like "the yellow cells must be covered AND the non-yellow cells must NOT be covered" — impossible here. So maybe the actual goal is different!
Alternatively, maybe the goal is the REVERSE: the images must cover exactly the yellow... impossible → so maybe the goal is something else entirely, e.g., the reflections must cover the yellow's "shape" in a different sense.
Hmm, let me reconsider. What if the yellow pattern represents where the reflections currently are NOT, and the goal is to make the reflections form a symmetric picture... 
Let me look at the yellow pattern's structure again with the (Lh=7, Lv=12) hypothesis in mind:
The union of the 8 images at the solution = 90 cells (42 yellow + 48 blue). Hmm.
Alternatively, maybe
… [5455 caracteres más]

```python
def sel7(fr):
    a=fr.ascii.split('\n')
    Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
    Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
    hr=Srows[len(Srows)//2]; vc=Scols[len(Scols)//2]
    W={(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'}
    if sum(1 for c in range(63) if (hr,c) in W)>5: return 'hline'
    if sum(1 for r in range(63) if (r,vc) in W)>5: return 'vline'
    blk=sorted({(r//3,c//3) for (r,c) in W})
    return 'blk@'+str(min(b[0] for b in blk))+','+str(min(b[1] for b in blk))+' n='+str(len(blk))
print('start',sel7(current_frame),'hline row',16,'vline col',10)
for i in range(4):
    res=action(['SPACE'])
    print(i,'->',sel7(current_frame),'lc',res.get('level_completed'))
print('budget',bar(cu
… [13 caracteres más]
```

```text
start hline hline row 16 vline col 10
[action] SPACE -> effect
0 -> vline lc False
[action] SPACE -> effect
1 -> blk@13,17 n=9 lc False
[action] SPACE -> effect
2 -> blk@16,5 n=14 lc False
[action] SPACE -> effect
3 -> hline lc False
budget 60
```

## Paso 38 · nivel 7 · acción 249

**Pensamiento:**

Cycle: hline → vline → O1 (staircase at 13,17) → O2 (cross at 16,5) → hline ✓. Budget 60, currently hline is selected.
Plan (starting from hline selected):
1. hline: 2 DOWN (row 5 → 7).
2. SPACE ×3 → O1: 12 UP + 2 LEFT (pose (13,17) → (1,15)).
   Wait, the cycle from hline: SPACE → vline, SPACE → O1. So 2 SPACEs to reach O1 ✓ (hline→vline→O1).
3. SPACE → O2: 6 UP + 3 RIGHT ((16,5) → (10,8)).
4. SPACE → vline: 9 RIGHT (col 3 → 12).
Order matters for collisions. Let me check:
- If I move the h-line down 2 first (to row 7): fine.
- O1 moves UP 12 → passes through rows 1-7 at cols 17-19. O2 at rows 16-19 cols 5-9 ✓ no collision.
- O2 moves UP 6 → rows 10-13 cols 5-9; O1 at rows 1-7 cols 15-17 ✓ fine. Then RIGHT 3 → cols 8-12 ✓.
- The v-line moving right from col 3 to 12: it crosses everything (lines are fine).
Total: 2 + 2 SPACE + 14 + 1 SPACE + 9 + 1 SPACE + 9 = 38 actions. Budget 60 ✓.
Let me execute in stages with verification. Stage 1: 2 DOWN for the h-line, verify Srows = [21,22,23].
Actually, let me batch more aggressively but verify after each stage using direct action() calls (avoiding try_act's stale-state halt). I'll write a helper that executes a batch and reports the level-completion status and any stop.
Let me do stage 1+2 in one call: ['DOWN','DOWN','SPACE','SPACE'] then the O1 moves, then check.
Careful: after moving the h-line, sel7's hline detection uses the middle S row — fine.
Let me execute: batch1 = ['DOWN','DOWN','SPACE','SPACE'] → then verify sel7 == 'blk@1
… [242 caracteres más]

```python
def st(fr):
    a=fr.ascii.split('\n')
    Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
    Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
    B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
    bl={b for b in {(r//3,c//3) for r,c in B}}
    o1=sorted(b for b in bl if b[0]<12)
    return Srows[0]//3 if Srows else None, Scols[0]//3 if Scols else None, sel7(fr)
res=action(['DOWN','DOWN','SPACE','SPACE'])
print('after hline 2DOWN + 2SPACE:',st(current_frame),'lc',res.get('level_completed'))
res=action(['UP']*12+['LEFT']*2)
a=current_frame.ascii.split('\n')
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
bl=sorted({(r//3,c//3) for r,c in B})
print('B blocks',bl,'sel',sel7(current_frame),'budget',bar(c
… [46 caracteres más]
```

```text
[action] batch of 4 actions, 4 executed: DOWN, DOWN, SPACE, SPACE
after hline 2DOWN + 2SPACE: (7, 3, 'blk@13,17 n=9') lc False
[action] batch of 14 actions, 14 executed: UP, UP, UP, UP, UP, UP, UP, UP, UP, UP, UP, UP, LEFT, LEFT
B blocks [(1, 17), (2, 17), (3, 16), (3, 17), (4, 16), (5, 15), (5, 16)
… [181 caracteres más]
```

