# cn04-2fe56bfb · pasada 1 · log de pensamiento

## Paso 1 · nivel 1 · acción 4

**Pensamiento:**

Let me inspect the board structure.

```python
print(current_frame.shape, current_frame.level, current_frame.step)
print(valid_actions)
seg = current_frame.segmentation
for n in seg['nodes']:
    print(n['id'], n['color'], n['pixels'], n['boundary'], n.get('children'))
print('adj', seg['adjacency_list'])
```

```text
(64, 64) 1 0
['UP', 'DOWN', 'LEFT', 'RIGHT', 'SPACE', 'MOUSE']
0 S 3704 [[0, 0], [0, 15], [1, 16], [1, 47], [0, 48], [0, 63], [63, 63], [63, 0]] [2, 3, 4, 5, 7, 8]
1 c 32 [[0, 16], [0, 47]] []
2 W 135 [[11, 11], [11, 25], [19, 25], [19, 23], [20, 22], [25, 22], [25, 20], [17, 20], [17, 22], [16, 23]
… [529 caracteres más]
```

**Pensamiento:**

Let me understand the board. Background is sky blue (S). There's a dark charcoal bar at top row cols 16-47 — likely a timer bar (full width 32 cells at row 0).
Object 2: white shape at rows 11-25, cols 11-25 — looks like a "plug" / key shape with two prongs pointing down. Objects 3,4: red 3x3 blocks at rows 26-28 cols 14-16 and 20-22 — these are the prong tips attached to the white shape.
Object 5: green (N light green) 20x8 rectangle at rows 29-49, cols 41-49, with a hole (child 6: sky blue 15x3 at rows 32-46, cols 44-46) — a socket/lock with a slot.
Objects 7,8: red 3x3 at rows 35-37 and 41-43, col 38-40 — to the left of the green rect. These look like pins.
Hmm. So the puzzle: the white plug shape needs to be moved into the green socket? Actually the white shape has two red prongs at bottom. The green has a vertical slot (45 cells, 15x3). Hmm.
Actually, maybe the picture: white shape is like a "plug" with two red pins at bottom; the green is a socket with a vertical slot and two red pins on the left side. Hmm.
Let me look at the ascii in the region to be careful.
Let me think about the mechanics: probably arrow keys move the white object (with red pins attached?) and we need to fit it into the green slot. But the green slot is 15x3 vertical, and the white shape is a big blob.
Alternatively, maybe the goal is to align red pins with red pins? Let's consider: the green object has two red squares protruding on its left at rows 35-37 and 41-43. The white object has two red squa
… [894 caracteres más]

```python
a = current_frame.ascii.split('\n')
for r in range(10, 30):
    print(r, a[r][8:28])
print()
for r in range(28, 51):
    print(r, a[r][36:52])
```

```text
10 SSSSSSSSSSSSSSSSSSSS
11 SSSWWWWWWWWWWWWWWWSS
12 SSSWWWWWWWWWWWWWWWSS
13 SSSWWWWWWWWWWWWWWWSS
14 SSSWWWSSSSSSSSSWWWSS
15 SSSWWWSSSSSSSSSWWWSS
16 SSSWWWSSSSSSSSSWWWSS
17 SSSWWWWWWSSSWWWWWWSS
18 SSSWWWWWWSSSWWWWWWSS
19 SSSWWWWWWSSSWWWWWWSS
20 SSSSSSWWWSSSWWWSSSSS
21 SSSSSSWWWSSSWWWSSSSS
22 SSSSSSWWW
… [640 caracteres más]
```

**Pensamiento:**

So the white object is a "plug" shape with two prongs, and the two red 3x3 blocks below the prongs (rows 26-28) are the prong tips. The green object is a "socket" with a vertical slot in the middle (3 wide, rows 32-46) and two red 3x3 blocks on the left side (rows 35-37, 41-43) at cols 38-40.
Hmm, wait. The green's slot is at cols 44-46 rows 32-46 — 15 tall, 3 wide. The white plug's prongs are 3 wide each, spaced 6 apart (cols 14-16 and 20-22, gap of 3 at cols 17-19). Hmm, the white plug's prongs... Actually look at the white shape: it's like a "H"/plug.
Maybe the mechanic: the white plug must be rotated 90° (so prongs point left) and inserted into the green from the left? But the green's slot is vertical 3 wide 15 tall; the plug would need to be 3 wide... no.
Alternative: maybe the red blocks are "connectors" and the goal is to make red blocks touch other red blocks. Like a circuit: the white shape with two red terminals is a "wire"; the green has two red terminals. We need to bring them together so all reds connect. The white plug rotated 90° clockwise would have prongs pointing left... Let's think: white plug with prongs pointing down, spaced 6 apart (centers col 15 and 21). Green's red terminals are spaced 6 apart (centers row 36 and 42) on the left side of the green. So if we rotate the white plug 90° counterclockwise, the prongs point left, spaced 6 apart vertically. Then the prong tips (red) would align with the green's red terminals at cols 38-40... but the green's re
… [3082 caracteres más]

```python
import copy
def summ(f):
    seg=f.segmentation
    return [(n['color'], n['pixels'], tuple(n['boundary'][0]), tuple(n['boundary'][-1])) for n in seg['nodes']]

for act in ['LEFT','RIGHT','UP','DOWN']:
    r = action([act])
    d = frame_diff()
    print(act, 'changed', d['changed_cell_count'], 'gameplay', last_action_call_result.get('gameplay_changed'))
    keys = [k for k in ('moved','rotated','appeared','disappeared','changed_color','resized')]
    for k in keys:
        if d.get(k):
            print('  ', k, d[k][:4])
    print('  res', {kk:vv for kk,vv in last_action_call_result.items() if kk!='animation'})
```

```text
[action] LEFT -> effect
LEFT changed 198 gameplay True
   moved [{'color': 'W', 'pixels': 135, 'hash': 'a6ec6271b7fe504c', 'from': [11, 11], 'to': [11, 8]}, {'color': 'R', 'pixels': 9, 'hash': '6664d4ea9c925dd4', 'from': [26, 14], 'to': [26, 11]}, {'color': 'R', 'pixels': 9, 'hash': '6664d4ea9c925dd
… [4217 caracteres más]
```

## Paso 2 · nivel 1 · acción 5

**Pensamiento:**

The arrows move the white plug (with its two red tips) by 3 cells per press. The top bar (c) shrinks — that's the step budget bar (32 → 31 → 30...). So each action consumes budget.
Now: the white plug moved back to original position (rows 11-25, red tips at rows 26-28). Good, we're back to start.
Now I need to figure out the goal: probably insert the plug into the green socket. The plug's prongs point down; the socket... hmm. Let's think about the geometry again.
Green object: rows 29-49, cols 41-49 (21 rows x 9 cols), with hole rows 32-46 cols 44-46 (15 x 3).
White plug shape:
```
row11: cols 11-25 white (15 wide)
row14-16: cols 11-13 and 23-25
row17-19: cols 11-16 and 20-25
row20-25: cols 14-16 and 20-22
red tips: row26-28 cols 14-16, 20-22
```
Hmm, so the plug body is 15 wide, and the two prongs are 3 wide at cols 14-16 and 20-22 (spacing: centers 15, 21; gap 3 between at cols 17-19).
Green: 9 wide, 21 tall, hole 3 wide 15 tall at cols 44-46 (center col 45, rows 32-46).
Hmm, if we rotate the plug 90°, the prongs point left/right. The plug would be 15 tall and 15 wide... The green's hole is only 3 wide.
Alternative interpretation: This is a "plug and socket" — maybe the plug needs to be rotated so prongs point LEFT, and then moved so the prongs insert into the green's hole from the left. But the hole is at cols 44-46, and the green's left edge is col 41. The hole is surrounded by green walls of 3 thickness on left (cols 41-43) and right (47-49), and 3 on top (rows 29-31) an
… [2858 caracteres más]

```python
a = current_frame.ascii.split('\n')
print('row0', a[0])
print('row1', a[1][:40])
seg = current_frame.segmentation
for n in seg['nodes']:
    print(n['id'], n['color'], n['pixels'], n['boundary'][0], n['boundary'][-1], n['rotation'])
```

```text
row0 SSSSSSSSSSSSSSSSWWccccccccccccccccccccccccccccccSSSSSSSSSSSSSSSS
row1 SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
0 S 3704 [0, 0] [63, 0] 270
1 W 2 [0, 16] [0, 17] 0
2 c 30 [0, 18] [0, 47] 0
3 W 135 [11, 11] [19, 11] 180
4 R 9 [26, 14] [28, 14] None
5 R 9 [26, 20] [28, 20] None
6 N 144 [29, 41] [4
… [94 caracteres más]
```

**Pensamiento:**

The bar: row0 cols 16-17 white (elapsed count), cols 18-47 dark (remaining 30). So budget = 32 total, 30 remaining after 4 actions? Hmm, 4 actions used but bar shows 2 white. Wait: initial was c at cols 16-47 (32 cells). Now W at 16-17 (2) and c at 18-47 (30). So only 2 consumed for 4 actions? Maybe the bar decrements every 2 actions, or it decrements per action but... Actually LEFT didn't shrink it, RIGHT shrank by 1, UP didn't, DOWN shrank by 1 (and W resized 1→2). Hmm, maybe the bar shrinks every action but the animation... whatever. It's a timer/step bar. 30 remaining — enough.
Now, test SPACE and MOUSE to find rotation.

```python
r = action(['SPACE'])
d = frame_diff()
print('SPACE changed', d['changed_cell_count'])
for k in ('moved','rotated','appeared','disappeared','changed_color','resized'):
    if d.get(k): print(' ',k,d[k][:5])
print({k:v for k,v in last_action_call_result.items() if k in ('level_completed','game_over','no_op','gameplay_changed','state')})
```

```text
[action] SPACE -> effect
SPACE changed 207
  moved [{'color': 'W', 'pixels': 135, 'hash': 'a6ec6271b7fe504c', 'rotated_by': 90, 'from': [11, 11], 'to': [11, 14]}, {'color': 'R', 'pixels': 9, 'hash': '6664d4ea9c925dd4', 'from': [26, 14], 'to': [20, 11]}, {'color': 'R', 'pixels': 9, 'hash': '6664d4ea9
… [340 caracteres más]
```

## Paso 3 · nivel 1 · acción 5

**Pensamiento:**

SPACE rotates the plug 90° clockwise (the prongs now point LEFT... wait, in the image the prongs point left with red tips on the left). Let me look: the white plug now has prongs pointing left with red tips at the left ends (rows ~14-16 and 20-22, cols 11-13). Hmm, that means the rotation was 90° clockwise? Original prongs pointed down; after 90° CW, down→left. Yes, CW: down becomes left. Correct.
Hmm, but I wanted prongs pointing right (to plug into the green contacts on the left side of green). Prongs pointing left means the plug approaches from the right of the contacts... but the contacts point left out of the green's left face. If the plug comes from the right, it would overlap the green body.
Hmm wait. Let's reconsider the geometry. Maybe the plug's prongs with red tips are meant to fit into the green's slot? Let me reconsider: the green's hole is 3 wide, 15 tall (rows 32-46, cols 44-46). The plug's prongs: white part 3 wide × 6 long + red tip 3×3. Two prongs with a 3-wide gap between them.
Hmm, what if the plug rotates and the whole plug's "body" (15 wide) fits... the green is 9 wide.
Alternative: maybe this is a "key and lock" where the plug must be inserted into the green so the red tips align with the red contacts on the green's left. Let's compute the shape of the plug's prong region: prongs at cols 14-16 and 20-22 (in original orientation), pointing down. The green's red contacts at rows 35-37 and 41-43, cols 38-40, pointing left from the green's face.
If the plug
… [1053 caracteres más]

```python
a = current_frame.ascii.split('\n')
for r in range(10, 26):
    print(r, a[r][10:28])
```

```text
10 SSSSSSSSSSSSSSSSSS
11 SSSSSSSSSSWWWWWWWW
12 SSSSSSSSSSWWWWWWWW
13 SSSSSSSSSSWWWWWWWW
14 SRRRWWWWWWWWWSSSWW
15 SRRRWWWWWWWWWSSSWW
16 SRRRWWWWWWWWWSSSWW
17 SSSSSSSSSSSSSSSSWW
18 SSSSSSSSSSSSSSSSWW
19 SSSSSSSSSSSSSSSSWW
20 SRRRWWWWWWWWWSSSWW
21 SRRRWWWWWWWWWSSSWW
22 SRRRWWWWWWWWWSSSWW
23 SSSSSSSSSSW
… [51 caracteres más]
```

**Pensamiento:**

Current plug (rotated 90° CW): bounding box rows 11-25, cols 11-25.
- Body: cols 23-25 (3 thick), rows 11-25 (15 tall).
- Two arms: rows 14-16 and 20-22, cols 14-22 white (9 long), plus red tips at cols 11-13 (3 wide).
- Also there's a middle part: rows 17-19 col 23-25? Actually body is cols 23-25 all rows 11-25. And row 14-16 cols 14-22 arms, cols 23-25 body. Rows 17-19: only cols 23-25. So the arms extend from body to the left, with red tips at cols 11-13.
Hmm wait, in the original orientation: body rows 11-13 (3 thick, 15 wide cols 11-25), arms rows 14-19 partially... Let me recheck original:
```
11: cols 11-25 W (15)
12: cols 11-25
13: cols 11-25
14: cols 11-13, 23-25
15: cols 11-13, 23-25
16: cols 11-13, 23-25
17: cols 11-16, 20-25
18: cols 11-16, 20-25
19: cols 11-16, 20-25
20-25: cols 14-16, 20-22
26-28: red at cols 14-16, 20-22
```
So the shape is like a "plug" with a rectangular frame (rows 11-19, with a hollow interior at rows 14-16 cols 14-22 and rows 17-19 cols 17-19), and two prongs.
OK so in the rotated version: the frame is at cols 23-25 (right side) plus arms. Structure: body/frame at right, two arms extending left with red tips.
Now, the green socket: rows 29-49, cols 41-49, hole rows 32-46 cols 44-46. Red contacts at rows 35-37 and 41-43, cols 38-40 (sticking out left).
Interesting: the plug's arms are 3 tall, spaced: rows 14-16 and 20-22, centers 15 and 21 → spacing 6. The green's contacts: rows 35-37 and 41-43, centers 36, 42 → spacing 6. 
Also the plug's 
… [982 caracteres más]

```python
a = current_frame.ascii.split('\n')
def rows(r0,r1,c0,c1):
    for r in range(r0,r1+1):
        print(r, a[r][c0:c1+1])
print('--- plug region cols 8..30')
rows(11,25,8,30)
print('--- seg')
for n in current_frame.segmentation['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'])
```

```text
--- plug region cols 8..30
11 SSSSSSSSSSSSWWWWWWWWWSS
12 SSSSSSSSSSSSWWWWWWWWWSS
13 SSSSSSSSSSSSWWWWWWWWWSS
14 SSSRRRWWWWWWWWWSSSWWWSS
15 SSSRRRWWWWWWWWWSSSWWWSS
16 SSSRRRWWWWWWWWWSSSWWWSS
17 SSSSSSSSSSSSSSSSSSWWWSS
18 SSSSSSSSSSSSSSSSSSWWWSS
19 SSSSSSSSSSSSSSSSSSWWWSS
20 SSSRRRWWWWWWWWWSSSWWWSS
21 
… [786 caracteres más]
```

**Pensamiento:**

Now the plug (rotated CW once): bbox rows 11-25, cols 11-28.
- Right frame: cols 26-28, rows 11-25 (3 wide, 15 tall).
- Top bar: rows 11-13, cols 20-28.
- Bottom bar: rows 23-25, cols 20-28.
- Arms: rows 14-16 and 20-22, cols 14-22 (white), red tips cols 11-13.
- Middle: cols 23-25 rows 14-22 is background (hollow).
Hmm interesting. So the plug is like a "C" frame opening to the left with two arms extending left.
Now the green socket: bbox rows 29-49 cols 41-49. Outer frame 3 thick all around, hollow 3 wide (cols 44-46) x 15 tall (rows 32-46). Contacts stick out left at rows 35-37, 41-43.
Hmm! Now compare: The plug's frame (cols 26-28 right, rows 11-13 top, rows 23-25 bottom) forms a "C" opening left with arms. The green's frame is a closed rectangle with a hollow inside.
Hmm, what if the plug is meant to be inserted into the green's hollow? The green's hollow is 3 wide x 15 tall. The plug's arms are 3 tall x 9 long. If the plug is rotated so the arms point UP or DOWN... no, the hollow is narrow.
Alternative idea: this is a "key fits into lock" where the plug's frame must overlap the green's frame? Sizes: plug frame is 15x15 outer, green outer is 21x9. Doesn't match.
Let me reconsider: maybe the plug's arms should insert into the green from the left, passing over the contacts, and the green's hollow... hmm, the arms would need to enter the hollow which is at cols 44-46. The contacts at cols 38-40 block the way (they're attached to green face cols 41-43 at those rows). Actuall
… [10897 caracteres más]

```python
def get_plug(f):
    cells=[]
    for n in f.segmentation['nodes']:
        if n['color'] in ('W','R') and n['pixels']>2 and n['boundary'][0][0]>5:
            pass
    return cells

# build plug cell set from ascii crop
a = current_frame.ascii.split('\n')
plug={}
for r in range(5,40):
    for c in range(5,35):
        ch=a[r][c]
        if ch in ('W','R'):
            plug[(r,c)]=ch
print('plug cells', len(plug), 'bbox', min(k[0] for k in plug), max(k[0] for k in plug), min(k[1] for k in plug), max(k[1] for k in plug))

def rot_cw(cells):
    rs=[k[0] for k in cells]; cs=[k[1] for k in cells]
    r0,c0=min(rs),min(cs)
    return {(c, c0 + (max(rs)-r)):v for (r,c),v in cells.items()}

cur=plug
for i in range(4):
    rs=[k[0] for k in cur]; cs=[k[1] for k in cur]
    tips=[(r,c) for (r,c),v
… [277 caracteres más]
```

```text
plug cells 153 bbox 11 25 11 28
0 bbox 11 25 11 28 tips rows 14 22 tips cols 11 13 ncells 153
1 bbox 11 28 11 25 tips rows 11 13 tips cols 14 22 ncells 153
2 bbox 11 25 11 28 tips rows 14 22 tips cols 26 28 ncells 153
3 bbox 11 28 11 25 tips rows 26 28 tips cols 14 22 ncells 153
```

## Paso 3 · nivel 1 · acción 17

**Pensamiento:**

My simulation matches the observed rotation (state 0 = current: tips rows 14-22, cols 11-13). Rotation state 2 = arms pointing RIGHT (tips cols 26-28, rows 14-22). So from current, 2 CW rotations gives arms-right.
Let me compute the arms-right shape in detail to see where the tips are:
State 2: bbox rows 11-25, cols 11-28; tips rows 14-22 cols 26-28. Let me print the state-2 grid to see arms rows and tip rows.
Then target: tips at rows 35-37 (tip A) and 41-43 (tip B), cols 35-37.
Let me compute the state-2 shape's cells and required translation.

```python
a = current_frame.ascii.split('\n')
plug={}
for r in range(5,40):
    for c in range(5,35):
        ch=a[r][c]
        if ch in ('W','R'): plug[(r,c)]=ch
def show(cells,tag):
    rs=[k[0] for k in cells]; cs=[k[1] for k in cells]
    print(tag)
    for r in range(min(rs),max(rs)+1):
        print(''.join(cells.get((r,c),'.') for c in range(min(cs),max(cs)+1)))
s1=rot_cw(plug); s2=rot_cw(s1)
show(s2,'state2 (arms right)')
tips=[(r,c) for (r,c),v in s2.items() if v=='R']
print('tips', sorted(tips))
```

```text
state2 (arms right)
WWWWWWWWW.........
WWWWWWWWW.........
WWWWWWWWW.........
WWW...WWWWWWWWWRRR
WWW...WWWWWWWWWRRR
WWW...WWWWWWWWWRRR
WWW...............
WWW...............
WWW...............
WWW...WWWWWWWWWRRR
WWW...WWWWWWWWWRRR
WWW...WWWWWWWWWRRR
WWWWWWWWW.........
WWWWWWWWW.........
WWWWWWWWW.....
… [190 caracteres más]
```

**Pensamiento:**

State 2 (arms right): left bar cols 11-13 rows 11-25; top/bottom bars rows 11-13 and 23-25 cols 11-19; arms rows 14-16 and 20-22, cols 14-22; tips cols 26-28 rows 14-16 and 20-22.
Now the target. The green socket's contacts are at rows 35-37 and 41-43, cols 38-40, sticking out left of the green face at col 41.
Option A (connect tips to contacts): tips need to be at rows 35-37 & 41-43, cols 35-37. Current state-2 tips: rows 14-16 & 20-22, cols 26-28. Required translation: rows +21, cols +9. Both multiples of 3 ✓. So 7 DOWN, 3 RIGHT. Total actions: 2 SPACE + 10 moves = 12.
But wait: would the plug's left bar (cols 11-13 → cols 20-22) and arms overlap the green? Green starts at col 41; plug's rightmost = tips at col 37. No overlap ✓. Plug rows 11-25 → 32-46. Fine.
Option B: maybe the plug's arms should go INTO the green's hollow. The hollow is cols 44-46, rows 32-46 (3 wide, 15 tall). The plug's arms are 3 tall x 9 long — can't fit into a 3-wide slot unless oriented vertically. Hmm, with arms pointing right, the arms are horizontal 3-tall bars — they'd have to pass through the green's left wall (cols 41-43) which is solid at rows other than the contacts. Actually the contacts occupy rows 35-37 and 41-43 at cols 38-40, and the wall cols 41-43 is solid there too (green). So no passage.
So Option A is the natural "plug it in": the red tips touch the red contacts.
Hmm, but actually consider: maybe the intent is for the tips to be adjacent to the contacts (touching), forming a contin
… [2798 caracteres más]

```python
plan = ['SPACE','SPACE','RIGHT','RIGHT','RIGHT','DOWN','DOWN','DOWN','DOWN','DOWN','DOWN','DOWN']
log=[]
for act in plan:
    r = action([act])
    res = last_action_call_result
    log.append((act, res.get('level_completed'), res.get('game_over'), res.get('no_op'), res.get('gameplay_changed')))
    if res.get('level_completed') or res.get('game_over') or res.get('done'):
        break
for L in log: print(L)
seg=current_frame.segmentation
for n in seg['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
```

```text
[action] SPACE -> effect
[action] SPACE -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
('SPACE
… [650 caracteres más]
```

**Nivel 1 completado → nivel 2 (acción 18)**

## Paso 4 · nivel 2 · acción 18

**Pensamiento:**

Interesting! The plug moved to rows 32-46, cols 20-37. But the red tips now appear merged with the contacts: node 7 R 18 pixels at rows 35-37 (bbox [35,35]-[37,35]) — 18 pixels = 3x6, meaning the tip (cols 35-37) merged with the contact (cols 38-40) into one 3x6 red object! Similarly node 8. So the red tips ARE now touching/adjacent to the contacts (merged into one component since same color and 4-connected).
But the level isn't completed. Also note node 6: S 72 at rows 35-43 col 23 — that's the background showing through the plug's hollow (the C-frame interior).
So the tips touching the contacts isn't the win condition. Hmm.
What else? Maybe the plug must be inserted INTO the green: the arms must go into the green's interior hollow. But the green's left wall is solid...
Wait — maybe the green object's hollow (3 wide, 15 tall) is meant to receive the plug's left bar? Hmm.
Let me reconsider: maybe the plug needs to be inserted so its arms go inside the green's hollow — but they can't pass the wall. Unless... the plug should be rotated so the arms point right and the plug's arms go INTO the green from the top or bottom? The hollow is rows 32-46 (15 tall) and the wall is rows 29-31 top, 47-49 bottom.
Hmm, alternatively maybe the correct target is: the plug's red tips must go INTO the green's interior (the hollow). The hollow is at cols 44-46, rows 32-46, 3 wide x 15 tall. The tips are 3x3 each, spaced 6 apart vertically. If the tips were oriented vertically (i.e., plug with arms
… [3827 caracteres más]

```python
r=action(['RIGHT']); res=last_action_call_result
print({k:v for k,v in res.items() if k in ('no_op','gameplay_changed','level_completed','game_over','board_changed')})
d=frame_diff()
print('changed',d['changed_cell_count'])
for k in ('moved','rotated','appeared','disappeared','changed_color','resized'):
    if d.get(k): print(' ',k,d[k][:5])
for n in current_frame.segmentation['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
```

```text
[action] RIGHT -> LEVEL COMPLETED
{'board_changed': True, 'level_completed': True, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
changed 4044
  appeared [{'color': 'O', 'pixels': 3515, 'hash': '53d32cf0dadb5ca9', 'shape_hash': '014791dffa82004d', 'at': [0, 0], 'bbox': [0, 0, 63, 63]}
… [1865 caracteres más]
```

## Paso 5 · nivel 2 · acción 18

**Pensamiento:**

Level 2! Background is orange (O). Objects: a white plug (smaller), a green plug-like shape, a yellow plug-like shape, a blue U shape. Red tips attached.
Level 1 solution recap: rotate the plug so its red tips align with the socket's red contacts and touch them (the final RIGHT moved the tips to overlap the contacts? Let me check: at the end, tips were at cols 35-37 adjacent to contacts at 38-40, then RIGHT moved the plug 3 right → tips at cols 38-40 = overlapping the contacts exactly! And the level completed. So the win condition = the plug's red tips land exactly on the socket's red contact cells (overlap/absorb).
Interesting: so the plug CAN overlap the contacts, and doing so completes the level. Actually the final animation showed 145 cells changed and changed back — the level-complete animation.
So level 1: the plug's tips must exactly cover the socket's contacts.
Now level 2: let me inspect the new board. There seem to be multiple plugs and multiple sockets? Let me get the segmentation.

```python
print(current_frame.shape, current_frame.level, current_frame.step)
seg=current_frame.segmentation
for n in seg['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1],n['children'],n['rotational_symmetry'])
print('adj',seg['adjacency_list'])
a=current_frame.ascii.split('\n')
print('row0',a[0][:60])
```

```text
(64, 64) 2 18
0 O 3515 [0, 0] [63, 0] [2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15, 16, 17, 18] 1
1 c 32 [0, 16] [0, 47] [] 2
2 W 90 [11, 11] [28, 11] [] 1
3 R 9 [14, 44] [16, 44] [] 4
4 N 90 [14, 47] [31, 47] [] 1
5 R 9 [20, 17] [22, 17] [] 4
6 R 9 [20, 50] [22, 50] [] 4
7 R 9 [26, 14] [28, 14] [] 4
… [667 caracteres más]
```

**Pensamiento:**

Level 2 board. Objects:
- W 90 at rows 11-28, cols 11-19 (white plug, smaller: 18 tall x 9 wide)
- N 90 (green) at rows 14-31, cols 44-52
- Y 162 (yellow) at rows 35-46, cols 20-35, with child O 54 (hole)
- b 45 (blue) at rows 53-58, cols 50-58
- Red tips: 9 red 3x3 blocks. Let me map which reds belong to which object (adjacency): 
  - [2,5]: W adj R at [20,17] ; [2,7]: W adj R at [26,14]. So white has 2 tips: at (20,17-19) and (26,14-16).
  - [3,4]: R at (14,44-46) adj N; [4,6]: R at (20,50-52) adj N; [4,8]: R at (26,50-52) adj N; [4,9]: R at (29,38-40) adj N. So green has 3 tips? Hmm: (14,44), (20,50), (26,50), (29,38). That's 4 reds adjacent to green. Hmm.
  - [10,11]: R (38,17) adj Y; [10,13]: R (38,32) adj Y; [10,14]: R (44,14) adj Y; [10,17]: R (53,26) adj Y. So yellow has 4 red neighbors.
  - [15,18]: R (50,50) adj blue; [16,18]: R (50,56) adj blue. Blue has 2 tips.
Total reds: 9: at (14,44),(20,17),(20,50),(26,14),(26,50),(29,38),(38,17),(38,32),(44,14),(50,50),(50,56),(53,26) — that's 12. Let me recount the list: nodes 3,5,6,7,8,9,11,13,14,15,16,17 = 12 red blocks. Yes 12.
So the picture: 4 objects (white, green, yellow, blue), each with some red tips. Hmm, so which are plugs and which are sockets? In level 1 there was one plug (white with 2 tips) and one socket (green with 2 contacts). Here we have 4 objects each with red tips.
Maybe the goal is to connect all of them into one chain/network — i.e., every plug's tips must land on another object's contacts.
Let me dra
… [90 caracteres más]

```python
a=current_frame.ascii.split('\n')
def crop(r0,r1,c0,c1,tag):
    print('==',tag)
    print('    '+''.join(str((c)//10%10) for c in range(c0,c1+1)))
    print('    '+''.join(str(c%10) for c in range(c0,c1+1)))
    for r in range(r0,r1+1):
        print(r,' ',''.join(a[r][c0:c1+1]))
crop(10,32,10,20,'white')
crop(12,32,36,58,'green')
```

```text
== white
    11111111112
    01234567890
10   OOOOOOOOOOO
11   OWWWWWWWWWO
12   OWWWWWWWWWO
13   OWWWWWWWWWO
14   OWWWOOOWWWO
15   OWWWOOOWWWO
16   OWWWOOOWWWO
17   OWWWOOOWWWO
18   OWWWOOOWWWO
19   OWWWOOOWWWO
20   OWWWOOORRRO
21   OWWWOOORRRO
22   OWWWOOORRRO
23   OWWWOOOOOOO
24   OWWWOOOOOOO
25  
… [805 caracteres más]
```

**Pensamiento:**

White object (rows 11-28, cols 11-19): 
```
11-13: cols 11-18 W (8 wide)
14-19: cols 11-13 W, cols 17-19 W
20-22: cols 11-13 W, cols 17-19 R (tip)
23-25: cols 11-13 W
26-28: cols 11-13 W, cols 14-16 R (tip)
```
Hmm, so white = a "C"-ish shape: left bar cols 11-13 rows 11-28 (18 tall), right bar cols 17-19 rows 11-22, top bar rows 11-13. Tips: one at (20-22, 17-19) [pointing right, at the end of the right bar] and one at (26-28, 14-16) [pointing down, at the bottom of the left bar].
Green (rows 14-32, cols 44-52):
```
14-16: cols 44-46 R (tip), cols 47-49 N
17-19: cols 47-49 N
20-22: cols 47-49 N, cols 50-52 R (tip)
23-25: cols 47-49 N
26-28: cols 47-49 N, cols 50-52 R (tip)
29-31: cols 38-40 R (tip), cols 47-49 N
32: cols 44-52 N (row 32: "OONNNNNNNNNNNNO" starting col 36 → cols 38-48? let me recount)
```
Hmm the crop was cols 36-58. Row 32: "OONNNNNNNNNNNNO" → index 0=col36 'O', 1=col37 'O', 2..12 = cols 38-48 N (11 cells), col49='O'. Hmm, but the green bbox was [14,47] to [31,47]... The segmentation said N 90 pixels with boundary [14,47] to [31,47]. Hmm, that means the N object spans rows 14-31 and the boundary points listed are just corners. Let me recount row 32 from the actual ascii rather than my misaligned crop. Actually the crop header shows rows; row 32 shows N from col 38 to col 48. But the green's bbox per segmentation starts at row 14... and the red at (29,38) is adjacent to N. Let me get the full green shape properly with a wider crop and also verify with node pi
… [93 caracteres más]

```python
a=current_frame.ascii.split('\n')
for r in range(30,35):
    print(r, a[r][36:54])
print()
for r in range(33,58):
    print(r, a[r][12:38])
```

```text
30 OORRROOOOOONNNOOOO
31 OORRROOOOOONNNOOOO
32 OONNNNNNNNNNNNOOOO
33 OONNNNNNNNNNNNOOOO
34 OONNNNNNNNNNNNOOOO

33 OOOOOOOOOOOOOOOOOOOOOOOOOO
34 OOOOOOOOOOOOOOOOOOOOOOOOOO
35 OOOOOOOOOOOYYYYYYYYYOOOOOO
36 OOOOOOOOOOOYYYYYYYYYOOOOOO
37 OOOOOOOOOOOYYYYYYYYYOOOOOO
38 OOOOORRROOOYYYOOOYYYRRROOO
39 OOOOOR
… [560 caracteres más]
```

## Paso 5 · nivel 2 · acción 19

**Pensamiento:**

Let me map all four objects precisely.
White (rows 11-28, cols 11-19), 90 px:
- rows 11-13: cols 11-18 (8 wide)
- rows 14-22: cols 11-13 and 17-19
- rows 20-22: right part is RED (cols 17-19) → tip pointing right at end of right bar
- rows 23-28: cols 11-13
- rows 26-28: cols 14-16 RED → tip pointing down at bottom of left bar... wait, the left bar is cols 11-13 rows 11-28, and the red at rows 26-28 cols 14-16 is to the RIGHT of the left bar at its bottom. Hmm, so it's a tip pointing right from the bottom of the left bar.
Let me recount rows 26-28: "OWWWRRROOOO" starting col 10 → col10=O, cols 11-13=W, cols 14-16=RRR. Yes, tip pointing right at rows 26-28, cols 14-16.
And rows 20-22: "OWWWOOORRRO" → cols 11-13 W, cols 14-16 O, cols 17-19 R. So the right bar's lower part (rows 20-22) is red, i.e., tip pointing down? The right bar is cols 17-19 rows 14-22; rows 20-22 of it are red. So the red is the last 3 rows of the right bar — a tip pointing DOWN at the bottom end of the right bar.
Hmm, so the tips are at the ends of arms: one tip is the end of the right bar (pointing down), and the other is attached to the right of the left bar's bottom (pointing right).
Green (rows 14-34, cols 38-52), 90 px:
- rows 14-16: cols 44-46 RED, cols 47-49 N
- rows 17-31: cols 47-49 N (vertical bar)
- rows 20-22: cols 50-52 RED (tip pointing right)
- rows 26-28: cols 50-52 RED (tip pointing right)
- rows 29-31: cols 38-40 RED (tip pointing left)
- rows 32-34: cols 38-48 N (horizontal bar, 11 wide)
… [11658 caracteres más]

```python
r=action(['LEFT']); res=last_action_call_result
print({k:v for k,v in res.items() if k in ('no_op','gameplay_changed','level_completed','game_over')})
d=frame_diff()
print('changed',d['changed_cell_count'])
for k in ('moved','rotated','appeared','disappeared','changed_color','resized'):
    if d.get(k): print(' ',k,[(e.get('color'),e.get('pixels'),e.get('from'),e.get('to'),e.get('at'),e.get('bbox')) for e in d[k]][:6])
```

```text
[action] LEFT -> effect
{'level_completed': False, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
changed 171
  moved [('W', 90, [11, 11], [11, 8], None, None), ('R', 9, [20, 17], [20, 14], None, None), ('R', 9, [26, 14], [26, 11], None, None)]
  resized [('O', None, None, None, None,
… [7 caracteres más]
```

## Paso 6 · nivel 2 · acción 19

**Pensamiento:**

The white piece moved left by 3 (the controllable piece is the white one, as in level 1). So we control only the white piece; the other three (green, yellow, blue) are fixed targets.
White has 2 tips. So we need to pair white's 2 tips with tips of other pieces? But which? Hmm — but in level 1 the plug's tips landed exactly on the socket's contacts and the level completed. Here, we have 3 fixed pieces with 10 tips among them. We probably need to place the white piece so its 2 tips overlap 2 of the other pieces' tips... but then the other 8 tips remain unpaired. That was fine in level 1 (only 2 tips existed besides the plug's).
Hmm wait. Maybe the win condition is different: maybe the white piece must fit into a "hole"/slot in the other pieces, or all pieces must become connected (one component) — the win in level 1 happened when the plug connected to the socket... but it was already connected when adjacent. Hmm, unless the game's win check requires "the plug's tips to be inside the socket's holes".
Let me reconsider level 1's geometry at win: plug tips at cols 38-40 rows 35-37 and 41-43; the green's contacts were at those cells. So the tips occupied the contacts' cells. Since the contacts are red and the tips are red, the result looks identical to before? No — before the final move, the tips were at cols 35-37 and the contacts at 38-40, forming a 3x6 red block. After the move, tips at 38-40, and the contacts... they'd be at the same cells (overwritten). So the final board look
… [7055 caracteres más]

```python
a=current_frame.ascii.split('\n')
def cells_of(color, r0,r1,c0,c1):
    out=set()
    for r in range(r0,r1+1):
        for c in range(c0,c1+1):
            if a[r][c]==color: out.add((r,c))
    return out
# white piece = W + adjacent R (its tips). current white bbox cols 8..16 rows 11..28
W = cells_of('W',9,30,6,20)
Wr = cells_of('R',9,30,6,20)
print('W',len(W),'Wr',sorted(Wr))
# other pieces' red tips
others={}
for col,(r0,r1,c0,c1) in {'N':(12,36,36,54),'Y':(33,57,12,37),'b':(48,60,48,60)}.items():
    others[col]=(cells_of(col,r0,r1,c0,c1), cells_of('R',r0,r1,c0,c1))
for k,(cs,rs) in others.items():
    print(k,'body',len(cs),'red',sorted(rs))
```

```text
W 90 Wr [(20, 14), (20, 15), (20, 16), (21, 14), (21, 15), (21, 16), (22, 14), (22, 15), (22, 16), (26, 11), (26, 12), (26, 13), (27, 11), (27, 12), (27, 13), (28, 11), (28, 12), (28, 13)]
N body 90 red [(14, 44), (14, 45), (14, 46), (15, 44), (15, 45), (15, 46), (16, 44), (16, 45), (16, 46), (20, 5
… [834 caracteres más]
```

## Paso 6 · nivel 2 · acción 19

**Pensamiento:**

Now let me build the search. White piece: body cells (W) + tips (R). Current bbox: rows 11-28, cols 8-16 (since LEFT moved it 3 left: cols 8-16).
Let me write a search: for each rotation k in 0..3 (rotating the combined shape about its bbox top-left), for each translation (dr,dc) with dr,dc ≡ 0 mod 3 (relative to current position), check:
- white tips coincide with red tips of other pieces (all tips of white must coincide with some red tip cells? or at least one?),
- white body cells must not overlap any other piece's cells (body or red) — except where white tips overlap red tips.
Also the white piece must stay within the board.
Then report placements with the number of matched tips and any overlaps.
I'll also compute placements where all white tips land on red tip cells (both tips) and no other overlap.
Let me define the rotation function carefully (as established): rot_cw(cells) maps (r,c) → (c, c0 + (max_r - r)) where c0=min col, max_r = max row. This keeps bbox top-left at (r0,c0) → new bbox rows [c0, c1] hmm wait: new row = old col, so new rows span [c0, c1]; the bbox top-left row should stay r0? In level 1 the bbox top-left stayed at (11,11) and old r0 = c0 = 11 so I couldn't distinguish. Here for the white piece, r0=11, c0=8. Hmm, the rotation anchor matters!
Let me think about how the game probably rotates: about the shape's center? In level 1, the combined bbox was rows 11-28, cols 11-25 (18x15) and after rotation rows 11-25, cols 11-28 (15x18). Under "rotate about t
… [4124 caracteres más]

```python
a=current_frame.ascii.split('\n')
def cells_of(color, r0,r1,c0,c1):
    return {(r,c) for r in range(r0,r1+1) for c in range(c0,c1+1) if a[r][c]==color}
Wbody=cells_of('W',9,32,4,22); Wtip=cells_of('R',9,32,4,22)
N=cells_of('N',12,36,36,54); Y=cells_of('Y',33,57,12,37); B=cells_of('b',48,62,46,62)
Nred=cells_of('R',12,36,36,54); Yred=cells_of('R',33,57,12,37); Bred=cells_of('R',48,62,46,62)
fixed = N|Y|B|Nred|Yred|Bred
def tips3x3(redset):
    seen=set(); out=[]
    for (r,c) in sorted(redset):
        blk=frozenset((r+dr,dc+c) for dr in range(3) for dc in range(3))
        if blk<=redset and blk not in seen:
            seen.add(blk); out.append((min(x[0] for x in blk), min(x[1] for x in blk)))
    return out
def blocks(s):
    return [b for b in tips3x3(s)]
print('white tips', blocks(Wti
… [435 caracteres más]
```

```text
white tips [(20, 14), (26, 11)] Nred [(14, 44), (20, 50), (26, 50), (29, 38)] Yred [(38, 17), (38, 32), (44, 14), (53, 26)] Bred [(50, 50), (50, 56)]

error:
Traceback (most recent call last):
  File "<python_tool>", line 21, in <module>
NameError: name 'open' is not defined
```

## Paso 6 · nivel 2 · acción 19

**Pensamiento:**

Good: tip blocks identified. Now build the search. I'll define a function that rebuilds state from current_frame each call (since variables reset). Let me write a comprehensive search function that:
1. Extracts white body/tips and fixed cells from current_frame.ascii.
2. Enumerates 4 rotations (anchored rule) and all translations with dr,dc in multiples of 3 (and also all translations to see if non-multiples are needed).
3. Scores: tips matched (white tip block coincides with a fixed red tip block), overlaps with fixed cells (excluding matched tip cells), out-of-bounds.
Report placements with 2 matched tips and 0 overlaps.
Note: the white tips are 3x3 blocks; the fixed red tips are 3x3 blocks. Matching = exact coincidence.
Let me write it as a retained function.

```python
def get_state(f):
    a=f.ascii.split('\n')
    def co(color,r0,r1,c0,c1):
        return {(r,c) for r in range(r0,r1+1) for c in range(c0,c1+1) if a[r][c]==color}
    Wb=co('W',5,36,2,26); Wt=co('R',5,36,2,26)
    fixed=set()
    for col,(r0,r1,c0,c1) in {'N':(10,40,34,60),'Y':(32,60,10,40),'b':(46,63,44,63)}.items():
        fixed|=co(col,r0,r1,c0,c1)
    for (r0,r1,c0,c1) in [(10,40,34,60),(32,60,10,40),(46,63,44,63)]:
        fixed|=co('R',r0,r1,c0,c1)
    return Wb,Wt,fixed

def rot_cw_anchor(cells):
    rs=[k[0] for k in cells]; cs=[k[1] for k in cells]
    r0,c0,r1=min(rs),min(cs),max(rs)
    return {(r0+c-c0, c0+(r1-r)):v for (r,c),v in cells.items()}

def search(f, verbose=True):
    Wb,Wt,fixed = get_state(f)
    combined = {(r,c):('W' if (r,c) in Wb else 'R') for (r,c) in (Wb|Wt
… [1528 caracteres más]
```

```text
tool: python
function_retention: |
  Retained your function get_state(f) for later Python calls in this game.
  Retained your function rot_cw_anchor(cells) for later Python calls in this game.
  Retained your function search(f, verbose=True) for later Python calls in this game.
returncode: 0
```

**Pensamiento:**

Wait, there's a bug: `wtip_blocks` is computed from the unrotated white tips, but I then shift by (dr,dc) — for rotated versions the tip blocks differ. I need to recompute the tip blocks for each rotation. Let me fix.
Also `ftip_blocks` computation is convoluted. Let me clean up: compute fixed red set separately in get_state.

```python
def get_state2(f):
    a=f.ascii.split('\n')
    def co(color,r0,r1,c0,c1):
        return {(r,c) for r in range(r0,r1+1) for c in range(c0,c1+1) if a[r][c]==color}
    Wb=co('W',5,36,2,26); Wt=co('R',5,36,2,26)
    fixed=set(); fred=set()
    for (r0,r1,c0,c1) in [(10,40,34,60),(32,60,10,40),(46,63,44,63)]:
        for col in ('N','Y','b','O'):
            if col!='O': fixed|=co(col,r0,r1,c0,c1)
        fred|=co('R',r0,r1,c0,c1)
    return Wb,Wt,fixed|fred,fred

def search2(f,top=20,verbose=True):
    Wb,Wt,fixed,fred=get_state2(f)
    combined={(r,c):('W' if (r,c) in Wb else 'R') for r,c in (Wb|Wt)}
    ftb=blocks(fred)
    results=[]; cur=combined
    for k in range(4):
        wtb=blocks({p for p,v in cur.items() if v=='R'})
        for dr in range(-40,41,3):
            for dc in rang
… [978 caracteres más]
```

```text
tool: python
function_retention: |
  Retained your function get_state2(f) for later Python calls in this game.
  Retained your function search2(f, top=20, verbose=True) for later Python calls in this game.
returncode: 0
```

**Pensamiento:**

Note: dr,dc restricted to multiples of 3 — but the range(-40,41,3) starts at -40 which is not aligned to multiples of 3 offsets relative to the current position... Actually dr is the offset from the current position, and moves are ±3, so dr must be a multiple of 3. range(-40,41,3) = -40,-37,... which are ≡ 2 mod 3. That's wrong. Let me use range(-42,43) and filter dr%3==0.
Let me fix and run.

```python
def search3(f,top=25,verbose=True):
    Wb,Wt,fixed,fred=get_state2(f)
    combined={(r,c):('W' if (r,c) in Wb else 'R') for r,c in (Wb|Wt)}
    ftb=blocks(fred)
    results=[]; cur=combined
    for k in range(4):
        wtb=blocks({p for p,v in cur.items() if v=='R'})
        for dr in range(-42,43):
            if dr%3: continue
            for dc in range(-42,43):
                if dc%3: continue
                moved={(r+dr,c+dc):v for (r,c),v in cur.items()}
                if min(r for r,_ in moved)<1 or max(r for r,_ in moved)>63 or min(c for _,c in moved)<0 or max(c for _,c in moved)>63: continue
                mt=0; matched=set()
                for b in wtb:
                    blk={(b[0]+i+dr, b[1]+j+dc) for i in range(3) for j in range(3)}
                    for fb in ftb:

… [547 caracteres más]
```

```text
n_results 16
(0, 18, 3, 2, 2)
(0, 12, 6, 1, 2)
(3, 0, 21, 1, 2)
(0, 24, 0, 1, 2)
(0, 3, 27, 1, 2)
(0, 9, 24, 1, 2)
(0, -6, 30, 1, 2)
(1, 0, 36, 1, 2)
(3, 33, -3, 1, 2)
(3, 39, 3, 1, 2)
(1, 24, 24, 1, 2)
(2, 9, 42, 1, 2)
(3, 42, 9, 1, 2)
(2, 15, 39, 1, 2)
(0, 24, 39, 1, 2)
(0, 30, 36, 1, 2)
```

## Paso 6 · nivel 2 · acción 26

**Pensamiento:**

Excellent! There's a unique solution with BOTH tips matched and no overlaps: rotation 0 (no rotation needed), dr=+18, dc=+3. That is: 6 DOWN, 1 RIGHT.
Let me verify: white tips currently at blocks (20,14) [pointing down] and (26,11) [pointing right]. After +18 rows, +3 cols: tips at (38,17) and (44,14) — both are yellow's red tip blocks! Yred = [(38,17), (38,32), (44,14), (53,26)]. Yes! So the white piece plugs into the yellow piece: tip W1 → Y1 (38,17) and W2 → Y3 (44,14). 
And no overlaps. This is a beautiful, unique fit (the only 2-tip match among 16 candidates). Strong evidence this is the solution.
Wait — but I should double check the "no rotation" case: rotation 0 means no SPACE needed. The plan: 6 DOWN + 1 RIGHT = 7 actions. But careful about the path: moving down first, would the white piece collide with the yellow piece along the way? The white piece at cols 8-16; the yellow piece spans cols 14-34 rows 35-55 (plus red tips at cols 14-16 rows 44-46 and 17-19 rows 38-40). Moving down at cols 8-16: the yellow's leftmost cells are cols 14-16 (the tip at rows 44-46) and cols 17-19 (bar). The white piece's cells in cols 14-16: W2 tip at rows 26-28 cols 11-13 (after LEFT: cols 11-13? hmm).
Let me recompute the current white piece position: after LEFT, the white bbox is rows 11-28, cols 8-16. Cells: left bar cols 8-10 rows 11-28; top bar rows 11-13 cols 8-15; right bar cols 14-16 rows 11-22 (with rows 20-22 red); tip W2 at rows 26-28 cols 11-13.
Target: +18 rows, +3 cols → l
… [2228 caracteres más]

```python
plan=['DOWN']*6+['RIGHT']
for act in plan:
    action([act]); res=last_action_call_result
    print(act, res.get('no_op'), res.get('level_completed'), res.get('game_over'))
    if res.get('level_completed') or res.get('game_over') or res.get('done'): break
print(cur:=(current_frame.level, current_frame.step))
```

```text
[action] DOWN -> effect
DOWN False False False
[action] DOWN -> effect
DOWN False False False
[action] DOWN -> effect
DOWN False False False
[action] DOWN -> effect
DOWN False False False
[action] DOWN -> effect
DOWN False False False
[action] DOWN -> effect
DOWN False False False
[action] RIGHT -> 
… [38 caracteres más]
```

## Paso 7 · nivel 2 · acción 27

**Pensamiento:**

Very interesting! The tips turned GRAY (G = dark gray) where they landed on the yellow's red tips! Look at the image: the white piece's tips are now gray at (38-40, 17-19) and (44-46, 14-16). So when a plug tip lands exactly on a socket contact, it becomes GRAY (locked/connected). And the level did NOT complete.
So the win condition is not just "the white piece's tips locked". Hmm. In level 1, when the plug's tips landed on the contacts, the level completed immediately. Here, only 2 of the 10 other tips are matched.
Hmm wait — maybe the gray indicates "connected" and the win requires ALL red tips to be grayed/connected. But we only control the white piece...
Hmm, maybe the gray means the white piece is now LOCKED to the yellow piece and can't move? Or maybe now a different piece becomes controllable? Let's check: maybe after connecting, the controllable piece changes (e.g., the connected assembly moves, or control passes to the yellow piece!).
That's a plausible mechanic: connect pieces one at a time; each connection turns the joint gray. Let's test: press LEFT/UP and see what moves now.
Let me check the current state and test a move.

```python
for n in current_frame.segmentation['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
print('---test move UP---')
action(['UP']); res=last_action_call_result
print({k:v for k,v in res.items() if k in ('no_op','gameplay_changed','level_completed','game_over')})
d=frame_diff()
print('changed',d['changed_cell_count'])
for k in ('moved','rotated','appeared','disappeared','changed_color','resized'):
    if d.get(k): print(' ',k,[(e.get('color'),e.get('pixels'),e.get('from'),e.get('to'),e.get('at'),e.get('bbox'),e.get('before_color'),e.get('after_color')) for e in d[k]][:8])
```

```text
0 O 3497 [0, 0] [63, 0]
1 W 3 [0, 16] [0, 18]
2 c 29 [0, 19] [0, 47]
3 R 9 [14, 44] [16, 44]
4 N 90 [14, 47] [31, 47]
5 R 9 [20, 50] [22, 50]
6 R 9 [26, 50] [28, 50]
7 W 90 [29, 11] [46, 11]
8 R 9 [29, 38] [31, 38]
9 O 36 [32, 14] [43, 14]
10 Y 162 [35, 23] [40, 23]
11 G 9 [38, 17] [40, 17]
12 O 54 
… [765 caracteres más]
```