## Paso 39 · nivel 7 · acción 259

**Pensamiento:**

O1 (staircase) is now at blocks (1,17),(2,17),(3,16),(3,17),(4,16),(5,15),(5,16),(6,15),(7,15) → bbox top-left (1,15) ✓ = the target pose ✓.
The h-line is at block row 7 ✓ (st() showed 7). The v-line at col 3.
Interesting: the reflections visible — the staircase's h-mirror (charcoal) is at rows 8-14 cols 15-17 ✓, and the v-mirror (off-board mostly, shown in blue at the bottom right?? the blue staircase at the bottom right is the v-mirror about col 3 → cols -13..-11 → hmm, that's off-board. The blue staircase shape at the bottom-right of the diff image is just the "changed cells" rendering of the original object's previous position (dark navy = unchanged; the blue shape is the object's old position rendered in its new color... hmm, whatever).
Wait, actually the blue staircase at the bottom right in the diff image is suspicious. In the diff image, unchanged cells are dark navy and changed cells are shown in their new true color. The blue staircase at cols ~38-42, rows ~28-42 (image coords) hmm. That region is where the object WAS (before moving up), and now it's blue (background) ✓ — makes sense: those cells changed from black to blue ✓.
Now: O2 (cross) → (10,8): 6 UP + 3 RIGHT. Then the v-line: 9 RIGHT.
Budget 42. Remaining: 1 SPACE + 9 + 1 SPACE + 9 = 20 ✓.
Let me execute: SPACE (→O2), 6 UP, 3 RIGHT, verify, then SPACE (→hline!) hmm — the cycle: O2 → hline → vline. So after O2, I need 2 SPACEs to reach the vline. Total 1+9+2+9 = 21 ≤ 42 ✓.
Let me execute the O2 stage first an
… [9 caracteres más]

```python
res=action(['SPACE'])
print('sel',sel7(current_frame))
res=action(['UP']*6+['RIGHT']*3)
a=current_frame.ascii.split('\n')
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
bl=sorted({(r//3,c//3) for r,c in B})
print('B blocks',bl,'sel',sel7(current_frame),'budget',bar(current_frame),'lc',res.get('level_completed'))
```

```text
[action] SPACE -> effect
sel blk@16,5 n=14
[action] batch of 9 actions, 9 executed: UP, UP, UP, UP, UP, UP, RIGHT, RIGHT, RIGHT
B blocks [(1, 17), (2, 17), (3, 16), (3, 17), (4, 16), (5, 15), (5, 16), (6, 15), (7, 15), (10, 9), (10, 11), (11, 8), (11, 9), (11, 10), (11, 11), (11, 12), (12, 8), (12, 
… [88 caracteres más]
```

**Nivel 7 completado → nivel 8 (acción 270)**

## Paso 40 · nivel 8 · acción 270

**Pensamiento:**

O2 (cross) is now at blocks (10,9),(10,11),(11,8..12),(12,8..12),(13,9),(13,11) → bbox top-left (10,8) ✓ target ✓.
Its h-mirror (charcoal) appears at rows 1-4 cols 8-12 ✓ (visible in the image at the top).
Now the final step: move the v-line from col 3 to col 12: 9 RIGHT. The cycle from O2: SPACE → hline, SPACE → vline. So 2 SPACEs + 9 RIGHT = 11 actions (budget 32 ✓).
Let me execute and check for completion.

```python
res=action(['SPACE','SPACE'])
print('sel',sel7(current_frame))
res=action(['RIGHT']*9)
print('lc',res.get('level_completed'),'go',res.get('game_over'),'done',res.get('run_complete'),'level',current_frame.level,'budget',bar(current_frame))
a=current_frame.ascii.split('\n')
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('Scols',Scols)
```

```text
[action] batch of 2 actions, 2 executed: SPACE, SPACE
sel vline
[action] batch of 9 actions, 9 executed: RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT | stop_reason: level_completed
lc True go False done False level 8 budget 64
Scols [9, 10, 11]
```

## Paso 41 · nivel 8 · acción 270

**Pensamiento:**

Level 8! New feature: the yellow pattern is a "line drawing" (thin paths, not blocks?) — it looks like continuous yellow paths (2 cells wide? or 3?). Also there's a black object partly crossing the h-line (with a charcoal part above the line — that's its reflection).
Also the yellow seems to extend to the right edge (col 63?) — the HUD is yellow here! Let me analyze carefully.
Let me get: the line positions, the yellow structure (is it block-aligned?), the black objects, and the budget.

```python
fr=current_frame
a=fr.ascii.split('\n')
Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
print('Srows',Srows,'Scols',Scols,'budget',bar(fr),'sel',sel7(fr))
print('counts',{ch:sum(a[r][c]==ch for r in range(64) for c in range(64)) for ch in 'bSYWcG'})
# yellow cell rows/cols profile
Y={(r,c) for r in range(63) for c in range(63) if a[r][c]=='Y'}
print('Y cells',len(Y))
rows=sorted({r for r,c in Y}); cols=sorted({c for r,c in Y})
print('Y rows',rows)
print('Y cols',cols)
```

```text
Srows [15, 16, 17] Scols [9, 10, 11] budget 64 sel hline
counts {'b': 2942, 'S': 312, 'Y': 588, 'W': 19, 'c': 52, 'G': 0}
Y cells 524
Y rows [9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59]
Y cols [12, 13,
… [112 caracteres más]
```

**Pensamiento:**

Hmm interesting: the yellow cells span rows 9-26 and 42-59, cols 12-26 and 48-62. But the image shows yellow at the top-right and bottom-right, and at cols 12-26. Note the yellow doesn't cover the full block grid — it's a "thick line drawing".
Hmm, wait: the yellow rows 9-26 (18 rows = 6 block rows) and 42-59 (18 rows = 6 block rows). The cols: 12-26 (15 cols = 5 block cols) and 48-62 (15 cols = 5 block cols). So the yellow occupies 4 quadrants-ish regions: top-left (rows 9-26, cols 12-26), top-right (rows 9-26, cols 48-62), bottom-left (rows 42-59, cols 12-26), bottom-right (rows 42-59, cols 48-62).
Interesting! So the yellow pattern is arranged in 4 corner blocks — consistent with the mirror-symmetric design (the pattern appears in the 4 mirrored positions) ✓. Each quadrant region is 6x5 blocks.
So the yellow pattern here is the same "target" concept. Let me extract the yellow blocks and check the symmetry. Also extract the black objects.
Note: the yellow total 524 cells; 524/9 = 58.2 → not a multiple of 9, so some yellow cells are partial blocks (because the objects cover some yellow cells, or the yellow isn't block-aligned).
Hmm, the yellow drawing has "thin" parts (e.g., 3-cell-wide paths) → each path segment is a line of 3x3 blocks ✓ block-aligned. Let me extract the block set and print the grid.

```python
fr=current_frame; a=fr.ascii.split('\n')
Yb=sorted({(r//3,c//3) for r in range(63) for c in range(63) if a[r][c]=='Y'})
print('Y blocks',len(Yb))
print('    '+''.join(str(c%10) for c in range(21)))
for r in range(0,21):
    print(f'{r:3d} '+''.join('#' if (r,c) in set(Yb) else '.' for c in range(21)))
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
seen=set(); objs=[]
for p in sorted(B):
    if p in seen: continue
    st=[p]; comp=set()
    while st:
        r,c=st.pop()
        if (r,c) in comp: continue
        comp.add((r,c))
        for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
            q=(r+dr,c+dc)
            if q in B and q not in comp: st.append(q)
    seen|=comp; objs.append(comp)
for o in objs:
    bl=sorted({(r//3,c//3) for r,c in o})
    print('obj',len(o),'px b
… [119 caracteres más]
```

```text
Y blocks 60
    012345678901234567890
  0 .....................
  1 .....................
  2 .....................
  3 ......###.......###..
  4 ......#...........#..
  5 ......#...........#..
  6 ....###...........###
  7 ....#.#...........#.#
  8 ....#####.......#####
  9 .....................
 1
… [526 caracteres más]
```

**Pensamiento:**

Now I see:
- Yellow: 60 blocks in 4 corner clusters (top: rows 3-8, bottom: rows 14-19, left: cols 4-8, right: cols 16-20). Each cluster is 15 blocks. 4 × 15 = 60 ✓.
- The pattern is symmetric: the top-left cluster (rows 3-8, cols 4-8):
```
r3:  . . # # # . . .   (cols 6,7,8)
r4:  . . . # . . . .   (col 6)
r5:  . . . #
r6:  . # # # . . . .   (cols 4,5,6)
r7:  . # . #
r8:  . # # # # #       (cols 4-8)
```
And the bottom-left is the mirror (rows 14-19 = mirror of rows 3-8 about row... 3↔19? Let me check: the mirror about row 11: r → 22-r: 3↔19 ✓, 8↔14 ✓. And the left-right mirror: cols 4-8 ↔ 16-20 → c → 24-c: 4↔20 ✓, 8↔16 ✓ (mirror about col 12).
So the yellow is symmetric about block row 11 and block col 12 ✓. So the target lines: Lh=11, Lv=12.
- Objects: 
  obj1 (7 blocks): (7,7),(7,8),(7,9),(8,9),(9,9),(10,9),(11,9) — an L-shape (3 wide + 5 tall).
  obj2 (8 blocks): (13,13),(13,14),(14,13),(15,13),(15,14),(15,15),(15,16),(15,17) — another L-ish shape.
  Total 15 blocks = exactly the size of one quadrant cluster (15) ✓✓. So the yellow = the 4 mirror images of the combined objects (each quadrant has the images of both objects: obj1's image (7) + obj2's image (8) = 15 ✓).
So the target: Lh=11, Lv=12, and each object's identity placed within one quadrant such that the 4 images tile the yellow exactly.
Note the yellow is exactly 4 copies (by symmetry) → the identity images must be inside one quadrant region (rows 3-8 or 14-19, cols 4-8 or 16-20) — actually the identity images cou
… [417 caracteres más]

```python
Yl=[(3,6),(3,7),(3,8),(3,16),(3,17),(3,18),(4,6),(4,16),(5,6),(5,16),(6,4),(6,5),(6,6),(6,18),(6,19),(6,20),(7,4),(7,6),(7,16),(7,18),(7,20),(8,4),(8,5),(8,6),(8,7),(8,8),(8,16),(8,17),(8,18),(8,19),(8,20),
(14,4),(14,5),(14,6),(14,7),(14,8),(14,16),(14,17),(14,18),(14,19),(14,20),(15,4),(15,6),(15,16),(15,18),(15,20),(16,4),(16,5),(16,6),(16,18),(16,19),(16,20),(17,6),(17,16),(18,6),(18,16),(19,6),(19,7),(19,8),(19,16),(19,17),(19,18)]
Yset=set(Yl); idx={b:i for i,b in enumerate(Yl)}
print('Y',len(Yl))
O1={(0,0),(0,1),(0,2),(1,2),(2,2),(3,2),(4,2)}
O2={(0,0),(0,1),(1,0),(2,0),(2,1),(2,2),(2,3),(2,4)}
def norm(S):
    r0=min(r for r,c in S); c0=min(c for r,c in S); return frozenset((r-r0,c-c0) for r,c in S)
print('O1 rel',sorted(norm(O1)),'O2 rel',sorted(norm(O2)))
def clip(S): return {p f
… [661 caracteres más]
```

```text
Y 62
O1 rel [(0, 0), (0, 1), (0, 2), (1, 2), (2, 2), (3, 2), (4, 2)] O2 rel [(0, 0), (0, 1), (1, 0), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4)]
sols []
```

## Paso 41 · nivel 8 · acción 270

**Pensamiento:**

My hand-typed Y list has 62 entries but the extraction said 60 — I mis-typed. Let me recompute Y from the frame programmatically instead of hand-typing, and redo the search. Also note the yellow may be partially hidden under the black objects (obj1 at rows 7-11 cols 7-9 overlaps the yellow's top-left cluster region rows 3-8 cols 4-8 → the block (7,7),(7,8) region... hmm, obj1's blocks (7,7),(7,8),(7,9) — and the yellow at row 7 has (7,4),(7,6) — so (7,7),(7,8) are NOT yellow (they're the object). But could there be yellow hidden under the object? The yellow cluster at rows 3-8 cols 4-8: 
r3: 6,7,8
r4: 6
r5: 6
r6: 4,5,6
r7: 4,6
r8: 4,5,6,7,8
The object obj1 covers (7,7),(7,8),(7,9),(8,9),(9,9),(10,9),(11,9). So (7,7),(7,8) are covered by the object → possibly yellow underneath!
Similarly obj2 covers (13,13),(13,14),(14,13),(15,13),(15,14),(15,15),(15,16),(15,17) — the yellow's bottom-left cluster is at rows 14-19 cols 4-8 and the bottom-right at cols 16-20. (15,16),(15,17) are covered by obj2 and the yellow at row 15 has (15,16) ✓ visible... wait, if obj2 covers (15,16), the yellow there wouldn't be visible. My extraction found (15,16) as yellow → contradiction? Let me recheck: obj2's blocks: (13,13),(13,14),(14,13),(15,13),(15,14),(15,15),(15,16),(15,17). And the yellow extraction found (15,16) and (15,18),(15,20)... 
Hmm, if obj2 occupies (15,16), then the yellow at (15,16) can't be visible. Unless my block extraction for the yellow picked up a cell in that block that is yel
… [550 caracteres más]

```python
a=current_frame.ascii.split('\n')
print('rows 39-48 cols 36-63')
for r in range(39,49): print(r,a[r][36:63])
print('rows 18-27 cols 12-33')
for r in range(18,28): print(r,a[r][12:33])
```

```text
rows 39-48 cols 36-63
39 bbbBBBBBBbbbbbbbbbbbbbbbbbb
40 bbbBbBBbBbbbbbbbbbbbbbbbbbb
41 bbbBBBBBBbbbbbbbbbbbbbbbbbb
42 bbbBBBbbbbbbYYYYYYYYYYYYYYY
43 bbbBbBbbbbbbYYYYYYYYYYYYYYY
44 bbbBBBbbbbbbYYYYYYYYYYYYYYY
45 bbbBBBBBBBBBBBBBBBYYYbbbYYY
46 bbbBbBBbBBbBBbBBbBYYYbbbYYY
47 bbbBBBBBBBBBBBBBBBYYYbbbYYY
… [303 caracteres más]
```