## Paso 8 · nivel 2 · acción 29

**Pensamiento:**

Interesting. Pressing UP moved the white piece up by 3, and the tips reverted from gray to red. So the gray indicated the tips were exactly on the contacts, and moving away reverted them to red. So gray = "tip seated in socket". The level didn't complete.
So my hypothesis about the win condition needs revision. In level 1, the plug's tips landed on the socket's 2 contacts → win. Here, the white piece's 2 tips landed on 2 of yellow's 4 tips → gray but no win.
Hmm! So maybe the win condition is: ALL red tips on the board must be seated/gray? But we only control the white piece... Unless connecting pieces changes which piece is controlled. Hmm, but the white piece moved freely away (up) after being connected, so no lock.
Alternative: maybe the win condition is that all pieces are CONNECTED into one component. Currently the white is connected to yellow (via gray joints), but green and blue are separate. So we need the white piece to bridge... but the white piece can only be in one place.
Hmm. Wait — maybe the win condition involves the white piece covering ALL the "socket" positions of a target piece? Hmm.
Let me reconsider. Maybe the gray state is a "connection" and the goal is to connect ALL pieces into a single connected component. The white piece can only connect to one piece at a time... unless the white piece can be placed such that it touches multiple pieces? Or unless, once the white piece is connected to yellow, the whole white+yellow assembly becomes movable?! Let's che
… [11324 caracteres más]

```python
for pos in [(41,30),(17,48)]:
    action([{'action':'MOUSE','row':pos[0],'col':pos[1]}]); res=last_action_call_result
    print('click',pos,{k:v for k,v in res.items() if k in ('no_op','gameplay_changed','level_completed','board_changed')})
    d=frame_diff()
    print(' changed',d['changed_cell_count'], [ (k,[ (e.get('color'),e.get('pixels'),e.get('from'),e.get('to')) for e in d[k]][:4]) for k in ('moved','appeared','disappeared','changed_color','resized') if d.get(k)])
```

```text
[action] MOUSE(row=41, col=30) -> effect
click (41, 30) {'board_changed': True, 'level_completed': False, 'gameplay_changed': True, 'no_op': False}
 changed 252 [('changed_color', [(None, 90, None, None), (None, 162, None, None)])]
[action] MOUSE(row=17, col=48) -> effect
click (17, 48) {'board_chan
… [228 caracteres más]
```

## Paso 9 · nivel 2 · acción 29

**Pensamiento:**

MOUSE clicks change colors! Clicking yellow (41,30) turned the WHITE piece purple (p) and the GREEN piece white? Let me look at the current image: the white plug (left) is now PURPLE, the green L is now WHITE, the yellow is still yellow, blue still blue.
So clicking a piece cycles the colors of pieces? It seems like clicking selects a piece and it becomes the "active" one (colored purple = selected?) and the previously active becomes white? Hmm, but the green became white.
Let me analyze: 
- Initial: white (active), green, yellow, blue.
- Click 1 on yellow (41,30): changed_color 90 px (white piece) and 162 px (yellow piece). So the white piece ↔ yellow piece swapped colors? 90 px = white piece, 162 = yellow piece. So they swapped colors: white piece became yellow, yellow became white? But the current image shows the left plug as PURPLE after two clicks and the green as white.
- Click 2 on green (17,48): changed_color 90 px and 162 px again. Hmm, that says a 90-px object and a 162-px object changed color. The 90-px object is the white plug (or the green L, also 90 px!). Hmm, both the white plug and green L are 90 px.
Let me just look at the current colors: left plug = purple, green L = white, yellow = yellow, blue = blue.
Sequence: after click1 on yellow: presumably left plug became yellow and yellow became white? Then after click2 on green: left plug (yellow, 90px) and yellow piece (162) changed... hmm confusing.
Let me get the actual current segmentation colors and the previ
… [34 caracteres más]

```python
def cols(f):
    return sorted([(n['color'],n['pixels'],tuple(n['boundary'][0])) for n in f.segmentation['nodes'] if n['pixels']>20])
print('now  ',cols(current_frame))
print('prev ',cols(previous_frame))
print('h-3  ',cols(history[-3].frame))
print('h-4  ',cols(history[-4].frame))
```

```text
now   [('O', 36, (29, 14)), ('O', 54, (38, 26)), ('O', 3479, (0, 0)), ('W', 90, (14, 47)), ('Y', 162, (35, 23)), ('b', 45, (53, 50)), ('c', 28, (0, 20)), ('p', 90, (26, 11))]
prev  [('N', 90, (14, 47)), ('O', 36, (29, 14)), ('O', 54, (38, 26)), ('O', 3479, (0, 0)), ('W', 162, (35, 23)), ('b', 45, (5
… [399 caracteres más]
```

**Pensamiento:**

Reconstruction:
- h-4 (before clicks): W at (29,11) [the plug], N at (14,47) [green L], Y at (35,23), b at (53,50).
- h-3 (after click1 on yellow): same colors! W plug, N green, Y yellow... wait h-3 shows W 90 at (26,11), N 90, Y 162. Hmm, h-3 is after the UP move? Let me index: history entries: [-1] = click2, [-2] = click1, [-3] = UP, [-4] = RIGHT (last of the DOWNx6+RIGHT batch)... Actually history includes every action. Let me be careful:
  - history[-1].frame = now (after click2)
  - history[-2].frame = after click1 = previous_frame
  - history[-3].frame = after UP
  - history[-4].frame = after the last RIGHT (seated position)
So: after UP (h-3): W plug at (26,11), N green, Y yellow — normal colors.
After click1 (prev): W 162 at (35,23) → the YELLOW piece became WHITE, and p 90 at (26,11) → the white plug became PURPLE. Green stayed N.
So click1 on yellow: yellow → white, white plug → purple. Interesting: so clicking a piece makes it the new "active" piece (white), and the previous active becomes purple?? Hmm, that's odd. Or: the click SWAPS the colors of the clicked piece and the active piece: yellow↔white. Then the piece that is white is the active one. But then why purple?
Hmm, after click1: the clicked piece (yellow, 162) is now white; the previously active (90 px at (26,11)) is now purple. So the colors swapped? No: white → purple, yellow → white. So it's a "rotation" of colors: the clicked piece takes the active color (white), the old active takes purple. Purple = "
… [6391 caracteres más]

```python
a=current_frame.ascii.split('\n')
def co(color,r0,r1,c0,c1):
    return {(r,c) for r in range(r0,r1+1) for c in range(c0,c1+1) if a[r][c]==color}
# current: plug(purple) at rows26-43 cols11-19 ; green(W) rows14-34 cols38-52 ; yellow rows35-55 cols14-34 ; blue rows50-58 cols50-58
pieces={}
pieces['P']= (co('p',24,45,9,21), co('R',24,45,9,21))
pieces['G']= (co('W',12,36,36,54), co('R',12,36,36,54))
pieces['Y']= (co('Y',33,57,12,36), co('R',33,57,12,36))
pieces['B']= (co('b',48,60,48,60), co('R',48,60,48,60))
for k,(b,t) in pieces.items():
    allc=b|t
    print(k,'body',len(b),'tips',len(t)//9,'bbox',min(x[0] for x in allc),max(x[0] for x in allc),min(x[1] for x in allc),max(x[1] for x in allc))
# convert to super coords
def sup(cells): return {((r-2)//3,(c-2)//3) for r,c in cells}
shapes={}
… [550 caracteres más]
```

```text
P body 90 tips 3 bbox 26 45 11 19
G body 90 tips 4 bbox 14 34 38 52
Y body 162 tips 6 bbox 35 55 14 34
B body 45 tips 2 bbox 50 58 50 58
== P 7 x 3 body 10 tips 4
###
#.#
#.#
#.T
#.T
#T.
.T.
== G 7 x 5 body 10 tips 4
..T#.
...#.
...#T
...#.
...#T
T..#.
####.
== Y 7 x 7 body 18 tips 6
.T.###.
.T.#.#T
… [77 caracteres más]
```

## Paso 9 · nivel 2 · acción 30

**Pensamiento:**

Note the tip counts: P has 3 tips?? "P body 90 tips 3" — because the plug's tip at rows 38-40? Wait, the purple plug is at rows 26-43; its red tips: (35-37, 17-19) and (41-43, 14-16)? Hmm, and also there's a red tip from yellow at (38,32) etc. My crop ranges overlapped: pieces['P'] crop (24,45,9,21) included yellow's red tip at (44,14)-(46,16)? That's rows 44-46, my crop went to row 45 → partial. Let me be careful. Also Y tips 6 (should be 4) — its crop (33,57,12,36) included the plug's red tips at (35-37,17-19) and (41-43,14-16).
Let me redo the extraction using segmentation node ids instead, with proper assignment: red blocks belong to the piece they're adjacent to.
Better approach: use segmentation nodes and adjacency to group red tips with their owner piece.
Also the super-grid shapes look reasonable:
P (7x3): 
```
###
#.#
#.#
#.T
#.T
#T.
.T.
```
Hmm, the last row '.T.' and '#T.' suggest contamination from the yellow's tip at rows 44-46 cols 14-16 (super row (44-2)/3 = 14; the plug's bbox rows 26-43 → super rows 8-13; the yellow tip at rows 44-46 → super row 14 = extra row). Yes, contaminated.
Let me redo properly with segmentation-based grouping.
Plan: 
1. Get nodes from segmentation. Bodies: colored objects (p/W/N/Y/b) — but careful, the active piece is white and the green is also white now! Ugh, the color-swap mechanic complicates identification. Let me first restore the original state by clicking to make the plug active again (click on the purple plug at (26,11)). The
… [270 caracteres más]

```python
action([{'action':'MOUSE','row':30,'col':12}]); res=last_action_call_result
print({k:v for k,v in res.items() if k in ('no_op','gameplay_changed','level_completed')})
for n in current_frame.segmentation['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
print('adj',current_frame.segmentation['adjacency_list'])
```

```text
[action] MOUSE(row=30, col=12) -> effect
{'level_completed': False, 'gameplay_changed': True, 'no_op': False}
0 O 3479 [0, 0] [63, 0]
1 W 4 [0, 16] [0, 19]
2 c 28 [0, 20] [0, 47]
3 R 9 [14, 44] [16, 44]
4 N 90 [14, 47] [31, 47]
5 R 9 [20, 50] [22, 50]
6 W 90 [26, 11] [43, 11]
7 R 9 [26, 50] [28, 50]
… [575 caracteres más]
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

Clicking the purple plug made it white (active) again and the green reverted to green. Confirmed: MOUSE selects the active piece; the active piece is rendered white.
Important: the white plug is now at rows 26-43 (moved up 3 from its initial rows 29-46? wait). Let me recompute the current position of the plug: node 6 W 90 at boundary [26,11] → rows 26-43, cols 11-19.
Now let me extract the shapes cleanly using segmentation + adjacency:
Bodies: node 6 (W, plug), node 4 (N, green), node 11 (Y, yellow), node 18 (b, blue).
Red tips: nodes 3,5,7,9,10(18px=2 blocks),13,14(18px),15,16,17.
Ownership via adjacency:
- N(4): adj 3,5,7,9 → tips: (14,44),(20,50),(26,50),(29,38) → 4 tips ✓
- W(6): adj 10 (18px = blocks at (35,17) and (38,17)? no wait) hmm. Node 10 is R 18 at [35,17]-[40,17] → that's a vertical 6x3 block spanning rows 35-40, cols 17-19 = two 3x3 blocks: (35,17) and (38,17). Hmm! That's the plug's tip (rows 35-37) plus... what's at rows 38-40 cols 17-19? The yellow's tip Y1 was at (38,17)-(40,19). So the plug's tip (35-37,17-19) is adjacent (vertically) to the yellow's tip (38-40,17-19) → merged into one 18-px red component. Right! Because the plug is 3 rows above the seated position, its down-tip is directly above the yellow's up-tip.
- node 14: R 18 at [41,14]-[46,14] → blocks (41,14) and (44,14): the plug's right tip (rows 41-43, cols 14-16) adjacent to the yellow's left tip (44-46, cols 14-16) ✓.
So the plug's tips: (35,17) and (41,14). Yellow's tips: (38,17),(38,32),(44
… [1965 caracteres más]

```python
def build_pieces(f):
    seg=f.segmentation; nodes=seg['nodes']; adj=seg['adjacency_list']
    bodies={}
    for n in nodes:
        if n['color'] in ('W','N','Y','b') and n['pixels']>=20 and n['boundary'][0][0]>3:
            bodies[n['id']]=n
    # red blocks: split red nodes into 3x3 blocks
    reds=[]
    for n in nodes:
        if n['color']=='R':
            cells=[]
            # reconstruct cells from ascii
            pass
    a=f.ascii.split('\n')
    def cellset(n):
        r0,c0=n['boundary'][0]; r1,c1=n['boundary'][-1]
        return {(r,c) for r in range(r0,r1+1) for c in range(c0,c1+1) if a[r][c]=='R'}
    # map red cells to owner body by adjacency
    owner={}
    for i,j in adj:
        if i in bodies and nodes[j]['color']=='R': owner[j]=i
        if j in bodies and nodes[
… [1574 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 45, in <module>
  File "<python_tool>", line 40, in norm
ValueError: min() iterable argument is empty
```

**Pensamiento:**

One piece had empty tips or body — probably the 'W' body detection picked up the HUD white cell node (W 4 at row 0) — no, I filtered boundary[0][0] > 3. Hmm, the error is in norm for a piece where sb|st is empty... Actually the error occurred at line 40 in norm called at line 45? Let me check: line 45 is `nb,ob=norm(sb)`? Actually I removed that line's use... Let me look: I have `nb,ob=norm(sb); nt,ot=norm(st)` then recompute. The error at line 40 in norm → min() empty means sb or st empty. Which piece? The 'b' (blue) piece: color 'b'. My filter includes 'b'. Hmm, maybe the issue is the tips: for a piece with no tips... all pieces have tips.
Wait — maybe the issue is that 'W' matched a HUD node? No, filtered.
Hmm, maybe the piece dict P has a key whose body is empty because the body color detection used n['color'] to scan the bbox, which is fine.
Let me debug by printing what bodies were found.

```python
P=build_pieces(current_frame)
for k,v in P.items(): print(k, len(v['body']), len(v['tips']))
```

```text
N 18 0
W 18 0
Y 6 0
b 6 0
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

Body counts are wrong (18, 18, 6, 6) — because `n['boundary'][0]` and `[-1]` are not the bbox corners; they're perimeter corner points of a polygon, so my bbox extraction is wrong. I need to compute the actual cell set. Since I can't get cells from the node directly, let me instead scan the whole board for each color and use connected components (4-connected) to get bodies. That's easy with BFS over the ascii.
Let me write a robust function: parse ascii into a grid, find 4-connected components per color, and identify piece bodies as components with size >= 20, and red components → split into 3x3 blocks, assign each block to the body component it's adjacent to.
Let me implement that.

```python
def grid_of(f):
    a=f.ascii.split('\n')
    return {r:{c:a[r][c] for c in range(len(a[r]))} for r in range(len(a))}
def comps(g, pred):
    seen=set(); out=[]
    for r,row in g.items():
        for c,v in row.items():
            if pred(v) and (r,c) not in seen:
                st=[(r,c)]; comp=set()
                while st:
                    x=st.pop()
                    if x in comp: continue
                    comp.add(x)
                    for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
                        y=(x[0]+dr,x[1]+dc)
                        if y in g and y not in comp and pred(g[y[0]][y[1]]): st.append(y)
                out.append(comp)
    return out
def pieces_of(f):
    g=grid_of(f)
    bodies={}
    for col in ('W','N','Y','b','p'):
        for comp in comps(g, la
… [815 caracteres más]
```

```text
tool: python
function_retention: |
  Retained your function grid_of(f) for later Python calls in this game.
  Retained your function comps(g, pred) for later Python calls in this game.
  Retained your function pieces_of(f) for later Python calls in this game.
  Retained your function split3(comp) fo
… [48 caracteres más]
```

**Pensamiento:**

No output printed?! That means `bodies` is empty. Hmm, the print loop printed nothing → bodies empty. Why? `min(r for r,_ in comp)>3` — the HUD white cells are a separate small component. Bodies should be found... unless `comps` has a bug: I use `g` as a dict of dicts; `y in g` works for rows; `g[y[0]][y[1]]` works. Should be fine.
Wait — the lambda in the loop: `lambda v,c=col: v==c` fine.
Hmm, but `comps(g, pred)` iterates `for r,row in g.items(): for c,v in row.items()`. OK.
Then `if len(comp)>=20 and min(...)>3`. The white plug has 90 cells. Should pass.
Unless... `pieces_of` returned empty because the print loop `for k in bodies` printed nothing AND no error. Maybe bodies is empty because `comps` returned components but the color chars differ? Let me debug quickly.

```python
g=grid_of(current_frame)
print('rows',len(g), 'cols', len(g[0]))
from collections import Counter
print(Counter(v for row in g.values() for v in row.values()))
for col in ('W','N','Y','b','p'):
    cs=comps(g, lambda v,c=col: v==c)
    print(col,[ (len(c), min(r for r,_ in c), min(x[1] for x in c)) for c in cs])
```

```text
rows 64 cols 64
Counter({'O': 3569, 'Y': 162, 'R': 108, 'W': 94, 'N': 90, 'b': 45, 'c': 28})
W [(1, 0, 16), (1, 0, 17), (1, 0, 18), (1, 0, 19), (1, 26, 11), (1, 26, 12), (1, 26, 13), (1, 26, 14), (1, 26, 15), (1, 26, 16), (1, 26, 17), (1, 26, 18), (1, 26, 19), (1, 27, 11), (1, 27, 12), (1, 27, 13), 
… [4888 caracteres más]
```

**Pensamiento:**

My `comps` function is broken: it returns each cell as its own component of size 1. Bug: in the loop I do `st=[(r,c)]`, then pop and add to comp, then push neighbors — but I check `if x in comp: continue` after popping... that looks right. Hmm, but the output shows components of size 1 for each cell, meaning the neighbors weren't added. Why? `for dr,dc in ...: y=...; if y in g and y not in comp and pred(g[y[0]][y[1]]): st.append(y)`. `pred` is the lambda; fine.
OH WAIT. The bug: `g` is a dict of dicts keyed by row → `y in g` checks the row key ✓. `g[y[0]][y[1]]` ✓. Hmm.
Hmm, but the printout shows `W [(1, 0, 16), (1, 0, 17), ...]` — each entry is `(len(c), min row, min col)` = (1, 0, 16) etc. So all components have size 1. So the neighbor check failed. Why? Because `pred` — I passed `lambda v,c=col: v==c`. In `comps`, `pred(v)` is called with one arg ✓.
Hmm... unless `comp.add(x)` happens but then... Let me re-check: 
```
st=[(r,c)]; comp=set()
while st:
    x=st.pop()
    if x in comp: continue
    comp.add(x)
    for dr,dc in ...:
        y=(x[0]+dr,x[1]+dc)
        if y in g and y not in comp and pred(g[y[0]][y[1]]): st.append(y)
out.append(comp)
```
That's correct BFS. Unless the outer loop's `if pred(v) and (r,c) not in seen` — and `seen` is never updated! I never add cells to `seen`. So each unvisited-in-seen cell starts a new component... and since `seen` is never updated, EVERY cell starts a new component, but each component should still be the full connected blob. Hm
… [2692 caracteres más]

```python
g=grid_of(current_frame)
st=[(26,11)]; comp=set()
while st:
    x=st.pop()
    if x in comp: continue
    comp.add(x)
    for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
        y=(x[0]+dr,x[1]+dc)
        if y in g and y not in comp and g[y[0]][y[1]]=='W': st.append(y)
print('manual bfs size',len(comp))
import inspect
print(inspect.getsource(comps)[:600])
```

```text
manual bfs size 1

error:
Traceback (most recent call last):
  File "<python_tool>", line 11, in <module>
ImportError: Module 'inspect' is not allowed in the sandbox.
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

Manual BFS from (26,11) gives size 1?! That means (26,12) is not 'W' in my grid. So grid_of is producing wrong data — maybe the ascii rows have different lengths or the string indexing is off. Let me check: `a[r][c]` should work. Unless the ascii string rows contain trailing characters or the grid isn't 64 wide... The Counter showed 64*64 = 4096 total? Counter: O 3569 + Y 162 + R 108 + W 94 + N 90 + b 45 + c 28 = 4096 ✓. So the grid is complete and correct.
So (26,11) is 'W' and (26,12) should be 'W'. The BFS says size 1 → the neighbor check failed. `y in g` where y=(26,12) → g has key 26 ✓ (dict of dicts, keys are ints 0..63). `g[26][12]` → 'W'? 
Hmm, unless grid_of's inner dict keys are... `{c: a[r][c] for c in range(len(a[r]))}` → int keys ✓.
Wait, maybe the issue is that `y in g` where g is a dict of dicts — `in` checks keys ✓.
Let me directly test: print g[26][11], g[26][12], (26,12) in g.

```python
g=grid_of(current_frame)
print(repr(g[26][11]), repr(g[26][12]), repr(g[26][13]), (26,12) in g, list(g[26].keys())[:5], type(list(g[26].keys())[0]))
a=current_frame.ascii.split('\n')
print(repr(a[26][8:22]))
print(len(a), len(a[26]))
```

```text
'W' 'W' 'W' False [0, 1, 2, 3, 4] <class 'int'>
'OOOWWWWWWWWWOO'
64 64
```

**Pensamiento:**

Found it: `(26,12) in g` is False because `g` is a dict keyed by row int, and I was checking a tuple against row keys! My BFS used `y in g` with y = (row, col) — that's the bug. I need `y[0] in g and y[1] in g[y[0]]`.
Let me rewrite comps with a proper 2D list grid. Let me redefine grid_of to return a list of lists.

```python
def grid2(f):
    a=f.ascii.split('\n')
    return [list(row) for row in a]
def comps2(G, pred):
    R=len(G); C=len(G[0]); seen=[[False]*C for _ in range(R)]; out=[]
    for r in range(R):
        for c in range(C):
            if pred(G[r][c]) and not seen[r][c]:
                st=[(r,c)]; comp=[]
                seen[r][c]=True
                while st:
                    x=st.pop(); comp.append(x)
                    for dr,dc in ((1,0),(-1,0),(0,1),(0,-1)):
                        y=(x[0]+dr,x[1]+dc)
                        if 0<=y[0]<R and 0<=y[1]<C and not seen[y[0]][y[1]] and pred(G[y[0]][y[1]]):
                            seen[y[0]][y[1]]=True; st.append(y)
                out.append(set(comp))
    return out
def pieces2(f):
    G=grid2(f)
    bodies={}
    for col in ('W','N',
… [569 caracteres más]
```

```text
W 90 2
N 90 4
Y 162 5
b 45 2
total red blocks 12
```

**Pensamiento:**

Now: W(plug) 2 tips, N 4, Y 5 (one of these is the plug's tip adjacent to yellow's body — since the plug's tip at (35-37,17-19) is adjacent to the yellow tip at (38-40,17-19) AND possibly adjacent to the yellow body? Let's see: the plug's down-tip at rows 35-37 cols 17-19; yellow body cells adjacent? Yellow's left bar is cols 17-19 rows 41-49, and the yellow's tip Y1 is at rows 38-40 cols 17-19. The plug's tip is adjacent to Y1 (red) only. Hmm, so why does Y have 5 tips? Because the plug's tip (35,17) is a red block adjacent to... the yellow's red block (38,17) which is part of yellow's red component (they merged into one 18px component), and my split3 gives two blocks; the adjacency check uses body adjacency — the merged red component's block (35,17) touches the plug body, and block (38,17) touches the yellow tip? Hmm, the yellow body adjacency: which yellow body cells touch red blocks? (38,17) block touches yellow's left bar top at (41,17)? No: block (38,17) spans rows 38-40, cols 17-19; the yellow body at rows 41-43 cols 17-19 → adjacent ✓. And the plug's tip block (35,17) rows 35-37 cols 17-19 is adjacent to the plug's white body (rows 32-34 cols 17-19) ✓ but not to yellow body. So Y's 5 tips must include something else. Similarly the plug's other tip (41,14) rows 41-43 cols 14-16 is adjacent to yellow's tip (44,14) rows 44-46 cols 14-16, which is adjacent to yellow body at (44,17)? Yes, yellow body at rows 44-46 cols 17-19 ✓. So Y's tips: (38,17),(44,14),(38,32),(53,26) 
… [2322 caracteres más]

```python
init=None
for h in history:
    if h.frame.level==2:
        init=h.frame; break
print('init step',init.step)
bodies,tips,reds=pieces2(init)
info={}
for k in bodies:
    sb={((r-2)//3,(c-2)//3) for r,c in bodies[k]}
    st=set()
    for b in tips[k]:
        for (r,c) in b: st.add(((r-2)//3,(c-2)//3))
    allc=sb|st
    r0=min(x[0] for x in allc); c0=min(x[1] for x in allc)
    nb=frozenset((r-r0,c-c0) for r,c in sb); nt=frozenset((r-r0,c-c0) for r,c in st)
    info[k]={'body':sorted(nb),'tips':sorted(nt),'pos':(r0,c0),'H':max(x[0] for x in nb|nt)+1,'W':max(x[1] for x in nb|nt)+1}
    H=info[k]['H']; W=info[k]['W']
    print('==',k,H,'x',W,'pos(super)',info[k]['pos'],'body',len(nb),'tips',len(nt))
    for r in range(H):
        print('   ',''.join('#' if (r,c) in nb else ('T' if (r,c) in n
… [173 caracteres más]
```

```text
init step 18
== W 6 x 3 pos(super) (3, 3) body 10 tips 2
    ###
    #.#
    #.#
    #.T
    #..
    #T.
== N 7 x 5 pos(super) (4, 12) body 10 tips 4
    ..T#.
    ...#.
    ...#T
    ...#.
    ...#T
    T..#.
    ####.
== Y 7 x 7 pos(super) (11, 4) body 18 tips 4
    ...###.
    .T.#.#T
    .###.#.
… [794 caracteres más]
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

Now I have the four pieces in super-coords (each super-cell = 3x3 real cells):
W (plug), 6x3, pos (3,3):
```
###
#.#
#.#
#.T
#..
#T.
```
body: (0,0),(0,1),(0,2),(1,0),(1,2),(2,0),(2,2),(3,0),(4,0),(5,0); tips: (3,2),(5,1)
N (green), 7x5, pos (4,12):
```
..T#.
...#.
...#T
...#.
...#T
T..#.
####.
```
Y (yellow), 7x7, pos (11,4):
```
...###.
.T.#.#T
.###.#.
T#...#.
.###.#.
...###.
....T..
```
b (blue), 3x3, pos (16,16):
```
T.T
#.#
###
```
Now search for an assembly: place each piece (4 rotations, any translation on the super-grid) so that:
- all 12 tips pair up (each tip coincides with exactly one other tip),
- no body-body overlap,
- tips don't land on other bodies.
Let me code a solver: 
- Generate all placements for each piece (rotation × translation within a 21x21 super-board).
- Backtracking: place pieces one by one; require that tip-to-tip pairings are consistent, no overlaps.
Rotation rule: rotate about the bbox top-left with dims swapping (as established). For a shape with bbox H×W, the rotated shape has bbox W×H, and cells map (r,c) → (c, H-1-r). Let me confirm with the real game: in level 1, the combined bbox was 18x15 (H=18,W=15), and the rotation mapped (r,c) → (r0 + (c-c0), c0 + (r1-r)) → in local coords (r,c) → (c, (r1-r0) - r) = (c, H-1-r) ✓. Great.
Now the search. Also, importantly: the assembly should probably be "compact" — the pieces form a connected figure.
Let me also consider: maybe the win condition is that all pieces are connected (not necessarily all ti
… [103 caracteres más]

```python
PIECES={'W':{'body':[(0,0),(0,1),(0,2),(1,0),(1,2),(2,0),(2,2),(3,0),(4,0),(5,0)],'tips':[(3,2),(5,1)],'pos':(3,3),'H':6,'W':3},
 'N':{'body':[(0,3),(1,3),(2,3),(3,3),(4,3),(5,3),(6,0),(6,1),(6,2),(6,3)],'tips':[(0,2),(2,4),(4,4),(5,0)],'pos':(4,12),'H':7,'W':5},
 'Y':{'body':[(0,3),(0,4),(0,5),(1,3),(1,5),(2,1),(2,2),(2,3),(2,5),(3,1),(3,5),(4,1),(4,2),(4,3),(4,5),(5,3),(5,4),(5,5)],'tips':[(1,1),(1,6),(3,0),(6,4)],'pos':(11,4),'H':7,'W':7},
 'b':{'body':[(1,0),(1,2),(2,0),(2,1),(2,2)],'tips':[(0,0),(0,2)],'pos':(16,16),'H':3,'W':3}}
def rot(shape,H,W):
    # (r,c)->(c, H-1-r), new dims W x H
    nb=[(c,H-1-r) for r,c in shape['body']]; nt=[(c,H-1-r) for r,c in shape['tips']]
    Hh,Wh=W,H
    r0=min(min([p[0] for p in nb]+[p[0] for p in nt]),0); c0=min(min([p[1] for p in nb]+[p[1] for p 
… [409 caracteres más]
```

```text
W [(0, 10, 2, 6, 3), (1, 10, 2, 3, 6), (2, 10, 2, 6, 3), (3, 10, 2, 3, 6)]
N [(0, 10, 4, 7, 5), (1, 10, 4, 5, 7), (2, 10, 4, 7, 5), (3, 10, 4, 5, 7)]
Y [(0, 18, 4, 7, 7), (1, 18, 4, 7, 7), (2, 18, 4, 7, 7), (3, 18, 4, 7, 7)]
b [(0, 5, 2, 3, 3), (1, 5, 2, 3, 3), (2, 5, 2, 3, 3), (3, 5, 2, 3, 3)]
```

**Pensamiento:**

Rotations work. Now the assembly solver. Board: super-grid 21x21 (rows 0..20, cols 0..20). Real cells: super (R,C) → rows 3R+2..3R+4. Real board is 64x64; the HUD is at row 0-1. Piece positions must keep cells within rows 1..63 → super rows 0..19 (since 3*19+4 = 61; super row 20 → rows 62-64, out of range). Let me just require real cells within [1,63] for rows and [0,63] for cols.
Solver: backtracking over pieces in order; maintain occupied body cells and tip cells. Constraints:
- Body cells of new piece must not intersect existing body or tips? Hmm — a body cell landing on another piece's tip: that would mean the tip is covered by a body. Is that allowed? In level 1, the plug's tips landed on the socket's tips (red on red). Body-on-tip probably not allowed (or maybe it is, but let's disallow).
- Tips: each tip of the new piece must either coincide with an existing tip (pairing) or be a "free" tip (to be paired later).
- Final: all tips paired.
Let me implement: place pieces; track for each cell: type (body/tip) and owner. New piece's body cells must not overlap any existing body or tip cells. New piece's tip cells must not overlap existing body cells; they may overlap existing tip cells (pairing, each at most once).
At the end, all tips must be paired (12 tips → 6 pairs).
Then also require the assembly to be connected (should follow from pairing).
Let me search with the board limited to super rows 0..19, cols 0..19. To reduce the search, I'll anchor the first piece and use r
… [3496 caracteres más]

```python
def all_variants(shape):
    out=[]; s={'body':list(shape['body']),'tips':list(shape['tips'])}; H=shape['H']; W=shape['W']
    for k in range(4):
        out.append((k,set(s['body']),set(s['tips']),H,W))
        s,H,W=rot(s,H,W)
    return out
VAR={k:all_variants(v) for k,v in PIECES.items()}
BR=20; BC=21  # super rows 0..19, cols 0..20
def place(variant, pos):
    k,b,t,H,W=variant
    r0,c0=pos
    return {('B',(r+r0,c+c0)) for r,c in b}, {('T',(r+r0,c+c0)) for r,c in t}, (r0,c0,H,W)
def solve(fixrot=0, fixpos=(11,4), maxsol=6):
    sols=[]
    order=['N','W','b']
    yv=VAR['Y'][fixrot]
    yb,yt,ymeta=place(yv,fixpos)
    if any(r<0 or r>=BR or c<0 or c>=BC for _,(r,c) in yb|yt): return sols
    state={'Y':(fixrot,fixpos,yb,yt)}
    occupied_b=set(yb); occupied_t=set(yt)
    def valid(
… [1295 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 7, in <module>
NameError: name 'PIECES' is not defined
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

PIECES wasn't retained (it was a plain assignment, not a function). I need to redefine PIECES inside each snippet, or better: make a retained function that returns it. Let me define `def PIECES_DATA(): return {...}` and use it. Let me combine everything into one snippet that defines the data function and the solver (and hope the solver is retained; the retention issue was that `place`/`solve` "did not execute" because the snippet errored).
Let me redo: define PIECES_DATA() retained, then in the same snippet define and run the solver.

```python
def PIECES_DATA():
    return {'W':{'body':[(0,0),(0,1),(0,2),(1,0),(1,2),(2,0),(2,2),(3,0),(4,0),(5,0)],'tips':[(3,2),(5,1)],'pos':(3,3),'H':6,'W':3},
 'N':{'body':[(0,3),(1,3),(2,3),(3,3),(4,3),(5,3),(6,0),(6,1),(6,2),(6,3)],'tips':[(0,2),(2,4),(4,4),(5,0)],'pos':(4,12),'H':7,'W':5},
 'Y':{'body':[(0,3),(0,4),(0,5),(1,3),(1,5),(2,1),(2,2),(2,3),(2,5),(3,1),(3,5),(4,1),(4,2),(4,3),(4,5),(5,3),(5,4),(5,5)],'tips':[(1,1),(1,6),(3,0),(6,4)],'pos':(11,4),'H':7,'W':7},
 'b':{'body':[(1,0),(1,2),(2,0),(2,1),(2,2)],'tips':[(0,0),(0,2)],'pos':(16,16),'H':3,'W':3}}
def all_variants2(shape):
    out=[]; s={'body':list(shape['body']),'tips':list(shape['tips'])}; H=shape['H']; W=shape['W']
    for k in range(4):
        out.append((k,frozenset(s['body']),frozenset(s['tips']),H,W))
        s,H,W=rot(s
… [1378 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 39, in <module>
  File "<python_tool>", line 37, in solve_asm
  File "<python_tool>", line 28, in rec
ValueError: too many values to unpack (expected 2)
```

**Pensamiento:**

Bug: `set(yt)` where yt elements are tuples ('T',r,c) — then in rec I iterate `for (ur,uc) in unpaired` but unpaired contains 3-tuples. Fix: store unpaired as set of (r,c) pairs. Let me convert tip sets to plain (r,c) coordinates.

```python
def solve_asm2(fixrot=0, fixpos=(11,4), maxsol=8, order=('N','W','b'), BR=20, BC=21):
    P=PIECES_DATA(); VAR={k:all_variants2(v) for k,v in P.items()}
    sols=[]
    def place(variant,pos):
        k,b,t,H,W=variant; r0,c0=pos
        return frozenset((r+r0,c+c0) for r,c in b), frozenset((r+r0,c+c0) for r,c in t)
    yv=VAR['Y'][fixrot]; yb,yt=place(yv,fixpos)
    if any(r<0 or r>=BR or c<0 or c>=BC for r,c in yb|yt): return sols
    def rec(occB,occT,placed,unpaired):
        if len(placed)==4:
            if not unpaired: sols.append({k:(v[0],v[1]) for k,v in placed.items()})
            return
        nxt=order[len(placed)-1]
        for vi,var in enumerate(VAR[nxt]):
            cand=set()
            for (tr,tc) in var[2]:
                for (ur,uc) in unpaired: cand.add((ur-tr,uc
… [603 caracteres más]
```

```text
Yrot 0 sols 1
    {'Y': (0, (11, 4)), 'N': (0, (12, 8)), 'W': (0, (9, 3)), 'b': (3, (14, 12))}
Yrot 1 sols 0
Yrot 2 sols 1
    {'Y': (2, (11, 4)), 'N': (2, (10, 2)), 'W': (2, (14, 9)), 'b': (1, (12, 0))}
Yrot 3 sols 1
    {'Y': (3, (11, 4)), 'N': (3, (9, 5)), 'W': (3, (16, 2)), 'b': (2, (7, 7))}
```

**Pensamiento:**

There's a unique assembly for each global rotation (they're the same assembly rotated). The Yrot=0 solution:
- Y at rot 0, pos (11,4) — unchanged from initial!
- N at rot 0, pos (12,8) — from (4,12) → move (+8 rows, -4 cols) in super units = +24 rows, -12 cols in real cells.
- W at rot 0, pos (9,3) — from (3,3) → +6 rows, 0 cols = +18 rows.
- b at rot 3, pos (14,12) — from (16,16) → -2 rows, -4 cols = -6 rows, -12 cols.
This is a beautiful unique solution where Y stays put. The W piece's target (9,3) is exactly the placement I already found (dr=+18, dc=0 in super = +18 rows) — consistent with my earlier solution (6 DOWN, 1 RIGHT... wait, earlier I computed dr=+18 rows, dc=+3 cols in real cells = +6 rows, +1 col in super). Hmm: the earlier search said white tips land on yellow tips with dc=+3 real cells (1 super col). But this assembly says W at pos (9,3) — the W's initial pos is (3,3), so dc=0!
Hmm, discrepancy. Let me recheck: W's initial super pos (3,3) corresponds to real bbox top-left: super (3,3) → real rows 3*3+2=11, cols 11 ✓ (the W piece's combined bbox was rows 11-28, cols 11-19).
The earlier search3 result (0,18,3,2,2): dr=18, dc=3 → real bbox top-left (29,14) → super ((29-2)/3, (14-2)/3) = (9,4). But the assembly says (9,3).
Hmm! One of them is off by 1 super col. Let me check the W piece's bbox in the earlier search: I used the combined white+red bbox. In the initial level-2 state, the W piece's combined bbox: rows 11-28 (18 rows = 6 super), cols 11-19 (9 cols = 3
… [6996 caracteres más]

```python
def asm_grid(sol):
    P=PIECES_DATA(); VAR={k:all_variants2(v) for k,v in P.items()}
    grid={}
    for name,(rotk,pos) in sol.items():
        var=VAR[name][rotk]; r0,c0=pos
        for (r,c) in var[1]: grid[(r+r0,c+c0)]=name
        for (r,c) in var[2]: grid[(r+r0,c+c0)]=name.lower()
    R=max(r for r,_ in grid)+1; C=max(c for _,c in grid)+1
    lines=[''.join(grid.get((r,c),'.') for c in range(C)) for r in range(R)]
    return lines
sol={'Y': (0, (11, 4)), 'N': (0, (12, 8)), 'W': (0, (9, 3)), 'b': (3, (14, 12))}
for L in asm_grid(sol): print(L)
```

```text
...............
...............
...............
...............
...............
...............
...............
...............
...............
...WWW.........
...W.W.........
...W.W.YYY.....
...W.w.Y.YnN...
...W.YYY.Y.N...
...WwY...Y.Nbbb
.....YYY.Y.N..b
.......YYY.Nbbb
........n..N...
........NNNN
… [3 caracteres más]
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

The assembly looks beautiful: all tips pair up (lowercase letters = tip cells, each shared between two pieces) and the pieces interlock into a compact figure. This is very likely the intended solution.
Now let me plan the moves with collision checking. Current positions (super):
- W: (8,3) [moved], target (9,3) rot 0
- N: (4,12) target (12,8) rot 0
- Y: (11,4) target (11,4) rot 0 (no move)
- b: (16,16) target (14,12) rot 3
Moves needed:
- N: +8 rows, -4 cols (in super) = 8 DOWN, 4 LEFT
- b: rotate 3 CW, then -2 rows, -4 cols = 2 UP, 4 LEFT
- W: +1 row = 1 DOWN
Order: do the blue first (isolated), then green (long path), then the plug last.
Collision checking: I'll simulate the super-grid with all pieces and check each intermediate position.
Let me write the planner. Note the blue rotation: rotating 3× CW about the bbox top-left. The blue's bbox is 3x3 (square) so rotation keeps the bbox. Its cells rotate within.
But careful: the rotation of the blue piece changes which rotation it's in; the target rot 3 means after 3 CW presses. And the target pos (14,12) is the bbox top-left after rotation. Since rotation keeps the bbox top-left fixed, I can rotate at (16,16) then move 2 UP 4 LEFT to (14,12) ✓.
Let me verify the blue's rot-3 shape and check it matches the assembly grid at (14,12): the assembly shows 'bbb' rows at row 14 cols 12-14... whatever, the solver computed it.
Now, path planning with collision checks. Let me write code that:
- Maintains a dict of piece → (rotk, pos) i
… [548 caracteres más]

```python
def cur_state(f):
    bodies,tips,reds=pieces2(f)
    out={}
    name={'W':'W','N':'N','Y':'Y','b':'b','p':'W'}
    for col,body in bodies.items():
        k=name[col]
        t=tips[col]
        allc=set(body)
        for b in t: allc|=set(b)
        r0=min(r for r,_ in allc); c0=min(c for _,c in allc)
        sb=frozenset(((r-2)//3,(c-2)//3) for r,c in body)
        st=frozenset(((r-2)//3,(c-2)//3) for b in t for r,c in b)
        sr0=(r0-2)//3; sc0=(c0-2)//3
        out[k]={'pos':(sr0,sc0),'body':frozenset((r-sr0,c-sc0) for r,c in sb),'tips':frozenset((r-sr0,c-sc0) for r,c in st)}
    return out
S=cur_state(current_frame)
for k,v in S.items(): print(k,v['pos'],len(v['body']),len(v['tips']))
# match each current shape to a rotation index of its piece
P=PIECES_DATA()
for k,v in S.items():
… [140 caracteres más]
```

```text
W (8, 3) 10 2
N (4, 12) 10 4
Y (11, 4) 18 5
b (16, 16) 5 2
W current rot = 0
N current rot = 0
b current rot = 0
```

**Pensamiento:**

The Y piece shows 5 tips (contamination from the plug's adjacent tips as discussed). Fine — I know Y is rot 0 at (11,4) and doesn't need to move.
Current state: W (8,3) rot0, N (4,12) rot0, Y (11,4) rot0, b (16,16) rot0.
Targets: W (9,3) rot0, N (12,8) rot0, b (14,12) rot3.
Now plan the moves with collision checks. Let me write the simulator with the real piece shapes (from PIECES_DATA variants).
Plan order: b (rotate 3, then 2 UP, 4 LEFT), N (8 DOWN, 4 LEFT in some order), W (1 DOWN).
Let me check collisions for candidate orders of N's moves: LEFT×4 then DOWN×8, DOWN×8 then LEFT×4, or interleaved. I'll BFS over the (row,col) grid for the moving piece avoiding overlaps with others (which are at their current/target positions depending on the order).
Let me code a generic planner: given the current positions of all pieces and a target for one piece (rot fixed), BFS a path of super-moves (each ±1 super cell in a direction) avoiding collisions with the other pieces (at their current positions). Then convert to actions (each super move = 1 arrow press since 1 super = 3 real cells = 1 press ✓ — wait, is one press = 3 real cells = 1 super? Yes, moves were 3 cells per press ✓).
Then the action sequence: for each piece: MOUSE click on one of its body cells (real coords), SPACE × rotations, then arrows.
Let me write this.

```python
def cells_of_state(state, name):
    P=PIECES_DATA(); v=all_variants2(P[name])[state[name]['rot']]
    r0,c0=state[name]['pos']
    return {('B',r+r0,c+c0) for r,c in v[1]}, {('T',r+r0,c+c0) for r,c in v[2]}
def check_all(state):
    occ={}
    for k in state:
        b,t=cells_of_state(state,k)
        for x in b:
            if x in occ: return False,(x,occ[x],'B'+k)
            occ[x]='B'+k
        for x in t:
            if x in occ and occ[x][0]=='B': return False,(x,occ[x],'T'+k)
            occ.setdefault(x,'T'+k)
    return True,None
def bfs_path(state, name, target_rot, target_pos, BR=20, BC=21):
    from collections import deque
    start=(state[name]['rot'], state[name]['pos'])
    goal=(target_rot,target_pos)
    others={k for k in state if k!=name}
    def occ_others():
      
… [1881 caracteres más]
```

```text
initial ok? (True, None)
blue rotated ok? True None
b path len 6 [(3, (16, 15)), (3, (16, 14)), (3, (16, 13))] ...
after blue True None
{"W": {"rot": 0, "pos": [8, 3]}, "N": {"rot": 0, "pos": [4, 12]}, "Y": {"rot": 0, "pos": [11, 4]}, "b": {"rot": 3, "pos": [14, 12]}}
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

The blue piece path works (6 moves: 3 rotations + ... wait, "path len 6" means 6 arrow moves: 4 LEFT + 2 UP ✓).
Now let me build the complete plan for all three pieces (blue, green, white) with clicks, and print it. Then execute step by step with verification.
Note: the click coordinates must target the piece's current body cells in real coordinates. I'll compute them from the state.
Let me build the full plan in one snippet (no actions executed), then execute it with checks.

```python
def real_cell(name, rot, pos):
    v=all_variants2(PIECES_DATA()[name])[rot]
    r,c=sorted(v[1])[len(v[1])//2]
    R=3*(pos[0]+r)+2; C=3*(pos[1]+c)+2
    return R,C
def build_plan(state):
    import copy
    st=copy.deepcopy(state); plan=[]
    targets={'b':(3,(14,12)),'N':(0,(12,8)),'W':(0,(9,3))}
    for name in ('b','N','W'):
        rt,pp=targets[name]
        R,C=real_cell(name, st[name]['rot'], st[name]['pos'])
        plan.append({'action':'MOUSE','row':R,'col':C})
        nr=(rt-st[name]['rot'])%4
        plan += ['SPACE']*nr
        st[name]['rot']=(st[name]['rot']+nr)%4
        path=bfs_path(st,name,rt,pp)
        if path is None:
            print('NO PATH',name); return None,None
        for (r,pos) in path[1:]:
            dr=pos[0]-st[name]['pos'][0]; dc=pos[1]-st[name]['pos
… [512 caracteres más]
```

```text
COLLIDE N DOWN (('B', 11, 9), 'BN', 'BY')

error:
Traceback (most recent call last):
  File "<python_tool>", line 31, in <module>
TypeError: object of type 'NoneType' has no len()
```

**Pensamiento:**

The green (N) can't move DOWN first because it would collide with the yellow at (11,9). The BFS should have avoided collisions along the path... but the BFS only checks the moving piece against the OTHER pieces' positions — and it found a path? No: the error says COLLIDE at N DOWN, meaning bfs_path returned a path but the incremental check flagged a collision. Hmm, that means bfs_path's `ok()` uses `occ_others` computed from `state` — but I passed `st` (the working state) — wait, in build_plan I call bfs_path(st,...) which is right. But then in the loop I re-check with check_all(st) which checks ALL pieces against each other, including... hmm, the collision reported is between B N at (11,9) and B Y — i.e., the green's body cell at super (11,9) collides with the yellow's body. But bfs_path's ok() should have prevented that...
Unless the yellow's shape in bfs_path is wrong! In bfs_path I use `all_variants2(PIECES_DATA()[name])[r]` — for the yellow, the state has rot 0 → correct shape. Hmm.
Oh wait! I see: in bfs_path, `ok(st)` checks the moving piece's cells against occO (others' cells). The green moving DOWN from (4,12): its bbox is 7x5, so at pos (11,8)... hmm, the path found goes to (12,8). The first move in the path is DOWN to (5,12) presumably, and my incremental loop applies the moves one at a time and checks. The reported collision is at (11,9) — that's the green's body cell (local (6,1) at pos (5,8)?) Hmm, the collision happened at some point along the path.
The bug: bf
… [1720 caracteres más]

```python
import copy
st={'W':{'rot':0,'pos':(8,3)},'N':{'rot':0,'pos':(4,12)},'Y':{'rot':0,'pos':(11,4)},'b':{'rot':3,'pos':(14,12)}}
path=bfs_path(st,'N',0,(12,8))
print('path',path)
Y=all_variants2(PIECES_DATA()['Y'])[0]
ycells={(r+11,c+4) for r,c in Y[1]|Y[2]}
for (r,pos) in path:
    v=all_variants2(PIECES_DATA()['N'])[r]
    cells={(rr+pos[0],cc+pos[1]) for rr,cc in v[1]|v[2]}
    bad=cells & ycells
    print(pos, 'overlapY', sorted(bad)[:5])
```

```text
path [(0, (4, 12)), (0, (4, 11)), (0, (4, 10)), (0, (4, 9)), (0, (4, 8)), (0, (5, 8)), (0, (6, 8)), (0, (7, 8)), (0, (8, 8)), (0, (9, 8)), (0, (10, 8)), (0, (11, 8)), (0, (12, 8))]
(4, 12) overlapY []
(4, 11) overlapY []
(4, 10) overlapY []
(4, 9) overlapY []
(4, 8) overlapY []
(5, 8) overlapY [(11,
… [245 caracteres más]
```

**Pensamiento:**

The BFS path is invalid — it collides with the yellow at every step after the first. So bfs_path's `ok()` isn't checking correctly. Why? Because in `ok(st)` I compute cells of the moving piece and check `any((rr,cc) in occO ...)`. occO should contain the yellow's cells. Let me check `cells_of_state` for 'Y': state['Y'] = {'rot':0,'pos':(11,4)} → cells = ('B', r+11, c+4) tuples! Note cells_of_state returns tuples with a 'B'/'T' PREFIX: ('B', r, c). But in ok() I build `cells` as plain (r,c) tuples and check `(rr,cc) in occO` where occO contains 3-tuples ('B',r,c). So the check never matches! That's the bug.
Fix: in bfs_path's ok(), compare against the set of plain coordinates: {x[1:] for x in occO}.
Let me redefine bfs_path (as bfs_path2) and rerun the plan.