**Pensamiento:**

Now I see the issue: the objects are NOT block-aligned! Look at rows 39-41: 'bbbBBBBBBbbbb...' at cols 36-42 → the object's cells at cols 39-45: that's block col 13 (cols 39-41) and block col 14 (cols 42-44) → hmm, 'bbbBBBBBBbbb' starting at col 36: cols 39,40,41 = B (block 13 ✓) and 42,43,44 = B? The string 'bbbBBBBBBbbbb' → indices 0-2 = 'bbb' (cols 36-38), then 7 B's at cols 39-45, then 'bbb' → so cols 39-45 are B: block col 13 (39-41) ✓, block col 14 (42-44) ✓, and col 45 (block 15's first cell) ✗ — so the object extends 1 cell into block col 15 → NOT block-aligned!
So in level 8 the objects are offset from the 3-grid. Interesting: the objects may be at arbitrary positions (moving 3 cells per press but starting off-grid).
Hmm, wait: maybe the objects ARE aligned to a 3-grid but with an offset (e.g., the object's blocks are at cols 39-45 = a 7-wide span?). Let me look at obj2's full shape at cell level to determine its exact geometry.
Let me print the full ascii of both objects' regions.

```python
a=current_frame.ascii.split('\n')
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
for (r0,r1,c0,c1),tag in [((36,50,36,52),'obj2 area'),((18,36,12,33),'obj1 area')]:
    print('===',tag)
    for r in range(r0,r1+1): print(r,a[r][c0:c1+1])
```

```text
=== obj2 area
36 bbbbbbbbbbbbbbbbb
37 bbbbbbbbbbbbbbbbb
38 bbbbbbbbbbbbbbbbb
39 bbbBBBBBBbbbbbbbb
40 bbbBbBBbBbbbbbbbb
41 bbbBBBBBBbbbbbbbb
42 bbbBBBbbbbbbYYYYY
43 bbbBbBbbbbbbYYYYY
44 bbbBBBbbbbbbYYYYY
45 bbbBBBBBBBBBBBBBB
46 bbbBbBBbBBbBBbBBb
47 bbbBBBBBBBBBBBBBB
48 bbbbbbbbbbbbbbbbb
49 bbbbbbbbbb
… [536 caracteres más]
```

**Pensamiento:**

Now I see the objects' exact cell geometry (cols offset by the crop):
obj1 area (crop starts at col 12):
rows 21-23: B at cols 21-29 (7 cells: 'BBBBBBBBB' at crop indices 9-17 → cols 21-29)
rows 24-35: B at cols 27-29 ('BBB' at crop indices 15-17 → cols 27-29)
So obj1 = a horizontal bar of 7 cells (rows 21-23, cols 21-29) + a vertical bar 3 wide × 12 rows (rows 24-35, cols 27-29).
Hmm, that's not block-aligned: the bar is 7 cells wide (not a multiple of 3) and 12 tall.
Hmm, interesting! So the objects are made of 3-wide strokes but with lengths that aren't multiples of 3 — i.e., the objects are "polyomino strokes" at CELL resolution, not block resolution!
And the yellow: rows 18-20 cols 12-20 (9x3), rows 21-23: cols 12-14 and 18-20, rows 24-26: cols 12-26 → the yellow is also at cell resolution with 3-wide strokes.
So in level 8, everything is 3-wide strokes but not aligned to a global 3-grid! The alignment: the yellow at rows 18-20 (3-aligned ✓), cols 12-20 (12 is 3-aligned ✓). obj1's bar at rows 21-23 (3-aligned ✓), cols 21-29 (21 = 3*7 ✓, 29 = 3*10-1 ✗ → 7 cells wide, so it spans cols 21-29 = block cols 7,8,9 but only 1 cell into block col 9 (cols 27,28,29 = block 9 ✓). Hmm: 21-23 = block 7, 24-26 = block 8, 27-29 = block 9 ✓ — that IS 3-aligned! cols 21-29 = blocks 7,8,9 ✓✓ (9 cells? no: 21,22,...,29 = 9 cells!). Let me recount 'BBBBBBBBB' = 9 characters? 'bbbBBBBBBBBBbbbb' → indices: 0,1,2='bbb', then 3..11 = 'BBBBBBBBB' (9 chars) → cols 15..23?? 
Hold on, the crop for o
… [1142 caracteres más]

```python
a=current_frame.ascii.split('\n')
B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
seen=set(); objs=[]
for p in sorted(B):
    if p in seen: continue
    st=[p]; comp=set()
    while st:
        r,c=st.pop()
        if (r,c) in comp: continue
        comp.add((r,c))
        for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
            q=(r+dr,c+dc)
            if q in B and q not in comp: st.append(q)
    seen|=comp; objs.append(comp)
for o in objs:
    rs=sorted({r for r,c in o}); cs=sorted({c for r,c in o})
    print('obj bbox',min(rs),min(cs),max(rs),max(cs),'cells',len(o))
    for r in range(min(rs),max(rs)+1):
        runs=[]
        c=min(cs)
        while c<=max(cs):
            if (r,c) in o:
                s=c
                while (r,c) in o: c+=1
                runs.app
… [61 caracteres más]
```

```text
obj bbox 21 21 35 29 cells 56
  21 [(21, 29)]
  22 [(21, 21), (23, 24), (26, 27), (29, 29)]
  23 [(21, 29)]
  24 [(27, 29)]
  25 [(27, 27), (29, 29)]
  26 [(27, 29)]
  27 [(27, 29)]
  28 [(27, 27), (29, 29)]
  29 [(27, 29)]
  30 [(27, 29)]
  31 [(27, 27), (29, 29)]
  32 [(27, 29)]
  33 [(27, 29)]
  
… [293 caracteres más]
```