```python
def bfs_path2(state, name, target_rot, target_pos, BR=20, BC=21):
    from collections import deque
    P=PIECES_DATA(); VAR=all_variants2(P[name])
    others={k for k in state if k!=name}
    occO=set()
    for k in others:
        b,t=cells_of_state(state,k)
        occO |= {x[1:] for x in b} | {x[1:] for x in t}
    def ok(st):
        r,pos=st; v=VAR[r]; r0,c0=pos
        cells=[(rr+r0,cc+c0) for rr,cc in (v[1]|v[2])]
        if any(rr<0 or rr>=BR or cc<0 or cc>=BC for rr,cc in cells): return False
        return not any((rr,cc) in occO for rr,cc in cells)
    start=(state[name]['rot'],state[name]['pos']); goal=(target_rot,target_pos)
    if not ok(goal): return None
    dq=deque([[start]]); seen={start}
    while dq:
        p=dq.popleft(); cur=p[-1]
        if cur==goal: return p
   
… [1312 caracteres más]
```

```text
NO PATH N
plan len None
None
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

No path for N given the current arrangement (blue already moved to target, W at (8,3), Y fixed). The green is "trapped" — it needs to pass through the yellow's region. Since the yellow never moves, the green must go around. Let me check: is the green's target reachable by moving it first (before the blue)? The blue doesn't block the green's path (the blue is at the bottom right, and its target is at (14,12) which is where the green passes?). Let me try different orders and also consider that the W piece must move last (it's the one that must be seated in the yellow's socket... but actually the W's target is (9,3) which is up-left of the yellow).
The green needs to get from (4,12) to (12,8). The yellow occupies a ring-ish structure at rows 11-17, cols 4-10. The green's target bbox rows 12-18, cols 8-12.
The green must approach from below/right maybe. Let me search paths for the green with different orders and with the W and blue at various positions. Actually, the issue: the green's target position overlaps the yellow's bbox but not its cells. To get there, the green must pass through positions where it overlaps yellow cells. Let me compute the free space for the green: positions (r,c) where the green doesn't overlap the yellow's cells. Then check connectivity from (4,12) to (12,8) in that free space (ignoring other pieces).
Let me compute that.

```python
P=PIECES_DATA(); NV=all_variants2(P['N'])[0]; YV=all_variants2(P['Y'])[0]
yc={(r+11,c+4) for r,c in YV[1]|YV[2]}
free=[]
for r in range(-4,21):
    for c in range(-6,21):
        cells={(rr+r,cc+c) for rr,cc in NV[1]|NV[2]}
        if any(x<0 or x[0]>19 or x[1]<0 or x[1]>20 for x in cells): continue
        if not (cells & yc): free.append((r,c))
free=set(free)
# connectivity
from collections import deque
start=(4,12); goal=(12,8)
print('start free?',start in free,'goal free?',goal in free)
dq=deque([start]); seen={start}
while dq:
    x=dq.popleft()
    for d in ((1,0),(-1,0),(0,1),(0,-1)):
        y=(x[0]+d[0],x[1]+d[1])
        if y in free and y not in seen: seen.add(y); dq.append(y)
print('goal reachable (only Y blocking)?', goal in seen, 'freesize',len(free),'reach',len(seen))
# show
… [165 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 7, in <module>
  File "<python_tool>", line 7, in <genexpr>
TypeError: '<' not supported between instances of 'tuple' and 'int'
```

**Pensamiento:**

Bug in the bounds check: `any(x<0 or x[0]>19 ...)` where x is a tuple. Fix: check x[1]<0.

```python
free=set()
for r in range(-6,21):
    for c in range(-8,21):
        cells={(rr+r,cc+c) for rr,cc in NV[1]|NV[2]}
        if any(rr<0 or rr>19 or cc<0 or cc>20 for rr,cc in cells): continue
        if not (cells & yc): free.add((r,c))
from collections import deque
start=(4,12); goal=(12,8)
print('start free?',start in free,'goal free?',goal in free)
dq=deque([start]); seen={start}
while dq:
    x=dq.popleft()
    for d in ((1,0),(-1,0),(0,1),(0,-1)):
        y=(x[0]+d[0],x[1]+d[1])
        if y in free and y not in seen: seen.add(y); dq.append(y)
print('reachable?',goal in seen,'free',len(free),'seen',len(seen))
for r in range(-6,20):
    print('%3d'%r, ''.join(('#' if (r,c) in seen else ('o' if (r,c) in free else '.')) for c in range(-8,21)))
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 4, in <module>
NameError: name 'NV' is not defined
```

**Pensamiento:**

Variables reset between calls! NV, yc, P, NV were defined in the previous (errored) call — the error happened before NV was... no, NV was defined on line 1 of the previous snippet. But variables reset between tool calls (only functions are retained). Right — data doesn't persist. I need to recompute everything in each snippet, or put it inside a function.
Let me write one self-contained snippet.

```python
def green_space():
    P=PIECES_DATA(); NV=all_variants2(P['N'])[0]; YV=all_variants2(P['Y'])[0]
    yc={(r+11,c+4) for r,c in YV[1]|YV[2]}
    free=set()
    for r in range(-6,20):
        for c in range(-8,21):
            cells={(rr+r,cc+c) for rr,cc in NV[1]|NV[2]}
            if any(rr<0 or rr>19 or cc<0 or cc>20 for rr,cc in cells): continue
            if not (cells & yc): free.add((r,c))
    return free
free=green_space()
from collections import deque
start=(4,12); goal=(12,8)
dq=deque([start]); seen={start}
while dq:
    x=dq.popleft()
    for d in ((1,0),(-1,0),(0,1),(0,-1)):
        y=(x[0]+d[0],x[1]+d[1])
        if y in free and y not in seen: seen.add(y); dq.append(y)
print('start free',start in free,'goal free',goal in free,'reachable',goal in seen,'free',len(free),'seen',le
… [142 caracteres más]
```

```text
start free True goal free False reachable False free 161 seen 159
 -6 .............................
 -5 .............................
 -4 .............................
 -3 .............................
 -2 .............................
 -1 .............................
  0 ........#################.
… [649 caracteres más]
```

**Pensamiento:**

Interesting: the goal position (12,8) is NOT free when only the yellow blocks — meaning the green at (12,8) overlaps the yellow?! But the assembly solver said the solution is valid with no overlaps. Let me re-check: the assembly grid showed N's body at rows 12-18... 
Hold on. In the assembly grid, the N pieces appear at rows 12-18 with the tip lowercase. Let me recheck the solver's validity check: `if b & (occB|occT) or t & occB: continue`. That checks the new piece's body against occupied body/tips and the new tips against occupied bodies. But it does NOT check the new piece's tips against... well, tips can overlap tips. So body-body overlap is prevented.
So why does my green_space say the goal overlaps the yellow? Because green_space includes the yellow's TIPS in `yc` (YV[1]|YV[2]) and the green's body may overlap the yellow's tips at (12,8) — which is allowed in the assembly (the green's body covering... no wait, that's not allowed either: the solver checks `t & occB` for the new piece's tips vs existing bodies, and `b & (occB|occT)` — the new body vs existing tips IS checked. Hmm, so body-over-tip is disallowed in the solver.
Wait, but the green at (12,8) in the assembly: does it overlap the yellow's tips? Let me check the assembly grid: row 12: '...W.w.Y.YnN...' → at row 12: cols: 3,4,5 = W W W? Let me index: the string '...W.w.Y.YnN...' positions: 0'.',1'.',2'.',3'W',4'.',5'w',6'.',7'Y',8'.',9'Y',10'n',11'N'. So at row 12, col 10 is 'n' (green tip) and col 11 'N' (green
… [916 caracteres más]

```python
P=PIECES_DATA(); NV=all_variants2(P['N'])[0]; YV=all_variants2(P['Y'])[0]
yb={(r+11,c+4) for r,c in YV[1]}; yt={(r+11,c+4) for r,c in YV[2]}
nb={(r+12,c+8) for r,c in NV[1]}; nt={(r+12,c+8) for r,c in NV[2]}
print('green body overlap yellow body', sorted(nb&yb))
print('green body overlap yellow tips', sorted(nb&yt))
print('green tips overlap yellow body', sorted(nt&yb))
print('green tips overlap yellow tips', sorted(nt&yt))
print('YV tips',sorted(YV[2]),'NV tips',sorted(NV[2]))
```

```text
green body overlap yellow body []
green body overlap yellow tips []
green tips overlap yellow body []
green tips overlap yellow tips [(12, 10), (17, 8)]
YV tips [(1, 1), (1, 6), (3, 0), (6, 4)] NV tips [(0, 2), (2, 4), (4, 4), (5, 0)]
```

## Paso 10 · nivel 2 · acción 30

**Pensamiento:**

The green at (12,8) is valid (only tip-tip overlaps with the yellow, which is intended). My green_space incorrectly treated the yellow's tips as blocking. Fix: blocking cells = yellow body only (tips are allowed to be overlapped by the moving piece's tips, but not by its body).
So the free-space check must be: moving body ∩ (other bodies ∪ other tips) = ∅ and moving tips ∩ other bodies = ∅.
Let me redo the path search with the correct rule, and consider moving orders. The green's path may need the W or blue moved out of the way first, or the green must go around.
Let me redo the connectivity check for the green with only the yellow BODY blocking (plus board bounds).

```python
def free_positions(mover, rot, blockers_body, blockers_tip, BR=19, BC=20):
    V=all_variants2(PIECES_DATA()[mover])[rot]
    body=V[1]; tips=V[2]
    out=set()
    for r in range(-8,21):
        for c in range(-8,21):
            b={(x+r,y+c) for x,y in body}; t={(x+r,y+c) for x,y in tips}
            if any(x<0 or x>BR or y<0 or y>BC for x,y in b|t): continue
            if b & (blockers_body|blockers_tip): continue
            if t & blockers_body: continue
            out.add((r,c))
    return out
def conn(free, start, goal):
    from collections import deque
    if start not in free or goal not in free: return None
    dq=deque([[start]]); seen={start}
    while dq:
        p=dq.popleft(); x=p[-1]
        if x==goal: return p
        for d in ((1,0),(-1,0),(0,1),(0,-1)):
            y
… [375 caracteres más]
```

```text
green path exists (Y body blocking): True 12
[(4, 12), (5, 12), (6, 12), (7, 12), (8, 12), (9, 12), (10, 12), (11, 12), (12, 12), (12, 11), (12, 10), (12, 9), (12, 8)]
```

**Pensamiento:**

The green's path: 8 DOWN then 4 LEFT. But I must also check the other pieces (W at (8,3), blue) don't block. W at (8,3) is far left (cols 3-5) — the green's path at rows 4-12, cols 8-12 → no conflict. Blue at (16,16) or its target (14,12): the green's path passes (12,12),(12,11),(12,10),(12,9),(12,8) — the blue's target at (14,12) occupies rows 14-16, cols 12-14 → no overlap with row 12 ✓.
But careful: the green's body/tips along the path vs the blue's target cells — checked by the full simulation.
Now let me rebuild the plan with the corrected path search (using free_positions + conn), for the order blue → green → white. Let me rewrite build_plan using the corrected helpers.

```python
def build_plan3(state, targets, order):
    import copy
    st=copy.deepcopy(state); plan=[]
    for name in order:
        rt,pp=targets[name]
        R,C=real_cell(name, st[name]['rot'], st[name]['pos'])
        plan.append({'action':'MOUSE','row':R,'col':C})
        nr=(rt-st[name]['rot'])%4
        plan += ['SPACE']*nr
        st[name]['rot']=(st[name]['rot']+nr)%4
        # blockers = all other pieces at current state
        bb=set(); bt=set()
        for k in st:
            if k==name: continue
            b,t=cells_of_state(st,k)
            bb|={x[1:] for x in b}; bt|={x[1:] for x in t}
        free=free_positions(name,rt,bb,bt)
        # path must also be valid for intermediate rotations (rot fixed here)
        path=conn(free, st[name]['pos'], pp)
        if path is None: print
… [704 caracteres más]
```

```text
NO PATH N
plan len None
None
final state None
```

**Pensamiento:**

Still no path for N. Why? Because in build_plan3 I compute `free=free_positions(name, rt, bb, bt)` where bb/bt include the W piece at (8,3) and the blue at its target. But also — the free_positions for the green uses rot=rt=0 ✓. Hmm, but the path found above worked with only the yellow blocking. Let me check what's blocking now: possibly the W piece at (8,3)?? Its cells: rows 8-13, cols 3-5. The green's path at cols 8-12 — no overlap. Hmm, but free_positions checks the green's BODY against blockers' bodies AND tips; the green's TIPS against blockers' bodies. The green's path position (12,9): its tips at (12,10)... hmm the W's tips are at (11,5)? and (13,4)? Let me compute the W piece at (8,3): tips local (3,2),(5,1) → (11,5),(13,4). The green's body at (12,8): cells... local body (6,0),(6,1),(6,2),(6,3) → (18,8),(18,9),(18,10),(18,11); (0..5,3) → (12,11)...(17,11). So the green's body includes (12,11)...(17,11) — no W cells (cols 3-5) ✓.
Hmm so why no path? Maybe the issue is the blue at its target (14,12) rot 3: its cells rows 14-16, cols 12-14. The green's path passes through (12,12): the green's body at (12,12) includes cells (12,15)...(17,15)? no: local body col 3 → col 15, rows 12-17 → (12,15)...(17,15); and the bottom bar rows 18, cols 12-15. The blue's target cells: rows 14-16 cols 12-14 → overlap with the green's body at (14,12)? The green's body at (12,12): local (6,0)→(18,12), (6,1)→(18,13), (6,2)→(18,14), (6,3)→(18,15), and (0,3)→(12,15),(1,3)→(13,15),... So no ove
… [775 caracteres más]

```python
for order in [['N','b','W'],['N','W','b'],['b','N','W'],['W','N','b'],['W','b','N'],['b','W','N']]:
    state={'W':{'rot':0,'pos':(8,3)},'N':{'rot':0,'pos':(4,12)},'Y':{'rot':0,'pos':(11,4)},'b':{'rot':0,'pos':(16,16)}}
    targets={'b':(3,(14,12)),'N':(0,(12,8)),'W':(0,(9,3))}
    plan,st=build_plan3(state,targets,order)
    print(order, 'OK' if plan else 'FAIL', len(plan) if plan else 0)
    if plan:
        print(plan); break
```

```text
['N', 'b', 'W'] OK 25
[{'action': 'MOUSE', 'row': 29, 'col': 47}, 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'LEFT', 'LEFT', 'LEFT', 'LEFT', {'action': 'MOUSE', 'row': 56, 'col': 50}, 'SPACE', 'SPACE', 'SPACE', 'UP', 'UP', 'LEFT', 'LEFT', 'LEFT', 'LEFT', {'action': 'MOUSE', 'row
… [26 caracteres más]
```

## Paso 10 · nivel 2 · acción 43

**Pensamiento:**

A 25-action plan. Let me execute it in stages with verification. First stage: click the green and move it (8 DOWN, 4 LEFT). Let me verify the click target: MOUSE(row=29,col=47) — the green's body: the green is at super (4,12) → real rows 14-34, cols 38-52. The vertical bar is at local col 3 → super col 15 → real cols 47-49 ✓ row 29 is within the bar ✓. Good.
But wait — one concern: does clicking on a piece while another is active cause any issue? Earlier clicks worked fine.
Another concern: the green moving DOWN 8 times: does it stay within the board? The green's bbox rows 14-34 → +24 → rows 38-58 ✓ (max 63).
Also: does the green's path pass over the yellow's tip cells with its BODY? The free_positions check ensures the body doesn't touch blockers' bodies or tips ✓.
Let me execute the first stage (12 actions: click + 8 DOWN + 4 LEFT) and verify.
Actually, let me be a bit careful about the risk that a blocked move (piece can't move because another piece is in the way) might do nothing — that's recoverable. Let me execute stage by stage with verification.
Stage 1: MOUSE(29,47), DOWN×8, LEFT×4 → then verify the green is at super (12,8).

```python
r=action([{'action':'MOUSE','row':29,'col':47}]+['DOWN']*8+['LEFT']*4)
print({k:v for k,v in r.items() if k in ('no_op','gameplay_changed','level_completed','game_over','stop_reason','executed','skipped')})
S=cur_state(current_frame)
for k,v in S.items(): print(k,v['pos'],len(v['body']),len(v['tips']))
```

```text
[action] batch of 13 actions, 13 executed: MOUSE(row=29, col=47), DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, LEFT, LEFT, LEFT, LEFT
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
W (8, 3) 10 2
Y (11, 4) 18 3
b (16, 16) 5 2
```

## Paso 11 · nivel 2 · acción 47

**Pensamiento:**

Excellent progress! The green moved to its target and two tips connected (gray at (41,26) and (53,26)) — the green's tips paired with the yellow's tips. The white plug became purple (inactive) since the green is now active.
Note cur_state shows only W, Y, b — the green is white now (rendered W) and merged with... hmm, cur_state lists 'W' (8,3) [the purple plug], 'Y' (11,4) with 3 tips, 'b' (16,16). The green (now white/active) isn't listed separately because both the plug and the green are... The plug is purple 'p' → mapped to 'W', and the green is 'N'→ no, the green is now the active piece so it's rendered 'W' too. Both are 'W' → my pieces2 dict keyed by color keeps only one component (the last one). Hmm, the dict `bodies[col]=comp` overwrites; both W components (plug 90 + green 90) → only one kept. In cur_state output, 'W' shows pos (8,3) with 10 body → that's the plug. The green isn't tracked. That's fine — I know where the green is (12,8).
Wait, but the diff image shows the green's ORIGINAL position as changed (orange = background) and the new position white. Yes, the green moved.
Also interesting: the gray tips confirm tip-pairing works as expected (2 gray pairs so far: (41,26)/(12,8)... let me not worry).
Now stage 2: the blue: MOUSE(56,50), SPACE×3, UP, UP, LEFT×4.
Let me check the blue's current position: super (16,16) → real rows 50-58, cols 50-58. Click (56,50): that's the bottom bar ✓ blue.
The rotation: 3 CW. Let me do it in one batch and verify the shape after.
R
… [135 caracteres más]

```python
r=action([{'action':'MOUSE','row':56,'col':50},'SPACE','SPACE','SPACE'])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over')})
G=grid2(current_frame)
# print blue bbox
cs={(r_,c_) for r_ in range(40,64) for c_ in range(40,64) if G[r_][c_]=='b'}
print('blue cells n',len(cs),'bbox',min(x[0] for x in cs),max(x[0] for x in cs),min(x[1] for x in cs),max(x[1] for x in cs))
for rr in range(min(x[0] for x in cs),max(x[0] for x in cs)+1):
    print(''.join(G[rr][cc] for cc in range(min(x[1] for x in cs),max(x[1] for x in cs)+1)))
```

```text
[action] batch of 4 actions, 4 executed: MOUSE(row=56, col=50), SPACE, SPACE, SPACE
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True}

error:
Traceback (most recent call last):
  File "<python_tool>", line 6, in <module>
ValueError: min() iterable argument is
… [6 caracteres más]
```

## Paso 12 · nivel 2 · acción 53

**Pensamiento:**

The blue piece is now white (active) and rotated. The image shows the blue piece (now white) at the bottom right with a shape like:
```
.##
.##   (with a red tip on the left at (50,50)? and (56,50) red)
###
```
Hmm, the diff image shows the rotated piece. Let me get the exact cells: the blue is now 'W' (active) at the bottom right. Let me find the white component in the bottom-right region and determine its shape/rotation.
Also note: the green reverted to green (inactive) ✓.
Let me analyze the current bottom-right white shape and match it to a rotation index.

```python
G=grid2(current_frame)
cs={(r,c) for r in range(44,64) for c in range(44,64) if G[r][c]=='W'}
print('n',len(cs),'bbox',min(x[0] for x in cs),max(x[0] for x in cs),min(x[1] for x in cs),max(x[1] for x in cs))
r0,c0=min(x[0] for x in cs),min(x[1] for x in cs)
for rr in range(r0,max(x[0] for x in cs)+1):
    print(''.join(G[rr][cc] for cc in range(c0,max(x[1] for x in cs)+1)))
red={(r,c) for r in range(44,64) for c in range(44,64) if G[r][c]=='R'}
print('red',sorted(red))
# which rotation of blue body does this correspond to (in super coords)?
sb={((r-2)//3,(c-2)//3) for r,c in cs}
rmin=min(x[0] for x in sb); cmin=min(x[1] for x in sb)
sb=frozenset((r-rmin,c-cmin) for r,c in sb)
print('super body',sorted(sb),'anchor super',(rmin,cmin))
for i,v in enumerate(all_variants2(PIECES_DATA()['b'])):

… [26 caracteres más]
```

```text
n 45 bbox 50 58 53 58
WWWWWW
WWWWWW
WWWWWW
OOOWWW
OOOWWW
OOOWWW
WWWWWW
WWWWWW
WWWWWW
red [(50, 50), (50, 51), (50, 52), (51, 50), (51, 51), (51, 52), (52, 50), (52, 51), (52, 52), (56, 50), (56, 51), (56, 52), (57, 50), (57, 51), (57, 52), (58, 50), (58, 51), (58, 52)]
super body [(0, 0), (0, 1), (1
… [215 caracteres más]
```

**Pensamiento:**

The blue piece's body in super coords (normalized) = [(0,0),(0,1),(1,1),(2,0),(2,1)] — that doesn't match any of the 4 variants! Variant 1 = [(0,0),(0,1),(1,0),(2,0),(2,1)]. Hmm, mine has (1,1) instead of (1,0).
Hmm, wait. My extraction: the white bbox is rows 50-58, cols 53-58. But the piece's bbox should include the tips: the red tips are at (50,50)-(52,52) and (56,50)-(58,52) → cols 50-52, so the combined bbox is cols 50-58 → super cols 16-18. The body's normalized super coords used only the body's own min → (16,17). So the body's position relative to the combined bbox: body super rows 16-18, cols 17-18... 
Hmm, the body cells in super: rows (50-2)/3=16, 17, 18; cols (53-2)/3=17, 18. So body super cells = {(16,17),(16,18),(17,18),(18,17),(18,18)}. Normalized: {(0,0),(0,1),(1,1),(2,0),(2,1)} ✓ as printed.
The combined bbox top-left in super = (16,16) (rows 50-58 → 16,17,18; cols 50-58 → 16,17,18). So the body relative to the bbox = {(0,1),(0,2),(1,2),(2,1),(2,2)} = variant 3 ✓✓. 
So the blue is at rot 3, pos (16,16) — exactly as the plan assumed. The tips are at super (16,16) and (18,16) → variant 3's tips: from the rotation of [(0,0),(0,2)] → let me trust it.
Now continue: UP, UP, LEFT, LEFT, LEFT, LEFT → target (14,12).
Wait, the plan said: 'UP','UP','LEFT','LEFT','LEFT','LEFT' ✓.
Let me execute and then the final W: MOUSE(32,11), DOWN.
Actually the plan's W click was MOUSE(row=32,col=11) — the plug is at super (8,3) → real rows 26-43, cols 11-19. Row 32, col 11 is a body
… [64 caracteres más]

```python
r=action(['UP','UP','LEFT','LEFT','LEFT','LEFT'])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over')})
G=grid2(current_frame)
cs={(rr,cc) for rr in range(38,60) for cc in range(30,52) if G[rr][cc]=='W'}
if cs:
    print('white(active) bbox',min(x[0] for x in cs),max(x[0] for x in cs),min(x[1] for x in cs),max(x[1] for x in cs),'n',len(cs))
red={(rr,cc) for rr in range(38,60) for cc in range(30,52) if G[rr][cc]=='R'}
print('reds',sorted(red))
gray={(rr,cc) for rr in range(38,60) for cc in range(30,52) if G[rr][cc]=='G'}
print('grays',sorted(gray))
```

```text
[action] batch of 6 actions, 6 executed: UP, UP, LEFT, LEFT, LEFT, LEFT
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True}
white(active) bbox 44 52 41 46 n 45
reds []
grays [(38, 32), (38, 33), (38, 34), (39, 32), (39, 33), (39, 34), (40, 32), (40, 33), (40, 3
… [183 caracteres más]
```

**Nivel 2 completado → nivel 3 (acción 55)**

## Paso 13 · nivel 3 · acción 55

**Pensamiento:**

Excellent! The blue piece connected to the green: two gray joints appeared at (44,38)-(46,40) and (50,38)-(52,40). The blue's bbox is now rows 44-52, cols 41-46 → super ((44-2)/3, (41-2)/3) = (14, 13). Hmm, the target was (14,12). The bbox includes tips: the blue's tips at rot 3 are at local... The combined bbox top-left = (14,13)? Let me check: real rows 44-52 → super rows 14,15,16; cols 41-46 → super cols 13,14. Hmm, that's only 2 cols wide — because the tips are now GRAY (connected), so the white body's bbox is cols 41-46 = 2 super cols, and the gray tips extend to col 38-40 = super col 12 ✓. So the combined bbox (body + tips, where tips are now gray) starts at super col 12 ✓ = target (14,12) ✓.
The gray joints are at (44,38) and (50,38) = super (14,12) and (16,12) ✓ exactly the blue's tips at the target position, now connected to the green's tips.
So 4 connections are made so far (2 green-yellow, 2 blue-green). 
Now the final step: click the plug and press DOWN. The plug is at super (8,3) → target (9,3).
The plug's real body: rows 26-43, cols 11-19. Click (32,11) ✓.
Let me do it: MOUSE(32,11), DOWN.
Then check for level completion.

```python
r=action([{'action':'MOUSE','row':32,'col':11},'DOWN'])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','run_complete','done','stop_reason')})
G=grid2(current_frame)
gray=[(rr,cc) for rr in range(64) for cc in range(64) if G[rr][cc]=='G']
red=[(rr,cc) for rr in range(64) for cc in range(64) if G[rr][cc]=='R']
print('gray cells',len(gray),'red cells',len(red))
print('red sample',sorted(red)[:12])
```

```text
[action] batch of 2 actions, 2 executed: MOUSE(row=32, col=11), DOWN | stop_reason: level_completed
{'executed': True, 'done': False, 'level_completed': True, 'game_over': False, 'run_complete': False, 'gameplay_changed': True, 'stop_reason': 'level_completed'}
gray cells 0 red cells 18
red sample [
… [119 caracteres más]
```

## Paso 14 · nivel 3 · acción 55

**Pensamiento:**

Level 3! The board shows:
- A green piece (top-left) with 2 red tips.
- A dark gray/charcoal piece (top-right) shaped like a long bar with a hook.
- Another dark gray piece (bottom-middle), larger, with a hook shape.
Wait, two dark pieces? Let me look: top-right is a dark horizontal bar with an upturned end (like a "J" rotated). Bottom-middle is a larger dark shape.
Hmm, and the background is orange. The white piece from before is gone; now there are dark gray ('G' or 'c') pieces.
Let me inspect the board via segmentation.
Note: the active piece is white in previous levels; here no white piece → maybe no piece is active yet? Or the active piece is rendered white but there is none... Hmm, in level 2 the initial state had a white piece (the plug). Here nothing is white → maybe the initial active piece is one of the dark ones rendered in its own color? Or maybe this level has different colors: pieces are dark gray, and the "active" one is... hmm.
Let me analyze the board structure first.

```python
f=current_frame
print('level',f.level,'step',f.step,'shape',f.shape)
for n in f.segmentation['nodes']:
    print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1],'rot',n['rotation'],'sym',n['rotational_symmetry'])
print('adj',f.segmentation['adjacency_list'])
G=grid2(f)
from collections import Counter
print(Counter(v for row in G for v in row))
```

```text
level 3 step 55 shape (64, 64)
0 O 3605 [0, 0] [63, 0] rot 0 sym 1
1 c 32 [0, 16] [0, 47] rot 90 sym 2
2 c 63 [11, 47] [13, 47] rot 180 sym 1
3 N 117 [14, 14] [19, 14] rot 180 sym 1
4 R 9 [14, 20] [16, 20] rot None sym 4
5 c 198 [29, 32] [31, 32] rot 180 sym 1
6 R 9 [32, 20] [34, 20] rot None sym 4

… [163 caracteres más]
```

**Pensamiento:**

Level 3 board:
- node 1: 'c' 32 px at row 0 → HUD bar (top).
- node 2: 'c' 63 px — the top-right dark piece (bbox rows 11-17?).
- node 3: 'N' 117 px — the green piece.
- node 4, 6: red tips (9 px each) adjacent to the green.
- node 5: 'c' 198 px — the big dark piece at rows 29-...
- node 7: 'O' 63 px enclosed inside node 5 → a hole in the big dark piece (orange region enclosed).
So there are 3 pieces: green (117), dark small (63), dark big (198 with a hole).
Interesting: two pieces have the SAME color 'c' (dark gray). In level 2 each piece had a distinct color. Here two pieces share the color, so color alone doesn't identify them.
Also, no piece is white → so which is active? Maybe none is active and clicking selects. Let me test clicking.
Wait, in level 2 the initial state had the white plug = active. Here nothing is white. Maybe the active piece is highlighted differently, or maybe clicking is needed to activate.
Hmm, also the tips: only 2 red tips (both on the green). So the dark pieces have NO tips? That's odd. Unless the dark pieces' "tips" are the hook shapes at their ends (the little upturned ends are part of the body).
Let me get the exact shapes. Let me print each piece's cells as ASCII (they're small enough).
Also the pieces are 1-cell thick (thin lines), unlike level 2's 3x3 blocks. Let me check: node 2 'c' 63 px: the image shows a bar of height 3 cells? Let me print.

```python
G=grid2(current_frame)
def show_region(r0,r1,c0,c1,tag):
    print('---',tag)
    for r in range(r0,r1+1):
        print('%2d'%r, ''.join(G[r][c] for c in range(c0,c1+1)))
show_region(9,19,30,52,'dark small (node2)')
show_region(27,52,28,52,'dark big (node5)')
show_region(12,36,6,24,'green (node3)')
```

```text
--- dark small (node2)
 9 OOOOOOOOOOOOOOOOOOOOOOO
10 OOOOOOOOOOOOOOOOOOOOOOO
11 OOOOOOOOOOOOOOOOOcccOOO
12 OOOOOOOOOOOOOOOOOcccOOO
13 OOOOOOOOOOOOOOOOOcccOOO
14 OOccccccccccccccccccOOO
15 OOccccccccccccccccccOOO
16 OOccccccccccccccccccOOO
17 OOOOOOOOOOOOOOOOOOOOOOO
18 OOOOOOOOOOOOOOOOOOOOOOO
19 OOOO
… [1387 caracteres más]
```

**Pensamiento:**

Now I see the level 3 structure. Everything is built from 3x3 blocks (super-cells) again:
- Green piece: a snake/staircase shape with 2 red tips (at the right end of the top arm and the right end of the bottom arm).
- Dark small: an L-shaped piece (long horizontal bar with an upturned right end).
- Dark big: a complex shape with a hole and two "prongs" (a comb-like structure with two teeth at the top: cols 2-4 and cols 9-11 going up, and a hook at the bottom right).
The goal is presumably the same: assemble all pieces into a connected assembly by pairing all tips. But there are only 2 red tips (both on the green piece). So the green's 2 tips must connect to... the dark pieces' ends? But the dark pieces have no red tips.
Hmm! Maybe the dark pieces' "sockets" are the ends of their arms (no red tip needed). In level 2, tips paired tip-to-tip (red+red → gray). Here maybe the green's tips plug into notches in the dark pieces.
Wait — maybe the dark pieces are the "socket" pieces (in level 1, there was a socket piece with red tips). Hmm, in level 1 the socket had red tips too.
Alternatively, maybe the two dark pieces are OBSTACLES/walls (fixed), and the goal is to move the green piece into a target position/shape? Hmm.
Let me think about the structure: the dark big piece has a hole (node 7 'O' 63 px enclosed = 7 super-cells). The dark big piece looks like a "frame with teeth". 
Let me convert to super-coords and see the shapes as polyominoes on the 3x3 lattice. Also note the pieces'
… [1140 caracteres más]

```python
def supshapes(f):
    G=grid2(f)
    from collections import defaultdict
    def comp(pred):
        R=len(G);C=len(G[0]);seen=[[False]*C for _ in range(R)];out=[]
        for r in range(R):
            for c in range(C):
                if pred(G[r][c]) and not seen[r][c]:
                    st=[(r,c)];seen[r][c]=True;cc=[]
                    while st:
                        x=st.pop();cc.append(x)
                        for d in ((1,0),(-1,0),(0,1),(0,-1)):
                            y=(x[0]+d[0],x[1]+d[1])
                            if 0<=y[0]<R and 0<=y[1]<C and not seen[y[0]][y[1]] and pred(G[y[0]][y[1]]):
                                seen[y[0]][y[1]]=True;st.append(y)
                    out.append(set(cc))
        return out
    shapes={}
    for col in ('N','c','W','p','Y'
… [733 caracteres más]
```

```text
== ('N', 117) pos (4, 2) 7 x 4
    ..##
    ..#.
    ###.
    #...
    ###.
    ..#.
    ..##
== ('c', 63) pos (3, 10) 2 x 6
    .....#
    ######
== ('c', 198) pos (9, 9) 7 x 7
    .#.....
    ###....
    #.#....
    #.#....
    #.####.
    #....##
    ######.
red tips super [(4, 6), (10, 6)]
```

## Paso 14 · nivel 3 · acción 56

**Pensamiento:**

Level 3 pieces (super coords):
Green (pos (4,2)), 7x4:
```
..##
..#.
###.
#...
###.
..#.
..##
```
Tips at super (4,6) and (10,6) — relative to the green's pos (4,2): tips local (0,4) and (6,4). So the green's tips extend right from the top-right arm and the bottom-right arm.
Dark small (pos (3,10)), 2x6:
```
.....#
######
```
Dark big (pos (9,9)), 7x7:
```
.#.....
###....
#.#....
#.#....
#.####.
#....##
######.
```
Interesting: the dark big shape has a "notch" pattern similar to the green's zigzag! Look at the green:
```
..##
..#.
###.
#...
###.
..#.
..##
```
and the dark big's left part:
```
.#...
###..
#.#..
#.#..
#.###   hmm
```
Actually the dark big's left column structure: col 0 is filled rows 1-6; col 1 filled rows 1, 4; col 2 filled rows 1, 4... 
Let me look at the dark big more carefully:
```
row0: .#.....
row1: ###....
row2: #.#....
row3: #.#....
row4: #.####.
row5: #....##
row6: ######.
```
Hmm, and the green:
```
row0: ..##
row1: ..#.
row2: ###.
row3: #...
row4: ###.
row5: ..#.
row6: ..##
```
The green looks like it could fit INTO the dark big's notch. The dark big has a channel: col 0 (rows 1-6) and col 1-2 gaps...
Actually consider: the green's shape complement within the dark big's "hole"? The dark big's hole (the enclosed orange region) is at super rows 11-13, cols 11-13 (7 cells: from node 7 'O' 63 px = 7 super cells).
Let me get the hole's shape: rows 35-43 real → super 11-13; cols 14-19 real → super 4-5. Wait, from the printout of the dark big region: rows 3
… [6071 caracteres más]

```python
r=action([{'action':'MOUSE','row':21,'col':3}])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','no_op')})
G=grid2(current_frame)
from collections import Counter
print(Counter(v for row in G for v in row))
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] MOUSE(row=21, col=3) -> NO-OP (executed, no change inside the board area)
{'executed': True, 'level_completed': False, 'gameplay_changed': False, 'no_op': True}
Counter({'O': 3668, 'c': 293, 'N': 117, 'R': 18})
0 O 3605 [0, 0]
1 c 32 [0, 16]
2 c 63 [11, 47]
3 N 117 [14, 14]
4 R 9 [14, 20]
5
… [46 caracteres más]
```

## Paso 15 · nivel 3 · acción 57

**Pensamiento:**

MOUSE(21,3) was a NO-OP. Row 21 col 3 — the green's body at rows 20-22 spans super cols 2-3 → real cols 8-13. Col 3 is orange (outside the green). My mistake: the green's pos is (4,2) → real cols 3*2+2 = 8. So the green's body is at cols 8-19, not 2-9.
Let me click on the green at (21,10) and check whether it turns white.

```python
r=action([{'action':'MOUSE','row':21,'col':10}])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','no_op')})
from collections import Counter
G=grid2(current_frame)
print(Counter(v for row in G for v in row))
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] MOUSE(row=21, col=10) -> effect
{'executed': True, 'level_completed': False, 'gameplay_changed': True, 'no_op': False}
Counter({'O': 3668, 'c': 427, 'W': 1})
0 O 3605 [0, 0]
1 W 1 [0, 16]
2 c 31 [0, 17]
3 c 63 [11, 47]
4 c 135 [14, 14]
5 c 198 [29, 32]
6 O 63 [35, 32]
```

## Paso 16 · nivel 3 · acción 58

**Pensamiento:**

Whoa! Clicking the green piece turned it DARK GRAY ('c' 135) and its red tips disappeared! Now all three pieces are 'c'. The HUD bar also changed (node 1 W 1 + node 2 c 31 → the bar shrank by 1 px? that's the timer).
So clicking the green made it... "inactive"? In level 2, clicking a piece made it the active (white) piece. Here clicking made the green dark gray and removed its red tips!
Hmm wait. Maybe the green piece is now "activated" and rendered in the same dark color as the others (all pieces are dark gray = the "inactive" color?). And the tips disappeared — that's concerning. Did clicking DELETE the tips?
Look: before: N 117 + R 18 (tips). After: c 135 = 117 + 18 = 135 ✓. So the tips became dark gray, i.e., the whole piece (body + tips) is now dark gray.
So the piece's color changed from green+red tips to all-dark. This is like the "color swap" mechanic: the active piece is rendered... hmm, in level 2 the active piece was white.
Maybe here, clicking "collects"/"absorbs" the piece? Or maybe clicking cycles the piece's color?
Let me click again on the same piece and see what happens.

```python
r=action([{'action':'MOUSE','row':21,'col':10}])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','no_op')})
from collections import Counter
print(Counter(v for row in grid2(current_frame) for v in row))
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] MOUSE(row=21, col=10) -> effect
{'executed': True, 'level_completed': False, 'gameplay_changed': True, 'no_op': False}
Counter({'O': 3668, 'c': 292, 'N': 117, 'R': 18, 'W': 1})
0 O 3605 [0, 0]
1 W 1 [0, 16]
2 c 31 [0, 17]
3 c 63 [11, 47]
4 N 117 [14, 14]
5 R 9 [14, 20]
6 c 198 [29, 32]
7 R 
… [26 caracteres más]
```

## Paso 17 · nivel 3 · acción 59

**Pensamiento:**

Clicking again restored the green + red tips. So clicking the green toggles its appearance: green+red tips ↔ all dark gray. That's odd. 
Interpretation: In level 2, clicking a piece made it ACTIVE (white). Here the pieces are all dark gray 'c' by default, and the green piece is... hmm.
Alternative interpretation: the pieces have two visual states — "free" (colored, with red tips shown) and "locked/immovable" (dark). Clicking toggles?? That seems weird.
Wait. Maybe the toggle is about the SELECTION: the selected piece is highlighted in its color (green with red tips) and unselected pieces are dark gray. Initially the green was "selected" (highlighted). Clicking it deselected it (all dark). Clicking again re-selected it.
So the selection is shown by COLOR (green) rather than white. And the dark gray pieces are unselected. That's consistent with level 2 where the selected piece was white and the others colored... hmm, not consistent (level 2: inactive pieces kept their own colors: green, yellow, blue; the active one was white).
But here, all pieces might have the same base color (dark gray), and the selected one is shown in green with red tips?! Hmm, but then the red tips are part of the highlight (showing the tips of the selected piece).
Let me test: click on the dark small piece (e.g., row 15, col 40) and see if it turns green with red tips while the green piece turns dark.
That would confirm: the "selected" piece is shown in green with red tips at its connection ends, and the
… [45 caracteres más]

```python
r=action([{'action':'MOUSE','row':15,'col':40}])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','no_op')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] MOUSE(row=15, col=40) -> effect
{'executed': True, 'gameplay_changed': True, 'no_op': False}
0 O 3605 [0, 0]
1 W 1 [0, 16]
2 c 31 [0, 17]
3 R 9 [11, 47]
4 c 135 [14, 14]
5 R 9 [14, 32]
6 Y 45 [14, 35]
7 c 198 [29, 32]
8 O 63 [35, 32]
```

## Paso 18 · nivel 3 · acción 60

**Pensamiento:**

Now the picture is clear: clicking a piece SELECTS it — the selected piece is rendered in a highlight color (green or yellow — apparently a per-piece color) with its tips shown in RED, and unselected pieces are dark gray.
The dark small piece (now selected) is yellow with 2 red tips: at (11,47)-(13,49) [the hook end] and (14,32)-(16,34) [the left end]. So the dark small piece's tips are its two ends!
Wait: node 3 R 9 at [11,47] = the hook block (row 0 col 5 in local super coords), node 5 R 9 at [14,32] = the left end (row 1 col 0). And the yellow body 45 px = 5 super cells. Total 7 ✓ (matches the 2x6 shape: 6 body + ... hmm: shape was
```
.....#
######
```
= 7 cells. With 2 tips (the hook and the left end) → body = 5 ✓.
So each piece has 2 tips (its ends). The green piece had 2 tips too. So the goal is to connect the pieces end-to-end: 3 pieces → the tips must pair up... but 3 pieces × 2 tips = 6 tips → 3 pairs. With 3 pieces in a chain, only 2 pairs can form (each connection uses 2 tips), leaving 2 tips free. Unless the pieces form a closed LOOP: 3 pieces in a ring → 3 connections, all 6 tips paired ✓.
So the goal: arrange the 3 pieces into a closed loop (all tips paired). That's a nice puzzle!
Now, the third piece (dark big, 198 px = 22 cells) — its tips are hidden while unselected. Let me click it to see its tips.
Then solve the loop puzzle.
Let me click the dark big piece: e.g., row 47, col 35 (its bottom bar).

```python
r=action([{'action':'MOUSE','row':47,'col':35}])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','no_op')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
G=grid2(current_frame)
red=[(rr,cc) for rr in range(64) for cc in range(64) if G[rr][cc]=='R']
print('red cells',sorted(red))
```

```text
[action] MOUSE(row=47, col=35) -> effect
{'executed': True, 'gameplay_changed': True, 'no_op': False}
0 O 3605 [0, 0] [63, 0]
1 W 1 [0, 16] [0, 16]
2 c 31 [0, 17] [0, 47]
3 c 63 [11, 47] [13, 47]
4 c 135 [14, 14] [19, 14]
5 R 9 [29, 32] [31, 32]
6 p 180 [32, 29] [49, 29]
7 O 63 [35, 32] [46, 32]
8 R
… [211 caracteres más]
```

## Paso 19 · nivel 3 · acción 66

**Pensamiento:**

The dark big piece is purple when selected, with 2 red tips:
- Tip at (29,32)-(31,34) = super (9,10) → local (0,1) — the top prong.
- Tip at (44,47)-(46,49) = super (14,15) → local (5,6) — the right hook end.
Body 180 px = 20 cells, tips 2 → total 22 ✓.
So the three pieces:
- Green (G): shape 7x4, tips at local (0,4) and (6,4) [relative to the combined bbox at super (4,2)]. Body:
```
..##
..#.
###.
#...
###.
..#.
..##
```
tips at (0,4),(6,4) (just outside the 4-wide body → the combined bbox is 7x5 with tips at col 4).
Hmm, earlier supshapes gave the green body pos (4,2) with 7x4 shape and tips at super (4,6),(10,6) → relative to pos (4,2): (0,4),(6,4) ✓.
- Yellow (Y): body 2x6: `.....#` / `######`, tips at local (0,5) and (1,0). So combined bbox 2x6: body = the 5 cells of the bottom row minus... hmm: body 5 cells: (1,0),(1,1),(1,2),(1,3),(1,4) and tips (0,5),(1,5)? Let me recompute: the piece's super cells: rows 11-16 → super 3-4; cols 32-49 → super 10-15. Body cells from the earlier print:
```
row 11-13: cols 47-49 → super (3,15)
row 14-16: cols 32-48 → super (4,10),(4,11),(4,12),(4,13),(4,14)
```
Wait, the earlier print (9-19, 30-52) showed:
row 11: 'ccc' at cols 47-49
row 14-16: 'cccccccccccccccc' at cols 32-48 (17 cols? that's 32-48 = 17 cells, hmm, should be 18 for 6 super cols). Let me not worry.
Now with the selection: red tips at (11,47) = super (3,15) and (14,32) = super (4,10). Body = 45 px = 5 super cells: (3,15)? no that's a tip. Body: (4,10),(4,11),(4,12),(4,13),
… [4395 caracteres más]

```python
def bbox_of(f, color):
    G=grid2(f)
    cs={(r,c) for r in range(3,64) for c in range(64) if G[r][c]==color}
    if not cs: return None,0
    return (min(x[0] for x in cs),min(x[1] for x in cs),max(x[0] for x in cs),max(x[1] for x in cs)),len(cs)
print('before',bbox_of(current_frame,'p'))
r=action(['LEFT']); print('after LEFT',bbox_of(current_frame,'p'), {k:v for k,v in r.items() if k in ('no_op','gameplay_changed')})
r=action(['RIGHT']); print('after RIGHT',bbox_of(current_frame,'p'))
for i in range(4):
    r=action(['SPACE']); print('after SPACE',i+1,bbox_of(current_frame,'p'))
```

```text
before ((32, 29, 49, 46), 180)
[action] LEFT -> effect
after LEFT ((32, 26, 49, 43), 180) {'gameplay_changed': True, 'no_op': False}
[action] RIGHT -> effect
after RIGHT ((32, 29, 49, 46), 180)
[action] SPACE -> effect
after SPACE 1 ((29, 29, 46, 46), 180)
[action] SPACE -> effect
after SPACE 2 ((29
… [145 caracteres más]
```

## Paso 20 · nivel 3 · acción 66

**Pensamiento:**

Confirmed:
- LEFT/RIGHT move by 3 cells (1 super unit) ✓
- SPACE rotates CW about the bbox top-left: the purple's body bbox before was (32,29)-(49,46); after 1 SPACE: (29,29)-(46,46). Hmm, the body bbox changed from rows 32-49 to 29-46 — the bbox top-left moved up by 3.
Careful: the rotation anchor is the COMBINED bbox (body + tips) top-left, not the body bbox. The combined bbox before rotation: body (32,29)-(49,46) plus tips at (29,32) and (44,47)-(46,49) → combined rows 29-49, cols 29-49 (21x21 = 7x7 super ✓). After 1 CW rotation: the combined bbox should stay at rows 29-49, cols 29-49 (since it's square 7x7). The body bbox after 1 SPACE: (29,29)-(46,46) ✓ plausible.
After 2 SPACE: body (29,32)-(46,49) ✓; after 3: (32,32)-(49,49); after 4: back to (32,29)-(49,46) ✓. Great — same rotation rule as level 2 (rotate about the combined bbox top-left, dims swap).
So the mechanics are identical to level 2. Now solve the loop assembly.
Piece data (super coords, local, with combined bbox):
Green: combined bbox 7x5 (body 7x4 + tips at col 4). Body:
(0,2),(0,3)
(1,2)
(2,0),(2,1),(2,2)
(3,0)
(4,0),(4,1),(4,2)
(5,2)
(6,2),(6,3)
Tips: (0,4),(6,4)
Yellow: combined bbox 2x6: body (1,1),(1,2),(1,3),(1,4),(1,5) + (0,5); tips (1,0),(0,5)?? 
Hmm wait, I need to be careful about which cells are tips. From the observation: red at (11,47) = super (3,15) and (14,32) = super (4,10). The yellow body (45px=5 cells): let me determine exactly. The dark piece's full extent: rows 11-16 (super 3-4), cols 3
… [1049 caracteres más]

```python
def L3():
    return {
 'G':{'body':[(0,2),(0,3),(1,2),(2,0),(2,1),(2,2),(3,0),(4,0),(4,1),(4,2),(5,2),(6,2),(6,3)],
      'tips':[(0,4),(6,4)],'pos':(4,2),'H':7,'W':5},
 'Y':{'body':[(1,1),(1,2),(1,3),(1,4),(1,5)],'tips':[(0,5),(1,0)],'pos':(3,10),'H':2,'W':6},
 'P':{'body':[(1,0),(1,1),(1,2),(2,0),(2,2),(3,0),(3,2),(4,0),(4,2),(4,3),(4,4),(4,5),(5,0),(5,5),(6,0),(6,1),(6,2),(6,3),(6,4),(6,5)],
      'tips':[(0,1),(5,6)],'pos':(9,9),'H':7,'W':7}}
def L3V():
    P=L3(); out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.append((i,frozenset(s['body']),frozenset(s['tips']),H,W))
            s,H,W=rot(s,H,W)
        out[k]=vs
    return out
def solve_loop(V, fix='P', fixrot=0, fixpos=(
… [1339 caracteres más]
```

```text
P rot 0 sols 2
   {'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (0, (8, 10))}
   {'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (2, (8, 10))}
P rot 1 sols 2
   {'P': (1, (9, 9)), 'G': (3, (15, 10)), 'Y': (1, (10, 15))}
   {'P': (1, (9, 9)), 'G': (3, (15, 10)), 'Y': (3, (10, 15))}
P rot 2 sols 2
   {'P': (2
… [239 caracteres más]
```

**Pensamiento:**

Solutions exist. For P rot 0 (no rotation of the purple needed!):
- G at rot 2, pos (8,15)
- Y at rot 0 or rot 2, pos (8,10)
Two solutions differing in the yellow's rotation (rot 0 vs rot 2 — the yellow's shape has 2-fold symmetry? Its shape: body (1,1..5) + tip (0,5),(1,0). Rotated 180: body (0,0..4)... they're different shapes (mirror-ish). Both give valid loops.
Let me render the assembly to check it looks like a sensible closed loop.
Let me print the assembly grid for solution 1 (P rot 0, G rot 2 pos (8,15), Y rot 0 pos (8,10)).

```python
def asm3(sol,V):
    grid={}
    for name,(rotk,pos) in sol.items():
        var=V[name][rotk]; r0,c0=pos
        for (r,c) in var[1]: grid[(r+r0,c+c0)]=name
        for (r,c) in var[2]: grid[(r+r0,c+c0)]=name.lower()
    R=max(r for r,_ in grid); C=max(c for _,c in grid)
    return [''.join(grid.get((r,c),'.') for c in range(C+1)) for r in range(R+1)]
V=L3V()
for sol in [{'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (0, (8, 10))},{'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (2, (8, 10))}]:
    print('---',{k:v for k,v in sol.items()})
    for L in asm3(sol,V): print('  ',L)
```

```text
--- {'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (0, (8, 10))}
   ....................
   ....................
   ....................
   ....................
   ....................
   ....................
   ....................
   ....................
   ...............yGG..
   ..........yYYYYY.G..
… [589 caracteres más]
```

## Paso 20 · nivel 3 · acción 66

**Pensamiento:**

The first solution looks like a proper closed loop: the pieces form a ring enclosing the purple's hole region... Let me verify the loop is closed: the tips pair up:
- Y's tip 'y' at (8,16)? In solution 1: row 8 shows '...............yGG..' → the 'y' at col 15 and G at 16,17. Row 9: '..........yYYYYY.G..' → 'y' at col 10 (Y's tip), Y body cols 11-15, '.' at 16, 'G' at 17.
Hmm, the lowercase letters overwrite: where a Y tip pairs with a G tip, the later-drawn piece's letter shows. So the pairing cells are correct by construction (the solver verified all tips paired).
The loop: Y's tips: (9,10) [pairs with... hmm] and (8,15)... 
Anyway, the solver guarantees all 6 tips are paired pairwise with no overlaps. 
Now, which solution to use? Both are similar; the difference is the yellow's rotation. In solution 1 (Y rot 0), the yellow keeps its current rotation (rot 0) and just moves from (3,10) to (8,10): +5 rows, 0 cols → 5 DOWN. That's minimal!
And the green: from (4,2) rot 0 → (8,15) rot 2: +4 rows, +13 cols, and 2 rotations (SPACE×2).
The purple stays at (9,9) rot 0 (no move!) — but wait, I already rotated it 4 times (back to rot 0) and moved LEFT/RIGHT (back to (9,9)) ✓ good, the purple is at its initial position and rotation.
Total plan: 
- Yellow: click, DOWN×5 → 6 actions.
- Green: click, SPACE×2, RIGHT×13, DOWN×4 → 20 actions.
Order and path validity must be checked (no collisions).
Alternatively the green could go first. Let me use the planner machinery: build a state and us
… [818 caracteres más]

```python
def cells3(V,name,rot,pos):
    var=V[name][rot]; r0,c0=pos
    return {(r+r0,c+c0) for r,c in var[1]}, {(r+r0,c+c0) for r,c in var[2]}
def check3(st):
    occ={}
    for k,v in st.items():
        b,t=cells3(L3V(),k,v['rot'],v['pos'])
        for x in b:
            if x in occ: return False,(x,occ[x],'B'+k)
            occ[x]='B'+k
        for x in t:
            if x in occ and occ[x][0]=='B': return False,(x,occ[x],'T'+k)
            occ.setdefault(x,'T'+k)
    return True,None
def plan3(st, targets, order, BR=19, BC=20):
    import copy
    V=L3V(); st=copy.deepcopy(st); plan=[]
    for name in order:
        rt,pp=targets[name]
        b,t=cells3(V,name,st[name]['rot'],st[name]['pos'])
        R,C=sorted(b)[len(b)//2]
        plan.append({'action':'MOUSE','row':3*R+2,'col':3*C+2})
  
… [1344 caracteres más]
```

```text
['Y', 'G'] -> 34
[{'action': 'MOUSE', 'row': 14, 'col': 41}, 'DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN', {'action': 'MOUSE', 'row': 23, 'col': 8}, 'SPACE', 'SPACE', 'UP', 'UP', 'UP', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'RIGHT', 'DOW
… [68 caracteres más]
```

**Pensamiento:**

A 34-action plan found for order [Y, G]. But the green's path is long and convoluted (UP×3, RIGHT×13, DOWN×7, LEFT) — 26 moves. Hmm, the path goes up and around. Total ~26 moves for the green vs. a naive 17 (13 right + 4 down). The detour is because of the purple and yellow bodies.
Wait — but there's an issue: the plan's green path ends with 'LEFT' — meaning it overshoots and comes back? That's just the BFS path shape.
Hmm, let me reconsider: maybe a different assembly solution has a shorter total path. Also, maybe I should consider the alternative yellow rotation (rot 2) which might make the green's path easier.
Also, is the budget sufficient? The HUD bar: 31 px remaining at (0,17). In level 2, the bar started at 29 px and we used ~38 actions... Let me check the bar's meaning: 1 px per action? At level 2 start the bar was 29 cells (cols 19-47?). Hmm, at level 2 step 18 the bar was 'c' 29 at (0,19) → 29 cells. We then used ~38 actions to complete level 2 (step 18 → 56). So the bar isn't 1 cell/action; more like 1 cell per ~6 actions? Actually at step 56 (level 3 start) the bar was 32 px at (0,16); now at step 67 it's 31 px at (0,17). That's 11 actions → 1 cell. Hmm, so the bar drains slowly — maybe it's a "steps" bar where each cell = ~10 actions? Whatever, it's generous.
Hmm, wait. Maybe the bar isn't a timer but a progress indicator. Either way, plenty of budget.
Let me try to optimize: search over the 8 assembly solutions (4 rotations of P × 2 yellow variants... but P's ro
… [537 caracteres más]

```python
V=L3V()
cands=[]
for fr in range(4):
    for sol in solve_loop(V,'P',fr,(9,9)):
        cands.append(sol)
best=None
for sol in cands:
    st={'G':{'rot':0,'pos':(4,2)},'Y':{'rot':0,'pos':(3,10)},'P':{'rot':0,'pos':(9,9)}}
    targets={k:(v[0],v[1]) for k,v in sol.items() if k!='P'}
    for order in [[k for k in targets]] + [[k for k in targets][::-1]]:
        p,s=plan3(st,targets,order)
        if p:
            cands_key=(len(p),str(order),str(sol))
            if best is None or len(p)<len(best[0]): best=(p,order,sol)
print('best len',len(best[0]),'order',best[1],'sol',best[2])
print(best[0])
```

```text
NO PATH G
NO PATH G
NO PATH G
NO PATH Y
NO PATH G
NO PATH G
NO PATH G
NO PATH Y
NO PATH G
NO PATH Y
NO PATH Y
NO PATH Y
NO PATH Y
NO PATH Y
best len 34 order ['Y', 'G'] sol {'P': (0, (9, 9)), 'G': (2, (8, 15)), 'Y': (0, (8, 10))}
[{'action': 'MOUSE', 'row': 14, 'col': 41}, 'DOWN', 'DOWN', 'DOWN', 'D
… [281 caracteres más]
```

## Paso 20 · nivel 3 · acción 72

**Pensamiento:**

The best plan is 34 actions with P unchanged. Most alternatives fail (no path) because the pieces get trapped.
Before executing this long plan, let me sanity check a couple of things:
1. The plan's green path: UP×3 then RIGHT×13 then DOWN... Let me verify the plan is sane by simulating it in my model and confirming the final state = the assembly.
2. The click coordinates: MOUSE(14,41) for the yellow — the yellow's body at super (4,11)-(4,15) → real rows 14-16, cols 35-49. Cell (14,41): super ((14-2)/3, (41-2)/3) = (4, 13) ✓ body.
   MOUSE(23,8) for the green: the green's body at super rows 4-10, cols 2-5 → real rows 14-34, cols 8-19. Cell (23,8): super ((23-2)/3, (23-2)/3)... row (23-2)/3 = 7, col (8-2)/3 = 2 → super (7,2) — is that a body cell? The green's local body at (7-4, 2-2) = (3,0) ✓ body.
3. Verify the plan simulation: let me re-simulate in code (my plan3 already did the collision checks and ended with check3 OK).
One risk: my assumption that the win condition is "all tips paired". In level 2, all 12 tips paired. Here, 6 tips → 3 pairs. Reasonable.
Another risk: maybe the win requires a specific shape (e.g., a closed loop is exactly what "all tips paired" gives).
Let me also double check the yellow's target: (8,10) with rot 0 → the yellow moves DOWN 5 from (3,10) → (8,10) ✓ 5 moves.
And the green: rot 2 at (8,15). From (4,2) rot 0: 2 SPACE then the path.
Let me simulate the plan step by step in the model and print the final assembly to confirm it matches the solution
… [1538 caracteres más]

```python
r=action([{'action':'MOUSE','row':14,'col':41}]+['DOWN']*5)
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','no_op')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] batch of 6 actions, 6 executed: MOUSE(row=14, col=41), DOWN, DOWN, DOWN, DOWN, DOWN
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
0 O 3614 [0, 0]
1 W 4 [0, 16]
2 c 28 [0, 20]
3 c 135 [14, 14]
4 R 9 [26, 47]
5 G 9 [29, 32]
6 Y 45 [
… [40 caracteres más]
```

## Paso 21 · nivel 3 · acción 91

**Pensamiento:**

The yellow moved down and one tip connected with the purple's top prong: a GRAY joint at (29,32) (node 5 is 'G' 9 = gray) ✓. The yellow's other tip (red) is at (26,47).
The yellow is now at super: body (9,11)-(9,15)? node 6 Y 45 at [29,35] → rows 29-31, cols 35-49 → super row 9, cols 11-15 ✓ = pos (8,10) with the combined bbox top-left at (8,10) (the tip at (8,15) is gray at rows 26-28? hmm).
Wait: the gray joint is at (29,32) = super (9,10). Hmm, that's the purple's tip at local (0,1) → super (9,10) ✓ and the yellow's tip should coincide with it. The yellow at pos (8,10): its tips are at local (0,5),(1,0) → super (8,15) and (9,10) ✓. Yes! The yellow's tip (9,10) pairs with the purple's tip (9,10) → gray ✓. And the yellow's other tip at (8,15) = rows 26-28, cols 47-49 → red at (26,47) ✓ matches node 4.
The yellow is at the target ✓.
Now stage 2: the green. MOUSE(23,8), SPACE×2, then UP×3, RIGHT×13, DOWN, RIGHT, DOWN×6, LEFT.
Wait, the plan path was: UP UP UP, RIGHT×13, DOWN, RIGHT, DOWN DOWN DOWN DOWN DOWN DOWN, LEFT.
Let me double check the plan's action list from the earlier output:
['SPACE','SPACE','UP','UP','UP','RIGHT'×13,'DOWN','RIGHT','DOWN'×6,'LEFT'] — from the printed plan:
SPACE, SPACE, UP, UP, UP, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, DOWN, RIGHT, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, LEFT
Count: 2 SPACE + 3 UP + 13 RIGHT + 1 DOWN + 1 RIGHT + 6 DOWN + 1 LEFT = 27 moves. Plus the click = 28. Total plan = 6 + 28 = 34
… [1484 caracteres más]

```python
st={'G':{'rot':0,'pos':(4,2)},'Y':{'rot':0,'pos':(3,10)},'P':{'rot':0,'pos':(9,9)}}
targets={'G':(2,(8,15)),'Y':(0,(8,10))}
p,s=plan3(st,targets,['Y','G'])
print('plan len',len(p))
from collections import Counter
print(Counter(a if isinstance(a,str) else 'MOUSE' for a in p))
print('final state',s)
# verify net moves for G
mov=[a for a in p if isinstance(a,str) and a!='SPACE']
dr=sum(1 for a in mov if a=='DOWN')-sum(1 for a in mov if a=='UP')
dc=sum(1 for a in mov if a=='RIGHT')-sum(1 for a in mov if a=='LEFT')
print('net',dr,dc)
print(p[6:])
```

```text
plan len 34
Counter({'RIGHT': 14, 'DOWN': 12, 'UP': 3, 'MOUSE': 2, 'SPACE': 2, 'LEFT': 1})
final state {'G': {'rot': 2, 'pos': (8, 15)}, 'Y': {'rot': 0, 'pos': (8, 10)}, 'P': {'rot': 0, 'pos': (9, 9)}}
net 9 13
[{'action': 'MOUSE', 'row': 23, 'col': 8}, 'SPACE', 'SPACE', 'UP', 'UP', 'UP', 'RIGHT', '
… [179 caracteres más]
```

**Pensamiento:**

I miscounted: the Counter over the whole plan includes the yellow's 5 DOWNs. Total DOWN=12 → green's DOWN = 7; UP=3 → net +4 rows ✓ (4 → 8). RIGHT=14 → green's = 14, LEFT=1 → net +13 ✓ (2 → 15). 
The final state matches the target ✓. My earlier manual count was wrong (there are 7 DOWNs for the green: 1 + 6 = 7 ✓, and net = -3 + 1 + 7 = +5? Hmm: UP×3 (-3), DOWN×7 (+7) → +4 ✓ (the 12 DOWNs total include 5 for the yellow → 7 for the green) ✓.
Good, the plan is valid.
Now execute stage 2: MOUSE(23,8), SPACE×2, then the path. Let me batch it and check for level completion.
Note: the green's click target (23,8) — the green hasn't moved, so it's still valid ✓.
Risk: if the green's path is blocked somewhere by the yellow's new position (the plan accounted for it ✓).
Let me execute the full stage-2 batch (28 actions). Actually, let me split: first the click + 2 SPACE + 3 UP + 13 RIGHT (verify), then the rest. Hmm, batching is more efficient. The plan was validated in my model; the main risk is a model mismatch. Let me do it in 2 batches to be safer: batch A = click, SPACE×2, UP×3, RIGHT×13 (19 actions); then verify the green's position; batch B = the remaining 9.
Let me do batch A.

```python
r=action([{'action':'MOUSE','row':23,'col':8},'SPACE','SPACE','UP','UP','UP']+['RIGHT']*13)
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','no_op')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] batch of 19 actions, 19 executed: MOUSE(row=23, col=8), SPACE, SPACE, UP, UP, UP, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
0 O 3614 [0,
… [110 caracteres más]
```

## Paso 22 · nivel 3 · acción 93

**Pensamiento:**

Interesting! The green moved to the top-right. But something unexpected: the yellow piece DISAPPEARED! Node 6 is 'c' 252 at (26,47) — that's the purple (180) + yellow (45) + gray joint (9) = 234? Hmm, 180+45+9 = 234, not 252. Hmm, 252 = 180 + 45 + 27? or 180+72?
Wait, the yellow is no longer a separate node, and there's no 'Y' node. Also the gray joint (node 5 'G') is gone... Actually node 5 is 'R' 9 at (23,47) — a red tip.
Let me look at the image: the green is at the top right with 2 red tips; the dark piece (purple, unselected) is at the bottom; the yellow piece is GONE from the image!
Hmm, the diff image shows the yellow's old position as orange (background) — the yellow moved?? No: the diff shows the yellow's old position changed to background. And the green's old position is orange too.
Where did the yellow go? Node 6 'c' 252 at (26,47) is a merged dark blob: the purple + the yellow (both dark gray now, touching) merged into one component ✓ 180 + 45 + 27? Let me compute: if the yellow's tip and the purple's tip are gray (connected), the gray cell is also 'G'... but the merged component is 'c' 252 = 180 (purple body) + 45 (yellow body) + 27 (3 blocks: the gray joint 9 + ... hmm 27 = 3 cells of 9 = the gray joint + 2 tips?).
Ah I see: the yellow became unselected (dark gray), so its tips are now dark gray too (they're part of the piece). So the merged dark component = purple body (180) + purple tips (18) + yellow body (45) + yellow tips (18) + gray joint (9) = 270? No: 18
… [1466 caracteres más]

```python
r=action(['DOWN','RIGHT']+['DOWN']*6+['LEFT'])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','no_op','stop_reason')})
from collections import Counter
print(Counter(v for row in grid2(current_frame) for v in row))
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] batch of 9 actions, 2 executed: DOWN, RIGHT | stop_reason: no_op_action
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': False, 'no_op': True, 'stop_reason': 'no_op_action'}
Counter({'O': 3686, 'c': 265, 'N': 117, 'W': 10, 'R': 9, 'G': 9})
0 O 3623 [0, 0]
… [108 caracteres más]
```

## Paso 23 · nivel 3 · acción 94

**Pensamiento:**

The green moved DOWN 1 (to pos (2,15)) and formed a SECOND gray joint at (26,47) — the green's bottom tip connected with the yellow's tip! Wait: node 5 'G' 9 at (26,47) = gray. And the yellow's free tip was at (8,15) super = rows 26-28, cols 47-49 ✓. So the green's tip (after moving down) landed on the yellow's tip ✓.
Then RIGHT was a NO-OP: the green couldn't move right. Why? Because it's connected (locked?) — hmm, or because moving right is blocked by... nothing? At pos (2,15), moving RIGHT to (2,16): the green's body cells would be at cols 16-19... The yellow's body is at super row 9, cols 11-15 — no conflict. Hmm, but the green's tip at (8,15)... wait, if the green is at (2,15), its tips are at local (6,0) and (0,0) for rot 2 → super (2,15) and (8,15). The tip at (8,15) is now CONNECTED (gray) to the yellow's tip.
So moving RIGHT would break the connection — and the game refused! That means: once connected, the piece CANNOT move away (unlike level 2 where the plug unseated... hmm, in level 2 I pressed UP with the plug seated and it unseated).
Hmm, wait. In level 2, when the plug was seated and I pressed UP, did it unseat? Let me recall: after the batch (6 DOWN + 1 RIGHT) the plug was seated with gray tips. Then I pressed UP and the tips became red again (the current frame showed red tips). Hmm, that suggests unseating was allowed.
Hmm, but maybe in level 2 the plug wasn't actually seated at that moment... Let me re-check: the batch ended with the plug at rows 29-46 cols 1
… [9730 caracteres más]

```python
r=action(['DOWN'])
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','no_op')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] DOWN -> effect
{'executed': True, 'level_completed': False, 'game_over': False, 'gameplay_changed': True, 'no_op': False}
0 O 3623 [0, 0]
1 W 10 [0, 16]
2 c 22 [0, 26]
3 R 9 [11, 47]
4 N 117 [11, 50]
5 c 9 [26, 47]
6 c 234 [29, 32]
7 R 9 [29, 47]
8 O 63 [35, 32]
```

## Paso 24 · nivel 3 · acción 94

**Pensamiento:**

The green moved DOWN to pos (3,15) — so unseating IS allowed (the joint broke). But look at the new state: node 5 is 'c' 9 at (26,47) — the previously gray joint cell is now DARK GRAY?! And node 7 'R' 9 at (29,47) — a red tip at rows 29-31, col 47-49 = super (9,15).
Hmm interesting. The yellow's tip: the yellow is at pos (8,10) with tips at (8,15) and (9,10). The tip at (8,15) = real rows 26-28, cols 47-49. Now node 5 'c' 9 at (26,47) means that cell is dark gray (not red!). And there's a red tip at (29,47) = super (9,15)?? 
Hmm, that's odd. Let me think: the merged dark component (node 6, 234 px) = purple + yellow. 234 = 180 + 45 + 9 (the gray joint became dark gray? no...). Let me compute: purple body 180 + purple tips 18 + yellow body 45 + yellow tip (9,10) 9 = 252 if all dark. Now: 234 + 9 (node 5) + 9 (node 7 red) = 252 ✓ total conserved.
So: node 5 'c' 9 at (26,47) = super (8,15) is dark gray — that's the yellow's tip at (8,15), now rendered dark gray instead of red!? And node 7 'R' 9 at (29,47) = super (9,15) is RED.
Hmm, wait. Maybe the yellow's tip MOVED? No, the yellow hasn't moved.
OH WAIT. I bet the tip is a "loose" element that can be re-rendered... Hmm. Or maybe: when the green's tip was on the yellow's tip, they became gray. Now the green moved away and the yellow's tip should be red at (8,15) — and indeed node 5 is at (26,47) but it's 'c' (dark) not 'R'.
And the red at (29,47) = super (9,15): is that the green's tip? The green is at pos (3,15) rot 2 → tips at 
… [1421 caracteres más]

```python
V=L3V()
st={'G':{'rot':2,'pos':(3,15)},'Y':{'rot':0,'pos':(8,10)},'P':{'rot':0,'pos':(9,9)}}
def freepos(V,name,rot,st,BR=19,BC=19):
    var=V[name][rot]
    bb=set(); bt=set()
    for k in st:
        if k==name: continue
        b,t=cells3(V,k,st[k]['rot'],st[k]['pos']); bb|=b; bt|=t
    out=set()
    for r in range(-8,22):
        for c in range(-8,22):
            B={(x+r,y+c) for x,y in var[1]}; T={(x+r,y+c) for x,y in var[2]}
            if any(x<0 or x>BR or y<0 or y>BC for x,y in B|T): continue
            if B&(bb|bt) or T&bb: continue
            out.add((r,c))
    return out
fp=freepos(V,'G',2,st)
print('start free?',(3,15) in fp,'target free?',(8,15) in fp)
path=conn(fp,(3,15),(8,15))
print('path',path)
if path:
    acts=[{(1,0):'DOWN',(-1,0):'UP',(0,1):'RIGHT',(0,-1):'LEFT'}[(
… [68 caracteres más]
```

```text
start free? False target free? True
path None
```

**Pensamiento:**

The start (3,15) is NOT free in my model → the green at (3,15) overlaps something. Let me find what.
Green rot 2 body (computed earlier): (6,2),(6,1),(5,2),(4,4),(4,3),(4,2),(3,4),(2,4),(2,3),(2,2),(1,2),(0,2),(0,1); tips (6,0),(0,0).
At pos (3,15): body = (9,17),(9,16),(8,17),(7,19),(7,18),(7,17),(6,19),(5,19),(5,18),(5,17),(4,17),(3,17),(3,16); tips (9,15),(3,15).
Yellow at (8,10): body (9,11),(9,12),(9,13),(9,14),(9,15); tips (8,15),(9,10).
Conflict: the green's body cell (9,16)? The yellow's body is cols 11-15 → no. Hmm, the green's tip (9,15) vs the yellow's body (9,15) → CONFLICT! The green's tip at (9,15) overlaps the yellow's BODY cell (9,15).
But in the real game the green IS at (3,15) with a red tip at (29,47) = super (9,15), and the yellow's body includes (9,15)... 
Hmm! So tip-on-body IS allowed in the real game?! The green's tip currently overlaps the yellow's body cell. Let me verify by looking at the actual board: node 7 'R' 9 at (29,47) → real rows 29-31, cols 47-49. The yellow's body: node 6 merged dark 'c' 234 at (29,32)... The yellow's body cells: super (9,11)-(9,15) = real rows 29-31, cols 35-49. So real (29,47) is within the yellow's body region (cols 47-49 = super col 15 ✓). But the rendering shows RED there (node 7), meaning the tip is drawn ON TOP of the yellow's body.
So the game allows a tip to overlap a body! Interesting — that contradicts my model's assumption (which came from level 2, where I assumed tips couldn't overlap bodies).
Hmm, in level 2 
… [922 caracteres más]

```python
def freepos2(V,name,rot,st,BR=19,BC=19,tip_on_body=True):
    var=V[name][rot]
    bb=set()
    for k in st:
        if k==name: continue
        b,t=cells3(V,k,st[k]['rot'],st[k]['pos']); bb|=b
    out=set()
    for r in range(-8,22):
        for c in range(-8,22):
            B={(x+r,y+c) for x,y in var[1]}
            if any(x<0 or x>BR or y<0 or y>BC for x,y in B): continue
            if B&bb: continue
            out.add((r,c))
    return out
fp=freepos2(V,'G',2,st)
print('start',(3,15) in fp,'target',(8,15) in fp)
path=conn(fp,(3,15),(8,15)); print('path',path)
acts=[{(1,0):'DOWN',(-1,0):'UP',(0,1):'RIGHT',(0,-1):'LEFT'}[(b[0]-a[0],b[1]-a[1])] for a,b in zip(path,path[1:])]
print(acts)
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 15, in <module>
NameError: name 'V' is not defined
```

**Nivel 3 completado → nivel 4 (acción 99)**

## Paso 24 · nivel 4 · acción 99

**Pensamiento:**

V wasn't defined (variables reset). Let me recompute V and the path. Also note the current image: the green's lower tip (red) is drawn over the yellow's body, and there's a dark gray block at (26,47) (the yellow's tip, unselected) — visible as a dark square above the red tip.
Let me redo the computation.

```python
V=L3V()
st={'G':{'rot':2,'pos':(3,15)},'Y':{'rot':0,'pos':(8,10)},'P':{'rot':0,'pos':(9,9)}}
fp=freepos2(V,'G',2,st)
print('start',(3,15) in fp,'target',(8,15) in fp)
path=conn(fp,(3,15),(8,15)); print('path',path)
if path:
    acts=[{(1,0):'DOWN',(-1,0):'UP',(0,1):'RIGHT',(0,-1):'LEFT'}[(b[0]-a[0],b[1]-a[1])] for a,b in zip(path,path[1:])]
    print(acts)
```

```text
start True target True
path [(3, 15), (4, 15), (5, 15), (6, 15), (7, 15), (8, 15)]
['DOWN', 'DOWN', 'DOWN', 'DOWN', 'DOWN']
```

**Pensamiento:**

Straight DOWN ×5 gets the green to (8,15). Let me execute and check for level completion.
At the final position, the green's tips: (8,15) pairs with the yellow's tip ✓, (14,15) pairs with the purple's tip ✓. And the yellow's other tip (9,10) pairs with the purple's tip ✓. All 6 tips paired → hopefully level complete.
One concern: the green's body at (8,15) rot 2 — does it overlap the yellow's body? Body cells at pos (8,15): (14,17),(14,16),(13,17),(12,19),(12,18),(12,17),(11,19),(10,19),(10,18),(10,17),(9,17),(8,17),(8,16). The yellow's body: (9,11)-(9,15) → no overlap ✓. The purple's body: rows 9-15, cols 9-14 → the green's cells are at cols ≥16 ✓ no overlap.
Execute DOWN×5.

```python
r=action(['DOWN']*5)
print({k:v for k,v in r.items() if k in ('executed','gameplay_changed','level_completed','game_over','no_op','stop_reason')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
from collections import Counter
print(Counter(v for row in grid2(current_frame) for v in row))
```

```text
[action] batch of 5 actions, 5 executed: DOWN, DOWN, DOWN, DOWN, DOWN | stop_reason: level_completed
{'executed': True, 'level_completed': True, 'game_over': False, 'gameplay_changed': True, 'no_op': False, 'stop_reason': 'level_completed'}
0 b 3533 [0, 0]
1 c 32 [0, 16]
2 S 207 [11, 8]
3 c 99 [20, 
… [131 caracteres más]
```

## Paso 25 · nivel 4 · acción 99

**Pensamiento:**

Level 4! Background is blue ('b'). Objects:
- node 2 'S' 207 at (11,8): sky-blue piece (selected, with 2 red tips at (26,23) and (32,8)).
- node 3 'c' 99 at (20,35): dark piece.
- node 6 'c' 144 at (41,44): dark piece.
- node 7 'b' 36 at (44,50): enclosed blue hole inside node 6.
- node 8 'c' 27 at (47,17): a small dark bar (3 super cells).
- node 1 'c' 32 at (0,16): HUD bar.
So 4 pieces? Let me analyze in super coords. Also the 'S' piece is selected (sky blue with red tips).
Let me get the shapes.

```python
f=current_frame
for n in f.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
G=grid2(f)
def reg(r0,r1,c0,c1,tag):
    print('--',tag)
    for r in range(r0,r1+1): print('%2d'%r,''.join(G[r][c] for c in range(c0,c1+1)))
reg(9,36,6,26,'S piece')
reg(18,34,33,48,'dark A')
reg(39,52,41,54,'dark B')
reg(45,50,14,22,'dark C bar')
```

```text
0 b 3533 [0, 0] [63, 0]
1 c 32 [0, 16] [0, 47]
2 S 207 [11, 8] [31, 8]
3 c 99 [20, 35] [22, 35]
4 R 9 [26, 23] [28, 23]
5 R 9 [32, 8] [34, 8]
6 c 144 [41, 44] [43, 44]
7 b 36 [44, 50] [55, 50]
8 c 27 [47, 17] [49, 17]
-- S piece
 9 bbbbbbbbbbbbbbbbbbbbb
10 bbbbbbbbbbbbbbbbbbbbb
11 bbSSSSSSSSSSSSSSSS
… [1332 caracteres más]
```

**Pensamiento:**

Level 4 pieces (super coords, real = 3*s+2):
S piece (sky blue, selected): rows 11-34, cols 8-26.
Super rows: (11-2)/3=3 to (34-2)/3 ≈ 10; cols: (8-2)/3=2 to (26-2)/3=8.
Let me map the shape:
row 11-13 (super 3): cols 8-26 (super 2-8) full → S: (3,2)..(3,8)
row 14-16 (super 4): cols 8-10, 23-25 → (4,2),(4,7)
row 17-19 (super 5): cols 8-10, 17-19, 23-25 → (5,2),(5,5),(5,7)
row 20-22 (super 6): cols 8-10, 17-19, 23-25 → (6,2),(6,5),(6,7)
row 23-25 (super 7): cols 8-10, 17-26 → (7,2),(7,5),(7,6),(7,7),(7,8)
row 26-28 (super 8): cols 8-10, 17-19, tips at 23-25 (RRR) → (8,2),(8,5), tip (8,8)
row 29-31 (super 9): cols 8-10 → (9,2)
row 32-34 (super 10): RRR at cols 8-10 → tip (10,2)
So the S piece: body 207/9 = 23 cells; tips 2 (at (8,8) and (10,2)); total 25.
Let me verify the body count: 
row3: 7, row4: 2, row5: 3, row6: 3, row7: 5, row8: 2 (cols 2,5) + tip, row9: 1, row10: tip.
7+2+3+3+5+2+1 = 23 ✓.
Dark A: rows 20-31, cols 35-49 → super rows 6-10, cols 11-15.
row 20-22 (super 6): cols 35-40 (super 11-12? (35-2)/3 = 11, (40-2)/3=12.67 → hmm. Let me be careful: super col c covers real cols 3c+2..3c+4. c=11 → 35-37; c=12 → 38-40; c=13 → 41-43; c=14 → 44-46; c=15 → 47-49.
row 20-22: 'bbccccccbbbccccc' from col 33: cols 35-40 = c (super 11,12), cols 41-43 = b, cols 44-49 = c (super 14,15).
row 23-28 (super 7,8): cols 38-40 (super 12), cols 44-46 (super 14).
row 29-31 (super 9): cols 38-49 → super 12,13,14,15.
So dark A (local, relative to (6,11)):
(0,0),(0,1),(0,3),(0,4)
(1,1),(1,3)

… [1445 caracteres más]

```python
def supblocks(f, colors, skip_top=3):
    G=grid2(f); R=len(G); C=len(G[0])
    out=[]
    for col in colors:
        seen=[[False]*C for _ in range(R)]
        for r in range(skip_top,R):
            for c in range(C):
                if G[r][c]==col and not seen[r][c]:
                    st=[(r,c)]; seen[r][c]=True; cc=[]
                    while st:
                        x=st.pop(); cc.append(x)
                        for d in ((1,0),(-1,0),(0,1),(0,-1)):
                            y=(x[0]+d[0],x[1]+d[1])
                            if 0<=y[0]<R and 0<=y[1]<C and not seen[y[0]][y[1]] and G[y[0]][y[1]]==col:
                                seen[y[0]][y[1]]=True; st.append(y)
                    if len(cc)>=9:
                        sb={((r-2)//3,(c-2)//3) for r,c in cc}
          
… [588 caracteres más]
```

```text
== S 207 pos (3, 2) bbox (11, 8, 31, 25) 7 x 6
    ######
    #....#
    #.##.#
    #.#..#
    #.####
    #.#...
    #.....
== c 99 pos (6, 11) bbox (20, 35, 31, 49) 4 x 5
    ##.##
    .#.#.
    .#.#.
    .###.
== c 144 pos (13, 14) bbox (41, 44, 58, 55) 6 x 4
    ####
    .#.#
    .#.#
    .#.#
  
… [175 caracteres más]
```

## Paso 25 · nivel 4 · acción 102

**Pensamiento:**

Level 4 pieces (super coords):
S (sky blue, selected) — combined bbox 7x6 at super (3,2), body 23 + 2 tips:
```
######
#....#
#.##.#
#.#..#
#.####
#.#...
#.....
```
with tips at local (5,5) [red at super (8,7)... hmm]. The red tips: super (8,7) and (10,2) → relative to the combined bbox pos (3,2): (5,5) and (7,0).
Let me recompute the shape from the print: the S shape print (7x6) includes the tips? It was computed from the 'S' component only (207 px = 23 cells) → the print shows only the body. Body local (relative to (3,2)):
```
r0: ######      (0,0..5)
r1: #....#      (1,0),(1,5)
r2: #.##.#      (2,0),(2,2),(2,3),(2,5)
r3: #.#..#      (3,0),(3,2),(3,5)
r4: #.####      (4,0),(4,2),(4,3),(4,4),(4,5)
r5: #.#...      (5,0),(5,2)
r6: #.....      (6,0)
```
count: 6+2+4+3+5+2+1 = 23 ✓
Tips: red at super (8,7) → local (5,5); red at super (10,2) → local (7,0).
So the combined bbox is 8x6 (rows 3-10, cols 2-7) — the print's pos (3,2) is the body's top-left, and the bbox is rows 3-10 → 8 tall, cols 2-7 → 6 wide.
Hmm, careful: the rotation anchor is the COMBINED bbox top-left. So I need the combined bbox dims: H=8, W=6.
Dark A: 4x5 at super (6,11), 11 cells:
```
##.##
.#.#.
.#.#.
.###.
```
This includes 2 tips (dark, unselected). Total 11 cells.
Dark B: 6x4 at super (13,14), 16 cells:
```
####
.#.#
.#.#
.#.#
.#.#
####
```
16 cells (with 2 tips among them).
Dark C: 1x3 at super (15,5), 3 cells: `###`.
Hmm, dark C is only 3 cells — with 2 tips that leaves 1 body cell. Hmm, that's a tiny p
… [1396 caracteres más]

```python
def snap(f):
    out={}
    for col in ('S','c','N','p','Y','W'):
        for c2,n,s,pos,bb in supblocks(f,[col]):
            out.setdefault(col,[]).append((n,s,pos,bb))
    red=[((r-2)//3,(c-2)//3) for r in range(64) for c in range(64) if grid2(f)[r][c]=='R']
    rs=set(red)
    return out,sorted(rs)
for (rr,cc),tag in [((21,36),'A'),((42,45),'B'),((48,18),'C')]:
    r=action([{'action':'MOUSE','row':rr,'col':cc}])
    o,reds=snap(current_frame)
    print('click',tag,{k:v for k,v in r.items() if k in ('no_op','gameplay_changed')})
    print('  red tips',reds)
    for col,items in o.items():
        for n,s,pos,bb in items:
            if col=='c' and n in (11,16,3):
                print('  dark',n,'pos',pos)
```

```text
[action] MOUSE(row=21, col=36) -> effect
click A {'gameplay_changed': True, 'no_op': False}
  red tips [(6, 11), (6, 15)]
[action] MOUSE(row=42, col=45) -> effect
click B {'gameplay_changed': True, 'no_op': False}
  red tips [(13, 14), (18, 14)]
[action] MOUSE(row=48, col=18) -> effect
click C {'gam
… [67 caracteres más]
```

## Paso 26 · nivel 4 · acción 102

**Pensamiento:**

Tips data:
- A (4x5 at (6,11)): tips at super (6,11) and (6,15) → local (0,0) and (0,4) ✓ (the two top ends).
- B (6x4 at (13,14)): tips at super (13,14) and (18,14) → local (0,0) and (5,0) ✓ (the left ends of the bracket).
- C (1x3 at (15,5)): tips at local (0,0) and (0,2), body = (0,1).
- S (body at (3,2), combined bbox 8x6 at (3,2)): tips at local (5,5) and (7,0).
Now define the pieces with combined bboxes:
S: H=8, W=6, pos (3,2). Body (local): 
(0,0..5), (1,0),(1,5), (2,0),(2,2),(2,3),(2,5), (3,0),(3,2),(3,5), (4,0),(4,2),(4,3),(4,4),(4,5), (5,0),(5,2), (6,0)
Tips: (5,5),(7,0)
A: H=4, W=5, pos (6,11). Body: (0,1),(0,3),(1,1),(1,3),(2,1),(2,3),(3,1),(3,2),(3,3) = 9; tips (0,0),(0,4) → total 11 ✓
B: H=6, W=4, pos (13,14). Body: (0,1),(0,2),(0,3),(1,1),(1,3),(2,1),(2,3),(3,1),(3,3),(4,1),(4,3),(5,1),(5,2),(5,3) = 14; tips (0,0),(5,0) → total 16 ✓
C: H=1, W=3, pos (15,5). Body: (0,1); tips (0,0),(0,2) ✓ total 3 ✓
Goal: closed loop, 4 connections (each pair of adjacent pieces in the loop shares a tip pair). With 4 pieces × 2 tips = 8 tips → 4 pairs → the piece-adjacency graph is a 4-cycle.
Total cells: 25+11+16+3 = 55 super cells.
Let me now write a general loop solver: given pieces with body/tips, find rotations+positions such that all tips are paired pairwise (no leftover), bodies don't overlap, and tips don't land on bodies (level 3 solution had no tip-on-body; but the game allows tip-on-body during movement — for the final assembly, tips pair with tips so it should be fine
… [1460 caracteres más]

```python
def L4():
    S={'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(0,5),(1,0),(1,5),(2,0),(2,2),(2,3),(2,5),(3,0),(3,2),(3,5),
               (4,0),(4,2),(4,3),(4,4),(4,5),(5,0),(5,2),(6,0)],
       'tips':[(5,5),(7,0)],'pos':(3,2),'H':8,'W':6}
    A={'body':[(0,1),(0,3),(1,1),(1,3),(2,1),(2,3),(3,1),(3,2),(3,3)],'tips':[(0,0),(0,4)],'pos':(6,11),'H':4,'W':5}
    B={'body':[(0,1),(0,2),(0,3),(1,1),(1,3),(2,1),(2,3),(3,1),(3,3),(4,1),(4,3),(5,1),(5,2),(5,3)],
       'tips':[(0,0),(5,0)],'pos':(13,14),'H':6,'W':4}
    C={'body':[(0,1)],'tips':[(0,0),(0,2)],'pos':(15,5),'H':1,'W':3}
    return {'S':S,'A':A,'B':B,'C':C}
def L4V():
    P=L4(); out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.appe
… [1570 caracteres más]
```

```text
S rot 0 sols 4
S rot 1 sols 0
S rot 2 sols 0
S rot 3 sols 4
total 8
('S', 0) {'S': (0, (3, 2)), 'A': (1, (8, 4)), 'B': (1, (12, 2)), 'C': (1, (10, 2))}
('S', 0) {'S': (0, (3, 2)), 'A': (1, (8, 4)), 'B': (1, (12, 2)), 'C': (3, (10, 2))}
('S', 0) {'S': (0, (3, 2)), 'A': (3, (8, 7)), 'B': (1, (12, 2)),
… [269 caracteres más]
```

## Paso 26 · nivel 4 · acción 102

**Pensamiento:**

8 solutions. Let me look at the assemblies to check they form a single connected 4-cycle, and compute the move cost for each (with the corrected bounds BR=BC=19 and tip-on-body allowed for movement).
Let me render the first few solutions and compute a plan cost. I need a generic planner for level 4: similar to plan3 but using L4V, freepos2 (body-only blocking), and allowing tips on bodies.
Also important: the mover's BODY can't overlap other bodies; can the mover's body overlap another piece's TIP? In level 3, I blocked body-on-tip. Is that right? Unknown. Let me keep blocking body-on-tip (conservative) but if paths fail, relax.
Also, the mover's tips CAN overlap bodies (proven in level 3).
Let me write plan4(st, targets, order) using freepos2 (which only blocks body-vs-body) — hmm, but freepos2 ignores tips entirely (both directions). Let me make it: body can't overlap other bodies OR other tips; tips can overlap bodies. That's the level-3-conservative version.
Then compute the total plan length for each solution and pick the best. Let me also verify the connectivity (single loop).

```python
def conn_graph(sol,V):
    import collections
    tips={}
    for name,(rotk,pos) in sol.items():
        var=V[name][rotk]; r0,c0=pos
        for (r,c) in var[2]: tips.setdefault((r+r0,c+c0),[]).append(name)
    g=collections.defaultdict(set)
    for k,v in tips.items():
        if len(v)==2:
            if len(set(v))==1: return None,'self-pair %s at %s'%(v[0],k)
            g[v[0]].add(v[1]); g[v[1]].add(v[0])
        elif len(v)>2: return None,'triple'
    return g,None
def plan4(st,targets,order,V,BR=19,BC=19):
    import copy
    st=copy.deepcopy(st); plan=[]
    for name in order:
        rt,pp=targets[name]
        b,t=cells3(V,name,st[name]['rot'],st[name]['pos'])
        R,C=sorted(b)[len(b)//2]
        plan.append({'action':'MOUSE','row':3*R+2,'col':3*C+2})
        nr=(rt-st[nam
… [1479 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 47, in <module>
NameError: name 'allsols' is not defined
```

**Pensamiento:**

Variables reset between calls. I need to rebuild allsols in the same call. Let me combine: build V, allsols, then plan. Keep it compact.

```python
V=L4V()
allsols=[]
for fr in range(4):
    for x in solve_cycle(V,'S',fr,(3,2)): allsols.append((fr,x))
cur={'S':{'rot':0,'pos':(3,2)},'A':{'rot':0,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
import itertools
best=[]; info=[]
for fr,sol in allsols:
    g,err=conn_graph(sol,V)
    if err: info.append((fr,'REJECT',err)); continue
    targets={k:(v[0],v[1]) for k,v in sol.items() if k!='S'}
    got=None
    for order in itertools.permutations(targets):
        p,_=plan4(cur,targets,list(order),V)
        if p and (got is None or len(p)<len(got[0])): got=(p,list(order))
    if got: best.append((len(got[0]),fr,got[1],sol)); info.append((fr,'ok',len(got[0]),got[1],len(g)))
    else: info.append((fr,'noplan',dict(targets)))
for i in info: print(i)
best.sort(key=lambda x:
… [125 caracteres más]
```

```text
(0, 'ok', 36, ['A', 'C', 'B'], 4)
(0, 'ok', 38, ['A', 'C', 'B'], 4)
(0, 'ok', 35, ['A', 'C', 'B'], 4)
(0, 'ok', 37, ['A', 'C', 'B'], 4)
(3, 'ok', 34, ['A', 'B', 'C'], 4)
(3, 'ok', 36, ['A', 'B', 'C'], 4)
(3, 'ok', 39, ['A', 'B', 'C'], 4)
(3, 'ok', 41, ['A', 'B', 'C'], 4)
BEST len 34 Srot 3 order ['A
… [167 caracteres más]
```

**Pensamiento:**

All 8 solutions form a valid 4-cycle graph. The best plan is 34 actions: S rotated 3 times (270° CW = 90° CCW) at (3,2), A at (3,7), B at (3,11), C at (8,9).
Hmm, the plan requires rotating the S piece 3 times and moving it? No — the plan's targets exclude S (S is fixed at (3,2) with rot 3). But wait: plan4's targets dict excludes 'S', so S is never moved or rotated in the plan! That's a bug: the solution requires S to be at rot 3, but my planner never rotates S. Then the other pieces' targets were computed relative to S at rot 3 — but the plan leaves S at rot 0 → the final assembly would be wrong!
Let me check: in plan4 I only iterate over `order` (the targets). Since 'S' isn't in targets, S stays at rot 0. So the plan is invalid.
I need to include the fixed piece's rotation in the plan. Let me fix: targets should include S with (3, (3,2)) and the order must include S (with 3 SPACE presses and 0 moves).
Also note: the S piece must be rotated FIRST (before the others move), since the others' targets depend on it. Also, rotating S while other pieces are nearby could be blocked (rotation is blocked if the rotated shape would overlap).
Let me redo: build targets for ALL pieces including S, with the order starting with S.
Also: is rotation blocked by collisions? In level 2/3, rotation happened when free. If a rotation would collide, presumably it's a no-op. Let me include a check: after each SPACE, verify no body overlap.
Let me also consider the alternative: fix a different piec
… [784 caracteres más]

```python
cur={'S':{'rot':0,'pos':(3,2)},'A':{'rot':0,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
V=L4V()
cands=[]
for fix in cur:
    for fr in range(4):
        rot_needed=(fr-cur[fix]['rot'])%4
        pos_needed=(cur[fix]['pos']!=cur[fix]['pos'])
        for sol in solve_cycle(V,fix,fr,cur[fix]['pos']):
            cands.append((fix,fr,sol))
print('cands',len(cands))
import itertools
res=[]
for fix,fr,sol in cands:
    g,err=conn_graph(sol,V)
    if err: continue
    targets={k:(v[0],v[1]) for k,v in sol.items()}
    others=[k for k in targets if k!=fix]
    got=None
    for order in itertools.permutations(others):
        o=[fix]+list(order)
        p,_=plan4(cur,targets,o,V)
        if p and (got is None or len(p)<len(got[0])): got=(p,o)
    if got: res.append((len(go
… [125 caracteres más]
```

```text
cands 20
33 A rot 2 ['A', 'S', 'B', 'C']
34 A rot 0 ['A', 'S', 'B', 'C']
34 A rot 3 ['A', 'S', 'B', 'C']
35 A rot 1 ['A', 'S', 'B', 'C']
35 A rot 2 ['A', 'S', 'B', 'C']
36 S rot 0 ['S', 'A', 'C', 'B']
BEST (33, 'A', 2, ['A', 'S', 'B', 'C'], {'A': (2, (6, 11)), 'S': (3, (9, 6)), 'B': (0, (9, 15)), 'C
… [18 caracteres más]
```

## Paso 26 · nivel 4 · acción 104

**Pensamiento:**

Best: 33 actions, fix A at rot 2 pos (6,11) — but wait, A's current rot is 0, so A needs 2 rotations (still at the same position). The plan order is [A, S, B, C].
Solution: A rot 2 at (6,11), S rot 3 at (9,6), B rot 0 at (9,15), C rot 0 at (14,13).
Hmm, S moves from (3,2) to (9,6) = +6 rows, +4 cols, and 3 rotations. B from (13,14) to (9,15): -4 rows, +1 col. C from (15,5) to (14,13): -1 row, +8 cols.
Let me render this assembly to double check, then execute the plan.
Also: I should double check the plan is collision-free (plan4 does BFS on free positions with body-vs-body/tip blocking; it doesn't check the final overlap of tips but the loop requires tips to pair).
One thing to verify: during movement, the mover's TIPS can pass over other bodies (allowed per level 3 evidence). My freepos in plan4 only blocks B&(bb|bt) — the mover's body can't hit other bodies or tips; tips can go anywhere. That matches the level-3 evidence.
Let me render the assembly and print the plan.

```python
V=L4V()
sol={'A': (2, (6, 11)), 'S': (3, (9, 6)), 'B': (0, (9, 15)), 'C': (0, (14, 13))}
print('\n'.join(asm3(sol,V)[5:16]))
cur={'S':{'rot':0,'pos':(3,2)},'A':{'rot':0,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
targets={k:v for k,v in sol.items()}
p,st=plan4(cur,targets,['A','S','B','C'],V)
print(len(p)); print(p)
```

```text
...................
............AAA....
............A.A....
............A.A....
......SSSSSsA.AbBBB
......S...S.....B.B
......S.S.S.....B.B
......S.SSSS....B.B
......S.........B.B
......SSSSSSScCcBBB
33
[{'action': 'MOUSE', 'row': 26, 'col': 38}, 'SPACE', 'SPACE', {'action': 'MOUSE', 'row': 17, 'col
… [315 caracteres más]
```

**Pensamiento:**

The assembly looks like a proper closed loop:
```
............AAA....
............A.A....
............A.A....
......SSSSSsA.AbBBB
......S...S.....B.B
......S.S.S.....B.B
......S.SSSS....B.B
......S.........B.B
......SSSSSSScCcBBB
```
Wait, the 'A' piece at rot 2 is at (6,11) — but in the render, A appears at rows 6-9 cols 12-16 ✓. And the S piece at (9,6) rot 3. The B at (9,15). The C at (14,13).
The lowercase letters are tips: 's' at (9,12) pairs with 'A'... hmm, the render shows 'SSSSSsA.AbBBB' — the tip positions are where two tips coincide; the later-drawn piece overwrote. Fine, the solver verified pairing.
The plan (33 actions):
1. MOUSE(26,38) → select A (A's body at super (7,12) → real (23,38)? Let me check: the planner picks sorted(b)[len(b)//2] of A's body at rot 0 pos (6,11): body cells → the middle one → real (3R+2, 3C+2). It chose (26,38) → super (8,12) ✓ a body cell of A.
2. SPACE ×2 → A rot 2.
3. MOUSE(17,23) → select S: super ((17-2)/3, (23-2)/3) = (5,7) → S's body at rot 0 pos (3,2) local (2,5) ✓ body.
4. SPACE×3, DOWN×6, RIGHT×4 → S to (9,6).
5. MOUSE(50,47) → select B: super (16,15) → B's body at rot 0 pos (13,14): local (3,1) ✓.
6. UP,UP,UP,RIGHT,UP → B to (9,15).
7. MOUSE(47,20) → select C: super (15,6) → C's body at (15,6) ✓ (C's body is the middle cell (15,6) ✓).
8. RIGHT×8, UP → C to (14,13).
Total 33 actions.
Concerns:
- The rotation of S (3 SPACEs) while A is at rot 2 at (6,11): the S piece rotating at pos (3,2) with dims 8x6 → rot 1: 6x8, etc. The pl
… [2230 caracteres más]

```python
r=action([{'action':'MOUSE','row':17,'col':23},{'action':'SPACE'}])
G=grid2(current_frame)
cs={(rr,cc) for rr in range(3,64) for cc in range(64) if G[rr][cc] in ('S','R')}
print('S+tips bbox',min(x[0] for x in cs),min(x[1] for x in cs),max(x[0] for x in cs),max(x[1] for x in cs),len(cs))
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
```

```text
[action] batch of 2 actions, 2 executed: MOUSE(row=17, col=23), SPACE
S+tips bbox 11 8 28 31 225
0 b 3533 [0, 0]
1 W 1 [0, 16]
2 c 31 [0, 17]
3 R 9 [11, 8]
4 S 207 [11, 11]
5 c 99 [20, 35]
6 R 9 [26, 14]
7 c 144 [41, 44]
8 b 36 [44, 50]
9 c 27 [47, 17]
```

## Paso 27 · nivel 4 · acción 116

**Pensamiento:**

The S piece rotated CW. The combined bbox (S + red tips): rows 11-28, cols 8-31 → super rows 3-8 (6 rows), cols 2-9 (8 cols) ✓ exactly matching my prediction: the anchor is the bbox top-left, new dims (W,H) = (6,8) → rows 3-8, cols 2-9 ✓✓.
The model is confirmed. Now S is at rot 1 pos (3,2). I need rot 3 → 2 more SPACE.
Then DOWN×6, RIGHT×4 → (9,6).
Let me now execute the rest of the plan, but in stages with verification:
Stage 1: SPACE×2 (S to rot 3), verify bbox.
Then the moves.
Note: the plan was: MOUSE(17,23) [done], SPACE×3 [1 done], DOWN×6, RIGHT×4, then MOUSE(50,47), UP,UP,UP,RIGHT,UP, then MOUSE(47,20), RIGHT×8, UP.
Let me execute SPACE×2 and check the bbox: expected rot 3 dims (6,8) → rows 3-8, cols 2-9 (same as now).
Then DOWN×6 → rows 21-38... let me just execute and verify positions against the model.
Actually, let me batch: SPACE×2, DOWN×6, RIGHT×4 (12 actions), then verify S's bbox = expected pos (9,6) with rot 3 dims (6,8) → rows 9-14 → real rows 29-44, cols 6-13 → real cols 20-41.
Let me do that.

```python
r=action(['SPACE','SPACE']+['DOWN']*6+['RIGHT']*4)
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason','level_completed')})
G=grid2(current_frame)
cs={(rr,cc) for rr in range(3,64) for cc in range(64) if G[rr][cc] in ('S','R')}
bb=(min(x[0] for x in cs),min(x[1] for x in cs),max(x[0] for x in cs),max(x[1] for x in cs))
print('S bbox',bb,'expected sup pos (9,6) rot3 -> real rows 29-44 cols 20-41')
print('sup pos',(bb[0]-2)//3,(bb[1]-2)//3)
```

```text
[action] batch of 12 actions, 12 executed: SPACE, SPACE, DOWN, DOWN, DOWN, DOWN, DOWN, DOWN, RIGHT, RIGHT, RIGHT, RIGHT
{'executed': True, 'level_completed': False, 'no_op': False}
S bbox (29, 20, 46, 43) expected sup pos (9,6) rot3 -> real rows 29-44 cols 20-41
sup pos 9 6
```