## Paso 41 · nivel 8 · acción 274

**Pensamiento:**

Now I have exact cell geometry:
obj1: bbox rows 21-35, cols 21-29.
  rows 21-23: a 9-wide bar (cols 21-29) — 3 rows × 9 cols = an L's horizontal arm (3 blocks wide)
  rows 24-35: cols 27-29 (3 wide × 12 tall = 4 blocks)
  So obj1 = an L-shape: a 3-block horizontal bar (3 blocks: cols 21-23,24-26,27-29 at rows 21-23) plus a 4-block vertical bar going down at cols 27-29 (rows 24-26, 27-29, 30-32, 33-35).
  In block terms: the bar occupies block rows 7, cols 7,8,9; the vertical part occupies block rows 8-11, block col 9.
  That's exactly what my block extraction said: (7,7),(7,8),(7,9),(8,9),(9,9),(10,9),(11,9) ✓ — 7 blocks ✓ and 3-aligned ✓.
  Note the dots: row 22 shows dots at cols 23,24 (a dot spanning cols 23-24?) hmm: row 22 runs: (21,21),(23,24),(26,27),(29,29) → the B cells are at 21, 23-24, 26-27, 29 and the dots (blue) at 22, 25, 28 → the dots are 1 cell wide at cols 22, 25, 28 (the block centers of block cols 7,8,9 ✓ = 22, 25, 28 ✓✓). 
  So the dots are 1x1 at the block centers ✓ (not 2x2 as in earlier levels). Fine.
obj2: bbox rows 39-47, cols 39-53.
  rows 39-41: cols 39-44 (6 wide = 2 blocks: cols 39-41, 42-44) ✓ 3-aligned ✓
  rows 42-44: cols 39-41 (1 block)
  rows 45-47: cols 39-53 (15 wide = 5 blocks: cols 39-41,...,51-53) ✓
  So obj2 in blocks: (13,13),(13,14),(14,13),(15,13),(15,14),(15,15),(15,16),(15,17) ✓ = my earlier extraction ✓ 3-aligned ✓.
Great, so everything IS 3-aligned; my earlier confusion was a misread.
So the search should work with block coordin
… [439 caracteres más]

```python
def solve8(fr,Lhs=None,Lvs=None):
    a=fr.ascii.split('\n')
    Y={(r//3,c//3) for r in range(63) for c in range(63) if a[r][c]=='Y'}
    Y={b for b in Y if b[1]<=20}
    B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
    seen=set(); objs=[]
    for p in sorted(B):
        if p in seen: continue
        st=[p]; comp=set()
        while st:
            r,c=st.pop()
            if (r,c) in comp: continue
            comp.add((r,c))
            for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
                q=(r+dr,c+dc)
                if q in B and q not in comp: st.append(q)
        seen|=comp; objs.append(comp)
    shapes=[]
    for o in objs:
        bl={(r//3,c//3) for r,c in o}
        r0=min(r for r,c in bl); c0=min(c for r,c in bl)
        shapes.append((frozenset((r-r0,c
… [1193 caracteres más]
```

```text
Y 60 shapes [(7, (7, 7)), (8, (13, 13))]
SOL (11, 12, ((3, 16), (6, 4)))
```

**Pensamiento:**

Found the unique solution for (Lh=11, Lv=12):
- obj1 (7 blocks, currently at pose (7,7)) → target pose (3,16)
- obj2 (8 blocks, currently at pose (13,13)) → target pose (6,4)
Wait, that's interesting: obj1 goes to the top-right quadrant and obj2 to the top-left quadrant. Hmm, but the identity images must be ⊆ Y; both are in the top quadrants (rows 3-8) ✓.
Let me double check: obj1 at (3,16): its blocks = (3,16),(3,17),(3,18),(4,18),(5,18),(6,18),(7,18) — is that ⊆ Y? Y has (3,16),(3,17),(3,18) ✓, (4,16) ✗ hmm — (4,18) — Y has (4,16) and (4,18)? Let me check my Y extraction... The printed grid earlier (hand-typed) is unreliable; the programmatic extraction found the exact tiling ✓ so it's consistent.
Hmm, but wait: obj1's shape is {(0,0),(0,1),(0,2),(1,2),(2,2),(3,2),(4,2)} → at (3,16): (3,16),(3,17),(3,18),(4,18),(5,18),(6,18),(7,18). And the top-left cluster of Y (rows 3-8, cols 4-8):
```
r3: 6,7,8
r4: 6
r5: 6
r6: 4,5,6
r7: 4,6
r8: 4,5,6,7,8
```
The mirror of obj1's identity about col 12 → cols 24-c: obj2 at (6,4): (6,4),(6,5),(6,6),(7,4),(7,6),(8,4),(8,5),(8,6),(8,7),(8,8)? Let me compute obj2's shape {(0,0),(0,1),(1,0),(2,0),(2,1),(2,2),(2,3),(2,4)} at (6,4): (6,4),(6,5),(7,4),(8,4),(8,5),(8,6),(8,7),(8,8) ✓ — all in the top-left cluster ✓ (Y has (6,4),(6,5),(6,6)... hmm (6,6) is covered by obj1's mirror? obj1's v-mirror: (3,8),(3,7),(3,6),(4,6),(5,6),(6,6),(7,6) ✓ = the remaining cells ✓. And the h-mirrors fill the bottom quadrants ✓.
The tiling works out exactly (the sea
… [5974 caracteres más]

```python
def selinfo(fr):
    s=sel7(fr)
    if s.startswith('blk'):
        parts=s.replace('blk@','').replace(' n=',' ').split()
        return ('blk',int(parts[0]),int(parts[1]),int(parts[2]))
    return (s,)
def ensure(target,maxp=6):
    for i in range(maxp):
        si=selinfo(current_frame)
        if target=='hline' and si[0]=='hline': return True
        if target=='vline' and si[0]=='vline': return True
        if target=='obj1' and si[0]=='blk' and si[3]==7: return True
        if target=='obj2' and si[0]=='blk' and si[3]==8: return True
        r=action(['SPACE'])
        if r.get('level_completed') or r.get('game_over'): return 'STOP'
    return False
print('start sel',selinfo(current_frame))
ok=ensure('vline')
print('vline selected?',ok)
res=action(['RIGHT']*3)
a=current_frame.ascii.s
… [182 caracteres más]
```

```text
start sel ('hline',)
[action] SPACE -> effect
vline selected? True
[action] batch of 3 actions, 3 executed: RIGHT, RIGHT, RIGHT
after 3 RIGHT Scols [18, 20] lc False budget 60
```

## Paso 42 · nivel 8 · acción 281

**Pensamiento:**

Hmm! After 3 RIGHT, Scols = [18, 20] — that's odd. The v-line moved from col 3 to... Scols [18,20] means the S cells in those columns. Wait, the detection uses columns with >20 S cells; the v-line is 3 columns wide (e.g., 9,10,11). Now Scols = [18,20]?? That suggests the line is now at cols 18-20 but with a gap (col 19 missing?). Hmm, maybe the line's dots at col 19 are covered by something (a white dot → W instead of S?). Hmm.
Actually, looking at the image: the vertical light-blue line is at around x=180-200 px → cols 60-66?? No: the image is 720 px wide for 64 cols → 11.25 px/col. The vertical line appears at x≈180-205 → cols 16-18. Hmm.
Wait, but the diff image shows the vertical line moved from x≈100 (col 9) to x≈205 (col 18)? The diff shows a new vertical strip at x≈205-230 (cols 18-20) ✓ and the old one at cols 9-11 turned blue ✓.
So 3 RIGHT moved the v-line from block col 3 to block col 6?? cols 18-20 = block col 6 ✓. So 1 press = 1 block col ✓ (3 → 6).
Scols=[18,20] because col 19's S count is lower (the dots at col 19 are W → not S) — right: the dots are at the block centers = col 19 ✓ (for block col 6, the center col is 19). So the S count in col 19 is 63-21=42... hmm, that's >20. Whatever, the detection is a bit off but fine.
Wait, but there's something important: the v-line moved 3 columns in 3 presses ✓ = 1 block per press ✓.
Hmm, but hold on: in the image I see the vertical line at cols 18-20 (block col 6) and the h-line still at row 5 (block row 5, cols 15-17 
… [595 caracteres más]

```python
def st8(fr):
    a=fr.ascii.split('\n')
    Srows=[r for r in range(63) if sum(1 for c in range(63) if a[r][c]=='S')>20]
    Scols=[c for c in range(63) if sum(1 for r in range(63) if a[r][c]=='S')>20]
    return (Srows[0]//3 if Srows else None, Scols[0]//3 if Scols else None)
res=action(['RIGHT']*6)
print('vline stage',st8(current_frame),'lc',res.get('level_completed'),'budget',bar(current_frame))
if not res.get('level_completed'):
    ok=ensure('obj1'); print('obj1 sel',ok,selinfo(current_frame))
    res=action(['UP']*4)
    print(' after 4UP',st8(current_frame),'lc',res.get('level_completed'))
    res=action(['RIGHT']*9)
    print(' after 9RIGHT',st8(current_frame),'lc',res.get('level_completed'),'budget',bar(current_frame))
```

```text
[action] batch of 6 actions, 6 executed: RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT
vline stage (5, 12) lc False budget 54
[action] SPACE -> effect

error:
Traceback (most recent call last):
  File "<python_tool>", line 9, in <module>
ValueError: invalid literal for int() with base 10: '13,13'
```

## Paso 43 · nivel 8 · acción 295

**Pensamiento:**

The v-line is now at block col 12 ✓ (st8 shows (5,12) — h-line row 5, v-line col 12 ✓ target reached for the v-line).
The error: selinfo failed parsing 'blk@13,13 n=8' → my replace produced '13,13 n=8' → split gave ['13,13','8']... Let me fix selinfo: parse properly.
Currently the selection after 1 SPACE from vline → obj2 (blk@13,13 n=8). Interesting: so the cycle here is hline → vline → obj2 → obj1? or the object order differs. Whatever — selinfo tells me what's selected.
Let me fix selinfo and continue: currently obj2 is selected (n=8, at 13,13). Target for obj2: (6,4) = 7 UP + 9 LEFT.
Let me do that now, then handle obj1 (UP 4 + RIGHT 9), then the h-line (DOWN 6).
Budget 54. Remaining: 16 + 1 + 13 + 1 + 6 = 37 ✓.
Note: obj2 first then obj1 — I earlier worried about a collision if obj2 moves left while obj1 is at (7,7): obj2 at pose (6,c0) transiting left, obj1 at (7,7): obj1's cells (7,7),(7,8),(7,9),(8,9),(9,9),(10,9),(11,9). obj2's cells at pose (6,c0): (6,c0),(6,c0+1),(7,c0),(8,c0),(8,c0+1),(8,c0+2),(8,c0+3),(8,c0+4). Collision when c0=4: obj2's (8,4..8) and obj1's (8,9)? no. (7,4) vs obj1's (7,7)? no. When c0=5: obj2's (8,5..9) → (8,9) collides with obj1's (8,9) ✗. But obj2 passes through c0=5 on its way to c0=4 → the collision would block the move at c0=5 (the object can't move further left) → STUCK.
So I must move obj1 FIRST. Currently obj2 is selected; I need obj1. The cycle: from obj2, one more SPACE → probably obj1 (or hline). Let me fix selinfo and use ensure('ob
… [30 caracteres más]

```python
import re
def selinfo(fr):
    s=sel7(fr)
    if s.startswith('blk'):
        m=re.match(r'blk@(\d+),(\d+) n=(\d+)',s)
        return ('blk',int(m.group(1)),int(m.group(2)),int(m.group(3)))
    return (s,)
print('now',selinfo(current_frame))
ok=ensure('obj1'); print('obj1 selected?',ok,selinfo(current_frame))
if ok is True:
    res=action(['UP']*4)
    print('4UP ->',selinfo(current_frame),'lc',res.get('level_completed'))
    res=action(['RIGHT']*9)
    print('9R ->',selinfo(current_frame),'lc',res.get('level_completed'),'budget',bar(current_frame))
```

```text
now ('blk', 13, 13, 8)
[action] SPACE -> effect
obj1 selected? True ('blk', 7, 7, 7)
[action] batch of 4 actions, 4 executed: UP, UP, UP, UP
4UP -> ('blk', 3, 9, 5) lc False
[action] batch of 9 actions, 9 executed: RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT

error:
Traceback (most
… [152 caracteres más]
```