## Paso 28 · nivel 4 · acción 116

**Pensamiento:**

The S piece is now at sup pos (9,6) rot 3 ✓ (bbox real rows 29-46... wait, the bbox was (29,20,46,43) → rows 29-46 = 18 rows?? Expected rows 29-44 (6 super rows = 18 real rows: 29 to 29+17 = 46 ✓). Yes, 6 super rows = 18 real rows → 29..46 ✓. And cols 20-43 = 24 real = 8 super cols ✓.
The S piece's tips are at (29,32)-(31,34) [red at sup (9,10)... hmm the image shows a red tip at the top-right of the S near the A piece] and another red tip at the bottom right (sup (14,13)).
Hmm, the target had C at (14,13) — and the S's tip is currently at (14,13)! Wait, in the target solution the S's tip at... whatever, the plan continues: C must go to (14,13).
Now: A needs 2 SPACE rotations (at (6,11)) — but the plan order was [A, S, B, C] and I did S first. Does the order matter? The plan's targets are absolute positions, and the BFS paths were computed with the other pieces at their (then-current) positions. Since I changed the order, the paths might be blocked. Let me recompute the plan dynamically: A: rot 2 at (6,11) (no move needed, just 2 SPACE); B: rot 0 at (9,15); C: rot 0 at (14,13).
Current state: S at rot 3 pos (9,6) ✓ done. A at rot 0 pos (6,11) → needs rot 2. B at rot 0 pos (13,14) → target (9,15). C at rot 0 pos (15,5) → target (14,13).
Order considerations: A must rotate in place (2 SPACE). Is the rotation blocked? A at (6,11) rot 0 dims 4x5 → rows 6-9, cols 11-15; rot 1 dims 5x4 → rows 6-10, cols 11-14; rot 2 dims 4x5 → rows 6-9, cols 11-15.
Does A's rotation sweep overlap t
… [621 caracteres más]

```python
V=L4()
cur={'S':{'rot':3,'pos':(9,6)},'A':{'rot':0,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
targets={'S':(3,(9,6)),'A':(2,(6,11)),'B':(0,(9,15)),'C':(0,(14,13))}
def bodies(st,V):
    d={}
    for k,v in st.items(): d[k]=cells3(V,k,v['rot'],v['pos'])
    return d
def ok(st,V,BR=19,BC=19):
    occ={}
    for k,(b,t) in bodies(st,V).items():
        for x in b:
            if x in occ: return False,(x,occ[x],k)
            occ[x]='B'+k
        for x in t:
            if x in occ and occ[x][0]=='B': return False,(x,occ[x],'T'+k)
            occ.setdefault(x,'T'+k)
    return True,None
print('current ok?',ok(cur,V))
import itertools
def build(st0,targets,order,V,BR=19,BC=19):
    import copy
    st=copy.deepcopy(st0); plan=[]
    for name in order:
        rt,pp=ta
… [1610 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 18, in <module>
  File "<python_tool>", line 10, in ok
  File "<python_tool>", line 6, in bodies
KeyError: 3
```

**Pensamiento:**

Bug: `V=L4()` returns a dict of piece DEFINITIONS (with 'body','tips','pos','H','W'), but cells3 expects V in the "variants" format (list of tuples). In the ok() call I passed V=L4() but cells3 indexes V[name][rot] expecting the variants list.
Let me use V=L4V() for cells3-based functions. Fix and rerun.

```python
V=L4V()
cur={'S':{'rot':3,'pos':(9,6)},'A':{'rot':0,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
targets={'S':(3,(9,6)),'A':(2,(6,11)),'B':(0,(9,15)),'C':(0,(14,13))}
print('current ok?',ok(cur,V))
def build(st0,targets,order,V,BR=19,BC=19):
    import copy
    st=copy.deepcopy(st0); plan=[]
    for name in order:
        rt,pp=targets[name]
        b,t=cells3(V,name,st[name]['rot'],st[name]['pos'])
        R,C=sorted(b)[len(b)//2]
        plan.append({'action':'MOUSE','row':3*R+2,'col':3*C+2})
        while st[name]['rot']!=rt:
            nr=(st[name]['rot']+1)%4
            st2=copy.deepcopy(st); st2[name]['rot']=nr
            good,info=ok(st2,V)
            if not good: return None,None,('rot-block',name,info)
            st=st2; plan.append('SPACE')
        v
… [1184 caracteres más]
```

```text
current ok? (True, None)
('A', 'B', 'C') FAIL ('rot-block', 'A', ((9, 11), 'TS', 'A'))
('A', 'C', 'B') FAIL ('rot-block', 'A', ((9, 11), 'TS', 'A'))
('B', 'A', 'C') FAIL ('move-block', 'B', ((9, 14), 'BA', 'TB'))
('B', 'C', 'A') FAIL ('move-block', 'B', ((9, 14), 'BA', 'TB'))
('C', 'A', 'B') FAIL ('
… [244 caracteres más]
```

## Paso 28 · nivel 4 · acción 118

**Pensamiento:**

My strict collision model (blocking a mover's BODY from overlapping other pieces' TIPS, and blocking rotations that put a tip on a body) is too strict — the game allows tips to overlap bodies. The failures:
- 'rot-block' A at (9,11) 'TS' vs 'A': A's rotation would put A's BODY? no — the error says cell (9,11) has 'TS' (S's tip) and the mover A has a body or tip there. Let me check: A at rot 1 pos (6,11) — its body/tip at (9,11)? And S's TIP is at (9,11)? Hmm, S at rot 3 pos (9,6): its tips are at... The S's tip currently visible in the image at sup (9,10)-ish (red near the A piece). So the conflict is A's cell vs S's tip.
If the game allows body-on-tip overlap, this isn't a real block. But I don't know whether body-on-tip is allowed. Evidence from level 3: the green's TIP overlapped the yellow's BODY (allowed). The reverse (body over tip) is untested.
- 'move-block' B at (9,14) 'BA' vs 'TB': B's tip on A's body → that's the same kind of allowed overlap (tip on body) → my ok() is too strict for the final state? Hmm, wait: in the TARGET solution, B's tip should pair with A's tip, not land on A's body. Let me look: the target has A at rot 2 pos (6,11) and B at rot 0 pos (9,15). B's tips at rot 0: (0,0),(5,0) → (9,15),(14,15). A at rot 2 pos (6,11): tips? A's rot 2 tips = rotate 180: (0,0)→(3,4), (0,4)→(3,0) → tips at (9,11) and (9,15) ✓. So B's tip (9,15) pairs with A's tip (9,15) ✓ good.
The reported conflict was during B's PATH (an intermediate position where B's tip was on A'
… [2044 caracteres más]

```python
r=action([{'action':'MOUSE','row':26,'col':38},{'action':'SPACE'}])
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason')})
bl=supblocks(current_frame,['c','p','Y','S','N','W'])
for col,n,s,pos,bb in bl:
    if n>9: print(col,n,'pos',pos,'bbox',bb)
G=grid2(current_frame)
print('red',[((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='R']])
```

```text
[action] batch of 2 actions, 2 executed: MOUSE(row=26, col=38), SPACE
{'executed': True, 'no_op': False}
c 243 pos (9, 5) bbox (29, 17, 49, 43)
c 144 pos (13, 14) bbox (41, 44, 58, 55)
N 81 pos (7, 11) bbox (23, 35, 31, 46)
red [(6, 14), (6, 14), (6, 14), (6, 14), (6, 14), (6, 14), (6, 14), (6, 14),
… [99 caracteres más]
```

## Paso 29 · nivel 4 · acción 125

**Pensamiento:**

Wait, something unexpected happened. The A piece (now selected, shown GREEN 'N' 81) rotated. Its bbox: (23,35)-(31,46) → super rows 7-9, cols 11-14 → 3 rows x 4 cols?? Hmm, that's the 'N' component only (81 px = 9 cells). But A's body is 9 cells ✓ (A's body = 9 cells). So A at rot 1: body rows 7-9, cols 11-14 (3x4) ✓ matches my rot1 computation (rows 1-3 → at pos 6 → rows 7-9 ✓, cols 0-3 → 11-14 ✓).
And the tips are at super (6,14) and (10,14) — red tips.
Hmm, but the 'c' 243 component at pos (9,5) bbox (29,17)-(49,43) — that's the S piece merged with...? 243 = 207 (S body) + ... hmm. The S piece is now DARK (unselected) and merged with the C bar? The C bar is at (47,17)-(49,25) = super (15,5-7). The S piece at rot 3 pos (9,6) → bbox rows 9-14, cols 6-13 → real rows 29-46, cols 20-41. The merged component bbox (29,17)-(49,43) covers both the S and the C bar (rows 47-49, cols 17-25) → they're touching/adjacent! And 243 = 207 + 27 (C bar 3 cells) + 9 (S's tips rendered dark) = 243 ✓.
So the S piece and the C bar are now adjacent (touching) — they merged into one dark component. That's fine (no overlap, just adjacency).
Hmm wait, is the C bar overlapping the S piece? The S's body at rot 3: let me check whether the S's bottom-left region touches the C bar at super (15,5),(15,6),(15,7). The S at rot 3 pos (9,6) occupies rows 9-14, cols 6-13 → the C bar at row 15, cols 5-7 is directly BELOW the S's bottom row (row 14) → adjacent, not overlapping ✓.
Hmm, but hold on: is the C bar's 
… [1467 caracteres más]

```python
V=L4V()
S={'rot':3,'pos':(9,6)}
b,t=cells3(V,'S',3,(9,6))
print('S body rows',min(x[0] for x in b),max(x[0] for x in b),'cols',min(x[1] for x in b),max(x[1] for x in b))
print('S tips',sorted(t))
cur={'S':{'rot':3,'pos':(9,6)},'A':{'rot':1,'pos':(6,11)},'B':{'rot':0,'pos':(13,14)},'C':{'rot':0,'pos':(15,5)}}
targets={'A':(2,(6,11)),'B':(0,(9,15)),'C':(0,(14,13))}
def okB(st,V):
    occ={}
    for k,v in st.items():
        b,t=cells3(V,k,v['rot'],v['pos'])
        for x in b:
            if x in occ: return False,(x,occ[x],k)
            occ[x]='B'+k
    return True,None
def build2(st0,targets,order,V,BR=19,BC=19):
    import copy
    st=copy.deepcopy(st0); plan=[]
    for name in order:
        rt,pp=targets[name]
        b,t=cells3(V,name,st[name]['rot'],st[name]['pos'])
        R,C=sort
… [1433 caracteres más]
```

```text
S body rows 9 14 cols 6 12
S tips [(9, 11), (14, 13)]
('A', 'B', 'C') 18 None
('A', 'C', 'B') 18 None
('B', 'A', 'C') 18 None
('B', 'C', 'A') 18 None
('C', 'A', 'B') 18 None
('C', 'B', 'A') 18 None
BEST 18 ['A', 'B', 'C']
[{'action': 'MOUSE', 'row': 26, 'col': 35}, 'SPACE', {'action': 'MOUSE', 'row'
… [171 caracteres más]
```

**Pensamiento:**

Confirmed: S's tips are at (9,11) and (14,13), and A's rot-1 body includes (9,11) → body-on-tip overlap IS allowed ✓ (the rotation happened).
Now the plan (18 actions), order [A, B, C]:
1. MOUSE(26,35) → select A (A's body cell: super (8,11) → real (26,35) ✓)
2. SPACE → A rot 2
3. MOUSE(50,47) → select B (super (16,15) ✓ B's body)
4. UP×4, RIGHT → B from (13,14) to (9,15) ✓
5. MOUSE(47,20) → select C (super (15,6) ✓ C's middle body cell)
6. RIGHT×7, UP, RIGHT → C from (15,5) to (14,13) ✓ (net +8 cols, -1 row)
Note: the final C position (14,13) — that's exactly where S's tip is → C's tip pairs with S's tip ✓.
One concern: when C moves right along row 15, does it pass through positions where its body overlaps the S body or the B body? The BFS handled that (blocking body-vs-body). And the final positions were verified by okB.
Also: the merged dark component (S + C touching) — after C moves away, they'll separate again.
Let me execute this plan. But note: the current selection is A already; the plan starts with MOUSE(26,35) which re-selects A (no-op? it's the same piece → clicking the same piece might DESELECT it (as in level 3, clicking the selected piece toggled it dark). In level 3, clicking the already-selected piece made it dark (deselected). Then clicking again re-selected. Hmm — does clicking a selected piece deselect it and make it unmovable? In level 3, after clicking the green (deselecting → dark), I pressed... nothing. Then clicked again → green again.
To be safe, sinc
… [529 caracteres más]

```python
r=action(['SPACE',{'action':'MOUSE','row':50,'col':47},'UP','UP','UP','UP','RIGHT'])
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason','level_completed')})
bl=supblocks(current_frame,['c','p','Y','S','N','W'])
for col,n,s,pos,bb in bl:
    if n>9: print(col,n,'pos',pos,'bbox',bb)
```

```text
[action] batch of 7 actions, 7 executed: SPACE, MOUSE(row=50, col=47), UP, UP, UP, UP, RIGHT
{'executed': True, 'level_completed': False, 'no_op': False}
c 333 pos (6, 5) bbox (20, 17, 49, 46)
```

**Nivel 4 completado → nivel 5 (acción 135)**

## Paso 30 · nivel 5 · acción 135

**Pensamiento:**

Progress: B (now ORANGE, selected) moved up 4 and right 1 → it connected to A: a GRAY joint appeared at super (9,15) ✓ (visible in the image as the gray block between the dark A piece and the orange B).
B's other tip is red at the bottom (super (14,15)... the image shows a red tip at the bottom-left of the orange piece).
The merged dark component 'c' 333 = S + C + A merged (all touching).
Now the last step: select C and move it RIGHT×7, UP, RIGHT to (14,13).
C is at (15,5) — its body cell is the middle (15,6) → real (47,20).
The plan: MOUSE(47,20), RIGHT×7, UP, RIGHT.
Wait, the plan from build2 was: MOUSE(47,20), RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, UP, RIGHT → 7 RIGHTs, UP, 1 RIGHT = net +8 cols, -1 row ✓ → (14,13) ✓.
Let me execute and check for level completion.

```python
r=action([{'action':'MOUSE','row':47,'col':20}]+['RIGHT']*7+['UP','RIGHT'])
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason','level_completed','game_over')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0],n['boundary'][-1])
```

```text
[action] batch of 10 actions, 10 executed: MOUSE(row=47, col=20), RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, RIGHT, UP, RIGHT | stop_reason: level_completed
{'executed': True, 'level_completed': True, 'game_over': False, 'no_op': False, 'stop_reason': 'level_completed'}
0 p 3749 [0, 0] [63, 0]
1 c 32
… [209 caracteres más]
```

## Paso 31 · nivel 5 · acción 135

**Pensamiento:**

Level 5! Background is purple 'p'. Objects:
- node 2 'c' 90 at (5,53)-(16,53): dark piece (top right).
- node 3 'Y' 36 at (14,26)-(22,26): yellow piece (selected) with 3 red tips (nodes 4,5,6) and one WHITE cell (node 7 'W' 9 at (23,26)).
Interesting! The yellow piece has 3 tips AND a white cell. The white cell is new — maybe a "special" cell (like a fixed/anchor cell, or a hole?).
- node 8 'c' 99 at (38,5)-(52,5): dark piece (left, "E" shape).
- node 9 'c' 54 at (47,47)-(55,47): dark piece (bottom right).
- node 1 'c' 32 at (0,16): HUD bar.
So 4 pieces again. The selected yellow piece: 36 px = 4 cells + 3 red tips (27) + 1 white cell (9) = 4+3+1 = 8 cells total.
Hmm, the white cell: in level 2, the ACTIVE piece was white. Here the piece is yellow with a white cell. Maybe the white cell is a "socket"/"pivot" marker? Or it's a piece of the assembly target?
Let me look at the shapes in detail.

```python
f=current_frame
G=grid2(f)
def reg(r0,r1,c0,c1,tag):
    print('--',tag)
    for r in range(r0,r1+1): print('%2d'%r,''.join(G[r][c] for c in range(c0,c1+1)))
reg(12,27,20,36,'yellow selected')
reg(3,18,50,63,'dark top-right')
reg(36,54,2,20,'dark E left')
reg(45,57,45,57,'dark bottom-right')
print('HUD',[ (n['color'],n['pixels'],n['boundary'][0]) for n in f.segmentation['nodes'] if n['pixels']<40 and n['boundary'][0][0]==0])
```

```text
-- yellow selected
12 ppppppppppppppppp
13 ppppppppppppppppp
14 ppppppYYYRRRppppp
15 ppppppYYYRRRppppp
16 ppppppYYYRRRppppp
17 pppRRRYYYpppppppp
18 pppRRRYYYpppppppp
19 pppRRRYYYpppppppp
20 ppppppYYYYYYRRRpp
21 ppppppYYYYYYRRRpp
22 ppppppYYYYYYRRRpp
23 ppppppWWWpppppppp
24 ppppppWWWpppppppp
25 ppppp
… [1079 caracteres más]
```

**Pensamiento:**

Level 5 pieces in super coords (real = 3s+2):
Yellow (selected): 
- rows 14-16 (super 4): cols 26-28 (super 8) = Y; cols 29-31 (super 9) = R (tip)
- rows 17-19 (super 5): cols 20-22 (super 6) = R (tip); cols 26-28 (super 8) = Y
- rows 20-22 (super 6): cols 26-31 (super 8,9) = Y; cols 32-34 (super 10) = R (tip)
- rows 23-25 (super 7): cols 26-28 (super 8) = W (white!)
So the yellow piece: body cells (super): (4,8),(5,8),(6,8),(6,9) + white (7,8); tips at (4,9),(5,6),(6,10).
The white cell is at (7,8) — attached below the body.
Dark top-right: 
- rows 5-16 (super 1-4): cols 53-55 (super 17) → wait: rows 5-16 = super 1,2,3,4 (rows 5-7=1, 8-10=2, 11-13=3, 14-16=4); cols 53-55 = super 17.
- rows 17-18 (super 5): cols 50-55 → hmm, 'cccccccc' = cols 50-57? The print shows row 17 'cccccccc' starting at index 0 = col 50 → cols 50-57. Hmm, that's 8 cells: super 16 (50-52) and super 17 (53-55) and then 56-57 partial? The print range was 50-63, and the row showed 'ccccccccpppppppp' → cols 50-57 are 'c'. Hmm, but super cells are 3-wide: col 50 → super 16 (50-52), col 53 → 17 (53-55), col 56 → 18 (56-58). So cols 50-57 spans super 16,17,18 partially → that can't be (pieces are aligned to the 3-grid).
Hmm, wait: the alignment might not be (r-2)%3 for this level! Let me check: the yellow piece's cells were at rows 14-16, cols 26-28 → (14-2)%3=0 ✓ aligned to the standard grid.
For the dark top-right: rows 5-16 → (5-2)%3 = 0 ✓ aligned (super rows 1-4). Cols: 53-55 → (53-2)%3 = 0 ✓ super 17. Th
… [1396 caracteres más]

```python
G=grid2(current_frame)
for r in range(15,21):
    print(r, ''.join(G[r][c] for c in range(46,62)))
print('    '+''.join(str(c%10) for c in range(46,62)))
for r in range(3,6):
    print(r, ''.join(G[r][c] for c in range(46,62)))
```

```text
15 pcccpppcccpppppp
16 pcccpppcccpppppp
17 pcccccccccpppppp
18 pcccccccccpppppp
19 pcccccccccpppppp
20 pppppppppppppppp
    6789012345678901
3 pppppppppppppppp
4 pppppppppppppppp
5 pppppppcccpppppp
```

**Pensamiento:**

Now with the correct column labels (46-61):
row 15: cols 47-49 = c, cols 53-55 = c
row 17: cols 46-56? Let me index: the string 'pccccccccccc' → position 0 = col 46 → 'p'; positions 1-11 = 'c' → cols 47-57. Hmm, 11 cells: cols 47-57. That's not a multiple of 3 (47-49, 50-52, 53-55, 56-57 partial).
Hmm! Wait, but rows 15-16 show 'c' at cols 47-49 (super 15) and 53-55 (super 17) — consistent with a U-shape. And row 17-19 has 'c' from 47 to 57 → super 15,16,17 + partial 18?
Hold on, maybe the last two chars are actually at cols 56,57 which belong to super 18 (56-58), and the print shows col 58 as 'p'... The string for row 17: 'pccccccccccc' + 'ppppp' → 1 'p' + 11 'c' + 4 'p' = 16 chars for cols 46-61. So cols 47-57 are 'c' and cols 58-61 are 'p'.
So the dark region ends at col 57 → the piece's bottom row spans super 15,16,17 fully (47-55) plus cols 56,57 (2 of the 3 cells of super 18).
That's strange. Unless... the piece's bottom row is 11 cells wide and the piece is NOT aligned to the 3x3 lattice in this level? But the vertical arms at rows 5-16 are at cols 47-49 and 53-55 (aligned).
Hmm, maybe the bottom row is actually 4 super cells wide (47-58) but one cell (col 58) is... no, col 58 is 'p'.
Let me look at the image: the top-right piece looks like a "U" with the left arm shorter... In the image, the top-right piece: a vertical bar at the top-left, a vertical bar at the top-right (longer), joined at the bottom by a horizontal bar. The bottom bar looks wider than the arms' span
… [917 caracteres más]

```python
G=grid2(current_frame)
rows=range(3,21); cols=range(44,62)
mask=[[1 if G[r][c]=='c' else 0 for c in cols] for r in rows]
for i,r in enumerate(rows): print(r,''.join('#' if v else '.' for v in mask[i]))
print('col sums', [sum(mask[i][j] for i in range(len(rows))) for j in range(len(cols))])
print('row sums', [sum(mask[i]) for i in range(len(rows))])
tot=sum(sum(m) for m in mask); print('total dark in region',tot)
```

```text
3 ..................
4 ..................
5 .........###......
6 .........###......
7 .........###......
8 ...###...###......
9 ...###...###......
10 ...###...###......
11 ...###...###......
12 ...###...###......
13 ...###...###......
14 ...###...###......
15 ...###...###......
16 ...###...###......
… [246 caracteres más]
```

## Paso 31 · nivel 5 · acción 138

**Pensamiento:**

Now I see the structure clearly (region rows 3-20, cols 44-61):
```
row 5-7:    cols 53-55 (#)
row 8-16:   cols 47-49 and 53-55
row 17-19:  cols 47-55
```
Wait, the row 17-19 line shows '...#########......' → 9 chars of '#' starting at index 3 = col 47 → cols 47-55 ✓ (9 = 3 super cells). My earlier reading was off by one because of the label offset.
So the top-right dark piece:
- super cols: 47-49 → 15; 50-52 → 16; 53-55 → 17.
- super rows: 5-7 → 1; 8-10 → 2; 11-13 → 3; 14-16 → 4; 17-19 → 5.
Cells: (1,17), (2,15),(2,17), (3,15),(3,17), (4,15),(4,17), (5,15),(5,16),(5,17) = 9 cells. Plus 1 more = 10 (90 px). Hmm, 9 cells = 81 px. But the total dark in the region = 90. Let me recount the row sums: rows 5,6,7 → 3 each (9 px); rows 8-16 (9 rows) → 6 each (54 px); rows 17,18,19 → 9 each (27 px). Total = 9+54+27 = 90 ✓.
In super cells: row 1 = 1 cell; rows 2,3,4 = 2 cells each = 6; row 5 = 3 cells → total 10 ✓ (90/9 = 10 ✓).
Shape (local, top-left at super (1,15)):
```
row0: ..#
row1: #.#
row2: #.#
row3: #.#
row4: ###
```
= 10 cells ✓. It's a "U" with an extra tall right arm.
The yellow piece: body (super, using (r-2)/3, (c-2)/3):
(4,8),(5,8),(6,8),(6,9) yellow; (7,8) white; tips (4,9),(5,6),(6,10).
Hmm, the white cell: it's part of the yellow piece (rendered white). What does it mean? Maybe it's a "hole"/"socket" cell — the piece has a cell that must NOT connect? Or maybe it's a "pivot" marker.
Hmm, in level 2 the active piece was entirely white. Here the active piece is yellow wi
… [2261 caracteres más]

```python
f=current_frame
for col in ('c','Y','W','R'):
    for c2,n,s,pos,bb in supblocks(f,[col]):
        H=max(x[0] for x in s)+1; W=max(x[1] for x in s)+1
        print('==',col,n,'px','pos',pos,'bbox',bb,H,'x',W)
        for r in range(H): print('   ',''.join('#' if (r,c) in s else '.' for c in range(W)))
```

```text
== c 90 px pos (1, 15) bbox (5, 47, 19, 55) 5 x 3
    ..#
    #.#
    #.#
    #.#
    ###
== c 99 px pos (12, 1) bbox (38, 5, 52, 13) 5 x 3
    ###
    #..
    ###
    #..
    ###
== c 54 px pos (15, 15) bbox (47, 47, 55, 55) 3 x 3
    #..
    #.#
    ###
== Y 36 px pos (4, 8) bbox (14, 26, 22, 31) 
… [247 caracteres más]
```

**Pensamiento:**

Now clear (the segmentation's boundary-based bbox differs from my print offsets; supblocks is authoritative):
Pieces:
- U (top-right dark): 10 cells at pos (1,15):
```
..#
#.#
#.#
#.#
###
```
- E (left dark): 11 cells at pos (12,1):
```
###
#..
###
#..
###
```
- L (bottom-right dark): 6 cells at pos (15,15):
```
#..
#.#
###
```
- Yellow (selected): body 4 cells at pos (4,8):
```
#.
#.
##
```
+ white cell at (7,8) + tips at (4,9),(5,7),(6,10).
Hmm, the yellow's body: (4,8),(5,8),(6,8),(6,9) = 4 cells; tips (4,9),(5,7),(6,10) — 3 tips; white (7,8).
Total yellow piece cells = 4 + 3 + 1 = 8.
Combined bbox: rows 4-7, cols 7-10 → 4x4.
Now the dark pieces' tips are unknown (rendered dark). Let me click each to reveal them: 3 clicks.
Note the white cell: it's attached to the yellow's body at (7,8), below (6,8). It might be a "connector" cell that must pair with something? Or the piece's shape includes a white cell that acts as a tip-like connector (a "socket"?).
Hypothesis: the white cell is a "plug" that must fit into a hole in another piece. Hmm.
Let me click the dark pieces to see their tips first.

```python
for (rr,cc),tag in [((6,54),'U'),((39,6),'E'),((48,48),'L')]:
    r=action([{'action':'MOUSE','row':rr,'col':cc}])
    G=grid2(current_frame)
    reds=sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='R']})
    wts=sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='W']})
    print(tag,{k:v for k,v in r.items() if k in ('no_op','gameplay_changed')},'red',reds,'white',wts)
```

```text
[action] MOUSE(row=6, col=54) -> effect
U {'gameplay_changed': True, 'no_op': False} red [(1, 17), (2, 15)] white []
[action] MOUSE(row=39, col=6) -> effect
E {'gameplay_changed': True, 'no_op': False} red [(12, 3), (14, 3), (16, 3)] white []
[action] MOUSE(row=48, col=48) -> effect
L {'gameplay_cha
… [69 caracteres más]
```

## Paso 32 · nivel 5 · acción 138

**Pensamiento:**

Tips data:
- U (pos (1,15), shape 5x3): tips at (1,17) → local (0,2) and (2,15) → local (1,0).
- E (pos (12,1), shape 5x3): tips at (12,3),(14,3),(16,3) → local (0,2),(2,2),(4,2) — 3 tips!
- L (pos (15,15), shape 3x3): tips at (15,15) → local (0,0) and (16,17) → local (1,2).
- Yellow (pos (4,8) body): tips (4,9),(5,7),(6,10) → local (0,1)... let me set the yellow's combined bbox: rows 4-7, cols 7-10 → 4x4, top-left (4,7). Body local: (4,8)→(0,1); (5,8)→(1,1); (6,8)→(2,1); (6,9)→(2,2); white (7,8)→(3,1); tips: (4,9)→(0,2); (5,7)→(1,0); (6,10)→(3,-1)?? 
Hmm: (6,10) → local row 6-4 = 2, col 10-7 = 3 → (2,3) ✓. And (5,7) → (1,0) ✓. And (4,9) → (0,2) ✓.
So the yellow's combined bbox: rows 4-7 (4), cols 7-10 (4) → 4x4 ✓.
Total tips: yellow 3 + U 2 + E 3 + L 2 = 10 → 5 connections.
The white cell: 1 cell. Hmm, what's its role? Maybe it's a "socket" that a tip can plug into? Or maybe it's just a differently-colored body cell (a marker).
Interesting thought: maybe the white cell is where a tip can connect WITHOUT a matching tip — i.e., a tip can connect to a white cell. That would explain the odd tip counts (3+3 on yellow and E).
Total tips 10 → 5 pairs, or some tips connect to white cells (1 white cell → 1 tip absorbed).
Hmm. Let me think about the total: if all 10 tips must pair among themselves → 5 connections. The parity: each piece's tip count: yellow 3, U 2, E 3, L 2. For a pairing where each pair is between two different pieces, the graph must have degrees 3,2,3,2 → possible: y
… [1659 caracteres más]

```python
def L5():
    return {
 'Y':{'body':[(0,1),(1,1),(2,1),(2,2),(3,1)],'tips':[(0,2),(1,0),(2,3)],'pos':(4,7),'H':4,'W':4},
 'U':{'body':[(1,2),(2,0),(2,2),(3,0),(3,2),(4,0),(4,1),(4,2)],'tips':[(0,2),(1,0)],'pos':(1,15),'H':5,'W':3},
 'E':{'body':[(0,0),(0,1),(1,0),(2,0),(2,1),(3,0),(4,0),(4,1)],'tips':[(0,2),(2,2),(4,2)],'pos':(12,1),'H':5,'W':3},
 'L':{'body':[(1,0),(2,0),(2,1),(2,2)],'tips':[(0,0),(1,2)],'pos':(15,15),'H':3,'W':3}}
def VARS(P):
    out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.append((i,frozenset(s['body']),frozenset(s['tips']),H,W))
            s,H,W=rot(s,H,W)
        out[k]=vs
    return out
def solve_all(P,V,fix,fixrot,fixpos,BR=19,BC=19,maxsol=400):
    s
… [1453 caracteres más]
```

```text
total sols 0
```

## Paso 32 · nivel 5 · acción 139

**Pensamiento:**

No solutions with all tips paired pairwise! So my model is wrong somewhere. Possibilities:
(a) The white cell is a "socket" that absorbs a tip (so one tip can connect to the white cell instead of another tip).
(b) A tip can connect to a body end (not just another tip).
(c) The white cell must be covered/occupied by something.
(d) My piece shapes/tips are wrong.
Let me reconsider. The white cell: in level 2, the ACTIVE piece was white. Hmm, here the yellow piece is selected (yellow) with one white cell. What if the white cell is a "hole" in the piece (i.e., not part of the piece — a marker on the background)? No, it's rendered as part of the piece's cluster.
Hmm, what if the white cell is a separate object: a 1-cell white token that is a "key"/"plug" piece? In level 2, the goal was to seat a plug. Here maybe the white cell is a separate 1-cell piece (a "dot") that must be placed into a socket!
Wait — the white cell is at (7,8), directly below the yellow's body cell (6,8). If it were a separate piece, it would be its own object (segmentation showed 'W' 9 px as its own node ✓). It IS its own node!
But is it a separate PIECE (movable) or attached to the yellow? Test: select the yellow and press an arrow; if the white cell stays, it's separate.
Also possible: the white cell is a "cursor"/"ghost" indicating where a piece should go? Hmm.
Let me test: click the yellow (it's already... currently L is selected). Let me click the yellow, press RIGHT, and see what moves.
Actually, better
… [148 caracteres más]

```python
r=action([{'action':'MOUSE','row':24,'col':27}])
print({k:v for k,v in r.items() if k in ('executed','no_op','gameplay_changed')})
for n in current_frame.segmentation['nodes']: print(n['id'],n['color'],n['pixels'],n['boundary'][0])
G=grid2(current_frame)
print('W cells',[(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='W'])
print('R',[(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='R'])
```

```text
[action] MOUSE(row=24, col=27) -> effect
{'executed': True, 'gameplay_changed': True, 'no_op': False}
0 p 3749 [0, 0]
1 W 1 [0, 16]
2 c 31 [0, 17]
3 c 90 [5, 53]
4 Y 36 [14, 26]
5 R 9 [14, 29]
6 R 9 [17, 23]
7 R 9 [20, 32]
8 W 9 [23, 26]
9 c 99 [38, 5]
10 c 54 [47, 47]
W cells [(0, 16), (23, 26), (2
… [350 caracteres más]
```

## Paso 33 · nivel 5 · acción 139

**Pensamiento:**

Clicking the white cell (24,27) selected the YELLOW piece again (it turned yellow with red tips; the L piece went back to dark). So the white cell click selected the yellow piece → the white cell IS part of the yellow piece ✓.
So the yellow piece has 5 body cells (4 yellow + 1 white) and 3 tips.
Now, since no solution exists with pure tip-tip pairing, the white cell must have a special role. Hypotheses:
(H1) The white cell is a "socket" that accepts a tip from another piece (so a tip can pair with the white cell).
(H2) The white cell must be covered by another piece's body cell.
Both are similar: the white cell acts like a "half-connector" that pairs with a tip.
With 10 tips and 1 white cell: if one tip pairs with the white cell, 9 tips remain → odd → impossible to pair all. So (H1) alone doesn't fix parity... unless the white cell can absorb 2 tips? Or the white cell absorbs 1 tip and... hmm, 10 tips: 1 absorbed by white → 9 left → odd. Not possible.
Unless a tip can pair with a BODY cell end. Hmm.
Let me reconsider: maybe I mis-identified a tip. Let me recheck the L piece's tips: (15,15) and (16,17). The L shape at pos (15,15): 
```
#..
#.#
###
```
tips (0,0) and (1,2) → body (1,0),(2,0),(2,1),(2,2) ✓ 4+2 = 6 ✓.
E: 11 cells, 3 tips, 8 body ✓.
U: 10 cells, 2 tips, 8 body ✓.
Y: 8 cells (5 body incl. white + 3 tips) ✓.
Total tips = 3+2+3+2 = 10 → 5 pairs ✓ even! Wait, 10 is even. So parity is fine for all-tip pairing. But no solution was found. Hmm, so maybe the constraint is 
… [1474 caracteres más]

```python
def solve_free(P,V,fix='E',maxsol=2000,BR=19,BC=19):
    sols=[]
    def place(var,pos):
        i,b,t,H,W=var; r0,c0=pos
        return frozenset((r+r0,c+c0) for r,c in b), frozenset((r+r0,c+c0) for r,c in t)
    names=[k for k in V if k!=fix]
    for fixrot in range(4):
        fb,ft=place(V[fix][fixrot],(0,0))
        def rec(occB,occT,placed,unpaired):
            if len(placed)==len(V):
                if not unpaired: sols.append((fixrot,{k:(v[0],v[1]) for k,v in placed.items()}))
                return
            nxt=names[len(placed)-1]
            for vi,var in enumerate(V[nxt]):
                cand=set()
                for (tr,tc) in var[2]:
                    for (ur,uc) in unpaired: cand.add((ur-tr,uc-tc))
                for pos in cand:
                    b,t=place(var,p
… [671 caracteres más]
```

```text
sols 0
uniq 0
```

**Pensamiento:**

Zero solutions even allowing arbitrary translations. So the pure tip-tip pairing model is definitely wrong for level 5. The white cell must matter.
New hypothesis: the white cell is a "hole"/"socket" that a TIP can plug into. Then the pairing rules are: tips pair with tips, OR a tip pairs with the white cell. With 10 tips and 1 white cell: 10 tips - 1 (absorbed) = 9 → odd → impossible. Unless the white cell can absorb 2 tips (e.g., it's a socket that one tip enters, but then the total would be 8 tips paired + ... no: if the white absorbs k tips, then 10-k must be even → k even → k=0 or 2. With k=0 → no solution found. So k=2: two tips plug into the white cell?! A single cell with 4 neighbors could accept up to 2 tips from opposite sides, or from any 2 sides.
Hmm, that seems odd. Alternative: maybe the yellow piece's white cell is NOT part of the yellow piece but a separate 1-cell piece that also has tips (invisible when unselected). Clicking it selected the yellow piece... but maybe that's because clicking a 1-cell piece adjacent to the yellow selected the yellow? Hmm, unlikely.
Wait, maybe the white cell IS a separate piece (a "dot") and clicking it selected IT (and the yellow's appearance is because... no, the yellow piece turned yellow with red tips = selected).
Hmm, let me re-examine: before my click, L was selected (orange). After clicking (24,27) [the white cell], the yellow piece is yellow with 3 red tips and the white cell is still white. If clicking the white cell ha
… [5780 caracteres más]

```python
st={'Y':{'rot':0,'pos':(4,7)},'U':{'rot':0,'pos':(1,15)},'E':{'rot':0,'pos':(12,1)},'L':{'rot':0,'pos':(15,15)}}
b,t=cells3(V,'Y',0,(4,7)); print('Y body',sorted(b),'tips',sorted(t))
r=action(['SPACE'])
bl=supblocks(current_frame,['Y','W','R'])
for col,n,s,pos,bb in bl: print(col,n,'pos',pos,'bbox',bb)
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 2, in <module>
NameError: name 'V' is not defined
```

## Paso 33 · nivel 5 · acción 140

**Pensamiento:**

The snippet failed before the action (V not defined) — no action was executed. Good.
Let me redo: rebuild V, then test the rotation of the yellow piece and observe the white cell's position.

```python
P=L5(); V=VARS(P)
def snap5(f):
    out={}
    for c2,n,s,pos,bb in supblocks(f,['Y','W','R','c','p']):
        if c2=='p' or n>15: continue
        out.setdefault(c2,[]).append((n,pos))
    return out
print('before',snap5(current_frame))
r=action(['SPACE'])
print({k:v for k,v in r.items() if k in ('executed','no_op','gameplay_changed')})
G=grid2(current_frame)
Y=sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='Y']})
Wt=sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='W' and r_>2]})
Rt=sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='R']})
print('Y',Y); print('W',Wt); print('R',Rt)
```

```text
before {'W': [(9, (7, 8))], 'R': [(9, (4, 9)), (9, (5, 7)), (9, (6, 10))]}
[action] SPACE -> effect
{'executed': True, 'gameplay_changed': True, 'no_op': False}
Y [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8)]
W [(8, 8)]
R [(4, 9), (5, 7), (6, 10), (7, 7)]
```

## Paso 34 · nivel 5 · acción 143

**Pensamiento:**

Very interesting! The SPACE press did NOT rotate the piece — it ADDED a tip! 
Before: Y body (4,8),(5,8),(6,8),(6,9),(7,8)[white]; tips (4,9),(5,7),(6,10).
After: Y body same; W at (8,8); tips (4,9),(5,7),(6,10),(7,7).
Wait, the white cell MOVED from (7,8) to (8,8)?? And a new red tip appeared at (7,7).
Hmm! Let me look at the diff image: the changed cells are at rows ~26-28 (super 8) and the tip at (7,7).
So after SPACE: the white cell is at (8,8) and there's a new red tip at (7,7) [left of (7,8)].
So the white cell moved DOWN by one and a red tip appeared where the white cell was?
Hmm, that means: the white cell is a "growing tip" that EXTENDED — i.e., the piece GREW: it added a cell at (7,8)→ now the body has (7,8)? Let me recheck the Y cells: Y = [(4,8),(5,8),(6,8),(6,9),(7,8)] — so (7,8) is now YELLOW (it was white before) and the white is now at (8,8), plus a new red tip at (7,7).
So the piece grew by one cell: the white cell (a "growth front"?) moved down one, converting the previous position to yellow, and a new tip appeared on the side.
Hmm, that's weird. Alternatively: SPACE = "extend/grow the piece by one cell in some direction"?
Wait. Let me reconsider. Maybe SPACE is not "rotate" in this level! Let me think about what changed:
- (7,8): W → Y
- (8,8): p → W (new white cell below)
- (7,7): p → R (new red tip to the left of (7,8))
Total: the piece gained 2 cells (the white moved down = +1 body cell effectively, and a new tip).
Hmm, so the piece grew downward by 1 ce
… [2219 caracteres más]

```python
def snapY(f):
    G=grid2(f)
    def S(col): return sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]==col]})
    return {'Y':S('Y'),'W':[x for x in S('W') if x[0]>2],'R':S('R')}
print(snapY(current_frame))
for i in range(3):
    r=action(['SPACE'])
    print(i,snapY(current_frame),{k:v for k,v in r.items() if k in ('no_op','gameplay_changed','level_completed')})
```

```text
{'Y': [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8)], 'W': [(8, 8)], 'R': [(4, 9), (5, 7), (6, 10), (7, 7)]}
[action] SPACE -> effect
0 {'Y': [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8), (8, 8), (8, 9), (8, 10), (8, 11)], 'W': [(9, 8)], 'R': [(4, 9), (5, 7), (6, 10), (7, 7), (8, 12)]} {'level_completed': Fals
… [593 caracteres más]
```

## Paso 35 · nivel 5 · acción 145

**Pensamiento:**

WOW. Now I understand: SPACE EXTENDS the piece! Each SPACE grows the piece by adding cells. Let me trace:
Step 0 (before any SPACE): body (4,8),(5,8),(6,8),(6,9) + white (7,8); tips (4,9),(5,7),(6,10).
After SPACE#1: body ...(7,8) yellow; white (8,8); new tip (7,7).
After SPACE#2: body adds (8,8),(8,9),(8,10),(8,11) [4 cells!]; white (9,8); new tip (8,12).
After SPACE#3: body adds (9,8); white (10,8); new tip (9,7).
After SPACE#4: body adds (10,8),(10,9),(10,10); white GONE (empty); new tip (10,11).
Hmm, the growth amounts vary: +1, +4, +1, +3. And the white cell moved down each time... then disappeared.
Hmm, wait. Maybe I'm misreading. Let me reconsider: maybe the piece is being DRAWN/extended by a "cursor" that moves. The white cell might be a "cursor" that moves down one row per SPACE and paints yellow cells along its path?!
Look: after SPACE#1, the white is at (8,8) and (7,8) became yellow.
After #2: white at (9,8), and row 8 got (8,8),(8,9),(8,10),(8,11) yellow.
Hmm, that's odd: the white moved down to (9,8) but the newly yellow cells are in row 8 extending right to col 11.
Hmm, so the "growth" isn't simply following the white cursor.
Alternative interpretation: the yellow piece is GROWING by adding a new "arm" each SPACE, and the arms alternate: down 1, right 4, down 1, right 3, ...
Actually let me look at the final image: the yellow piece looks like an "E" shape with 3 prongs pointing right and a spine going down:
```
(4,8)  Y R
(5,8) R Y
(6,8)  Y Y R  -> (6,9) + tip (
… [16121 caracteres más]

```python
for i in range(2):
    r=action(['SPACE'])
    print(i,snapY(current_frame),{k:v for k,v in r.items() if k in ('no_op','gameplay_changed','level_completed')})
```

```text
[action] SPACE -> effect
0 {'Y': [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8), (8, 8), (8, 9), (8, 10), (8, 11), (9, 8)], 'W': [(10, 8)], 'R': [(4, 9), (5, 7), (6, 10), (7, 7), (8, 12), (9, 7)]} {'level_completed': False, 'gameplay_changed': True, 'no_op': False}
[action] SPACE -> effect
1 {'Y': [(4, 8),
… [200 caracteres más]
```

## Paso 36 · nivel 5 · acción 148

**Pensamiento:**

Now this is very interesting: SPACE #5 (i=0) SHRANK the piece (removed (10,8),(10,9),(10,10) and the tip (10,11)), and SPACE #6 (i=1) shrank further (removed (9,8) and the tip (9,7)).
So SPACE is a TOGGLE/UNDO: it grows the piece, and pressing it again shrinks it back? Let's see the sequence:
state0 (initial): spine rows 4,5,6 + prong (6,9); tips 3.
S1: + (7,8), tip (7,7) → 4 tips
S2: + (8,8..11), tip (8,12) → 5 tips
S3: + (9,8), tip (9,7) → 6
S4: + (10,8..10), tip (10,11) → 7
S5: - (10,8..10), tip (10,11) → 6
S6: - (9,8), tip (9,7) → 5
So SPACE alternates grow/shrink?! Or maybe SPACE cycles through a sequence of "growth states" forward and backward — like a "retractable" piece.
Hmm, that's a strange mechanic. Unless... SPACE toggles between two growth steps each press? Like the piece is "telescoping".
Actually here's a cleaner hypothesis: SPACE extends the piece by one segment; but the segment added is the NEXT in a cyclic list, and the observed shrink is because... no.
Let me test: press SPACE 2 more times and see if it grows again (S7 = +?) — the pattern might be a sawtooth: grow to max then shrink to min, repeating. The max was 7 tips (4 prongs). Currently at 5 tips (3 prongs: rows 4,6,8).
Hmm, S4 gave the max (7 tips, white cell disappeared) — maybe the max growth is 7 tips = the number of dark tips, and after reaching the max the next SPACE shrinks.
Hmm, that would be a weird design. Alternatively the growth sequence is a fixed cycle of states and SPACE advances through
… [208 caracteres más]

```python
for i in range(3):
    r=action(['SPACE'])
    s=snapY(current_frame)
    print(i,len(s['R']),s['Y'],s['W'])
```

```text
[action] SPACE -> effect
0 4 [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8)] [(8, 8)]
[action] SPACE -> effect
1 3 [(4, 8), (5, 8), (6, 8), (6, 9)] [(7, 8)]
[action] SPACE -> effect
2 4 [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8)] [(8, 8)]
```

## Paso 37 · nivel 5 · acción 150

**Pensamiento:**

Confirmed ping-pong: the growth oscillates: ... 7 (max) → 6 → 5 → 4 → 3 (min) → 4 → 5 → ...
So SPACE moves the growth level ±1, bouncing between min=3 tips and max=7 tips.
Growth levels (number of tips): 3,4,5,6,7,6,5,4,3,4,5,...
Currently (after 9 SPACEs from the initial 3): let me count: S1..S4 → 7; S5,S6,S7,S8 → 3; S9 → 4. Current: 4 tips ✓ (matches the print: 4 tips).
So the growth level g ∈ {0,1,2,3,4} (0 = initial 3 tips), and SPACE toggles direction at the ends. I can control g by pressing SPACE the right number of times, but the direction state matters (I need to know the current direction).
Now, what determines the growth shape at each level?
g=0: body: spine rows 4,5,6 + (6,9); tips (4,9),(5,7),(6,10) [3 tips]
g=1: + (7,8), tip (7,7) → 4 tips
g=2: + (8,8),(8,9),(8,10),(8,11), tip (8,12) → 5
g=3: + (9,8), tip (9,7) → 6
g=4: + (10,8),(10,9),(10,10), tip (10,11) → 7
So the piece at g=4 has 7 tips = exactly the total of the dark pieces' tips (2+3+2=7).
And the growth shape is FIXED (the same at every visit). So the puzzle: choose the growth level g and the piece's position so that all the tips pair up with the dark pieces' tips.
Wait, but at g=4, do the yellow's tips all pair? The yellow has 7 tips at g=4 and the dark pieces have 7 tips total. So we need a perfect matching between the yellow's 7 tips and the darks' 7 tips.
But earlier my "all tips paired" solver (with the fixed initial yellow shape) found no solution — because the yellow's shape must be the grown one!
S
… [3045 caracteres más]

```python
r=action([{'action':'MOUSE','row':48,'col':48}])
before=snap5(current_frame)
r=action(['SPACE'])
after=snap5(current_frame)
print({k:v for k,v in r.items() if k in ('no_op','gameplay_changed')})
G=grid2(current_frame)
def S(col): return sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]==col]})
print('O/N cells',[c for c in 'NOp' if S(c) and c!='p'])
for c in 'NORcYW': 
    if S(c): print(c,S(c))
```

```text
[action] MOUSE(row=48, col=48) -> effect
[action] SPACE -> effect
{'gameplay_changed': True, 'no_op': False}
O/N cells ['O']
O [(15, 15), (15, 16), (16, 15), (17, 15)]
R [(15, 17), (17, 16)]
c [(-1, 5), (-1, 6), (-1, 7), (-1, 8), (-1, 9), (-1, 10), (-1, 11), (-1, 12), (-1, 13), (-1, 14), (-1, 15), (
… [289 caracteres más]
```

## Paso 38 · nivel 5 · acción 150

**Pensamiento:**

The L piece (now orange, selected) rotated with SPACE! Its new cells: O [(15,15),(15,16),(16,15),(17,15)] with tips R [(15,17),(17,16)].
Original L: body (1,0),(2,0),(2,1),(2,2) at pos (15,15) → body cells (16,15),(17,15),(17,16),(17,17); tips (15,15),(16,17).
After SPACE: body (15,15),(15,16),(16,15),(17,15); tips (15,17),(17,16).
So the L piece ROTATED (CW): the shape #../#.#/### rotated → let me verify: rot0 body (1,0),(2,0),(2,1),(2,2) + tips (0,0),(1,2). rot1 (H=3,W=3): body (1,0)→(0,1); (2,0)→(0,0); (2,1)→(1,0); (2,2)→(2,0); tips (0,0)→(0,2); (1,2)→(2,1). At pos (15,15): body (15,16),(15,15),(16,15),(17,15) ✓ tips (15,17),(17,16) ✓✓ PERFECT match.
So: the DARK pieces rotate with SPACE (as in previous levels), but the YELLOW piece GROWS with SPACE. Interesting — the yellow piece is special: it can't rotate, it grows.
Also note: the yellow piece currently is at g=1 (4 tips: after my oscillation, the last print showed 4 tips → g=1).
Now the puzzle: choose the yellow's growth level g ∈ {0..4} and position; the darks rotate/translate; all tips must pair.
Total tips: yellow (3+g... wait: g=0→3, g=1→4, g=2→5, g=3→6, g=4→7) and darks 7. For a perfect pairing, the yellow's tips must equal 7 (if all pair with darks) → g=4. But dark-dark pairs are also possible, so the yellow's tip count could be less: yellow tips 3+g... hmm, the number of yellow-dark pairs + 2*(dark-dark pairs) = 7 and yellow-dark pairs + 2*(yellow-yellow) = 3+g. Since yellow-yellow pairs are impossible (a piece 
… [2175 caracteres más]

```python
def YG(g):
    body=[(0,1),(1,1),(2,1),(2,2)]; tips=[(0,2),(1,0),(2,3)]; H=3; W=4
    add={1:([(3,1)],[(3,0)]),
         2:([(4,1),(4,2),(4,3),(4,4)],[(4,5)]),
         3:([(5,1)],[(5,0)]),
         4:([(6,1),(6,2),(6,3)],[(6,4)])}
    for k in range(1,g+1):
        b,t=add[k]; body=body+b; tips=tips+t
    H=max(r for r,c in body)+1
    H=max(H,max(r for r,c in tips)+1); W=max(W,max(c for r,c in body+tips)+1)
    return body,tips,H,W
for g in range(5): print(g,YG(g))
def DARK():
    return {'U':{'body':[(1,2),(2,0),(2,2),(3,0),(3,2),(4,0),(4,1),(4,2)],'tips':[(0,2),(1,0)],'H':5,'W':3},
            'E':{'body':[(0,0),(0,1),(1,0),(2,0),(2,1),(3,0),(4,0),(4,1)],'tips':[(0,2),(2,2),(4,2)],'H':5,'W':3},
            'L':{'body':[(1,0),(2,0),(2,1),(2,2)],'tips':[(0,0),(1,2)],'H':3,'W':3}}
def mkV
… [1294 caracteres más]
```

```text
0 ([(0, 1), (1, 1), (2, 1), (2, 2)], [(0, 2), (1, 0), (2, 3)], 3, 4)
1 ([(0, 1), (1, 1), (2, 1), (2, 2), (3, 1)], [(0, 2), (1, 0), (2, 3), (3, 0)], 4, 4)
2 ([(0, 1), (1, 1), (2, 1), (2, 2), (3, 1), (4, 1), (4, 2), (4, 3), (4, 4)], [(0, 2), (1, 0), (2, 3), (3, 0), (4, 5)], 5, 6)
3 ([(0, 1), (1, 1), (
… [417 caracteres más]
```

## Paso 38 · nivel 5 · acción 150

**Pensamiento:**

Excellent! Exactly ONE solution at g=4 (max growth):
- U at rot 3, pos (0,2) [relative to the yellow's anchor at (0,0)]
- E at rot 0, pos (1,-2)
- L at rot 3, pos (4,4)
where the yellow's local frame has its anchor at local (0,1) = the spine top.
Let me render this assembly to verify, then compute the absolute positions and the plan.
The yellow's local origin (0,0) is at the tip-column left; the spine is at col 1. Currently the yellow's spine top is at super (4,8) → the local origin (0,0) is at (4,7).
So with the yellow at origin (R,C):
- U at (R+0, C+2) rot 3
- E at (R+1, C-2) rot 0
- L at (R+4, C+4) rot 3
Current positions:
- U: pos (1,15) rot 0 → target rot 3, pos (R, C+2)
- E: pos (12,1) rot 0 → target rot 0, pos (R+1, C-2)
- L: pos (15,15) rot 1 (I rotated it once!) → target rot 3, pos (R+4, C+4)
- Y: origin (4,7) → g must be 4.
Constraints: all positions ≥ 0 and within the board (BR=BC=19), and the pieces must fit.
E at (R+1, C-2): E is 5x3 → needs C-2 ≥ 0 → C ≥ 2; and E's cols C-2..C → fine.
U at (R, C+2) rot 3: dims 3x5 → rows R..R+2, cols C+2..C+6.
L at (R+4, C+4) rot 3: dims 3x3 → rows R+4..R+6, cols C+4..C+6.
The yellow: rows R..R+6, cols C..C+5 (W=6).
Board: rows ≤ 19, cols ≤ 19.
The yellow's spine top currently at row 4 → R=4 gives rows 4-10 ✓. C=7 currently.
With R=4, C=7: E at (5,5) ✓ (that's what I predicted earlier!), U at (4,9) rot 3, L at (8,11) rot 3.
Let me check the board bounds: L at (8,11) rot3 dims 3x3 → rows 8-10, cols 11-13 ✓. U at (4,9) rot3 dims 3
… [1771 caracteres más]

```python
yb,yt,yH,yW=YG(4)
P=DARK(); V=mkV(P)
sol={'U':(3,(0,2)),'E':(0,(1,-2)),'L':(3,(4,4))}
def cellsL(name,rot,pos):
    var=V[name][rot]; r0,c0=pos
    return {(r+r0,c+c0) for r,c in var[1]},{(r+r0,c+c0) for r,c in var[2]}
def draw(R,C):
    W=20; H=20
    g=[['.']*W for _ in range(H)]
    for r,c in yb: g[r+R][c+C]='Y'
    for r,c in yt: g[r+R][c+C]='r'
    for k,(rt,pp) in sol.items():
        b,t=cellsL(k,rt,(pp[0]+R,pp[1]+C))
        for r,c in b: g[r][c]=k.lower()
        for r,c in t: g[r][c]='r'
    return '\n'.join(''.join(x) for x in g[:12])
print(draw(4,7))
cur={'Y':{'rot':0,'pos':(4,7)},'U':{'rot':0,'pos':(1,15)},'E':{'rot':0,'pos':(12,1)},'L':{'rot':1,'pos':(15,15)}}
tg={'U':(3,(0,2)),'E':(0,(1,-2)),'L':(3,(4,4))}
best=None
for R in range(0,14):
    for C in range(2,16):
        tt
… [758 caracteres más]
```

```text
....................
....................
....................
....................
........Yruuuu......
.....eerY....u......
.....e..YYruuu......
.....eerY...........
.....e..YYYYrl......
.....eerY....l......
........YYYrll......
....................
best cost 36 R 4 C 7
{'U': (3, (4, 9)), 'E': (0,
… [46 caracteres más]
```

**Pensamiento:**

The assembly looks like a nice closed ring:
```
........Yruuuu......
.....eerY....u......
.....e..YYruuu......
.....eerY...........
.....e..YYYYrl......
.....eerY....l......
........YYYrll......
```
All tips (r) pair up: U's tips pair with the yellow's right tips, E's tips with the yellow's left tips, L's tips with the yellow's bottom-right tips.
Wait, let me verify the pairing count: yellow has 7 tips; U 2, E 3, L 2 = 7 ✓.
The best translation is R=4, C=7 (the yellow doesn't move!) with cost 36 (rotations + moves).
Plan:
1. Click the yellow (need a body cell: e.g., the spine top (4,8) → real (14,26)).
2. SPACE ×3 (grow to g=4; assuming the state is level 1 dir up).
3. Click U, rotate 3 times (rot 0→3), move DOWN 3, LEFT 6 → to (4,9).
4. Click E, move UP 7, RIGHT 4 → to (5,5).
5. Click L, rotate 2 (rot 1→3), move UP 7, LEFT 4 → to (8,11).
Order matters for path planning (avoid collisions). Let me compute the paths with BFS using the "body can't overlap other bodies" rule (tips can overlap bodies).
Careful about the growth: growing while other pieces are in the way might be blocked. Currently the yellow is at (4,7) and grows down/right into empty space ✓ (the U is at rows 1-5 cols 15-17; the growth region is rows 4-10, cols 7-12 → clear ✓).
Also careful: the yellow's growth must happen before the U moves into place (the U's final position overlaps the growth area).
Let me now compute the full plan with build2-like logic but with the yellow having no rotation and the shapes fro
… [1014 caracteres más]

```python
def plan5(cur,tg,V,yb,yt,g_order,BR=19,BC=19):
    import copy
    st=copy.deepcopy(cur); plan=[]
    def shape(k):
        if k=='Y': return frozenset(yb),frozenset(yt)
        var=V[k][st[k]['rot']]; r0,c0=st[k]['pos']
        return frozenset((r+r0,c+c0) for r,c in var[1]),frozenset((r+r0,c+c0) for r,c in var[2])
    def bodies_all(exclude=None):
        s=set()
        for k in st:
            if k==exclude: continue
            b,t=shape(k); s|=b
        return s
    for name in g_order:
        rt,pp=tg[name]
        b,t=shape(name)
        R,C=sorted(b)[len(b)//2]
        plan.append({'action':'MOUSE','row':3*R+2,'col':3*C+2})
        if name!='Y':
            while st[name]['rot']!=rt:
                st[name]['rot']=(st[name]['rot']+1)%4
                b2,t2=shape(name)
         
… [1532 caracteres más]
```

```text
('E', 'U', 'L') 40 None
('E', 'L', 'U') 40 None
('U', 'E', 'L') 40 None
('U', 'L', 'E') 40 None
('L', 'E', 'U') 40 None
('L', 'U', 'E') 40 None
BEST 40 ['E', 'U', 'L']
[{'action': 'MOUSE', 'row': 14, 'col': 8}, {'action': 'MOUSE', 'row': 44, 'col': 8}, 'UP', 'UP', 'UP', 'UP', 'UP', 'RIGHT', 'RIGHT',
… [307 caracteres más]
```

## Paso 38 · nivel 5 · acción 154

**Pensamiento:**

The plan is 40 actions (including the yellow's click). Note: the plan's first action clicks the yellow (14,8) — that's a body cell of the yellow (super (4,2)?? hmm: (14-2)/3 = 4, (8-2)/3 = 2 → super (4,2) — that's NOT the yellow! The yellow's body is at cols 8-9.
The planner picked `sorted(b)[len(b)//2]` where b = the yellow's body at g=0 shape... wait no, in plan5 I used shape('Y') = (yb,yt) from YG(4) — the GROWN shape — but the yellow is currently at g=1! So the click cell computed from the g=4 shape is wrong.
Hmm, and the yellow's pos in my model is (4,7) (the local origin), but for the g=4 shape, sorted(b)[len(b)//2] gave a cell at super (4,2) → real (14,8). That's wrong for the current state.
Let me fix: for the yellow's click, use the CURRENT shape (g=1). Since the yellow doesn't move in the plan, I can just click a known current body cell: the spine top (4,8) → real (14,26).
Also important: the growth must happen while the yellow is selected. So: click the yellow, then 3 SPACEs (grow to g=4), then proceed.
But wait: my plan5 assumed the yellow is already at g=4 for the collision checks of the other pieces' paths — and the growth happens first, so that's consistent ✓.
Let me restructure the plan manually:
1. MOUSE(14,26) → select the yellow (spine top (4,8) ✓ body).
2. SPACE ×3 → g=4 (verify 7 tips).
3. E: MOUSE on E's body. E at (12,1) rot 0: body cells (12,1),(12,2),(13,1),(14,1),(14,2),(15,1),(16,1),(16,2) → pick (14,1) → real (44,5). The plan said MOUSE(44,8) → sup
… [3146 caracteres más]

```python
r=action([{'action':'MOUSE','row':14,'col':26},'SPACE','SPACE','SPACE'])
print({k:v for k,v in r.items() if k in ('executed','no_op','gameplay_changed','level_completed')})
s=snapY(current_frame); print('tips',len(s['R']),'Y',s['Y'],'W',s['W'])
```

```text
[action] batch of 4 actions, 4 executed: MOUSE(row=14, col=26), SPACE, SPACE, SPACE
{'executed': True, 'level_completed': False, 'gameplay_changed': True, 'no_op': False}
tips 7 Y [(4, 8), (5, 8), (6, 8), (6, 9), (7, 8), (8, 8), (8, 9), (8, 10), (8, 11), (9, 8), (10, 8), (10, 9), (10, 10)] W []
```

## Paso 39 · nivel 5 · acción 179

**Pensamiento:**

The yellow piece is at max growth (7 tips) ✓ exactly matching YG(4) ✓.
Now execute stage B (the E piece): MOUSE(44,8), UP×5, RIGHT×3, UP×2, RIGHT.
Then stage C (U): MOUSE(14,53), SPACE×3, DOWN×3, LEFT×6.
Then stage D (L): MOUSE(50,47), SPACE×2, UP×7, LEFT×4.
Let me batch B and C together, then verify, then D. Actually, let me batch B+C+D all at once? The risk: if something goes wrong mid-way, the batch continues (but the batch stops on a no-op). The plan was verified by the BFS. Let me batch B and C first (22 actions), verify, then D.

```python
r=action([{'action':'MOUSE','row':44,'col':8},'UP','UP','UP','UP','UP','RIGHT','RIGHT','RIGHT','UP','UP','RIGHT',
           {'action':'MOUSE','row':14,'col':53},'SPACE','SPACE','SPACE','DOWN','DOWN','DOWN','LEFT','LEFT','LEFT','LEFT','LEFT','LEFT'])
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason','level_completed')})
for c2,n,s,pos,bb in supblocks(current_frame,['c','Y','R']): print(c2,n,'pos',pos)
```

```text
[action] batch of 25 actions, 25 executed: MOUSE(row=44, col=8), UP, UP, UP, UP, UP, RIGHT, RIGHT, RIGHT, UP, UP, RIGHT, MOUSE(row=14, col=53), SPACE, SPACE, SPACE, DOWN, DOWN, DOWN, LEFT, LEFT, LEFT, LEFT, LEFT, LEFT
{'executed': True, 'level_completed': False, 'no_op': False}
c 234 pos (4, 5)
c 54
… [13 caracteres más]
```

**Nivel 5 completado → nivel 6 (acción 193)**

## Paso 40 · nivel 6 · acción 193

**Pensamiento:**

Progress: E moved to (5,5)... wait, the image shows the E piece (dark) connected to the yellow (which is now dark since unselected) and the U (sky blue = selected) connected with 2 gray joints ✓.
The 'c' 234 component at pos (4,5) = the merged E+Y+U cluster ✓ (they're connected).
The U is still selected (sky blue) — it's at (4,9) rot 3 ✓.
The L piece is still at (15,15) rot 1 (dark, bottom right).
Now stage D: click the L, rotate 2, up 7, left 4.
The L's body at rot 1: (15,15),(15,16),(16,15),(17,15) → click (16,15) → real (50,47) ✓.
Let me execute.

```python
r=action([{'action':'MOUSE','row':50,'col':47},'SPACE','SPACE','UP','UP','UP','UP','UP','UP','UP','LEFT','LEFT','LEFT','LEFT'])
print({k:v for k,v in r.items() if k in ('executed','no_op','stop_reason','level_completed','game_over')})
for c2,n,s,pos,bb in supblocks(current_frame,['c','Y','R','p']): print(c2,n,'pos',pos,'bbox',bb)
```

```text
[action] batch of 14 actions, 14 executed: MOUSE(row=50, col=47), SPACE, SPACE, UP, UP, UP, UP, UP, UP, UP, LEFT, LEFT, LEFT, LEFT | stop_reason: level_completed
{'executed': True, 'level_completed': True, 'game_over': False, 'no_op': False, 'stop_reason': 'level_completed'}
c 90 pos (1, 15) bbox (5
… [238 caracteres más]
```

## Paso 41 · nivel 6 · acción 195

**Pensamiento:**

Level 6! Background blue 'b'. Objects:
- A green piece (top-left, selected) with 3 red tips.
- 4 dark pieces.
So: 5 pieces total. The green is the "growable" piece (like the yellow in level 5).
Let me inspect the shapes precisely with supblocks, then click each dark piece to reveal tips.
Note: the green piece is already selected at level start (like the yellow was).
Let me get the shapes.

```python
f=current_frame
print('shape',f.shape,'level',f.level)
for c2,n,s,pos,bb in supblocks(f,['c','N','R','Y','W','p','O','G','b','S','M','P','r','w','B']):
    if c2=='b': continue
    H=max(x[0] for x in s)+1; W=max(x[1] for x in s)+1
    print('==',c2,n,'px pos',pos,'bbox',bb,H,'x',W)
    for r in range(H): print('   ',''.join('#' if (r,c) in s else '.' for c in range(W)))
```

```text
shape (64, 64) level 6
== c 90 px pos (1, 15) bbox (5, 47, 16, 58) 4 x 4
    ####
    #..#
    #..#
    ..##
== c 63 px pos (6, 6) bbox (20, 20, 34, 28) 5 x 3
    ..#
    .##
    ##.
    .#.
    .#.
== c 63 px pos (12, 1) bbox (38, 5, 55, 10) 6 x 2
    #.
    #.
    #.
    #.
    #.
    ##
== c 144 
… [358 caracteres más]
```

**Pensamiento:**

Level 6 pieces:
- Green (selected): body 11 cells at pos (1,1) [5x5]:
```
#####
#...#
#....
#....
##...
```
minus the tips... wait, supblocks with 'N' gave the body only (99 px = 11 cells) and the tips are separate R nodes at (3,5),(5,3),(6,1).
Hmm, but the 'N' shape includes (0,4) which is at (1,5)... and the tip at (3,5) is at local (2,4). Let me map: pos (1,1) → local (r,c) = (R-1, C-1).
Tips: (3,5) → (2,4); (5,3) → (4,2); (6,1) → (5,0).
So the green's combined bbox: rows 1-6 (6), cols 1-5 (5). Body 11 + 3 tips = 14 cells.
- Dark A (top-right) 4x4 at (1,15):
```
####
#..#
#..#
..##
```
10 cells.
- Dark B (middle) 5x3 at (6,6):
```
..#
.##
##.
.#.
.#.
```
9 cells (63 px ✓).
- Dark C (left) 6x2 at (12,1):
```
#.
#.
#.
#.
#.
##
```
7 cells.
- Dark D (bottom) 5x6 at (14,9):
```
..#.#.
..#.#.
.##.##
##...#
.#####
```
16 cells (144 px ✓).
Total dark cells: 10+9+7+16 = 42; green 14 (incl. tips).
Now let me click each dark piece to reveal its tips. Then figure out the growth pattern of the green (press SPACE and observe).
Let me click the 4 dark pieces one at a time and record the red cells.

```python
def reds(f):
    G=grid2(f)
    return sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]=='R']})
for (rr,cc),tag in [((6,50),'A_topright'),((22,23),'B_mid'),((40,6),'C_left'),((46,32),'D_bottom')]:
    r=action([{'action':'MOUSE','row':rr,'col':cc}])
    print(tag,{k:v for k,v in r.items() if k=='no_op'},reds(current_frame))
```

```text
[action] MOUSE(row=6, col=50) -> effect
A_topright {'no_op': False} [(3, 15), (4, 17)]
[action] MOUSE(row=22, col=23) -> NO-OP (executed, no change inside the board area)
B_mid {'no_op': True} [(3, 15), (4, 17)]

error:
Traceback (most recent call last):
  File "<python_tool>", line 5, in <module>
S
… [483 caracteres más]
```

## Paso 42 · nivel 6 · acción 198

**Pensamiento:**

The click at (22,23) was a no-op — that cell is the middle piece B at (6,6) 5x3: its cells are at super rows 6-10, cols 6-8. Real cell for super (6,8) = row 20, col 26. My click (22,23) → super ((22-2)/3, (23-2)/3) = (6,7) → is (6,7) part of B? B's shape row 0 = '..#' → only (6,8). So (6,7) is empty → no-op ✓.
Careful: clicks must be on actual piece cells.
A's tips: (3,15),(4,17) → A at pos (1,15) 4x4 → local (2,0),(3,2).
Let me now click B, C, D with correct cells:
B at (6,6): cells (6,8),(7,7),(7,8),(8,6),(8,7),(9,7),(10,7) → click super (9,7) → real (29,23).
C at (12,1): cells (12,1)...(16,1),(16,2) → click super (14,1) → real (44,5).
D at (14,9): shape 5x6: row0: (14,11),(14,13); row1: (15,11),(15,13); row2: (16,10),(16,11),(16,14),(16,15); row3: (17,9),(17,10),(17,15); row4: (18,10..14) → click super (18,12) → real (56,38).
Let me click them one at a time (with a check that each is not a no-op).

```python
for (rr,cc),tag in [((29,23),'B'),((44,5),'C'),((56,38),'D')]:
    r=action([{'action':'MOUSE','row':rr,'col':cc}])
    print(tag,{k:v for k,v in r.items() if k=='no_op'},reds(current_frame))
```

```text
[action] MOUSE(row=29, col=23) -> effect
B {'no_op': False} [(6, 8), (8, 6)]
[action] MOUSE(row=44, col=5) -> effect
C {'no_op': False} [(12, 1), (17, 2)]
[action] MOUSE(row=56, col=38) -> effect
D {'no_op': False} [(14, 11), (14, 13), (17, 9)]
```

## Paso 43 · nivel 6 · acción 199

**Pensamiento:**

Interesting! The D piece (bottom, now selected, shown purple 'p'-ish? it's rendered as pink/purple) has 3 tips: (14,11),(14,13),(17,9) — and a WHITE cell! Looking at the image, there's a white cell in the D piece's bottom row (at about super (18,12)).
Hmm wait, the 'W' node wasn't listed in my earlier supblocks scan... Actually I did include 'W' in the scan list and no W node appeared. So the white cell appeared only now — when the piece is selected?! 
Hmm no. Let me look again: in the level-5 game, the yellow (growable) piece had a white cell = the growth cursor. Here the D piece has a white cell when selected → D is ALSO a growable piece?!
Hmm, but the green piece also has 3 tips and no white cell (it was selected at the start... let me check: at the start, the green was selected and I saw no white cell in the supblocks scan ('W' wasn't in the output list — I did include 'W' in the color list and got no W entry).
Hmm! But wait: the green piece's tips are (3,5),(5,3),(6,1) = 3 tips. And now D has 3 tips + 1 white cell.
Hmm, so maybe the white cell is a "growth front" for a piece that can grow. Let me check whether the D piece grows with SPACE.
Wait, actually, maybe the white cell IS part of the D piece's body and it's a "hole" marker. Let me look at the D piece's shape from the image:
```
row 14: . . # . # .      tips at (14,11),(14,13) [the two red cells at the top]
row 15: . . # . # .
row 16: . # # . # #
row 17: # # . . . #      tip at (17,9)
row 18: . # # W # #      white
… [2072 caracteres más]

```python
def snapN(f):
    G=grid2(f)
    def S(col): return sorted({((x[0]-2)//3,(x[1]-2)//3) for x in [(r_,c_) for r_ in range(64) for c_ in range(64) if G[r_][c_]==col]})
    return {'N':S('N'),'W':[x for x in S('W') if x[0]>2],'R':S('R'),'p':[x for x in S('p') if x[0]>2]}
print(snapN(current_frame))
r=action(['SPACE'])
s=snapN(current_frame)
print('after space',{k:v for k,v in r.items() if k in ('no_op','gameplay_changed')})
for k,v in s.items():
    if v: print(k,len(v),v)
```

```text
{'N': [], 'W': [(18, 12)], 'R': [(14, 11), (14, 13), (17, 9)], 'p': [(15, 11), (15, 13), (16, 10), (16, 11), (16, 13), (16, 14), (17, 10), (17, 14), (18, 10), (18, 11), (18, 13), (18, 14)]}
[action] SPACE -> effect
after space {'gameplay_changed': True, 'no_op': False}
W 1 [(18, 13)]
R 3 [(14, 11), 
… [154 caracteres más]
```

## Paso 44 · nivel 6 · acción 203

**Pensamiento:**

Hmm, the diff image is confusing (it shows some cells as blue = the background color, meaning they changed to background). Let me carefully compare before/after:
Before SPACE: p cells (12): (15,11),(15,13),(16,10),(16,11),(16,13),(16,14),(17,10),(17,14),(18,10),(18,11),(18,13),(18,14); W (18,12); R (14,11),(14,13),(17,9).
After SPACE: p cells (13): (15,11),(15,14),(16,10),(16,11),(16,14),(16,15),(17,10),(17,15),(18,10),(18,11),(18,12),(18,14),(18,15); W (18,13); R (14,11),(14,14),(17,9).
Hmm! The piece changed shape significantly: it looks like the RIGHT part of the piece shifted right by 1!
Before: right arm at cols 13-14: (15,13),(16,13),(16,14),(17,14),(18,13),(18,14).
After: right arm at cols 14-15: (15,14),(16,14),(16,15),(17,15),(18,14),(18,15) + (18,12) became pink.
And the white cell moved from (18,12) to (18,13).
So: the white cell moved RIGHT by 1, and the piece's right portion shifted right by 1 → i.e., the piece GREW horizontally: the white cell acts like a "expander" that pushes the part of the piece to its right?
Hmm, that's like the piece is being "stretched": the white cell is a gap that moves right, and everything to the right of the white cell shifts right by one.
Interesting! In level 5, the growth was: the white cell moved down and the piece grew.
Actually, maybe the mechanic is: the white cell is a "1-cell insertion" that moves along the piece's "spine" path, and as it moves it inserts a cell into the piece.
Let me think of level 5 again with this model: 
… [1250 caracteres más]

```python
for i in range(4):
    r=action(['SPACE'])
    s=snapN(current_frame)
    print(i,'W',s['W'],'R',s['R'])
    print('  p',s['p'])
```

```text
[action] SPACE -> effect
0 W [(18, 14)] R [(14, 11), (14, 15), (17, 9)]
  p [(15, 11), (15, 15), (16, 10), (16, 11), (16, 15), (16, 16), (17, 10), (17, 16), (18, 10), (18, 11), (18, 12), (18, 13), (18, 15), (18, 16)]
[action] SPACE -> effect
1 W [] R [(14, 11), (14, 16), (17, 9)]
  p [(15, 11), (15,
… [569 caracteres más]
```

## Paso 45 · nivel 6 · acción 205

**Pensamiento:**

The D piece oscillates: the "stretch" grows and shrinks. Sequence of states (by the white cell's col / the right arm's offset):
state0 (initial): right arm at cols 13-14, white at 12 → offset 0
state1: white 13, arm at 14-15 → offset 1
state2: white 14, arm 15-16 → offset 2
state3: white gone (max), arm 16-17 → offset 3
state4: white 14 → offset 2
state5: white 13 → offset 1 (current)
So the D piece "stretches" horizontally: the right part slides right, inserting cells into the bottom row. Ping-pong like level 5 ✓ Same mechanic family.
So the D piece is a "stretchable" piece. The green piece: does it stretch too? The green had 3 tips and no white cell... Hmm. But wait — maybe the green piece is a NORMAL (rotatable) piece and there are 4 stretchable... no.
Hmm, in level 5: the yellow (yellow = growable) + 3 dark (rotatable). Here: D is stretchable, and the other 4 (green, A, B, C) are rotatable? But the green is not dark-colored... it was rendered green at the start = "selected" color? In level 5, the selected piece was rendered yellow. Hmm! In level 5, the yellow piece was the selected piece AND the growable one. Was the yellow color = selection color or the piece's own color?
Let me check: in level 5, when I clicked a dark piece, it turned ORANGE (the L piece turned orange when selected). So the selection color varies per piece? The L turned orange when selected; the U turned sky-blue when selected. So each piece has its own "selected" color. So the green piece's own color i
… [1701 caracteres más]

```python
r=action([{'action':'MOUSE','row':5,'col':5}])
print('click green',{k:v for k,v in r.items() if k=='no_op'})
before=snapN(current_frame); print('before',{k:v for k,v in before.items() if v})
r=action(['SPACE'])
after=snapN(current_frame); print('after',{k:v for k,v in r.items() if k=='no_op'})
for k,v in after.items():
    if v: print(k,len(v),v)
```

```text
[action] MOUSE(row=5, col=5) -> effect
click green {'no_op': False}
before {'N': [(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 5), (3, 1), (4, 1), (5, 1), (5, 2)], 'R': [(3, 5), (5, 3), (6, 1)]}
[action] SPACE -> effect
after {'no_op': False}
N 11 [(1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 
… [72 caracteres más]
```

## Paso 46 · nivel 6 · acción 205

**Pensamiento:**

The green piece rotated (mirrored shape). Before: body (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,5),(3,1),(4,1),(5,1),(5,2); tips (3,5),(5,3),(6,1).
After: body (1,2),(1,3),(1,4),(1,5),(1,6),(2,2),(2,6),(3,6),(4,6),(5,5),(5,6); tips (1,1),(3,2),(5,4).
Hmm, the piece moved right by 1 (its bbox shifted from cols 1-5 to cols 1-6 → wait, the tips: before (6,1) is at row 6; after there's no row-6 cell. Let me see: after body rows 1-5, cols 2-6; tips (1,1),(3,2),(5,4).
Hmm, the rotation happened about some anchor and the piece's bbox changed from 5x5 (rows 1-6? the tip (6,1) made it 6 rows) to 5x6.
Anyway: the green ROTATES ✓. So the green is a normal rotatable piece.
So level 6: 4 rotatable pieces (green, A, B, C) + 1 stretchable piece (D).
Now the goal: same as level 5 — pair all tips.
Tips: green 3, A 2, B 2, C 2, D 3 = 12 → 6 pairs.
Now I need the pieces' shapes and tip positions, and D's stretch states (offset 0..3, with the shape known for each).
Let me define all pieces in local coords:
GREEN (rot 0, pos = top-left of the shape bbox). I'll use the state after 1 rotation? No — let me use the ORIGINAL (rot 0) as seen at the level start:
body: (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,5),(3,1),(4,1),(5,1),(5,2) at pos (1,1) → local: (0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1); tips: (3,5)→(2,4), (5,3)→(4,2), (6,1)→(5,0).
So the green's local frame (with the tip at (5,0) needing row 5 and the tip at (2,4) needing col 4): H=6, W=5, body local: (0,0),(0,1),(0,2),(0
… [8351 caracteres más]

```python
def L6():
    P={}
    P['G']={'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1)],
            'tips':[(2,4),(4,2),(5,0)],'H':6,'W':5}
    P['A']={'body':[(0,0),(0,1),(0,2),(0,3),(1,0),(1,3),(2,3),(3,3)],
            'tips':[(2,0),(3,2)],'H':4,'W':4}
    P['B']={'body':[(1,1),(1,2),(2,1),(3,1),(4,1)],
            'tips':[(0,2),(2,0)],'H':5,'W':3}
    P['C']={'body':[(1,0),(2,0),(3,0),(4,0)],
            'tips':[(0,0),(5,1)],'H':6,'W':2}
    return P
def D6(k):
    b=[(1,2),(2,1),(2,2),(3,1),(4,1),(4,2)]
    arm=[(1,2+k),(2,3+k),(2,4+k),(3,4+k),(4,3+k),(4,4+k)]
    for j in range(k): arm=arm+[]
    body=b+arm
    fill=[(4,3+j) for j in range(k)]
    body=body+fill
    tips=[(0,2),(0,2+k),(3,0)]
    H=5; W=5+k
    return {'body':sorted(set(body)),'tips':tips,'H':H,'W'
… [37 caracteres más]
```

```text
0 {'body': [(1, 2), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 4), (4, 1), (4, 2), (4, 3), (4, 4)], 'tips': [(0, 2), (0, 2), (3, 0)], 'H': 5, 'W': 5}
1 {'body': [(1, 2), (1, 3), (2, 1), (2, 2), (2, 4), (2, 5), (3, 1), (3, 5), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5)], 'tips': [(0, 2), (0, 3), (3, 0)]
… [375 caracteres más]
```

## Paso 46 · nivel 6 · acción 205

**Pensamiento:**

My D6 reconstruction is buggy (k=0 has duplicate tips and wrong cells). Let me rebuild it directly from the observed data (super coords, bbox top-left (14,9)):
k=0: body(12)+white(1) = {(15,11),(15,13),(16,10),(16,11),(16,13),(16,14),(17,10),(17,14),(18,10),(18,11),(18,12),(18,13),(18,14)}
 → local: (1,2),(1,4),(2,1),(2,2),(2,4),(2,5),(3,1),(3,5),(4,1),(4,2),(4,3),(4,4),(4,5)
 tips: (0,2),(0,4),(3,0). W=6 (max col 5).
k=1: body(13)+white(1) = {(15,11),(15,14),(16,10),(16,11),(16,14),(16,15),(17,10),(17,15),(18,10),(18,11),(18,12),(18,13),(18,14),(18,15)}
 → local: (1,2),(1,5),(2,1),(2,2),(2,5),(2,6),(3,1),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
 tips: (0,2),(0,5),(3,0). W=7.
k=2: local: (1,2),(1,6),(2,1),(2,2),(2,6),(2,7),(3,1),(3,7),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7) → wait, the observed k=2 body was: (15,11),(15,15),(16,10),(16,11),(16,15),(16,16),(17,10),(17,16),(18,10),(18,11),(18,12),(18,13),(18,15),(18,16) + white (18,14).
 → local: (1,2),(1,6),(2,1),(2,2),(2,6),(2,7),(3,1),(3,7),(4,1),(4,2),(4,3),(4,4),(4,5),(4,7) + white (4,6)
 tips: (0,2),(0,6),(3,0). W=8.
k=3: observed: (15,11),(15,16),(16,10),(16,11),(16,16),(16,17),(17,10),(17,17),(18,10),(18,11),(18,12),(18,13),(18,14),(18,15),(18,16),(18,17)
 → local: (1,2),(1,7),(2,1),(2,2),(2,7),(2,8),(3,1),(3,8),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7),(4,8)
 tips: (0,2),(0,7),(3,0). W=9.
So the pattern: left part fixed: (1,2),(2,1),(2,2),(3,1),(4,1),(4,2); bottom row filled (4,3..4,2+k); right arm: (1,2+k),(2,3+k),
… [529 caracteres más]

```python
def D6(k):
    obs={
    0:[(1,2),(1,4),(2,1),(2,2),(2,4),(2,5),(3,1),(3,5),(4,1),(4,2),(4,3),(4,4),(4,5)],
    1:[(1,2),(1,5),(2,1),(2,2),(2,5),(2,6),(3,1),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)],
    2:[(1,2),(1,6),(2,1),(2,2),(2,6),(2,7),(3,1),(3,7),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7)],
    3:[(1,2),(1,7),(2,1),(2,2),(2,7),(2,8),(3,1),(3,8),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7),(4,8)]}
    return {'body':obs[k],'tips':[(0,2),(0,2+k),(3,0)],'H':5,'W':6+k}
for k in range(4):
    d=D6(k); print(k,len(d['body']),d['tips'],d['W'])
P=L6()
def mkV6(P,D):
    out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.append((i,frozenset(s['body']),frozenset(s['tips']),H,W)); s,H,W=r
… [1216 caracteres más]
```

```text
0 13 [(0, 2), (0, 2), (3, 0)] 6
1 14 [(0, 2), (0, 3), (3, 0)] 7
2 15 [(0, 2), (0, 4), (3, 0)] 8
3 16 [(0, 2), (0, 5), (3, 0)] 9
sols 0
```

**Pensamiento:**

The D6 function is the retained (old buggy) version? No — the tool says it retained my new D6. But the printout shows tips [(0,2),(0,2),(3,0)] for k=0 — that's from `[(0,2),(0,2+k),(3,0)]` with k=0 → (0,2),(0,2) duplicated. Right, for k=0 the two top tips coincide in my hardcoded... but the OBSERVED k=0 tips were (14,11) and (14,13) → local (0,2) and (0,4)! Not (0,2+k).
Let me recheck the observed tips per k:
- k=0 (initial, before any SPACE): R = (14,11),(14,13),(17,9) → local (0,2),(0,4),(3,0).
- After 1 SPACE (k=1): R = (14,11),(14,14),(17,9) → local (0,2),(0,5),(3,0).
- k=2: (14,11),(14,15) → (0,2),(0,6).
- k=3: (14,11),(14,16) → (0,2),(0,7).
So the second tip's local col = 4+k (not 2+k). Hmm, but wait: which one is "the moving tip"? The right tip at (14,13) at k=0 is at local col 4; the right arm at k=0 spans cols 13-14 (local 4,5). So the tip sits above the arm's left cell.
So tips = [(0,2),(0,4+k),(3,0)] ✓.
Also the body: at k=0 the body includes (1,4) [the cell below the tip] ✓ consistent with my hardcoded obs[0] which has (1,4) ✓.
Let me fix the tips formula and re-solve.

```python
def D6(k):
    obs={
    0:[(1,2),(1,4),(2,1),(2,2),(2,4),(2,5),(3,1),(3,5),(4,1),(4,2),(4,3),(4,4),(4,5)],
    1:[(1,2),(1,5),(2,1),(2,2),(2,5),(2,6),(3,1),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)],
    2:[(1,2),(1,6),(2,1),(2,2),(2,6),(2,7),(3,1),(3,7),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7)],
    3:[(1,2),(1,7),(2,1),(2,2),(2,7),(2,8),(3,1),(3,8),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(4,7),(4,8)]}
    return {'body':obs[k],'tips':[(0,2),(0,4+k),(3,0)],'H':5,'W':6+k}
s6=solve6()
print('sols',len(s6))
for s in s6[:8]: print(s)
```

```text
sols 0
```

## Paso 46 · nivel 6 · acción 210

**Pensamiento:**

No solutions with the green fixed at rot 0. But the green can rotate! I fixed V['G'][0] (rot 0). I should try all 4 rotations of the green as the anchor. Let me modify solve6 to try each rotation of the fixed piece.
Also, maybe my assumption "all tips must pair" is wrong. Let me first try all rotations of the anchor.

```python
def solve6b(fixname='G',fixrot=0):
    P=L6(); V=mkV6(P,D6)
    names=[n for n in ['G','A','B','C','D'] if n!=fixname]
    fv=V[fixname][fixrot]
    sols=[]
    def rec(occB,occT,placed,unpaired,idx):
        if idx==len(names):
            if not unpaired: sols.append({fixname:(fixrot,(0,0)),**placed})
            return
        nxt=names[idx]
        for var in V[nxt]:
            cand=set()
            for (tr,tc) in var[2]:
                for (ur,uc) in unpaired: cand.add((ur-tr,uc-tc))
            for pos in cand:
                r0,c0=pos
                b=frozenset((r+r0,c+c0) for r,c in var[1]); t=frozenset((r+r0,c+c0) for r,c in var[2])
                if b&(occB|occT) or t&occB: continue
                nu=(unpaired|set(t))-(unpaired&set(t))
                p2=dict(placed); p2[n
… [281 caracteres más]
```

```text
Grot 0 sols 0
Grot 1 sols 0
Grot 2 sols 0
Grot 3 sols 0
```

**Pensamiento:**

No solutions. Hmm. So my "all tips must pair" model is wrong for level 6, or one of my shape/tip readings is wrong.
Let me double check the pieces' tip readings. A concern: for the pieces A, B, C, I read the tips by clicking them. But when I clicked A, the previous selection was the green (whose tips were red). Clicking A should switch the red tips to A's. The reds after clicking A = [(3,15),(4,17)] ✓ only 2 → A has 2 tips ✓.
After clicking B: [(6,8),(8,6)] ✓ 2 tips.
After clicking C: [(12,1),(17,2)] ✓ 2.
After clicking D: [(14,11),(14,13),(17,9)] ✓ 3.
Green: [(3,5),(5,3),(6,1)] → after 1 rotation: [(1,1),(3,2),(5,4)] ✓ 3.
Total 12 tips → 6 pairs. Hmm.
Maybe the pieces' bodies I derived are wrong. Let me re-derive carefully using the CURRENT frame: click each piece, then read its colored cells (the selected piece is rendered in its own color) + red tips.
That's the cleanest: for the selected piece, the body = the piece's color cells + the white cell (if any).
Let me do that for each piece now: click, then read all non-background colors.
Note: the selected piece's color for A/B/C/D was orange/skyblue/purple etc. Let me just take all cells that are not background 'b' and not red and not the top bar (rows 0-1 super... the bar is at super row -1, i.e., real rows 0-2 → hmm, real rows 0,1,2 map to super rows -1,0,0. Careful: super = (real-2)//3 → real 0,1,2 → -1,-1,-1... hmm (0-2)//3 = -1, (1-2)//3 = -1, (2-2)//3 = 0. So real rows 0-2 → super -1. The bar occupies real rows 0-2? Ear
… [171 caracteres más]

```python
def sel_shape(f):
    G=grid2(f)
    cols={}
    for r_ in range(64):
        for c_ in range(64):
            ch=G[r_][c_]
            if ch=='b': continue
            R,C=(r_-2)//3,(c_-2)//3
            if R<0: continue
            cols.setdefault(ch,[]).append((R,C))
    return {k:sorted(v) for k,v in cols.items()}
for (rr,cc),tag in [((5,5),'G'),((6,50),'A'),((29,23),'B'),((44,5),'C'),((56,38),'D')]:
    r=action([{'action':'MOUSE','row':rr,'col':cc}])
    ss=sel_shape(current_frame)
    print('==',tag,{k:len(v) for k,v in ss.items()})
    for k,v in ss.items():
        H=max(x[0] for x in v)+1; W=max(x[1] for x in v)+1
        print('  ',k,'pos',min(v),'H',H,'W',W)
        for rr2 in range(H): print('     ',''.join('#' if (rr2,c2) in set(v) else '.' for c2 in range(W)))
```

```text
[action] MOUSE(row=5, col=5) -> effect
== G {'c': 495}
   c pos (1, 1) H 19 W 19
      ...................
      .######........####
      ..#...#........#..#
      ..#...#........#..#
      ......#..........##
      ....###............
      ........#..........
      .......##..........
      .....
… [5147 caracteres más]
```

## Paso 47 · nivel 6 · acción 215

**Pensamiento:**

Wait, the green piece got rotated again by my clicks? No — the clicks don't rotate. Hmm, the image shows the green piece at the top-left rendered DARK now (unselected) and its shape looks different from the original: it now shows a "Z/S" like shape. That's because I pressed SPACE earlier (rotating it once). Right ✓ the green is at rot 1.
Important data from the click on B: the selected B piece is rendered 'Y' (yellow) with a 'W' cell! B has a white cell at (10,7)!
Look: B (selected): Y cells: (7,7),(7,8),(8,7),(9,7) + W (10,7). And R tips (6,8),(8,6).
So B's body = (7,7),(7,8),(8,7),(9,7) + white (10,7) = 5 cells, tips (6,8),(8,6).
So B is ALSO a stretchable/growable piece (has a white cell)!
And C (selected, sky blue 'S'): cells (13,1),(14,1),(15,1),(16,1),(17,1) = 5 cells; tips (12,1),(17,2). No white cell → C is a normal rotatable piece.
And A (orange): O cells (1,15),(1,16),(1,17),(1,18),(2,15),(2,18),(3,18),(4,18) = 8 cells; tips (3,15),(4,17). No white → normal.
And D (purple): p cells: (15,11),(15,14),(16,10),(16,11),(16,14),(16,15),(17,10),(17,15),(18,10),(18,11),(18,12),(18,13),(18,15)... let me recount from the print: p pos (15,11) H19 W16, rows 15-18:
row15: '...........#..#.' → cols 11,14
row16: '..........##..##' → cols 10,11,14,15
row17: '..........#....#' → cols 10,15
row18: '..........###.##' → cols 10,11,12,13,15,16? Hmm, '..........###.##' → positions 10,11,12 then '.' at 13 then 14,15 → cols 10,11,12,14,15. Hmm, and the W at (18,13).
So D: p cells 13 + W (1
… [553 caracteres más]

```python
r=action([{'action':'MOUSE','row':23,'col':23}])
print('click B',r.get('no_op'),sel_shape(current_frame).get('Y'),sel_shape(current_frame).get('W'))
for i in range(4):
    r=action(['SPACE'])
    ss=sel_shape(current_frame)
    print(i,{k:v for k,v in ss.items() if k!='c'})
```

```text
[action] MOUSE(row=23, col=23) -> effect
click B False [(7, 7), (7, 7), (7, 7), (7, 7), (7, 7), (7, 7), (7, 7), (7, 7), (7, 7), (7, 8), (7, 8), (7, 8), (7, 8), (7, 8), (7, 8), (7, 8), (7, 8), (7, 8), (8, 7), (8, 7), (8, 7), (8, 7), (8, 7), (8, 7), (8, 7), (8, 7), (8, 7), (9, 7), (9, 7), (9, 7), (9, 
… [4569 caracteres más]
```

## Paso 48 · nivel 6 · acción 221

**Pensamiento:**

Now I see B's growth. The B piece (yellow, selected) has grown a lot:
Current state (after 4 SPACEs):
Y cells: (7,7),(7,8),(8,7),(8,12),(9,7),(9,12),(10,7),(10,8),(10,9),(10,10),(10,11),(10,12)
W: (7,12)
R tips: (6,8),(8,6),(11,7),(11,12)
So B now has 4 tips! And the shape is a "U": 
```
row 6:  . . T . . . . .       tip (6,8)
row 7:  . . # # . . . W       (7,7),(7,8) + white (7,12)
row 8:  T # . . . . . #       tip (8,6), (8,7),(8,12)
row 9:  . # . . . . . #       (9,7),(9,12)
row10:  . # # # # # # #       (10,7..12)
row11:  . . T . . . . T       tips (11,7),(11,12)
```
So the B piece grew a right arm down and around. The growth sequence:
state0: body (7,7),(7,8),(8,7),(9,7) + W(10,7); tips (6,8),(8,6) → 2 tips
state1 (after 1 SPACE): Y: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8); W (10,9); tips (6,8),(8,6),(11,7) → 3 tips. So the white moved right (10,7)→(10,8)→(10,9), converting cells, and a new tip appeared at (11,7) (below the old white position).
state2: Y: +(10,9),(10,10),(10,11)? Let me look: after 2nd SPACE: Y = (7,7),(7,8),(8,7),(9,7),(10,7),(10,8),(10,9),(10,10),(10,11),(10,12)?? 
Hmm the print for i=1 shows Y: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8),(10,9),(10,10) and W (10,11); tips (6,8),(8,6),(11,7) → 3 tips.
i=2: Y: ... (10,7..12) and W (9,12); tips (6,8),(8,6),(11,7),(11,12) → 4 tips.
i=3: Y: (7,7),(7,8),(8,7),(8,12),(9,7),(9,12),(10,7..12); W (7,12); tips (6,8),(8,6),(11,7),(11,12) → 4 tips.
So the growth path: the white cell travels: (10,7) → (10,8) [tip (11,7) ap
… [1639 caracteres más]

```python
def sigB(f):
    ss=sel_shape(f)
    Y=set(ss.get('Y',[]))|set(ss.get('W',[]))
    return {'W':ss.get('W',[]),'R':ss.get('R',[]),'n':len(Y)}
prev=None
for i in range(6):
    r=action(['SPACE'])
    s=sigB(current_frame)
    print(i,'W',s['W'],'n',s['n'],'R',s['R'])
    if prev is not None and s['W']==prev: print('  REPEAT of earlier'); break
    prev=s['W']
```

```text
[action] SPACE -> effect
0 W [] n 14 R [(6, 8), (6, 8), (6, 8), (6, 8), (6, 8), (6, 8), (6, 8), (6, 8), (6, 8), (6, 11), (6, 11), (6, 11), (6, 11), (6, 11), (6, 11), (6, 11), (6, 11), (6, 11), (7, 13), (7, 13), (7, 13), (7, 13), (7, 13), (7, 13), (7, 13), (7, 13), (7, 13), (8, 6), (8, 6), (8, 6), (8
… [2041 caracteres más]
```

## Paso 49 · nivel 6 · acción 226

**Pensamiento:**

Now I have B's full growth cycle. Let me reconstruct B's states (in super coords, with the piece's bbox top-left presumably fixed at (6,6)... let me verify: at state 0 the tips were (6,8),(8,6) and the body (7,7),(7,8),(8,7),(9,7)+W(10,7) → bbox rows 6-10, cols 6-8.
The growth states (n = body count incl. white):
S0: n=5, W(10,7), tips (6,8),(8,6)
S1: n=7, W(10,9), tips (6,8),(8,6),(11,7) — body: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8),(10,9)? Hmm n=7 means 7 cells: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8) + W(10,9) = 7 ✓
S2: n=9, W(10,11), tips + (11,12)? No: at i=1 (S2) the tips were (6,8),(8,6),(11,7) and W(10,11) — hmm, and the body: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8),(10,9),(10,10) + W(10,11) = 9 ✓
S3: n=11, W(9,12), tips (6,8),(8,6),(11,7),(11,12) — body: (7,7),(7,8),(8,7),(9,7),(10,7..12)=6 cells → 4+6 = 10 + W(9,12) = 11 ✓
S4: n=13, W(7,12)? Hmm, at i=3 (S4): Y cells (7,7),(7,8),(8,7),(8,12),(9,7),(9,12),(10,7..12) = 12 + W(7,12) = 13 ✓ tips 4.
S5 (i=0 of the last run): n=14, W=[] (max!), tips (6,8),(6,11),(7,13),(8,6),(11,7),(11,12) → 6 tips!
   Body at max: previous + (7,12),(7,13)? Hmm: n=14 = 13 + 1 → the white (7,12) became body and... W is empty and there are new tips (6,11),(7,13). Let me get the exact max state body. I didn't print it. Hmm.
   Let me reason: at S4 the white was at (7,12) and the body had (8,12),(9,12). The next step: the white moves up? to (6,12)? But W=[] at max, meaning the growth reached the end and the white cell disappeared, and 2 new tips 
… [1971 caracteres más]

```python
r=action(['SPACE']*5)
ss=sel_shape(current_frame)
Y=sorted(set(ss.get('Y',[]))|set(ss.get('W',[])))
print('W',ss.get('W',[])); print('R',sorted(set(ss.get('R',[]))))
print('body',Y)
allc=sorted(set(Y)|set(ss.get('R',[])))
H=max(x[0] for x in allc)+1; W=max(x[1] for x in allc)+1; r0=min(x[0] for x in allc); c0=min(x[1] for x in allc)
Ys=set(Y); Rs=set(ss.get('R',[]))
for rr in range(r0,H+1): print(''.join('#' if (rr,c) in Ys else ('T' if (rr,c) in Rs else '.') for c in range(c0,W+1)))
```

```text
[action] batch of 5 actions, 5 executed: SPACE, SPACE, SPACE, SPACE, SPACE
W []
R [(6, 8), (6, 11), (7, 13), (8, 6), (11, 7), (11, 12)]
body [(6, 12), (7, 7), (7, 8), (7, 12), (8, 7), (8, 12), (9, 7), (9, 12), (10, 7), (10, 8), (10, 9), (10, 10), (10, 11), (10, 12)]
..T..T#..
.##...#T.
T#....#..
.#.
… [36 caracteres más]
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

B's max state (state 5), in local coords with the bbox top-left = (6,6) (since the min row is 6 and min col is 6 — the tips (6,8),(8,6) define the bbox):
```
row6:  . . T . . T # .     → tips (6,8),(6,11); body (6,12)
row7:  . # # . . . # T     → body (7,7),(7,8),(7,12); tip (7,13)
row8:  T # . . . . # .     → tip (8,6); body (8,7),(8,12)
row9:  . # . . . . # .     → body (9,7),(9,12)
row10: . # # # # # # .     → body (10,7..12)
row11: . T . . . . T .     → tips (11,7),(11,12)
```
Local (subtract (6,6)): body: (0,6),(1,1),(1,2),(1,6),(2,1),(2,6),(3,1),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6); tips: (0,2),(0,5),(1,7),(2,0),(5,1),(5,6). H=6, W=8.
Now I have B's 6 states. Let me write them all in local coords (bbox top-left (6,6)):
S0: body: (1,1),(1,2),(2,1),(3,1),(4,1)[W] ; tips: (0,2),(2,0)
   Wait: S0 body = (7,7),(7,8),(8,7),(9,7) + W(10,7) → local (1,1),(1,2),(2,1),(3,1),(4,1); tips (0,2),(2,0) ✓
S1: body: (1,1),(1,2),(2,1),(3,1),(4,1),(4,2),(4,3)[W]; tips: (0,2),(2,0),(5,1)
S2: body: +(4,4),(4,5)[W] → (1,1),(1,2),(2,1),(3,1),(4,1..5); tips (0,2),(2,0),(5,1)
   Hmm, S2 = n=9: (7,7),(7,8),(8,7),(9,7),(10,7),(10,8),(10,9),(10,10) + W(10,11) = 9 ✓ → local (1,1),(1,2),(2,1),(3,1),(4,1),(4,2),(4,3),(4,4),(4,5) ✓ tips (0,2),(2,0),(5,1)
S3: n=11: body (1,1),(1,2),(2,1),(3,1),(4,1..6) + W(3,6) → local: (7,7),(7,8),(8,7),(9,7),(10,7..12),(9,12) = 4+6+1 = 11 ✓ tips (0,2),(2,0),(5,1),(5,6)
S4: n=13: body (1,1),(1,2),(2,1),(3,1),(4,1..6),(3,6),(2,6),(1,6)[W] → 13 ✓ tips (0,2),(2,0),(
… [1364 caracteres más]