## Paso 44 · nivel 8 · acción 297

**Pensamiento:**

obj1 moved: 4 UP then 9 RIGHT. The error was in selinfo when no W blocks exist (the selection is not an object). Let me make selinfo robust.
Now obj1 should be at pose (3,16)... The image shows the top-right object (black with dots) at rows ~90-270, cols ~530-640 → block rows 3-7, cols 17-19?? Hmm, let me verify with code.
Also I notice the object's shape in the image at the top-left looks like a "C" (charcoal) — that's the mirror.
Let me check the current state: the objects' block sets, the line positions, and the yellow.
Then move obj2 to (6,4): 7 UP + 9 LEFT.
Then the h-line DOWN 6 → row 11.
Let me first inspect.

```python
def safe_selinfo(fr):
    try: return selinfo(fr)
    except Exception: return (sel7(fr),)
def objposes(fr):
    a=fr.ascii.split('\n')
    B={(r,c) for r in range(63) for c in range(63) if a[r][c]=='B'}
    seen=set(); out=[]
    for p in sorted(B):
        if p in seen: continue
        st=[p]; comp=set()
        while st:
            r,c=st.pop()
            if (r,c) in comp: continue
            comp.add((r,c))
            for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
                q=(r+dr,c+dc)
                if q in B and q not in comp: st.append(q)
        seen|=comp
        bl={(r//3,c//3) for r,c in comp}
        out.append((min(r for r,c in bl),min(c for r,c in bl),len(bl),sorted(bl)))
    return out
for o in objposes(current_frame): print('pose',o[0],o[1],'n',o[2])
print('lines',
… [81 caracteres más]
```

```text
pose 3 16 n 7
pose 13 13 n 8

error:
Traceback (most recent call last):
  File "<python_tool>", line 23, in <module>
  File "<python_tool>", line 3, in safe_selinfo
ValueError: min() iterable argument is empty
```

**Pensamiento:**

obj1 is at pose (3,16) ✓ target reached!
obj2 still at (13,13) → needs 7 UP + 9 LEFT to (6,4).
The error is in sel7 itself (it uses min() on an empty W set → the selection is a line, not a block). Let me patch sel7 usage: wrap in try and return 'line/other'.
sel7 crashed → meaning there are NO W cells at all?! That means the current selection... hmm, if the selection is the hline or vline, the W dots are on the line → not empty. Unless the selection is on an object whose dotted blocks... no, objposes shows both objects with dots presumably.
Hmm, sel7 crashed at 'min(b[0] for b in blk)' with blk empty → W exists (else the earlier W-count checks would have returned 'hline'/'vline'... no wait: those checks require >5 W cells on the h-row/v-col; if W is empty, both checks fail and then blk is empty → crash. So there are no W cells at all right now.
That means nothing is selected?? Or the selection indicator is elsewhere. Hmm. Maybe after the batch, the "selection" moved to something else (e.g., a 5th selectable = the yellow target?). Let me check the W count and the S positions, and cycle SPACE to see.
Actually, maybe the selection is now on an object but the dots are rendered differently... Let me just check the W count.

```python
a=current_frame.ascii.split('\n')
W=sorted({(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'})
print('W cells',len(W),W[:20])
print('W blocks',sorted({(r//3,c//3) for r,c in W}))
print('lines',st8(current_frame),'budget',bar(current_frame))
```

```text
W cells 0 []
W blocks []
lines (5, 12) budget 39
```

**Pensamiento:**

No W cells at all → the selection is "nothing" (the cycle may include a null state, or pressing SPACE cycles: hline → vline → obj1 → obj2 → nothing?). Hmm. Earlier at level 8's start, the h-line was selected with W dots on it (19 W cells).
Hmm, budget 39. Used so far: 282→296 = 14 actions in the last two calls; total from 64 → 39 = 25 used. Wait, 64-39 = 25 ✓.
Hmm, so what is selected now? Maybe the "selection" indicator is a white dot on the selected object's blocks — and if no W cells exist, maybe the selection is on... hmm.
Wait — maybe the dots disappear when an object is at its correct position? Interesting hypothesis! obj1 is now at its target pose (3,16) and maybe... no, obj2 isn't at its target.
Alternatively, the selection is on the yellow target pattern (a "no-op" selectable).
Let me just press SPACE and see what becomes selected.
Also, I should double check the h-line target: 11 (currently 5) → 6 DOWN.
Budget 39: needed: obj2 (16) + h-line (6) + a few SPACEs ≈ 24 ✓.
Let me press SPACE once and inspect.

```python
r=action(['SPACE'])
a=current_frame.ascii.split('\n')
W=sorted({(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'})
print('after SPACE W blocks',sorted({(r//3,c//3) for r,c in W}),'lc',r.get('level_completed'))
r=action(['SPACE'])
a=current_frame.ascii.split('\n')
W=sorted({(r,c) for r in range(63) for c in range(63) if a[r][c]=='W'})
print('after 2nd SPACE W blocks',sorted({(r//3,c//3) for r,c in W}),'lc',r.get('level_completed'))
```

```text
[action] SPACE -> effect
after SPACE W blocks [(5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 7), (5, 8), (5, 9), (5, 10), (5, 11), (5, 12), (5, 13), (5, 14), (5, 15), (5, 16), (5, 17), (5, 19), (5, 20)] lc False
[action] SPACE -> effect
after 2nd SPACE W blocks [(0, 12), (1, 12), (2, 12), (3, 
… [177 caracteres más]
```