```python
def B6(s):
    base=[(1,1),(1,2),(2,1),(3,1),(4,1)]
    st={0:(base,[(0,2),(2,0)]),
        1:(base+[(4,2),(4,3)],[(0,2),(2,0),(5,1)]),
        2:(base+[(4,2),(4,3),(4,4),(4,5)],[(0,2),(2,0),(5,1)]),
        3:(base+[(4,2),(4,3),(4,4),(4,5),(4,6),(3,6)],[(0,2),(2,0),(5,1),(5,6)]),
        4:(base+[(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6)],[(0,2),(2,0),(5,1),(5,6)]),
        5:(base+[(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6),(0,6)],[(0,2),(0,5),(1,7),(2,0),(5,1),(5,6)])}
    b,t=st[s]
    allc=set(b)|set(t)
    return {'body':sorted(set(b)),'tips':t,'H':max(x[0] for x in allc)+1,'W':max(x[1] for x in allc)+1}
for s in range(6):
    d=B6(s); print(s,len(d['body']),d['tips'],d['H'],d['W'])
def L6P():
    P={}
    P['G']={'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,
… [1797 caracteres más]
```

```text
0 5 [(0, 2), (2, 0)] 5 3
1 7 [(0, 2), (2, 0), (5, 1)] 6 4
2 9 [(0, 2), (2, 0), (5, 1)] 6 6
3 11 [(0, 2), (2, 0), (5, 1), (5, 6)] 6 7
4 13 [(0, 2), (2, 0), (5, 1), (5, 6)] 6 7
5 14 [(0, 2), (0, 5), (1, 7), (2, 0), (5, 1), (5, 6)] 6 8
Grot 0 sols 0
Grot 1 sols 0
Grot 2 sols 0
Grot 3 sols 0
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

Still no solutions. Hmm. My assumption that the goal is "all tips pair" may be wrong for level 6, OR the growable pieces can also rotate (maybe with a different action?), OR the green piece's shape/rotation model is off, OR the pieces can also be reflected...
Let me reconsider. Maybe the goal isn't "all tips pair". Let me reconsider what happened at the END of level 5: the level completed when all tips paired. In level 4 (and earlier) similar.
Alternatively, maybe the win condition is that the pieces form a closed loop / all tips pair, but tips can also pair with tips of the SAME piece? No.
Hmm, wait. Maybe I should reconsider: can the growable pieces (B, D) ROTATE too? In level 5, the yellow couldn't rotate (SPACE grew it). But maybe here the growable pieces can rotate via... hmm, there's no other action.
Hmm, let me reconsider the D piece. When D is at max stretch (k=3), the white cell is gone. Hmm, but for B at max, the white is gone too. What if, at max stretch, pressing SPACE again does something else (like rotating)? For B: from max, pressing SPACE went back to S4 (shrink). So no.
Let me question my tip-pairing model more carefully. In level 5, the winning configuration had ALL tips paired (7 yellow + 7 dark = 14 → 7 pairs). Let me re-verify that the level-5 win happened exactly when the last pair connected — yes, the final LEFT action completed the assembly and the level completed.
Hmm, but actually, maybe the win condition is that all pieces form ONE connected compone
… [4670 caracteres más]

```python
def solve7b(fixrot=0,maxpairs_want=99,limit=400000):
    V=mkV7(); names=['A','C','B','D']
    fv=V['G'][fixrot]
    best=[]
    def occ(placed):
        b=set(); t=set()
        for k,(vi,pos) in placed.items():
            var=V[k][vi]; r0,c0=pos
            b|=set((r+r0,c+c0) for r,c in var[1]); t|=set((r+r0,c+c0) for r,c in var[2])
        return b,t
    def rec(placed,usedcells_b,usedcells_t,pairs,idx):
        if len(placed)==5:
            best.append((pairs,{k:v for k,v in placed.items()}))
            return
        if idx>limit: return
        for nxt in names:
            if nxt in placed: continue
            for var in V[nxt]:
                # candidate positions: align each of var's tips with each placed tip
                cands=set()
                for (tr,tc) in var[2]:

… [894 caracteres más]
```

```text
Tool timed out after 30s
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

Whoa — all my retained functions were dropped! The tool message says all functions are no longer retained (probably because the timed-out snippet broke the retention chain, or because a function's dependency chain was invalidated). That's a big setback but the knowledge is in my context. I'll redefine the essentials as needed.
Also the search timed out (too slow, and it allowed huge configurations).
Let me step back and think about the win condition more cleverly rather than brute-forcing.
Key insight attempt: In level 5 the solution was unique with all tips paired. Here, maybe the intended solution also pairs all tips, but I'm missing something about the pieces. Possibilities:
(a) The growable pieces B and D can also ROTATE (maybe by pressing SPACE at max growth, or maybe rotation happens with a different key).
(b) The tips I recorded for the green piece change with rotation in a way my rot() model doesn't capture (unlikely; verified once).
(c) There are more growth states for D (I only saw k=0..3 oscillating; the max had no white cell and 3 tips — but for B the max state had 6 tips with the white gone... For D, maybe the max state is beyond k=3? The oscillation went 0,1,2,3,2,1,0,1,... so 3 is the max ✓).
Hmm, let me reconsider (a). In level 5, the yellow piece: did it have a rotation ability? SPACE grew/shrank it. No rotation. And the level solved with the yellow unrotated ✓.
So here, with B and D not rotatable, the pairing search found nothing. Let me double check my D sh
… [7269 caracteres más]

```python
import time
def rot(s,H,W):
    nb=[(c,H-1-r) for r,c in s['body']]; nt=[(c,H-1-r) for r,c in s['tips']]
    return {'body':nb,'tips':nt},W,H
def L6P():
    return {'G':{'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1)],'tips':[(2,4),(4,2),(5,0)],'H':6,'W':5},
            'A':{'body':[(0,0),(0,1),(0,2),(0,3),(1,0),(1,3),(2,3),(3,3)],'tips':[(2,0),(3,2)],'H':4,'W':4},
            'C':{'body':[(1,0),(2,0),(3,0),(4,0)],'tips':[(0,0),(5,1)],'H':6,'W':2}}
def B6(s):
    base=[(1,1),(1,2),(2,1),(3,1),(4,1)]; ext=[[],[(4,2),(4,3)],[(4,2),(4,3),(4,4),(4,5)],
      [(4,2),(4,3),(4,4),(4,5),(4,6),(3,6)],[(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6)],
      [(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6),(0,6)]]
    tp={0:[(0,2),(2,0)],1:[(0,2),(2,0),(5,1)],2:[(0,2),(2,0)
… [1295 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 1, in <module>
ImportError: Module 'time' is not allowed in the sandbox.
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

`time` isn't importable. Let me redefine without it (I'll use a node counter for the budget instead).

```python
def rot(s,H,W):
    nb=[(c,H-1-r) for r,c in s['body']]; nt=[(c,H-1-r) for r,c in s['tips']]
    return {'body':nb,'tips':nt},W,H
def L6P():
    return {'G':{'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1)],'tips':[(2,4),(4,2),(5,0)],'H':6,'W':5},
            'A':{'body':[(0,0),(0,1),(0,2),(0,3),(1,0),(1,3),(2,3),(3,3)],'tips':[(2,0),(3,2)],'H':4,'W':4},
            'C':{'body':[(1,0),(2,0),(3,0),(4,0)],'tips':[(0,0),(5,1)],'H':6,'W':2}}
def B6(s):
    base=[(1,1),(1,2),(2,1),(3,1),(4,1)]; ext=[[],[(4,2),(4,3)],[(4,2),(4,3),(4,4),(4,5)],
      [(4,2),(4,3),(4,4),(4,5),(4,6),(3,6)],[(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6)],
      [(4,2),(4,3),(4,4),(4,5),(4,6),(3,6),(2,6),(1,6),(0,6)]]
    tp={0:[(0,2),(2,0)],1:[(0,2),(2,0),(5,1)],2:[(0,2),(2,0),(5,1)],3:[(
… [1283 caracteres más]
```

```text
{'G': [(0, 11, 3, 6, 5), (1, 11, 3, 5, 6), (2, 11, 3, 6, 5), (3, 11, 3, 5, 6)], 'A': [(0, 8, 2, 4, 4), (1, 8, 2, 4, 4), (2, 8, 2, 4, 4), (3, 8, 2, 4, 4)], 'C': [(0, 4, 2, 6, 2), (1, 4, 2, 2, 6), (2, 4, 2, 6, 2), (3, 4, 2, 2, 6)], 'B': [(0, 5, 2, 5, 3), (1, 7, 3, 6, 4), (2, 9, 3, 6, 6), (3, 11, 4, 6,
… [120 caracteres más]
```

**Pensamiento:**

Now let me do a bounded search for connected configurations maximizing tip-tip pairs. I'll use a node budget counter.
Plan: anchor G at rot 0 pos (0,0) (and try the other 3 rots). DFS placing pieces in a fixed order [A, C, B, D] but allowing each new piece to attach to ANY placed piece. Candidate offsets: for each placed piece's tips × new piece's tips → offset. Then filter overlaps. Also bound the total bbox size to ≤ 12x12 to keep it compact.
To limit the explosion, I'll cap the number of solutions collected and use a node budget of ~150k.
I'll record the best (max pairs) configs.

```python
def search_conn(fixrot=0,budget=120000,bboxmax=12):
    V=V7; order=['A','C','B','D']
    fv=V['G'][fixrot]
    best=[]; nodes=[0]
    def rec(placed,occB,occT,cells,pairs):
        if len(placed)==5:
            best.append((pairs,dict(placed))); return
        if nodes[0]>budget: return
        for nxt in order:
            if nxt in placed: continue
            for var in V[nxt]:
                cands=set()
                for (tr,tc) in var[2]:
                    for (ur,uc) in occT: cands.add((ur-tr,uc-tc))
                for pos in cands:
                    nodes[0]+=1
                    if nodes[0]>budget: return
                    r0,c0=pos
                    b=set((r+r0,c+c0) for r,c in var[1]); t=set((r+r0,c+c0) for r,c in var[2])
                    if b&(occB|occT) or t&o
… [652 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 32, in <module>
  File "<python_tool>", line 2, in search_conn
NameError: name 'V7' is not defined
```

**Pensamiento:**

V7 (the global variable) isn't retained across calls — only functions are. I need to build V7 inside the function or pass it. Let me make search_conn build V7 itself via mkV7().

```python
def search_conn(fixrot=0,budget=120000,bboxmax=12):
    V=mkV7(); order=['A','C','B','D']
    fv=V['G'][fixrot]
    best=[]; nodes=[0]
    def rec(placed,occB,occT,cells,pairs):
        if len(placed)==5:
            best.append((pairs,dict(placed))); return
        if nodes[0]>budget: return
        for nxt in order:
            if nxt in placed: continue
            for var in V[nxt]:
                cands=set()
                for (tr,tc) in var[2]:
                    for (ur,uc) in occT: cands.add((ur-tr,uc-tc))
                for pos in cands:
                    nodes[0]+=1
                    if nodes[0]>budget: return
                    r0,c0=pos
                    b=set((r+r0,c+c0) for r,c in var[1]); t=set((r+r0,c+c0) for r,c in var[2])
                    if b&(occB|occT) or
… [656 caracteres más]
```

```text
rot 0 nodes 120004 found 2991 bestpairs [6, 6, 6, 6, 6, 6, 6, 6]
rot 1 nodes 120004 found 2034 bestpairs [5, 5, 5, 5, 5, 5, 5, 5]
rot 2 nodes 120004 found 1016 bestpairs [5, 5, 5, 5, 4, 4, 4, 4]
rot 3 nodes 120004 found 2072 bestpairs [5, 5, 4, 4, 4, 4, 4, 4]
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

Best = 6 pairs with G at rot 0. Total tips at rot 0 with B state and D state varying: 3(G)+2(A)+2(C)+Bt+3(D) = 10+Bt. If pairs=6, that's 12 tips paired, so total tips ≥ 12 → Bt ≥ 2 ✓. If Bt=2 → total 12 → ALL tips paired! 
Wait! With Bt=2 (B state 0), total tips = 12 → 6 pairs = ALL PAIRED! But my exhaustive full-pairing search (solve7) found nothing... because solve7 required the pieces to be placed in a specific order with all tips paired and used the green at each rotation. Hmm, it should have found this. Unless the search order/pruning missed it? solve7 placed pieces in the order A,C,B,D and required each new piece to pair with unpaired tips; that's complete for the "all paired" case... hmm, but there's a subtlety: my "unpaired" set logic. When I place a piece whose tip matches an unpaired tip, they cancel. That's correct. But the candidate positions were generated only by aligning the new piece's tips with currently-unpaired tips. In a full-pairing solution, every piece must have at least one tip pairing with an already-placed piece... not necessarily! A piece could pair its tips only with pieces placed LATER. E.g., in the order A,C,B,D, if A's tips both pair with B (placed later), then when placing A there are no unpaired tips to match → pruned. That's the flaw!
The search_conn has the same flaw but it explores all orders (the `for nxt in order` loop picks any unplaced piece each step), so it can find configs where each piece attaches to an already-placed one. Still, a 
… [759 caracteres más]

```python
b,n=search_conn(0,budget=200000)
V=mkV7()
res=[]
for pairs,pl in b:
    if pairs<6: continue
    tot=0; occB=set(); occT=set()
    for k,(vi,pos) in pl.items():
        var=V[k][vi]; r0,c0=pos
        tot+=len(var[2])
        occB|=set((r+r0,c+c0) for r,c in var[1]); occT|=set((r+r0,c+c0) for r,c in var[2])
    unpaired=len(occT)
    res.append((tot-unpaired*0, pairs,tot,unpaired,{k:v for k,v in pl.items()}))
res.sort(key=lambda x:(x[3],-x[1]))
print(len(res))
for r in res[:5]: print('tips',r[2],'pairs',r[1],'unpaired',r[3],r[4])
```

```text
62
tips 13 pairs 6 unpaired 7 {'G': (0, (0, 0)), 'C': (0, (5, 0)), 'B': (1, (2, 2)), 'D': (1, (7, 1)), 'A': (0, (5, 6))}
tips 13 pairs 6 unpaired 7 {'G': (0, (0, 0)), 'C': (0, (5, 0)), 'B': (1, (2, 2)), 'D': (2, (7, 1)), 'A': (0, (5, 7))}
tips 13 pairs 6 unpaired 7 {'G': (0, (0, 0)), 'C': (0, (5, 0)
… [292 caracteres más]
```

**Pensamiento:**

Hmm, "unpaired 7" is computed as len(occT) where occT is the set of tip cells (pairs collapse to the same cell so they're counted once). That metric is wrong. Let me recompute properly: total tips = 13 (G3+A2+C2+B3+D3 → B state 1 has 3 tips). Pairs = 6 → 12 tips involved, 1 unpaired. Hmm, total 13 is odd so at least 1 unpaired.
So the 6-pair configs have 13 tips with 1 unpaired. Hmm.
But wait: is the "unpaired" count actually meaningful? Let me recompute the number of distinct tip cells: if 6 pairs, the occupied tip cells = 13 - 6 = 7 ✓ (each pair merges 2 into 1). So yes: 13 tips, 6 pairs, 1 leftover tip.
Hmm, so with B in state 1 (3 tips) the total is 13 (odd) → 1 leftover.
For an all-paired config we need total tips even: Bt ∈ {2,4,6} → totals 12, 14, 16 → pairs 6, 7, 8.
The search found max 6 pairs. With Bt=2 (B state 0, total 12), 6 pairs = all paired. Did the search find any 6-pair config with B state 0? The top results all show B state 1. Let me filter the 62 results for B state 0 and check whether all tips paired.
Let me look at all distinct (B state, D state, pairs) combos among the 6-pair solutions.

```python
from collections import Counter
V=mkV7()
c=Counter()
for pairs,pl in b:
    c[(pl['B'][0],pl['D'][0],pairs)]+=1
print(sorted(c.items()))
# check all-paired candidates: total tips 12 (B state 0) & pairs 6, or 14 & 7, or 16 & 8
good=[]
for pairs,pl in b:
    tot=sum(len(V[k][vi][2]) for k,(vi,pos) in pl.items())
    if 2*pairs==tot: good.append((pairs,tot,pl))
print('all-paired found:',len(good))
for g in good[:5]: print(g)
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 4, in <module>
NameError: name 'b' is not defined
```

**Pensamiento:**

Right, variables don't persist. Let me redo the search and the analysis in one call, with a bigger budget but careful about the 30s limit. The search with budget 200000 took some time. Let me just run budget=150000 for rot 0 and analyze.

```python
b,n=search_conn(0,budget=150000)
V=mkV7()
from collections import Counter
c=Counter()
for pairs,pl in b: c[(pl['B'][0],pl['D'][0],pairs)]+=1
print('nodes',n,'found',len(b))
print(sorted(c.items()))
good=[(pairs,tot,pl) for pairs,pl in b for tot in [sum(len(V[k][vi][2]) for k,(vi,pos) in pl.items())] if 2*pairs==tot]
print('all-paired:',len(good))
for g in good[:4]: print(g)
```

```text
nodes 150004 found 3700
[((0, 0, 4), 445), ((0, 1, 4), 290), ((0, 2, 4), 180), ((0, 3, 4), 180), ((1, 0, 4), 386), ((1, 0, 5), 29), ((1, 1, 4), 220), ((1, 1, 5), 19), ((1, 2, 4), 180), ((1, 2, 5), 16), ((1, 3, 4), 194), ((1, 3, 5), 34), ((2, 0, 4), 178), ((2, 0, 5), 24), ((2, 1, 4), 108), ((2, 1, 5)
… [543 caracteres más]
```

**Pensamiento:**

No all-paired configs found (with the bbox ≤ 12 constraint and this budget). Max pairs = 6, occurring with B state 3/4/5 and D state 3.
Hmm, with B state 5 (6 tips) and D state 3: total = 3+2+2+6+3 = 16 → 6 pairs = 12 tips paired, 4 unpaired. That doesn't look like a "solved" state.
Let me step back and reconsider the win condition. Maybe the win condition isn't about tips at all!
Let me reconsider: What if the goal is to make the pieces form a specific shape (like a filled rectangle or a symmetric pattern)? Hmm.
Alternatively, maybe the win condition is: all pieces connected into ONE piece (any contact, including tip-body or body-body adjacency?). Hmm.
Let me look at the earlier levels' evidence: In levels 3-5, the level completed when the assembly was complete (all tips paired). The "tips" (red) are clearly connectors.
Hmm, wait. Maybe I should reconsider whether the growth oscillation is really the whole story. What if the growth path DEPENDS on the piece's position — e.g., the growth extends along a ray until it hits another piece or the board edge! That would explain:
- Level 5's yellow: prong lengths 1, 3, 2 (varied) — but nothing was near... Hmm, the yellow's prongs grew right to cols 10, 12, 11 — no obstacles there.
Hmm no.
What if the growth path is a fixed "program" per piece, and the piece's shape at max growth is the "target shape"? Then the goal would be to grow each growable piece to the right state and assemble.
Let me try assuming the win condition = all tips 
… [12179 caracteres más]

```python
def cost_model():
    cur={'G':{'rot':1,'pos':(1,1)},'A':{'rot':0,'pos':(1,15)},'C':{'rot':0,'pos':(12,1)},
         'B':{'st':5,'dir':-1,'pos':(6,6)},'D':{'st':1,'dir':-1,'pos':(14,9)}}
    return cur
def spaces_to(st,dirn,target,nmax_B=6,nmax_D=4):
    # ping-pong: state in [0..nmax-1], dir +1/-1 ; returns presses needed
    n=nmax_B if st is not None else 0
    return None
def presses(cur_st,dirn,target,nmax):
    s=cur_st; d=dirn; cnt=0
    if s==target: return 0
    while True:
        s=s+d
        if s>=nmax-1: s=nmax-1; d=-1
        elif s<=0: s=0; d=1
        cnt+=1
        if s==target: return cnt
        if cnt>200: return 10**6
def eval_cfg(pl,cur,V,BR=19,BC=19):
    # pl: name -> (variant, relpos) ; find best translation
    names=list(pl)
    best=None
    for dr in range(-20
… [1061 caracteres más]
```

```text
configs 5974
cost 31 pairs 4 dr 1 dc 3 {'G': (3, (0, 0)), 'A': (0, (2, 5)), 'B': (0, (5, 5)), 'D': (1, (7, 3)), 'C': (1, (10, -2))}
cost 32 pairs 4 dr 2 dc 3 {'G': (0, (0, 0)), 'A': (1, (0, 4)), 'B': (5, (4, 0)), 'C': (0, (6, 0)), 'D': (0, (6, 6))}
cost 32 pairs 4 dr 2 dc 3 {'G': (0, (0, 0)), 'A': (
… [421 caracteres más]
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

Cheapest connected configs cost ~31-32 model actions (mostly translation). That's a reasonable probe: if connectivity wins the level, ~35 real actions.
But before executing a 30-action plan on an unverified hypothesis, let me find a cheaper DISCRIMINATING test. 
Idea: A cheap partial test of the connectivity hypothesis: connect just TWO pieces (e.g., A and C, or G and A) and see if anything happens (no win, but I can check whether the two pieces MERGE into one object — e.g., do they stay linked when I move one away? Does the game show any feedback?). Hmm, that doesn't test the WIN condition (which needs all 5 connected).
Alternatively, think about the structure: maybe the win condition is that all tips are paired OR the pieces form a closed loop... 
Hmm, let me think about the "4 pairs" configs: with 5 pieces, 4 pairs = a tree (chain). The tips left unpaired: total tips (say 13) - 8 = 5 unpaired. That seems like an "unsolved" state visually (lots of red tips sticking out). In levels 3-5, the solved state had NO red tips visible (all paired → the red disappeared? Let me check: in the level-5 final frame, were there red cells? The final winning frame... I recall the pieces merged and the level completed. Hmm.
Actually! Here's a thought: when two tips pair, do they turn into body cells (the red disappears)? In my search model I assumed paired tips occupy the same cell (still red?). Let me check the earlier evidence: in level 5, at the end, was there any red left? If pairing cons
… [767 caracteres más]

```python
lv=[ (i,e.frame.level,e.frame.step) for i,e in enumerate(history)]
# find boundary where level becomes 6
b_idx=[i for i,l,s in lv if l==6][0]
print('first L6 idx',b_idx,'total hist',len(history))
for i in range(max(0,b_idx-3),min(len(history),b_idx+1)):
    f=history[i].frame
    g=grid2(f) if False else None
    print(i,'L',f.level,'step',f.step,'action',history[i].action)
# count red cells in last L5 frame and first L6 frame
def count_colors(f):
    from collections import Counter
    c=Counter()
    for row in f.ascii.split('\n'):
        for ch in row: c[ch]+=1
    return dict(c)
print('last L5 frame colors',count_colors(history[b_idx-1].frame))
print('first L6 frame colors',count_colors(history[b_idx].frame))
```

```text
first L6 idx 193 total hist 227
190 L 5 step 190 action LEFT
191 L 5 step 191 action LEFT
192 L 5 step 192 action LEFT
193 L 6 step 193 action LEFT
last L5 frame colors {'p': 3686, 'W': 12, 'c': 344, 'R': 18, 'O': 36}
first L6 frame colors {'b': 3578, 'c': 392, 'N': 99, 'R': 27}
```

**Pensamiento:**

Very interesting! The LAST level-5 frame (history[192], the frame where the level completed) still had R: 18 (red cells = 2 tip cells × 9 px each = 18 px → 2 tip cells). And O: 36 (4 cells of orange) and p: 3686 (purple background?? no...). Hmm, wait: 'p' is purple and 3686 cells — that's the background?! In level 5 the background was... hmm, 'p' = purple? That doesn't look right. Oh wait — the level-5 background might have been a light blue 'b'... Let me re-read: 'p': 3686. Hmm, that's the dominant color = background. So the level-5 background was purple?? The image shows blue. Hmm, ARC color letters: 'b' = blue. In the first L6 frame the background is 'b' (3578) ✓ blue.
Hmm, so in level 5's last frame the background was 'p' (3686)? That seems odd. Whatever — maybe at level completion there's a flash/recolor animation (the final frame might be a "win flash" with the whole board recolored).
Key: in the level-5 completion frame there were 18 red px = 2 red tip cells. Hmm, that's the frame AFTER the winning action (history[192].frame is the post-action frame for the last L5 action). So at completion there were still 2 red tip cells? Hmm, or the frame is a transition/flash frame.
Let me look at the level-5 completion frame more carefully: count the red cells' positions and see the overall structure. Let me crop the region.
Actually, more useful: let me check the level-5 completion frame's structure to see if the pieces merged into one connected object and whether all tips but on
… [1046 caracteres más]

```python
for i in range(186,196):
    e=history[i]; r=e.result or {}
    f=e.frame
    print(i,'L',f.level,'step',f.step,str(e.action)[:28],'res',{k:v for k,v in r.items() if k in('level_completed','game_over','run_complete','done','board_changed','gameplay_changed')},'colors',count_colors(f))
```

```text
186 L 5 step 186 UP res {'board_changed': True, 'gameplay_changed': True, 'done': False, 'level_completed': False, 'game_over': False, 'run_complete': False} colors {'p': 3686, 'W': 11, 'c': 345, 'R': 18, 'O': 36}
187 L 5 step 187 UP res {'board_changed': True, 'gameplay_changed': True, 'done': Fals
… [1858 caracteres más]
```

**Pensamiento:**

Excellent! The level_completed=True flag came with history[193] (the LEFT action at step 193), and the level-5 frames 186-192 all had exactly 18 red px = 2 red cells. So at the moment of level 5's completion, there were 2 unpaired tips! 
Wait, but hold on — maybe those 2 red cells were the "plug/connector" of a selected piece? Hmm, in level 5, when a piece is selected its tips turn red. Hmm! Actually no — the tips are always red (that's how I read them).
Hmm, but 18 red px = 2 cells. In level 5's final config, my model said all 14 tips paired. So where do 2 red cells come from? 
OH WAIT. Maybe when two tips pair, the game renders the joined cell as red (a leftover "seam")! I.e., a paired tip pair leaves ONE red cell? Hmm, 2 red cells... 
Hmm, let me look at the level-5 final frame's structure to see where the red cells are and whether the pieces are all merged. Let me crop the region around the assembly in history[192].frame.
Also important: the 'p' background in level 5 = purple?? And 'O' 36px = 4 orange cells. Hmm, in level 5 the pieces were... Let me recall: level 5 had a yellow piece and dark pieces. Hmm, 'c' = charcoal (344 px = 38 cells) — that's a lot for the dark pieces. Hmm, maybe the level-5 background was 'p'?? No wait — 'p' is 3686 px = 410 cells which is the whole board area minus... The board is 64x64 = 4096; 3686+344+36+18+12 = 4096 ✓. So the background is 'p' (purple-ish) in level 5? The image I saw for level 5 looked blue... maybe it was 'b'. Hmm, but the cou
… [290 caracteres más]

```python
def grid2(f):
    return [list(r) for r in f.ascii.split('\n')]
def supergrid(f):
    g=grid2(f); S=[]
    for R in range(21):
        row=[]
        for C in range(21):
            r=3*R+2; c=3*C+2
            row.append(g[r][c] if r<64 and c<64 else '.')
        S.append(row)
    return S
f=history[192].frame
S=supergrid(f)
for r in range(21): print(''.join(S[r]))
```

```text
ppppppppppppppppppppp
ppppppppppppppppppppp
ppppppppppppppppppppp
ppppppppppppppppppppp
ppppppppccccccppppppp
pppppccccppppcppppppp
pppppcppccccccppppppp
pppppccccpppppppppppp
pppppcppcccccROpppppp
pppppccccpppppOpppppp
ppppppppccccROOpppppp
ppppppppppppppppppppp
ppppppppppppppppppppp
pppppppppppppp
… [161 caracteres más]
```

## Paso 50 · nivel 6 · acción 226

**Pensamiento:**

WAIT. This level-5 final frame is completely different from what I expected! The background is 'p' and there's a small assembly at rows 4-10, cols 4-13 with 'c' (charcoal), 'R' and 'O' cells. This looks like a DIFFERENT level's board — a small cluster.
Hmm, this must be a "level transition" frame: after completing level 5, the board shows... hmm, no. Actually, wait: this could be the level-5 win animation frame showing the merged piece (charcoal = the merged shape?) plus 'R'/'O' cells.
Hmm, but the background changed to 'p' (purple) — this is the "flash" frame. The merged shape:
```
row4:  cccccc          (cols 5-10)
row5:  cccc ppp c      (5-8) and (12)? 
```
Let me re-read:
row4: `ppppppppccccccppppppp` → cols 8-13 c
row5: `pppppccccppppcppppppp` → cols 5-8 c, cols 12-13 c
row6: `pppppcppccccccppppppp` → col5 c, cols 8-13 c
row7: `pppppccccpppppppppppp` → cols 5-8 c
row8: `pppppcppcccccROpppppp` → col5 c, cols 8-12 c, R at 13, O at 14
row9: `pppppccccpppppOpppppp` → cols 5-8 c, O at 13
row10:`ppppppppccccROOpppppp` → cols 8-11 c, R at 12, O at 13, O at 14
Hmm, this is a mess — probably a mid-animation frame where the merged assembly is being recolored. The two pieces (yellow + darks) merged into one and the colors are transitioning.
So the level-5 win frame shows the merged assembly = ONE connected object ✓ consistent with the connectivity hypothesis. And the R/O cells are animation artifacts (the yellow piece turning... hmm, 'O' orange = selected piece color? and R red = t
… [7964 caracteres más]

```python
def cells_of(V,k,vi,pos):
    var=V[k][vi]; r0,c0=pos
    b=set((r+r0,c+c0) for r,c in var[1]); t=set((r+r0,c+c0) for r,c in var[2])
    return b,t
def bfs_move(V,k,vi,start,goal,blockB,blockT,BR=19,BC=19):
    var=V[k][vi]; body=var[1]; tips=var[2]
    def ok(pos):
        r0,c0=pos
        b=set((r+r0,c+c0) for r,c in body); t=set((r+r0,c+c0) for r,c in tips)
        if r0<0 or c0<0: return False
        if max(r for r,_ in b)>BR or max(c for _,c in b)>BC: return False
        if min(r for r,_ in t)<0 or min(c for _,c in t)<0: return False
        if b&(blockB|blockT): return False
        if t&blockB: return False
        return True
    if not ok(goal): return None
    from collections import deque
    q=deque([start]); prev={start:None}
    if start==goal: return []
    while q:
     
… [2763 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 78, in <module>
  File "<python_tool>", line 58, in build_plan6
  File "<python_tool>", line 22, in bfs_move
ValueError: not enough values to unpack (expected 2, got 1)
```

## Paso 50 · nivel 6 · acción 228

**Pensamiento:**

I need to fix the bfs_move bug (the leftover junk loop `for d,(dr,dc) in [((-1),'U'),...]`). Let me remove it.
Also, before executing a 30+ action plan, I should verify the movement mechanic on level 6 (arrow keys move only the selected piece). Let me do a quick probe: click a piece, press an arrow, check the diff. That's 2 actions and it validates the core assumption.
Let me do: fix bfs_move, then run a probe (MOUSE on A, then LEFT), then verify only A moved.

```python
def bfs_move(V,k,vi,start,goal,blockB,blockT,BR=19,BC=19):
    var=V[k][vi]; body=var[1]; tips=var[2]
    def ok(pos):
        r0,c0=pos
        b=set((r+r0,c+c0) for r,c in body); t=set((r+r0,c+c0) for r,c in tips)
        if r0<0 or c0<0: return False
        if max(r for r,_ in b)>BR or max(c for _,c in b)>BC: return False
        if min(r for r,_ in t)<0 or min(c for _,c in t)<0: return False
        if b&(blockB|blockT): return False
        if t&blockB: return False
        return True
    if not ok(goal): return None
    if start==goal: return []
    from collections import deque
    q=deque([start]); prev={start:None}
    while q:
        p=q.popleft()
        for dr,dc,mv in [(-1,0,'UP'),(1,0,'DOWN'),(0,-1,'LEFT'),(0,1,'RIGHT')]:
            np_=(p[0]+dr,p[1]+dc)
            if np
… [746 caracteres más]
```

```text
[action] MOUSE(row=5, col=47) -> effect
click A {'b': 3452, 'W': 5, 'c': 549, 'O': 72, 'R': 18}
[action] LEFT -> effect
after LEFT: {'moved': 3, 'rotated': 0, 'appeared': 0, 'disappeared': 0, 'changed_color': 0, 'resized': 3}
   moved {'color': 'O', 'pixels': 72, 'hash': '6fb71e872e71fd21', 'from': 
… [758 caracteres más]
```

## Paso 51 · nivel 6 · acción 228

**Pensamiento:**

Confirmed: only the selected piece (A, orange) moved LEFT by 1 super cell (3 real px), along with its red tips. The B piece (now dark, unselected) is visible in the middle at max growth — and interestingly it shows 6 tips (the max state) ✓.
Also note: the W count changed 5→6 and the 'c' bar resized — that's the top bar shrinking (HUD/timer). So there IS a step budget! The white segment on the top bar grows/shrinks. Let me measure the bar: at step 193 (level start) W was 12 px (?), now W=6. Hmm, the W at the top-left of the bar: 'W' 5 px at step 228, 6 at step 229. And 'c' at row 0 changed from 27 to 26 px. So the bar is shrinking → I have limited steps left!
Let me measure the bar precisely: the top row (real row 0 or 1) — count the 'c' cells in the top rows. At the level start vs now. Let me compute the bar length over history to estimate the budget.
Note: the diff image shows the B piece at max growth with 6 tips, and the A piece moved.
Let me quickly measure the bar: for each history entry in level 6, count 'c' px in real rows 0..2 (super row -1).

```python
def bar(f):
    g=grid2(f)
    row=g[0]
    return ''.join(row[:40])
import itertools
start=None
for i,e in enumerate(history):
    if e.frame.level!=6: continue
    b=bar(e.frame)
    n=b.count('c')+b.count('W')
    if start is None: start=(i,e.frame.step,b)
    last=(i,e.frame.step,b)
print('first',start)
print('last ',last)
# count of non-bg chars in top row over time
vals=[(e.frame.step,bar(e.frame).count('c'),bar(e.frame).count('W')) for e in history if e.frame.level==6]
print(vals[:6],'...',vals[-6:])
```

```text
first (193, 193, 'bbbbbbbbbbbbbbbbcccccccccccccccccccccccc')
last  (228, 228, 'bbbbbbbbbbbbbbbbWWWWWWcccccccccccccccccc')
[(193, 24, 0), (194, 24, 0), (195, 24, 0), (196, 24, 0), (197, 23, 1), (198, 23, 1)] ... [(223, 19, 5), (224, 19, 5), (225, 19, 5), (226, 19, 5), (227, 19, 5), (228, 18, 6)]
```

**Pensamiento:**

The top row shows: at step 193, 24 'c' cells (and 16 'b' = background at the left). At step 228: 18 'c' + 6 'W'. So the total bar (c+W) = 24 constant → the bar shrinks by 1 per ~5 steps? Hmm: 193→196: 24c; 197: 23c+1W; ... 223-227: 19c+5W (24 total); 228: 18c+6W.
So the bar decreases by 1 unit every ~5 actions. Started at 24 units at step 193, now 18 units at step 228 (35 actions → 6 units lost ≈ 5.8 actions/unit). Hmm, actually it seems the "W" grows from the left and 'c' shrinks — the white part is the "remaining" indicator? Or the c part is remaining?
Interpretation: the bar has 24 units; the white segment (6 now) grows as steps are consumed → the remaining budget = 24 - 6 = 18 units → about 18 × 5.8 ≈ 104 actions left. Hmm, that's if the rate is 5.8 actions per unit. Hmm, but is the rate exactly 5? Let me check the transitions: 196→197 (1 action) the bar dropped 24→23. Then 197→223 (26 actions) dropped 23→19 (4 units) → 6.5 actions/unit. Hmm, inconsistent. Some actions were batched (each action = 1 step regardless).
Hmm, whatever: it's a limited budget. Roughly 18 units left; the consumption rate is ~1 unit per 5-6 actions → ~90-100 actions left. My plan needs ~40 actions. Should be OK, but I shouldn't dawdle.
Note: the level-5 bar was 24 units too? And the level-5 completion happened at step 193 with the bar not depleted.
OK, let me now build and execute the plan. But WAIT — before spending 40 actions on an unverified win hypothesis, let me consider a cheaper decisive te
… [4493 caracteres más]

```python
def snap6(f,V):
    S=supergrid(f)
    cells={}
    for R in range(1,21):
        for C in range(21):
            ch=S[R][C]
            if ch in 'pbc.': continue
            cells.setdefault(ch,set()).add((R,C))
    return cells
V=mkV7()
model={'G':(1,(1,1)),'A':(0,(1,14)),'C':(0,(12,1)),'B':(5,(6,6)),'D':(1,(14,9))}
cur=cells=0
S=supergrid(current_frame)
occ={}
for R in range(1,21):
    for C in range(21):
        ch=S[R][C]
        if ch in 'pbc.': continue
        occ[(R,C)]=ch
pred={}
for k,(vi,pos) in model.items():
    b,t=cells_of(V,k,vi,pos)
    for c in b: pred[c]=k
    for c in t: pred[c]=k
missing=[c for c in pred if c not in occ]
extra=[c for c in occ if c not in pred]
print('model mismatch: predicted-but-absent',missing[:10],'present-but-unpredicted',extra[:10])
print('n occ'
… [29 caracteres más]
```

```text
model mismatch: predicted-but-absent [(1, 2), (5, 5), (1, 5), (4, 6), (1, 4), (2, 6), (5, 6), (3, 6), (2, 2), (1, 6)] present-but-unpredicted []
n occ 10 n pred 67
```

## Paso 51 · nivel 6 · acción 228

**Pensamiento:**

My snap6 filter excluded 'c' (charcoal) — that's why only 10 cells (the orange A + red) were found. I should NOT exclude 'c' but exclude the top bar row (real row 0 → super row -1... hmm, my loop starts at R=1 so the bar at super row -1/0 is excluded ✓). But wait, the bar is at real row 0 → super row (0-2)//3 = -1 ✓ excluded.
So the issue: I excluded 'c' which IS the pieces' color. Let me fix: exclude only 'b' and 'p' (backgrounds) and '.'.
Let me redo the model check with 'c' included.

```python
V=mkV7()
model={'G':(1,(1,1)),'A':(0,(1,14)),'C':(0,(12,1)),'B':(5,(6,6)),'D':(1,(14,9))}
S=supergrid(current_frame)
occ={}
for R in range(1,21):
    for C in range(21):
        ch=S[R][C]
        if ch in 'bp.': continue
        occ[(R,C)]=ch
pred={}
for k,(vi,pos) in model.items():
    b,t=cells_of(V,k,vi,pos)
    for c in b|t: pred[c]=k
missing=sorted(set(pred)-set(occ)); extra=sorted(set(occ)-set(pred))
print('occ',len(occ),'pred',len(pred),'missing',missing[:12],'extra',extra[:12])
```

```text
occ 68 pred 67 missing [] extra [(17, 1)]
```

**Pensamiento:**

The model matches except one extra cell at (17,1). Hmm, that's near the C piece (pos (12,1), rot 0: body local (1,0)..(4,0) → abs (13,1),(14,1),(15,1),(16,1); tips (12,1),(17,2)).
So (17,1) is an extra dark cell adjacent to the C body's bottom (16,1). Hmm! That means C is NOT in the state I think. Let me look: the image shows the bottom-left piece as an "L" shape: a vertical bar of 4-5 cells with a foot at the bottom-right.
In the level-6 initial image, the bottom-left piece: a vertical bar (rows 13-17?) with a foot at the bottom-right (col 2). Hmm, so C's body is 5 cells: (13,1),(14,1),(15,1),(16,1),(17,1) + a foot (17,2)?
Wait, the initial scan of C: 'S' cells (13,1),(14,1),(15,1),(16,1),(17,1) — 5 cells (I mis-modeled it as 4!). And the tips (12,1) and (17,2).
Hmm, but the image shows the foot at the bottom-right at row 17 col 2... and the tip at (17,2) is the red cell when selected. In the current image (unselected), the bottom-left piece shows a vertical bar with a foot to the right at the bottom — that foot is the tip cell (17,2) rendered dark when unselected!
So C's body = 5 cells (rows 13-17, col 1) → local (1,0),(2,0),(3,0),(4,0),(5,0)?? But then the tip (17,2) would be adjacent to the body...
Hold on. Let me recount from the earlier scan output:
"C pos (13,1) H 18 W 2" for 'S' — the S cells were listed as rows 13-17 col 1 (5 cells: the print showed 5 '#' in the last 5 rows of column 1).
Hmm, the print for 'S' was:
```
S pos (13, 1) H 18 W 2
   .. (rows 0..12 all '..
… [1713 caracteres más]

```python
import builtins
def L6P():
    return {'G':{'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1)],'tips':[(2,4),(4,2),(5,0)],'H':6,'W':5},
            'A':{'body':[(0,0),(0,1),(0,2),(0,3),(1,0),(1,3),(2,3),(3,3)],'tips':[(2,0),(3,2)],'H':4,'W':4},
            'C':{'body':[(1,0),(2,0),(3,0),(4,0),(5,0)],'tips':[(0,0),(5,1)],'H':6,'W':2}}
def mkV7():
    P=L6P(); out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.append((i,frozenset(s['body']),frozenset(s['tips']),H,W)); s,H,W=rot(s,H,W)
        out[k]=vs
    for nm,F,rng in (('B',B6,6),('D',D6,4)):
        out[nm]=[(i,frozenset(d['body']),frozenset(d['tips']),d['H'],d['W']) for i,d in enumerate([F(j) for j in ran
… [1668 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 1, in <module>
ImportError: Module 'builtins' is not allowed in the sandbox.
```

## Paso 51 · nivel 6 · acción 228

**Pensamiento:**

Oops, `import builtins` isn't allowed. I don't need it — just define L6P/mkV7 normally (redefining retained functions is allowed).

```python
def L6P():
    return {'G':{'body':[(0,0),(0,1),(0,2),(0,3),(0,4),(1,0),(1,4),(2,0),(3,0),(4,0),(4,1)],'tips':[(2,4),(4,2),(5,0)],'H':6,'W':5},
            'A':{'body':[(0,0),(0,1),(0,2),(0,3),(1,0),(1,3),(2,3),(3,3)],'tips':[(2,0),(3,2)],'H':4,'W':4},
            'C':{'body':[(1,0),(2,0),(3,0),(4,0),(5,0)],'tips':[(0,0),(5,1)],'H':6,'W':2}}
def mkV7():
    P=L6P(); out={}
    for k,v in P.items():
        s={'body':list(v['body']),'tips':list(v['tips'])}; H=v['H']; W=v['W']; vs=[]
        for i in range(4):
            vs.append((i,frozenset(s['body']),frozenset(s['tips']),H,W)); s,H,W=rot(s,H,W)
        out[k]=vs
    for nm,F,rng in (('B',B6,6),('D',D6,4)):
        out[nm]=[(i,frozenset(d['body']),frozenset(d['tips']),d['H'],d['W']) for i,d in enumerate([F(j) for j in range(rng)])]
    r
… [1593 caracteres más]
```

```text
missing [] extra []
fixrot 0 nodes 400004 sols 0
fixrot 1 nodes 400004 sols 0
fixrot 2 nodes 400004 sols 0
fixrot 3 nodes 400004 sols 0
```

**Pensamiento:**

The model now matches the board exactly (missing/extra empty) ✓ — so C has 5 body cells ✓ and my other shapes are right.
But still no all-paired solutions (within the 400k node budget; the search may not be exhaustive but it explored a lot).
Note: the search is still incomplete in the sense that a piece might pair only with pieces placed later. Since I iterate over all orders (`for nxt in names` picks any unplaced), a config where all tips pair has at least one valid order? Not necessarily: consider a config where the pieces form a cycle... hmm, with all tips paired, take any piece P; its tips pair with neighbors. Start with G, then any piece that shares a pair with G can be placed (its tip aligns with an unpaired tip of G ✓). Then continue: since the assembly is connected (all tips paired implies the pieces connect via tip pairs; if the assembly is disconnected into two groups, each group's tips are internally paired — then some order works anyway as long as each group is connected... but a group could be a "cycle" where... no: in any connected graph, there's always a piece adjacent to the placed set whose tip pairs with an unpaired tip of the placed set ✓. And if the assembly is disconnected, we'd need to place a disconnected piece with no tip alignment → my search requires each new piece to align with an unpaired tip → it can't build a disconnected assembly. Hmm! Could the winning config have 2 separate groups (each internally all-paired)? Possible in principle.
Let me han
… [2603 caracteres más]

```python
for i in [140,160,175,185,190,191,192]:
    e=history[i]
    if e.frame.level!=5: continue
    c=count_colors(e.frame)
    print(i,e.frame.step,str(e.action)[:20],{k:v for k,v in c.items() if v<800})
```

```text
140 140 SPACE {'W': 10, 'c': 274, 'Y': 45, 'R': 36}
160 160 UP {'W': 5, 'c': 351, 'N': 72, 'R': 27}
175 175 LEFT {'W': 9, 'c': 329, 'R': 18, 'S': 72}
185 185 UP {'W': 11, 'c': 345, 'R': 18, 'O': 36}
190 190 LEFT {'W': 12, 'c': 344, 'R': 18, 'O': 36}
191 191 LEFT {'W': 12, 'c': 344, 'R': 18, 'O': 36}
… [51 caracteres más]
```

## Paso 51 · nivel 6 · acción 228

**Pensamiento:**

Interesting: at step 140 (level 5) the colors were W 10, c 274, Y 45, R 36 → the yellow piece was 'Y' (selected) with 5 cells (45px) and 4 tips (36px=4 cells)? Hmm, R 36 = 4 cells. And at step 160: N 72 (8 cells green?) hmm, level 5's colors varied because the selected piece is recolored.
At step 185-192: 'O' 36 = 4 cells orange, R 18 = 2 red cells, c 344.
Hmm, so in level 5's final frames, only 2 red cells existed. The pieces were: 4 darks + 1 growable. The selected piece (orange, 4 cells) — hmm, in level 5 the last selected piece was the L-shaped one (4 cells?) hmm.
So at the moment of the win, only 2 red cells = the selected piece's 2 tips (unpaired!). Hmm, but my level-5 solution had all tips paired...
Wait, maybe my level-5 solution did NOT have all tips paired! Let me check the level-5 final frame (history[192]) more carefully: I printed the supergrid and saw the assembly at rows 4-10. The 'c' cells were all connected. The R cells at (8,13) and (10,12), O at (8,14),(9,13),(10,13),(10,14).
Hmm, the O piece: (8,14) and (9,13),(10,13),(10,14) — that's not a connected shape... (8,14)-(9,14)? no, (9,13) is not adjacent to (8,14). Hmm, (9,13),(10,13),(10,14) are connected; (8,14) is not adjacent to any of them (8,14)-(9,14) empty.
So the frame is mid-animation with pieces being recolored/moved. Confusing. It's a win animation.
Key takeaway: at the win, the pieces formed one connected blob ✓. I can't be sure about the tips.
Given the level-5 win happened when the last piece at
… [1632 caracteres más]

```python
def cost_model2():
    return {'G':{'rot':1,'pos':(1,1)},'A':{'rot':0,'pos':(1,14)},'C':{'rot':0,'pos':(12,1)},
            'B':{'st':5,'dir':-1,'pos':(6,6)},'D':{'st':1,'dir':-1,'pos':(14,9)}}
def build_plan6b(pl,cur,V,order,BR=19,BC=19):
    st={k:dict(pos=cur[k]['pos'],vi=(cur[k]['rot'] if k in 'GAC' else cur[k]['st'])) for k in pl}
    tgt={k:(pl[k][0],pl[k][1]) for k in pl}
    acts=[]
    def others_cells(k,use_target=False):
        b=set(); t=set()
        for o in pl:
            if o==k: continue
            vi=st[o]['vi']; pos=st[o]['pos']
            ob,ot=cells_of(V,o,vi,pos); b|=ob; t|=ot
        return b,t
    for k in order:
        vi_goal,pos_goal=tgt[k]
        if k in 'GAC': n=(vi_goal-st[k]['vi'])%4
        else: n=presses(st[k]['vi'],cur[k]['dir'],vi_goal,6 if k=='B' 
… [1731 caracteres más]
```

```text
best None
```

**Pensamiento:**

No feasible 6-pair plan found (the loop `if pairs<6: break` stops at the first config with pairs<6, and among the sorted list, the earlier ones are cheap with pairs=4 → break immediately!). Oops: the list is sorted by cost, so the first entry has pairs=4 → break at once. I need to filter to pairs>=6 first.
Let me fix: filter scored for pairs==6, then iterate.

```python
V=mkV7(); cur=cost_model2()
allcfg=[]
for fr in range(4):
    bb,nn=search_conn(fr,budget=60000); allcfg+=bb
scored=[]
for pairs,pl in allcfg:
    e=eval_cfg(pl,cur,V)
    if e: scored.append((e[0],-pairs,e[1],e[2],pairs,pl))
scored.sort(key=lambda x:(x[0],x[1]))
hi=[s for s in scored if s[4]>=6]
print('n configs',len(scored),'with pairs>=6:',len(hi),'cheapest hi cost',hi[0][0] if hi else None)
best=None; tried=0
for cost,mp,dr,dc,pairs,pl in hi[:25]:
    pl2={k:(v[0],(v[1][0]+dr,v[1][1]+dc)) for k,v in pl.items()}
    for order in itertools.permutations(list(pl2)):
        tried+=1
        r=build_plan6b(pl2,cur,V,order)
        if r:
            acts,stp=r; n=sum(len(a) for a in acts)
            if best is None or n<best[0]: best=(n,order,acts,pl2,pairs)
            break
print('tried o
… [154 caracteres más]
```

```text
n configs 3969 with pairs>=6: 24 cheapest hi cost 47

error:
Traceback (most recent call last):
  File "<python_tool>", line 15, in <module>
NameError: name 'itertools' is not defined
```

## Paso 51 · nivel 6 · acción 228

**Pensamiento:**

24 configs with pairs≥6, cheapest cost 47. Hmm, that's expensive (47 model actions ≈ 47 real + clicks). Budget ~18 bar units ≈ maybe 90 actions. Risky but doable.
The cheapest overall (4 pairs) is ~30.
Hmm, let me think about the trade-off. If connectivity is the win condition, the 4-pair config (30 actions) wins. If more pairs are needed, the 6-pair config (47) might win.
Actually, wait. Let me think about this differently! What if the win condition is that all pieces are connected into one component — and importantly, in level 5, the win happened exactly when the last connection was made ✓.
Also consider: the game is probably from the "snake/pipe connection" family where the goal is to connect all pieces into one. The tips are connectors. The count parity doesn't need to be even.
I'll go with the cheapest connected config (~30 actions) — but hmm, if the win needs more, I'd have spent 30 actions and be at ~13 bar units.
Alternatively, a middle ground: pick a config with pairs=5 if it's cheap (~35?). Let me look at the cost distribution by pairs.
Let me compute the min cost per pairs value. Then decide.
Also, I realize there might be an even better approach for the win condition: maybe the win requires ALL tips paired OR all connected... Let me just test connectivity with the cheapest and see. If the board ends up connected but no win, I'll then work on the 6-pair config (from that state, the pieces are already merged though — that's the risk!).
Hmm, the risk of merging: if p
… [3416 caracteres más]

```python
V=mkV7(); cur=cost_model2()
def curvi(k): return cur[k]['rot'] if k in 'GAC' else cur[k]['st']
names=['G','A','C','B','D']
res=[]
for i in names:
    for j in names:
        if i==j: continue
        vi=curvi(i); vj=curvi(j)
        bJ,tJ=cells_of(V,j,vj,cur[j]['pos'])
        bi0,ti0=cells_of(V,i,vi,cur[i]['pos'])
        for (tr,tc) in ti0:
            for (ur,uc) in tJ:
                d=(ur-tr,uc-tc)
                bi=set((r+d[0],c+d[1]) for r,c in bi0); ti=set((r+d[0],c+d[1]) for r,c in ti0)
                if bi&(bJ|tJ) or ti&bJ: continue
                cost=abs(d[0])+abs(d[1])
                res.append((cost,i,j,(tr,tc),(ur,uc),d))
res.sort()
for r in res[:12]: print(r)
```

```text
(4, 'B', 'D', (11, 12), (14, 11), (3, -1))
(4, 'D', 'B', (14, 11), (11, 12), (-3, 1))
(5, 'A', 'B', (3, 14), (7, 13), (4, -1))
(5, 'B', 'A', (7, 13), (3, 14), (-4, 1))
(5, 'B', 'D', (11, 12), (14, 14), (3, 2))
(5, 'B', 'G', (6, 8), (5, 4), (-1, -4))
(5, 'D', 'B', (14, 14), (11, 12), (-3, -2))
(5, 'G
… [195 caracteres más]
```

**Pensamiento:**

The cheapest connection: move B by (3,-1) to pair B's tip (11,12) with D's tip (14,11) → 4 moves. B is currently at max growth (S5). Moving B down 3, left 1 → then its tip (11,12)→(14,11) = D's tip ✓.
Check the path is collision-free: B's body at max spans rows 6-11, cols 6-13; D is at rows 14-18, cols 9-15. Moving B down 3 → rows 9-14 — could collide with D's top (row 14)? The check above says the final position has no body-body/tip-body overlap ✓. The path needs checking step by step.
Let me verify the path with bfs_move and then execute: click B (real coords of a body cell: super (7,7) → real (23,23)), then DOWN DOWN DOWN LEFT.
Then observe: do B and D merge (tips pair, red disappears)? That's the probe (5 actions).
Let me do it.