## Paso 45 · nivel 8 · acción 314

**Pensamiento:**

The cycle: (nothing) → hline → vline → ... So the cycle is: hline → vline → obj? → obj? → (nothing) → hline. Earlier: at level start hline was selected; SPACE → vline; SPACE → obj2 (13,13); SPACE → obj1 (7,7); then after obj1's moves, the selection showed no W (the "nothing" state?). Hmm, that came after obj1's moves — the selection stayed on obj1 but with no dots? That's odd.
Hmm, actually the "no W" state might be a "nothing selected" state that occurs after the last object. Then SPACE → hline ✓ (observed), SPACE → vline ✓ (observed).
Currently the vline is selected. I need obj2 (13,13) → 1 SPACE (if the cycle is hline→vline→obj2→obj1→none).
Then obj2: 7 UP + 9 LEFT → pose (6,4). Then the h-line: DOWN 6.
Budget: 39 - 2 = 37. Needed: 1 + 16 + then hline: from obj2's state, the cycle next → obj1 → none → hline = 3 SPACEs + 6 DOWN = 9. Total 26 ✓ fits in 37.
Let me execute: SPACE (→obj2), verify, then 7 UP + 9 LEFT, verify, then check completion; if not, cycle to hline and 6 DOWN.
Careful about obj2's transit: obj1 is at (3,16) (rows 3-7, cols 16-18); obj2 moving UP from (13,13) to (6,13): at pose (6,13) its cells are (6,13),(6,14),(7,13),(8,13),(8,14),(8,15),(8,16),(8,17) → obj1's cells: (3,16),(3,17),(3,18),(4,18),(5,18),(6,18),(7,18) → no overlap ✓. Then LEFT to (6,4): the transit passes (6,5): obj2's cells (8,5..9) — obj1 is gone from there ✓. Fine.
Let me do it.

```python
r=action(['SPACE'])
a=current_frame.ascii.split('\n')
Wb=sorted({(r_//3,c_//3) for r_ in range(63) for c_ in range(63) if a[r_][c_]=='W'})
print('sel blocks',Wb[:5],'n',len(Wb))
if len(Wb)==8 and Wb[0]==(13,13):
    r=action(['UP']*7)
    print('after 7UP',objposes(current_frame)[1][:3],'lc',r.get('level_completed'))
    r=action(['LEFT']*9)
    print('after 9L',objposes(current_frame)[1][:3],'lc',r.get('level_completed'),'budget',bar(current_frame))
```

```text
[action] SPACE -> effect
sel blocks [(13, 13), (13, 14), (14, 13), (15, 13), (15, 14)] n 8
[action] batch of 7 actions, 7 executed: UP, UP, UP, UP, UP, UP, UP
after 7UP (6, 13, 8) lc False
[action] batch of 9 actions, 9 executed: LEFT, LEFT, LEFT, LEFT, LEFT, LEFT, LEFT, LEFT, LEFT
after 9L (6, 4, 8
… [20 caracteres más]
```

## Paso 46 · nivel 8 · acción 315

**Pensamiento:**

Both objects are now at their target poses: obj1 (3,16), obj2 (6,4) ✓. The v-line is at 12 ✓. The h-line is still at 5 → needs 6 DOWN to reach 11.
Budget 20 ✓ plenty.
The remaining yellow is at the bottom (rows 14-19) ✓ — consistent: the top quadrants are covered by the objects, and the bottom quadrants need the h-mirrors (which will appear once the h-line moves to row 11).
Currently the h-line at row 5 → the h-mirrors of the objects are at rows 2*5-3.. = rows 3-7 (mirrored onto the top, overlapping the objects themselves).
Let me cycle to the hline: from obj2, the cycle is obj2 → obj1 → none → hline = 3 SPACEs. Then 6 DOWN. Total 9 ≤ 20 ✓.
Let me implement a robust "cycle to hline" that presses SPACE until the W blocks are on the h-line's row (block row 5 → many W in the same block row).
Then 6 DOWN and check completion.

```python
def wstate(fr):
    a=fr.ascii.split('\n')
    W={(r//3,c//3) for r in range(63) for c in range(63) if a[r][c]=='W'}
    if not W: return 'none'
    rows={}
    for r,c in W: rows[r]=rows.get(r,0)+1
    cols={}
    for r,c in W: cols[c]=cols.get(c,0)+1
    if any(v>10 for v in rows.values()): return 'hline'
    if any(v>10 for v in cols.values()): return 'vline'
    return 'blk%d@%d,%d'%(len(W),min(r for r,c in W),min(c for r,c in W))
for i in range(4):
    s=wstate(current_frame)
    if s=='hline': break
    action(['SPACE'])
print('sel now',wstate(current_frame))
res=action(['DOWN']*6)
print('lines',st8(current_frame),'lc',res.get('level_completed'),'go',res.get('game_over'),'done',res.get('run_complete'),'level',current_frame.level,'budget',bar(current_frame))
```

```text
[action] SPACE -> NO-OP (executed, no change inside the board area)

error:
Traceback (most recent call last):
  File "<python_tool>", line 15, in <module>
StaleStateActionError: SPACE was not executed. The action immediately before it, SPACE, was a no-op - it produced no change inside the board are
… [309 caracteres más]
```

## Paso 47 · nivel 8 · acción 316

**Pensamiento:**

A SPACE press was a no-op (the selection didn't change visibly). Hmm — the cycle might be: obj2 → obj1 → none → hline, but the "none" state's SPACE → hline... The no-op happened at some point. Note the previous no-op detection: the harness halts when an action produces no gameplay change. Pressing SPACE when the selection goes from "none" to... hmm.
Wait, maybe the cycle doesn't include a "none" state; maybe the "no W" state I saw earlier was because the selection was on the object that is at its target?? Hmm no.
Let me check the current state: wstate now, and then press SPACE carefully one at a time, checking the result each time (catching StaleStateActionError).
Budget: 20 - 1 = 19. Needed: reach hline + 6 DOWN.
Let me carefully press SPACE one at a time with try/except and print the wstate before/after.

```python
print('wstate',wstate(current_frame),'budget',bar(current_frame),'lines',st8(current_frame))
for i in range(3):
    try:
        r=action(['SPACE'])
        print(i,'SPACE ok ->',wstate(current_frame),'budget',bar(current_frame))
    except Exception as e:
        print(i,'SPACE no-op:',type(e).__name__,wstate(current_frame))
        break
    if wstate(current_frame)=='hline': break
```

```text
wstate none budget 19 lines (5, 12)
[action] SPACE -> effect
0 SPACE ok -> hline budget 18
```

## Paso 48 · nivel 8 · acción 322

**Pensamiento:**

The h-line is now selected (wstate 'hline', budget 18). Now press DOWN 6 to move the h-line from block row 5 to 11.
Note: 6 DOWN = 6 actions, budget 18 ✓.
Let me execute and check for completion.

```python
res=action(['DOWN']*6)
print('lines',st8(current_frame),'lc',res.get('level_completed'),'go',res.get('game_over'),'done',res.get('run_complete'),'level',current_frame.level,'budget',bar(current_frame))
```

```text
[action] batch of 6 actions, 6 executed: DOWN, DOWN, DOWN, DOWN, DOWN, DOWN | stop_reason: run_complete
lines (11, 12) lc False go False done True level 8 budget 13
```