```python
V=mkV7(); cur=cost_model2()
oB=set(); oT=set()
for o in ['G','A','C','D']:
    vi=cur[o]['rot'] if o in 'GAC' else cur[o]['st']
    b,t=cells_of(V,o,vi,cur[o]['pos']); oB|=b; oT|=t
path=bfs_move(V,'B',5,(6,6),(9,5),oB,oT)
print('path',path)
if path:
    r=action([{'action':'MOUSE','row':23,'col':23}]+[{'action':p} for p in path])
    print('executed',r.get('executed') if isinstance(r,dict) else r)
    S=supergrid(current_frame)
    for R in range(4,20): print(R,''.join(S[R][4:18]))
    print('res',last_action_call_result.get('level_completed'),last_action_call_result.get('game_over'))
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 6, in <module>
TypeError: 'NoneType' object is not subscriptable
```

## Paso 51 · nivel 6 · acción 233

**Pensamiento:**

bfs_move returned None → the goal (9,5) was rejected by `ok()`. Why? Let me check: B at state 5, pos (9,5): body cells local: (0,6),(1,1),(1,2),(1,6),(2,1),(2,6),(3,1),(3,6),(4,1..6) → abs rows 9-13, cols 6-11. Tips local: (0,2),(0,5),(1,7),(2,0),(5,1),(5,6) → abs (9,7),(9,10),(10,12),(11,5),(14,6),(14,11).
D at state 1 pos (14,9): body local: (1,2),(1,5),(2,1),(2,2),(2,5),(2,6),(3,1),(3,6),(4,1..6) → abs rows 15-18, cols 10-15. Tips: (0,2),(0,5),(3,0) → abs (14,11),(14,14),(17,9).
B's tip (14,11) coincides with D's tip (14,11) ✓ (that's the pair).
Is B's body overlapping D's body? B's body rows 9-13, D's rows 15-18 → no.
Is B's tip (14,6) overlapping D's body? D's body cols 10-15 → no.
So why None? Maybe the PATH is blocked. B moving down from (6,6) to (9,5): intermediate (7,6),(8,6),(9,6) then left to (9,5). At (9,6): B's tips → (14,7),(14,12) etc. D's body at rows 15-18 → fine. Hmm, but what about B's tip (14,7) vs D's tip (17,9)? fine.
Hmm, maybe the issue is my `ok()` bounds check: `max(r for r,_ in b)>BR` with BR=19 → B's body max row 13 ✓. Tips min row 9 ✓. Hmm.
Wait — maybe the goal check `if not ok(goal): return None` failed because of the tip-body check with the OTHER pieces: B's tip (14,11) is D's tip ✓ allowed; but B's tip (14,6)? D's body? no.
Hmm, what about A? A rot0 pos (1,14): body rows 1-4. No.
Let me debug: print why ok(goal) fails.
Oh wait! I bet the problem is `oB`/`oT`: I built them from cur for G,A,C,D — but 'G' is the green at rot 1 pos (1,1) ✓, 'A' ro
… [153 caracteres más]

```python
V=mkV7(); cur=cost_model2()
oB=set(); oT=set()
for o in ['G','A','C','D']:
    vi=cur[o]['rot'] if o in 'GAC' else cur[o]['st']
    b,t=cells_of(V,o,vi,cur[o]['pos']); oB|=b; oT|=t
    print(o,vi,cur[o]['pos'],'body',sorted(b)[:3],'...',sorted(t))
var=V['B'][5]
goal=(9,5)
b=set((r+goal[0],c+goal[1]) for r,c in var[1]); t=set((r+goal[0],c+goal[1]) for r,c in var[2])
print('B body max',max(r for r,_ in b),max(c for _,c in b))
print('B tips',sorted(t))
print('body&occB',sorted(b&oB),'body&occT',sorted(b&oT),'tips&occB',sorted(t&oB))
```

```text
G 1 (1, 1) body [(1, 2), (1, 3), (1, 4)] ... [(1, 1), (3, 2), (5, 4)]
A 0 (1, 14) body [(1, 14), (1, 15), (1, 16)] ... [(3, 14), (4, 16)]
C 0 (12, 1) body [(13, 1), (14, 1), (15, 1)] ... [(12, 1), (17, 2)]
D 1 (14, 9) body [(15, 11), (15, 14), (16, 10)] ... [(14, 11), (14, 14), (17, 9)]
B body max 1
… [106 caracteres más]
```

**Pensamiento:**

No conflicts at the goal. So the path must be blocked. Let me check the intermediate positions: from (6,6) moving DOWN to (7,6),(8,6),(9,6):
At (8,6): B's body rows 8-12, cols 6-11; tips: (8,8),(8,11),(9,13),(10,6),(13,7),(13,12).
D's body: rows 15-18 → no conflict. D's tips (14,11),(14,14),(17,9) → B's tip (13,12) vs D's body? no.
Hmm, what about B's tip at (13,12) and D's tip (14,11)? no conflict.
At (9,6): B tips (9,8),(9,11),(10,13),(12,6),(14,7),(14,12); D's body rows 15-18 cols 10-15 → (14,7),(14,12) are tips of B, not body ✓; D's tips (14,11),(14,14),(17,9) → B's tip (14,12) is adjacent to D's tip (14,11) but that's fine (tips can coexist).
Hmm, so why?
OH WAIT. The `ok()` function checks `if b&(blockB|blockT)`. B's BODY at (9,6): rows 9-13 cols 6-11. D's TIPS: (14,11),(14,14),(17,9) → no.
Hmm. Let me just run the BFS manually and print each position's ok status.
Actually — maybe the issue is the START position: `start=(6,6)` must be ok too! At the start, B is at (6,6) and the current board is exactly that ✓. But `ok(start)` isn't checked... The BFS starts from `start` regardless.
Hmm, unless... the goal check: `if not ok(goal): return None` — I verified no conflicts. Let me re-run bfs_move and print the interior.
Ah, I see a possible bug: in bfs_move I compute `var=V[k][vi]` — V[k][vi] assumes the variant index equals vi ✓ (the list is ordered by rot/state 0..n).
Hmm, and `ok(pos)` uses `max(r for r,_ in b)>BR` → BR=19, B's body max row 13 ✓.
`min(r for r,_ in t)<0` ✓
… [36 caracteres más]

```python
V=mkV7(); cur=cost_model2()
oB=set(); oT=set()
for o in ['G','A','C','D']:
    vi=cur[o]['rot'] if o in 'GAC' else cur[o]['st']
    b,t=cells_of(V,o,vi,cur[o]['pos']); oB|=b; oT|=t
var=V['B'][5]; body=var[1]; tips=var[2]
def ok(pos):
    r0,c0=pos
    b=set((r+r0,c+c0) for r,c in body); t=set((r+r0,c+c0) for r,c in tips)
    if r0<0 or c0<0: return 'neg'
    if max(r for r,_ in b)>19 or max(c for _,c in b)>19: return 'maxbody'
    if min(r for r,_ in t)<0 or min(c for _,c in t)<0: return 'negtip'
    if b&oB: return 'body/occB '+str(sorted(b&oB))
    if b&oT: return 'body/occT '+str(sorted(b&oT))
    if t&oB: return 'tip/occB '+str(sorted(t&oB))
    return True
for pos in [(6,6),(7,6),(8,6),(9,6),(9,5),(6,5),(7,5),(8,5)]:
    print(pos,ok(pos))
```

```text
(6, 6) True
(7, 6) True
(8, 6) True
(9, 6) True
(9, 5) True
(6, 5) True
(7, 5) True
(8, 5) True
```

**Pensamiento:**

All these positions are ok! So bfs_move should have found the path. Unless... the bfs_move signature has default BR=19, BC=19 but I passed oB,oT as blockB,blockT ✓. Hmm, and `bfs_move(V,'B',5,(6,6),(9,5),oB,oT)` → inside, `ok(goal)` → True; then BFS from start... 
OH! I see the bug: in bfs_move I set `prev[np_]=(p,mv)` but the initial `prev={start:None}`, and in the path reconstruction I check `while prev[cur][0] is not None` — for the start node, prev[start] is None → `prev[cur][0]` → TypeError on None! That would raise an exception, not return None... unless the goal is reached at a node whose parent is the start: prev[cur] = (start,'DOWN') → prev[cur][0] = start = (6,6) which is not None → continue → cur=start → prev[start][0] → TypeError.
But we got None, not an error. Hmm.
Wait, the earlier error was: `path=bfs_move(...)` → then `if path:` → the traceback said "'NoneType' object is not subscriptable" at line 6, which is the `path=bfs_move(...)` line? Line 6 in that snippet was `path=bfs_move(V,'B',5,(6,6),(9,5),oB,oT)`. Hmm, the error was at line 6 = the bfs_move call → so bfs_move raised the TypeError (from prev[start][0] where prev[start] is None) ✓ That's it! The path WAS found but reconstruction crashed.
Let me fix the reconstruction.

```python
def bfs_move(V,k,vi,start,goal,blockB,blockT,BR=19,BC=19):
    var=V[k][vi]; body=var[1]; tips=var[2]
    def okf(pos):
        r0,c0=pos
        b=set((r+r0,c+c0) for r,c in body); t=set((r+r0,c+c0) for r,c in tips)
        if r0<0 or c0<0: return False
        if max(r for r,_ in b)>BR or max(c for _,c in b)>BC: return False
        if min(r for r,_ in t)<0 or min(c for _,c in t)<0: return False
        return not (b&(blockB|blockT) or t&blockB)
    if not okf(goal): return None
    if start==goal: return []
    from collections import deque
    q=deque([start]); prev={start:(None,None)}
    while q:
        p=q.popleft()
        for dr,dc,mv in [(-1,0,'UP'),(1,0,'DOWN'),(0,-1,'LEFT'),(0,1,'RIGHT')]:
            np_=(p[0]+dr,p[1]+dc)
            if np_ in prev or not okf(np_): continue
 
… [744 caracteres más]
```

```text
path ['DOWN', 'DOWN', 'DOWN', 'LEFT']
[action] batch of 5 actions, 5 executed: MOUSE(row=23, col=23), DOWN, DOWN, DOWN, LEFT
6 bbbbbbbbbbbbbbb
7 bbbbbbbbbbbbbbb
8 bbbbbbbbbbbbbbb
9 bbbbRbbRYbbbbbb
10 bbbYYbbbYRbbbbb
11 bbRYbbbbYbbbbbb
12 bbbYbbbbYbbbbbb
13 bbbYYYYYYbbbbbb
14 bbbRbbbbGbbcbbb
15 bbbbb
… [123 caracteres más]
```

## Paso 52 · nivel 6 · acción 234

**Pensamiento:**

Excellent! HUGE finding: the B tip and D tip paired, and the joined cell turned GRAY ('G' in the supergrid at (14,11) → shown as gray in the image)! So a paired tip becomes a gray/neutral cell — the pieces are now CONNECTED (B yellow selected, D dark, joined via a gray cell at (14,11)).
The level didn't complete (only 2 of 5 pieces connected) ✓ as expected.
So the mechanic: tip+tip → gray cell (a "weld"). The pieces are now linked. 
Now: is the win condition "all pieces connected"? Very likely. Note the gray cell is neither red nor body — so a paired tip pair leaves a gray cell. In the level-5 win frame, there were 2 red cells and 4 orange... hmm, whatever.
IMPORTANT: the level-5 win frame had 'R' 18px = 2 red cells. If the win requires all tips paired, there'd be 0 red. So at level 5's completion there were 2 unpaired tips → the win condition is NOT all-tips-paired ✓✓. It's connectivity (all pieces in one component).
Great. So now my task: connect all 5 pieces into one component, as cheaply as possible.
Now B and D are linked (B at (9,5) state 5, D at (14,9) state 1). They form a merged group. Moving one will move the other? Hmm — careful! If they're welded, moving B might drag D (or the move might be blocked). That could be a problem: I need to move pieces independently to build the assembly.
Hmm, this is a crucial mechanic question: after welding, do the pieces move together? In level 5, I welded pieces and then... hmm, in my level-5 solution I welded the last piece and th
… [1074 caracteres más]

```python
r=action([{'action':'MOUSE','row':38,'col':23},{'action':'UP'}])
d=frame_diff()
print('moved:',[(m['color'],m['from'],m['to'],m['pixels']) for m in d.get('moved',[])])
print('resized:',[(m['color'],m['at_before'],m['at_after'],m['before_pixels'],m['after_pixels']) for m in d.get('resized',[])][:5])
S=supergrid(current_frame)
for R in range(5,20): print(R,''.join(S[R][3:18]))
```

```text
[action] batch of 2 actions, 1 executed: MOUSE(row=38, col=23) | stop_reason: no_op_action
moved: []
resized: [('c', [0, 22], [0, 23], 26, 25), ('W', [0, 16], [0, 16], 6, 7)]
5 bcccbbbbbbbbbbb
6 bbbbbbbbbbbbbbb
7 bbbbbbbbbbbbbbb
8 bbbbbbbbbbbbbbb
9 bbbbRbbRYbbbbbb
10 bbbYYbbbYRbbbbb
11 bbRYbbbbYbbbb
… [154 caracteres más]
```

## Paso 53 · nivel 6 · acción 236

**Pensamiento:**

The MOUSE at (38,23) was a no-op — it didn't select D. Why? Real (38,23) → super ((38-2)//3, (23-2)//3) = (12, 7). That's empty space. I meant to click D: D's body at super (15,11) → real (47,35). Let me click there.
Also, note: B is currently selected (yellow). The gray weld cell is at (14,11).
Let me click D at real (47,35) and then press UP to test whether D moves alone or drags B.
Careful: pressing UP while D is selected might be blocked if the group can't move (B's body would collide... nothing above B). Let's see.
Actually, a cheaper test: click D, press UP, diff. 2 actions.

```python
r=action([{'action':'MOUSE','row':47,'col':35}])
print('sel D?',{k:v for k,v in count_colors(current_frame).items() if v<800})
r=action(['UP'])
d=frame_diff()
print('moved:',[(m['color'],m['from'],m['to'],m['pixels']) for m in d.get('moved',[])])
S=supergrid(current_frame)
for R in range(5,20): print(R,''.join(S[R][3:18]))
```

```text
[action] MOUSE(row=47, col=35) -> effect
sel D? {'W': 16, 'c': 475, 'G': 9, 'R': 18, 'p': 117}
[action] UP -> effect
moved: [('R', [44, 44], [41, 44], 9), ('R', [53, 29], [50, 29], 9), ('p', [47, 32], [44, 32], 63), ('p', [47, 44], [44, 44], 54), ('W', [56, 41], [53, 41], 9)]
5 bcccbbbbbbbbbbb
6 bbb
… [256 caracteres más]
```

## Paso 54 · nivel 6 · acción 236

**Pensamiento:**

VERY IMPORTANT: D moved UP by 1 (D is now selected, shown purple 'p'), and B did NOT move — B stayed at rows 9-13 (now dark 'c' since unselected). And the weld cell: at (13,11) there's now a RED cell! Look at the supergrid: row13 col 11 = 'R' and row 14 col 8 = 'R' (D's tip moved from (14,11) to (13,11)...).
Hmm, let me parse: after D moved up, D's tip that was at (14,11) [welded with B's tip] is now at (13,11), and it's RED again — the weld BROKE! The gray cell is gone (no 'G' in the grid now... wait, 'G' appeared in the color count before the move: G:9 = 1 gray cell). After the move: the grid shows R at (13,11) and the B tip at (13,11)?? 
Let me look at the current supergrid:
row 13: `bbbcccccRbbRbbb` → cols 3-7 'c', col 8 'R', cols 11 'R'
Hmm, wait, the columns: the print starts at col 3. So row13: cols 3,4='c','c'... let me index: string index i → col 3+i.
row13: 'bbbcccccRbbRbbb' → i0..2='bbb', i3..7='ccccc' → cols 6-10 = 'c'; i8='R' → col 11; i11='R' → col 14.
So (13,11)='R' and (13,14)='R'.
B's body at pos (9,5): body cells rows 9-13: (13,6),(13,7),(13,8),(13,9),(13,10),(13,11) → hmm, B's body local (4,1..6) + pos (9,5) → row 13, cols 6-11. So (13,11) is B's BODY cell... but it shows 'R'?!
Hmm, that's confusing. Let me re-derive: B state 5 body: (0,6),(1,1),(1,2),(1,6),(2,1),(2,6),(3,1),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6) + pos (9,5) → (9,11),(10,6),(10,7),(10,11),(11,6),(11,11),(12,6),(12,11),(13,6..11) ✓. And tips: (9,7),(9,10),(10,12),(11,5),(14,6),(14,11).
So
… [2820 caracteres más]

```python
def cost_model3():
    return {'G':{'rot':1,'pos':(1,1)},'A':{'rot':0,'pos':(1,14)},'C':{'rot':0,'pos':(12,1)},
            'B':{'st':5,'dir':-1,'pos':(9,5)},'D':{'st':1,'dir':-1,'pos':(13,9)}}
V=mkV7(); cur=cost_model3()
allcfg=[]
for fr in range(4):
    bb,nn=search_conn(fr,budget=60000); allcfg+=bb
scored=[]
for pairs,pl in allcfg:
    e=eval_cfg(pl,cur,V)
    if e: scored.append((e[0],-pairs,e[1],e[2],pairs,pl))
scored.sort(key=lambda x:(x[0],x[1]))
print('n',len(scored),'cheapest',scored[0][0],scored[0][4])
import itertools
best=None
for cost,mp,dr,dc,pairs,pl in scored[:25]:
    pl2={k:(v[0],(v[1][0]+dr,v[1][1]+dc)) for k,v in pl.items()}
    for order in itertools.permutations(list(pl2)):
        r=build_plan6b(pl2,cur,V,order)
        if r:
            acts,stp=r; n=sum(len(a) for 
… [284 caracteres más]
```

```text
n 3969 cheapest 29 4
best cost (37, ('G', 'A', 'B', 'C', 'D'), 4)
   MOUSE 3 ['SPACE', 'SPACE', 'SPACE']
   MOUSE2 6 
   MOUSE 1 ['SPACE']
   MOUSE2 11 
   MOUSE2 2 
   MOUSE2 3 
   MOUSE 1 ['SPACE']
   MOUSE2 2 
targets {'G': (0, (5, 3)), 'A': (1, (5, 7)), 'B': (5, (9, 3)), 'C': (0, (11, 3)), 'D': 
… [13 caracteres más]
```

**Pensamiento:**

A 37-action plan exists (including 4 MOUSE clicks). The bar shows W=16?? Hmm, earlier the W count was 6 and now the color count showed W:16 — because the selected piece's white cell counts as W (D has a white cell). Let me measure the bar properly with bar() = the top row: W count in row 0.
Budget: at step 237, bar W count = ? Let me check. Earlier at step 228: 6. Let me measure now.
If ~8 units consumed of 24 → 16 left ≈ 16 × 5.8 ≈ 90 actions. Plenty for 37.
The plan: 
1. MOUSE on G + 3 SPACE (rotate green from rot1 to rot0: (0-1)%4 = 3 ✓)
2. Move G 6 steps to (5,3)
3. MOUSE on A + 1 SPACE (A rot 0→1)
4. Move A 11 steps to (5,7)
5. Move B 2 steps to (9,3)
6. Move C 3 steps to (11,3)
7. MOUSE on D + 1 SPACE (D st1→0)
8. Move D 2 steps to (11,9)
Total = 4+6+2+11+2+3+2+2 = 32? The print says 37 total actions including MOUSE clicks: 1+3+6+1+1+11+2+3+1+1+2 = 32... whatever, ~32-37.
Wait, there's an issue: the plan's first entry is "MOUSE 3 ['SPACE','SPACE','SPACE']" — the MOUSE entry doesn't say WHERE to click. I need to compute the real coordinates for clicking each piece at its then-current position. Let me handle that in the executor: given the piece's current pos and variant, pick a body cell → real coords.
Also the "MOUSE2" marker means "click the piece before moving it".
Let me now write the executor:
- Maintain the model state (pos, variant) per piece.
- For each action group: if it's a shape change, click the piece (compute real coords from a body cell), then press SPACE 
… [2189 caracteres más]

```python
def real_of(R,C): return (3*R+2,3*C+2)
def occ_set(f):
    S=supergrid(f)
    return set((R,C) for R in range(1,21) for C in range(21) if S[R][C] not in 'bp.')
def model_set(V,st):
    s=set()
    for k,d in st.items(): s|=cells_of(V,k,d['vi'],d['pos'])[0]|cells_of(V,k,d['vi'],d['pos'])[1]
    return s
def exec_plan6(acts,plan,V,verbose=True):
    st={k:dict(vi=(d['rot'] if k in 'GAC' else d['st']),pos=d['pos']) for k,d in plan['cur'].items()}
    tgt={k:plan['pl'][k] for k in plan['pl']}
    order=plan['order']; log=[]
    idx=0
    # acts structure: list of groups; rebuild from plan instead
    def click_at(k):
        b,t=cells_of(V,k,st[k]['vi'],st[k]['pos'])
        cell=sorted(b)[0]
        r,c=real_of(*cell)
        return {'action':'MOUSE','row':r,'col':c}
    for k in order:
     
… [1007 caracteres más]
```

```text
Python syntax error: '(' was never closed (<python_tool>, line 31)
```

## Paso 54 · nivel 6 · acción 242

**Pensamiento:**

Oops, that code got mangled. Let me write a clean executor.
Structure: 
```python
def exec_plan6(plan, V, cur, order, pl):
    st = {k: dict(vi=(cur[k]['rot'] if k in 'GAC' else cur[k]['st']), pos=cur[k]['pos']) for k in pl}
    log=[]
    def click_at(k): ...
    def others(k):
        b=set(); t=set()
        for o in pl:
            if o==k: continue
            ob,ot=cells_of(V,o,st[o]['vi'],st[o]['pos']); b|=ob; t|=ot
        return b,t
    for k in order:
        vi_goal, pos_goal = pl[k]
        n = (vi_goal-st[k]['vi'])%4 if k in 'GAC' else presses(st[k]['vi'], cur[k]['dir'], vi_goal, 6 if k=='B' else 4)
        if n:
            res = action([click_at(k)]+[{'action':'SPACE'}]*n)
            st[k]['vi']=vi_goal
            if model_set(V,st)!=occ_set(current_frame): return st,['shape mismatch '+k]
        ob,ot = others(k)
        path = bfs_move(V,k,vi_goal,st[k]['pos'],pos_goal,ob,ot)
        if path is None: return st,['no path '+k]
        res = action([click_at(k)]+[{'action':m} for m in path])
        st[k]['pos']=pos_goal
        if model_set(V,st)!=occ_set(current_frame): return st,['move mismatch '+k]
        log.append((k,len(path)))
    return st,log
```
Note: the model_set vs occ_set comparison — one subtlety: when two tips coincide (a weld), the model set has the cell once and the board has it once ✓. When a tip coincides with another piece's body (allowed during movement? my bfs allows mover's tips on blocker bodies), the board shows it once ✓.
Careful: 
… [1223 caracteres más]

```python
def exec_plan6(pl,order,V,cur,stop_after=None):
    st={k:dict(vi=(cur[k]['rot'] if k in 'GAC' else cur[k]['st']),pos=cur[k]['pos']) for k in pl}
    log=[]
    def click_at(k):
        b,t=cells_of(V,k,st[k]['vi'],st[k]['pos'])
        r,c=real_of(*sorted(b)[0]); return {'action':'MOUSE','row':r,'col':c}
    def others(k):
        b=set(); t=set()
        for o in pl:
            if o==k: continue
            ob,ot=cells_of(V,o,st[o]['vi'],st[o]['pos']); b|=ob; t|=ot
        return b,t
    for k in order:
        vi_goal,pos_goal=pl[k]
        n=(vi_goal-st[k]['vi'])%4 if k in 'GAC' else presses(st[k]['vi'],cur[k]['dir'],vi_goal,6 if k=='B' else 4)
        if n:
            action([click_at(k)]+[{'action':'SPACE'}]*n)
            st[k]['vi']=vi_goal
            exp=model_set(V,st); got=oc
… [883 caracteres más]
```

```text
helpers ready
```

**Pensamiento:**

Now let me run the plan. Targets: G(0,(5,3)), A(1,(5,7)), B(5,(9,3)), C(0,(11,3)), D(0,(11,9)); order G,A,B,C,D; cur=cost_model3().
Let me first verify the target config is connected (4 pairs) by computing the welds. Then execute stage by stage: run with stop_after='G' first, check, then continue from A... but exec_plan6 restarts the state from cur each time. Better: run the whole plan in one call (it self-verifies and stops on mismatch).
Let me do that.

```python
V=mkV7(); cur=cost_model3()
pl={'G':(0,(5,3)),'A':(1,(5,7)),'B':(5,(9,3)),'C':(0,(11,3)),'D':(0,(11,9))}
order=['G','A','B','C','D']
# sanity: compute welds in target config
occT={}
for k,(vi,pos) in pl.items():
    b,t=cells_of(V,k,vi,pos)
    for c in t: occT.setdefault(c,[]).append(k)
welds={c:v for c,v in occT.items() if len(v)>1}
print('welds',welds)
st,log=exec_plan6(pl,order,V,cur)
print('log',log)
print('completed?',last_action_call_result.get('level_completed'),'over',last_action_call_result.get('game_over'))
print('bar W',bar(current_frame).count('W'),'step',current_frame.step)
```

```text
welds {(9, 5): ['G', 'B'], (7, 7): ['G', 'A'], (11, 3): ['B', 'C'], (14, 9): ['B', 'D']}
[action] batch of 4 actions, 4 executed: MOUSE(row=5, col=8), SPACE, SPACE, SPACE
[action] batch of 7 actions, 2 executed: MOUSE(row=5, col=5), DOWN | stop_reason: no_op_action
log ['MISMATCH-move-G[(1, 1), (1, 
… [82 caracteres más]
```

## Paso 55 · nivel 6 · acción 243

**Pensamiento:**

Interesting! Several things happened:
1. The 3 SPACEs on the green: the green rotated from rot1 → rot0? The diff shows the green piece changed shape (rotated) ✓. But note: the green's TIPS disappeared from the diff (no red cells in the diff for the green!). Hmm, the current image shows NO red tips anywhere! Look: the image shows the green piece at top-left (dark), B and D in the middle (dark), A at top-right (dark), C at bottom-left (dark) — and NO red tips visible anywhere!
Wait, what? Where did the tips go?!
Hmm, the diff image shows the top-left piece with blue (sky) cells — that's the changed cells. Hmm, the current image shows the top-left piece in a shape like "P" (rot 0 of the green? The green rot 0 = 
```
#####
#...#
#....
#....
##...
```
The image shows: a top row of 5, a left column, a right column going down 2, and a foot. Yes that's the green rot 0 ✓ but no red tips.
2. The 'DOWN' on the green was a NO-OP → the green couldn't move down. Why? Because... hmm.
3. No red tips anywhere now! And the earlier color counts: 'R' 18 at step 236 (2 tips: D's tips should be 3!). Hmm.
Let me look at the current frame carefully: count colors and check for red.
Something important: maybe the tips are only shown for the SELECTED piece! Yes!! That's it — earlier when I clicked pieces, the red tips appeared for the selected piece only. And when nothing was selected (or after deselecting?), no red. But earlier frames showed red tips for unselected pieces too (e.g., at the level start
… [2815 caracteres más]

```python
S=supergrid(current_frame)
print('   '+''.join(str(c%10) for c in range(20)))
for R in range(0,20): print(R,''.join(S[R][0:20]))
print('colors',{k:v for k,v in count_colors(current_frame).items() if v<900})
```

```text
01234567890123456789
0 bbbbbbbbbbbbbbbbbbbb
1 bcccccbbbbbbbbccccbb
2 bcbbbcbbbbbbbbcbbcbb
3 bcbbbcbbbbbbbbcbbcbb
4 bcbbbbbbbbbbbbbbccbb
5 bcccbbbbbbbbbbbbbbbb
6 bcbbbbbbbbbbbbbbbbbb
7 bbbbbbbbbbbbbbbbbbbb
8 bbbbbbbbbbbbbbbbbbbb
9 bbbbbbbcbbccbbbbbbbb
10 bbbbbbccbbbccbbbbbbb
11 bbbbbccbbbbcbbbbbbbb
1
… [216 caracteres más]
```

**Pensamiento:**

Now I see the real state: NO red cells at all, and no white cell either (the D piece's white cell is gone!). Colors: only 'c' (charcoal) 618 px and 'W' 8 (the bar).
So NOTHING is selected now?! And the tips are invisible (rendered as 'c' — same as the bodies, so the tips are there but indistinguishable).
Hmm! Look at row 5: 'bccc...' → cols 1,2,3 = 'c'. And row 6: 'bc...' → col 1. So the green piece at rot 0: body (1,1)-(1,5),(2,1),(2,5),(3,1),(3,5),(4,1)?? 
Row 1: cols 1-5 ✓ (5 cells)
Row 2: col 1, col 5
Row 3: col 1, col 5
Row 4: col 1
Row 5: cols 1,2,3 → hmm, the green rot 0's body has (4,0),(4,1) = rows 5 cols 1,2 — but here we see cols 1,2,3.
Hmm! Row 4: 'bcbbbb...' → only col 1. Row 5: cols 1,2,3.
Expected green rot0 at pos (1,1): body (1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,5),(3,1),(4,1),(5,1),(5,2) and tips (3,5),(5,3),(6,1).
Observed: row1: 1,2,3,4,5 ✓; row2: 1,5 ✓; row3: 1,5 → hmm, (3,5) is the TIP (rendered 'c' now since unselected ✓); row4: 1 ✓; row5: 1,2 and (5,3) is the tip ✓; row6: col 1 = the tip (6,1) ✓.
So the green IS at rot 0 pos (1,1) with its 3 tips rendered as 'c' (unselected). ✓ My model is right!
The tips are only RED when the piece is selected. Good — that also means my earlier "unselected" reads of tips were via selection ✓.
So why was DOWN a no-op for the green? Hmm! Maybe because the green's tip (6,1)... moving down → tip (7,1). Free. Body max row 6 → 7. Fine.
Hmm, unless the click at (5,5) selected a DIFFERENT piece? Real (5,5) → super (1,1) = th
… [3053 caracteres más]

```python
def exec2(pl,order,V,cur,sel=None):
    st={k:dict(vi=(cur[k]['rot'] if k in 'GAC' else cur[k]['st']),pos=cur[k]['pos']) for k in pl}
    log=[]
    def click_at(k):
        b,t=cells_of(V,k,st[k]['vi'],st[k]['pos'])
        r,c=real_of(*sorted(b)[0]); return {'action':'MOUSE','row':r,'col':c}
    def others(k):
        b=set(); t=set()
        for o in pl:
            if o==k: continue
            ob,ot=cells_of(V,o,st[o]['vi'],st[o]['pos']); b|=ob; t|=ot
        return b,t
    def ensure_sel(k):
        nonlocal sel
        if sel==k: return []
        sel=k
        return [click_at(k)]
    for k in order:
        vi_goal,pos_goal=pl[k]
        n=(vi_goal-st[k]['vi'])%4 if k in 'GAC' else presses(st[k]['vi'],cur[k]['dir'],vi_goal,6 if k=='B' else 4)
        acts=ensure_sel(k)+[{'action':
… [1159 caracteres más]
```

```text
[action] batch of 6 actions, 1 executed: DOWN | stop_reason: no_op_action
log ['MISMATCH-move-G[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1)]'] sel G
completed False over False bar 8 step 243
```

## Paso 56 · nivel 6 · acción 244

**Pensamiento:**

DOWN on the green is a NO-OP even though the green is selected (sel='G' — my code assumed sel=None so it sent a click first... wait, the trace shows only DOWN was executed (1 action) — meaning my ensure_sel didn't add a click? It did: sel=None → ensure_sel returns [click]. The batch was "6 actions, 1 executed: DOWN" → hmm, that means the batch was [DOWN, DOWN, DOWN, DOWN, RIGHT, RIGHT]?? No: "batch of 6 actions, 1 executed: DOWN" — the 6 actions were [MOUSE, DOWN, DOWN, DOWN, DOWN, RIGHT]? The trace shows only 1 executed action named DOWN at position 1. So position 0 was the MOUSE (which must have been... hmm, the trace shows only DOWN at position 1 → so position 0 was the MOUSE click and it DID execute (it's not shown as position 0?). Confusing.
Hmm, "batch of 6 actions, 1 executed: DOWN" and the trace lists "1: DOWN -> NO-OP". So the numbering starts at the first executed action? The MOUSE at position 0 presumably executed but was ALSO a no-op?! If the MOUSE click was a no-op, the batch would stop at position 0...
Hmm, the message says "action 'DOWN' (position 1 in that batch) executed but produced no change... The remaining 5 action(s) ['DOWN','DOWN','DOWN','RIGHT','RIGHT'] were skipped" → 1 (DOWN) + 5 = 6 → so position 0 (the MOUSE) executed with an effect ✓, then DOWN at position 1 was a no-op.
So: the green is selected (the click worked) but DOWN does nothing!
Why can't the green move down? Its body spans rows 1-5, tips at (3,5),(5,3),(6,1). Moving down → rows 2-6, tips
… [1717 caracteres más]

```python
r=action(['UP'])
print('UP ->',last_action_call_result.get('stop_reason'),last_action_call_result.get('executed'))
S=supergrid(current_frame)
print('row1-7 cols0-6:',[ ''.join(S[R][0:7]) for R in range(1,8)])
```

```text
[action] UP -> NO-OP (executed, no change inside the board area)
UP -> None True
row1-7 cols0-6: ['bcccccb', 'bcbbbcb', 'bcbbbcb', 'bcbbbbb', 'bcccbbb', 'bcbbbbb', 'bbbbbbb']
```

## Paso 57 · nivel 6 · acción 246

**Pensamiento:**

UP is also a no-op. So the green piece can't move at all?! But the green is at rot 0 pos (1,1) — hmm, its tip is at (3,5),(5,3),(6,1) and the body's bbox is rows 1-5.
Wait — the piece is at the TOP of the board: body row 1. UP would put the body at row 0. Maybe row 0 is not playable (the bar is at row -1/0?). Actually the bar occupies super row -1 (real rows 0-1). Hmm, super row 0 = real rows 2-4. So moving up 1 → the body at row 0 → real rows 2-4, which is right below the bar. Maybe that's blocked.
But DOWN should be free!
Unless the green is NOT selected. Let me reconsider: maybe the MOUSE click at (5,5) DESELECTED the green (because it was already selected from the earlier 3 SPACEs? No wait — before the click at (5,5), the green WAS selected (I had clicked it at (5,8) and pressed SPACE 3 times). So the click at (5,5) DESELECTED it! Then my later ensure_sel('G') in exec2 sent a click at (5,5) again → that would RE-SELECT it. Hmm, but in exec2 the click was sent and then DOWN was a no-op.
Hmm, unless the click in exec2 landed on a cell that is now... The click cell = sorted(body)[0] = the green's body cell (1,1) → real (5,5) ✓ same as before.
Hmm, so: click (5,5) → selects the green → DOWN → no-op??
Unless the click TOGGLED: if the green was already selected (from my earlier click at (5,8) + 3 SPACEs, then the click at (5,5) deselected, then UP/DOWN no-ops), then in exec2 the click at (5,5) re-selected it → DOWN should work.
But DOWN was a no-op in exec2 too. And now UP is a
… [606 caracteres más]

```python
r=action([{'action':'MOUSE','row':5,'col':5}])
c1={k:v for k,v in count_colors(current_frame).items() if v<900}
print('after click',c1,'stop',last_action_call_result.get('stop_reason'))
r=action(['DOWN'])
print('after DOWN',{k:v for k,v in count_colors(current_frame).items() if v<900},'stop',last_action_call_result.get('stop_reason'))
S=supergrid(current_frame); print(''.join(S[1][0:7]),''.join(S[6][0:7]),''.join(S[7][0:7]))
```

```text
[action] MOUSE(row=5, col=5) -> effect
after click {'W': 8, 'c': 492, 'N': 99, 'R': 27} stop None
[action] DOWN -> effect
after DOWN {'W': 8, 'c': 492, 'N': 99, 'R': 27} stop None
bbbbbbb bNNRbbb bRbbbbb
```

## Paso 58 · nivel 6 · acción 251

**Pensamiento:**

Now the green is selected (N = green cells, R = 27 = 3 tips) and DOWN worked! The supergrid shows row 6: 'bNNRbbb' and row 7: 'bRbbbbb' → the green moved DOWN by 1 ✓ (the body now at rows 2-6, tip at (7,1)).
So the earlier failure: the green was NOT selected when I pressed DOWN (the click at (5,5) had DESELECTED it, and in exec2 the click... hmm, in exec2 the click at (5,5) should have re-selected it).
Hmm, wait: in exec2, before the click, was the green selected? Sequence: [click(5,5) deselect] → then UP no-op (step 245) → then in the next call I did click(5,5) → SELECT (effect ✓) → DOWN → effect ✓ moved.
But in exec2 (step 243-244): the state before was: nothing selected (after the earlier deselect). exec2 sent click(5,5) → should select. Then DOWN → no-op?!
Unless the click at (5,5) at that moment DESELECTED... Let me check the history: at step 242 the frame had NO red (nothing selected). Then exec2: click(5,5) at step 243 → the trace says the MOUSE "executed" (not marked NO-OP) → then DOWN at step 244 → NO-OP.
Hmm, so the click had an effect (selection) but DOWN did nothing. Weird.
OH! I think I understand now! Maybe the click at (5,5) selected the piece, but the piece can only be moved if the click lands on a cell that... hmm.
OR: maybe the selection has TWO roles: clicking selects the piece for MOVEMENT, but the "active" piece for arrows is a different concept? Hmm.
Alternatively, maybe there's a "grab" mechanic: the first click selects, and the arrows move the piece on
… [1235 caracteres más]

```python
def try_step(k,mv,V,st,others_excl=None):
    action([{'action':mv}])
    exp=model_set(V,st); got=occ_set(current_frame)
    if exp==got: return True
    # retry: click piece then repeat move
    b,t=cells_of(V,k,st[k]['vi'],st[k]['pos'])
    r,c=real_of(*sorted(b)[0])
    action([{'action':'MOUSE','row':r,'col':c},{'action':mv}])
    return model_set(V,st)==occ_set(current_frame)
V=mkV7()
st={'G':{'vi':0,'pos':(2,1)},'A':{'vi':0,'pos':(1,14)},'C':{'vi':0,'pos':(12,1)},'B':{'vi':5,'pos':(9,5)},'D':{'vi':1,'pos':(13,9)}}
def others(k):
    b=set(); t=set()
    for o in st:
        if o==k: continue
        ob,ot=cells_of(V,o,st[o]['vi'],st[o]['pos']); b|=ob; t|=ot
    return b,t
def move_to(k,pos_goal):
    ob,ot=others(k)
    path=bfs_move(V,k,st[k]['vi'],st[k]['pos'],pos_goal,ob,ot)
    
… [430 caracteres más]
```

```text
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] RIGHT -> effect
[action] RIGHT -> effect
G move ok(5, 3)
completed False bar 9
```

## Paso 59 · nivel 6 · acción 264

**Pensamiento:**

The green moved to (5,3) ✓ and the verification passed (the model set matches the board) ✓. The green is still selected (green color with red tips).
Note: the bar W count went from 8 to 9?! Hmm, the bar is at the top; W 9 vs 8 — the bar's white segment count fluctuates as it shrinks? Whatever, the bar is small.
Hmm, actually the W count includes the D piece's white cell when D is selected. Currently the green is selected → W = the bar only = 9. Earlier it was 8? Hmm, it went UP? That's odd for a timer. Maybe the bar isn't a timer. Let me not worry.
Now continue: A: rotate 0→1 (1 SPACE) then move to (5,7). The green is currently selected; clicking A selects A ✓.
Then B: 2 LEFT to (9,3). Then C: 2 DOWN 2 RIGHT to (11,3). Then D: 1 SPACE (st1→0) then 2 UP to (11,9).
Let me write the full robust sequence with the retry logic. I'll define move_to and click helpers taking V and st as arguments so they can be retained.
Plan for this call: handle A (rotate + move). Then next call: B, C, D.
Actually, let me do all of it in one call with per-step verification; if something goes wrong it stops and reports.
Careful with the shape change for A: click A, then 1 SPACE. Verify.
For the shape change, I need to be careful about the deselect-toggle issue: clicking a DIFFERENT piece always selects it ✓ (observed). The green is currently selected; clicking A → selects A ✓.
Let me write a comprehensive function exec_rest(V, st, steps) where steps is a list of (kind, k, arg).

```python
def others_of(V,st,k):
    b=set(); t=set()
    for o in st:
        if o==k: continue
        ob,ot=cells_of(V,o,st[o]['vi'],st[o]['pos']); b|=ob; t|=ot
    return b,t
def click_piece(V,st,k):
    b,t=cells_of(V,k,st[k]['vi'],st[k]['pos'])
    r,c=real_of(*sorted(b)[0])
    action([{'action':'MOUSE','row':r,'col':c}])
def move_seq(V,st,k,path):
    for mv in path:
        dr={'UP':-1,'DOWN':1}.get(mv,0); dc={'LEFT':-1,'RIGHT':1}.get(mv,0)
        st[k]['pos']=(st[k]['pos'][0]+dr,st[k]['pos'][1]+dc)
        action([{'action':mv}])
        if model_set(V,st)!=occ_set(current_frame):
            click_piece(V,st,k); action([{'action':mv}])
            if model_set(V,st)!=occ_set(current_frame): return 'stuck:'+mv
    return 'ok'
def shape_seq(V,st,k,n,dirn=None,nmax=4,goal_vi=None):
    if n
… [807 caracteres más]
```

```text
[action] MOUSE(row=5, col=44) -> effect
[action] SPACE -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] DOWN -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> effect
[action] LEFT -> ef
… [210 caracteres más]
```

## Paso 60 · nivel 6 · acción 274

**Pensamiento:**

Excellent!! A is now at (5,7) rot 1 and there's a GRAY weld cell at (7,7) — G and A are now connected ✓ (the weld formed when A arrived). The A piece is orange (selected) with 1 red tip visible at (5,7)... 
Wait, A rot 1 should have 2 tips. Hmm, one tip is welded (gray at (7,7)) and the other is red at (5,7)? Hmm, the image shows 1 red cell at the top-left of the orange piece and the gray cell at its left-middle. OK ✓ consistent.
Now: B, C, D remain. Targets: B(5,(9,3)): from (9,5) → 2 LEFT; C(0,(11,3)): from (12,1) → 1 DOWN + 2 RIGHT; D(0,(11,9)): from (13,9) st1 → st0 (1 SPACE) then 2 UP.
The welds: (9,5) G-B ✓ (G's tip at (9,5)? G rot0 at pos (5,3): tips (7,8),(9,6),(10,3)... hmm, earlier the weld list said (9,5): ['G','B'] — let me trust the earlier computation: welds {(9,5):[G,B], (7,7):[G,A], (11,3):[B,C], (14,9):[B,D]}.
Hmm, but the gray cell I see is at (7,7) ✓ matches [G,A].
Let me continue: B 2 LEFT, then C, then D.
Note: after B moves to (9,3), B's tip welds with G at (9,5) ✓ and with C at (11,3) — but C must already be in place BEFORE B arrives for that weld to form; order doesn't matter for the final state though (welds form when both are in place). The level completes when all are connected.
Order: B first, then C, then D. But careful: when B moves left 2, does it pass through positions overlapping G's cells? The bfs computed the path with the others as blockers ✓ (it returned a path presumably).
Also careful: B's move might create the weld with G as soon as B a
… [884 caracteres más]

```python
V=mkV7()
st={'G':{'vi':0,'pos':(5,3)},'A':{'vi':1,'pos':(5,7)},'C':{'vi':0,'pos':(12,1)},'B':{'vi':5,'pos':(9,5)},'D':{'vi':1,'pos':(13,9)}}
log=[]
for k,goal in [('B',(9,3)),('C',(11,3))]:
    ob,ot=others_of(V,st,k); p=bfs_move(V,k,st[k]['vi'],st[k]['pos'],goal,ob,ot)
    log.append((k,p,move_seq(V,st,k,p) if p else 'NOPATH'))
log.append(('D-shape',shape_seq(V,st,'D',1,goal_vi=0)))
ob,ot=others_of(V,st,'D'); p=bfs_move(V,'D',0,st['D']['pos'],(11,9),ob,ot)
log.append(('D-move',p,move_seq(V,st,'D',p) if p else 'NOPATH'))
print(log)
print('st',{k:v['pos'] for k,v in st.items()})
lr=last_action_call_result
print('completed',lr.get('level_completed'),'over',lr.get('game_over'),'step',current_frame.step)
print('colors',{k:v for k,v in count_colors(current_frame).items() if v<900})
```

```text
[action] LEFT -> effect
[action] MOUSE(row=29, col=32) -> effect
[action] LEFT -> effect
[action] UP -> effect
[action] MOUSE(row=38, col=5) -> effect
[action] UP -> effect
[action] MOUSE(row=44, col=35) -> effect
[action] SPACE -> effect
[action] MOUSE(row=44, col=35) -> effect
[action] SPACE -> NO
… [322 caracteres más]
```

## Paso 61 · nivel 6 · acción 274

**Pensamiento:**

Some moves got "stuck" and my model state is now out of sync with the board. The colors show only 'c' (nothing selected) → 604 px of charcoal.
The "stuck" cases: B moved LEFT once (from (9,5) to (9,4)) then the second LEFT was a no-op even after a re-click. Similarly C moved UP once then stuck. And D's SPACE didn't work.
Why? The deselect-toggle behavior: my `move_seq` sends the arrow first (without clicking). If the piece is already selected, the arrow works ✓. But if it's NOT selected, the arrow is a no-op → then my retry clicks the piece and repeats the arrow. Hmm, but the retry failed too.
Hmm, why would the retry fail? Because the click on the piece... Ahh, I think I understand the real mechanic now! Maybe clicking a piece selects it, but the ARROW only works if the click was the LAST action (i.e., the selection takes effect) — no...
Let me look at the trace:
1. LEFT → effect (B moved, B was already selected from the previous call? yes, A was selected... hmm, no: after A's move, A was selected. So the first LEFT should have moved A, not B!
Hmm! But the trace shows "LEFT -> effect" then "MOUSE(29,32)" then "LEFT -> effect".
Hmm, my code for B: move_seq(V,st,'B',p) sends LEFT (no click first!) — but A was the selected piece! So the first LEFT moved A! Then the verification failed (model mismatch) → the retry clicked B at (29,32) → LEFT → effect (B moved). Then the verification compared... hmm.
So my move_seq's assumption "the piece is already selected" is WRONG — the previ
… [1022 caracteres más]

```python
print(snap6.__doc__)
import inspect
print(inspect.getsource(snap6)[:800])
```

```text
None

error:
Traceback (most recent call last):
  File "<python_tool>", line 2, in <module>
ImportError: Module 'inspect' is not allowed in the sandbox.
```

**Pensamiento:**

Let me just call snap6(current_frame, V) and see what it returns.

```python
V=mkV7()
try:
    print(snap6(current_frame,V))
except Exception as e:
    print('err',e)
```

```text
{}
```

**Pensamiento:**

snap6 returned {} — it didn't fit anything (maybe it requires a selected piece with red tips, or its filter excludes 'c'). Let me write a fresh fitter: for each piece, try all variants and positions to cover the board's non-bg cells exactly with no overlap and full coverage. That's a set-cover/exact-cover problem with 5 pieces — feasible with a DFS: pick the topmost-leftmost uncovered cell, try all (piece, variant, position) that cover it and don't overlap.
The board has 604/9 ≈ 67 cells. Let me do the DFS.

```python
def fit_board(f,V,names=('G','A','C','B','D')):
    occ=occ_set(f)
    cells=sorted(occ)
    variants={}
    for k in names:
        lst=[]
        for vi in range(len(V[k])):
            b,t=cells_of(V,k,vi,(0,0))
            lst.append((vi,frozenset(b),frozenset(t)))
        variants[k]=lst
    sols=[]
    def rec(rem,placed,used):
        if not rem:
            sols.append(dict(placed)); return True
        r0,c0=min(rem)
        for k in names:
            if k in used: continue
            for vi,b,t in variants[k]:
                for (br,bc) in sorted(b):
                    pos=(r0-br,c0-bc)
                    cc=frozenset(((x+pos[0],y+pos[1]) for x,y in b)|((x+pos[0],y+pos[1]) for x,y in t))
                    if not cc<=occ: continue
                    if cc&used: continue
  
… [271 caracteres más]
```

```text
Traceback (most recent call last):
  File "<python_tool>", line 31, in <module>
  File "<python_tool>", line 28, in fit_board
  File "<python_tool>", line 21, in rec
TypeError: unsupported operand type(s) for |: 'generator' and 'generator'
```

**Pensamiento:**

Fix the generator/set union: use set(...) | set(...).
Also the "return True on first solution" logic returns as soon as a full cover is found ✓.
Note: a subtlety — the tips of one piece may coincide with another's body/tips (welds), so requiring cc disjoint from `used` is wrong for welded tips. Let me allow tip-tip and tip-body overlaps: build the placement as (body_set, tip_set); require body ∩ used_body = ∅, body ∩ used_tip... hmm, actually a body cell can't coincide with anything. A tip can coincide with another tip (weld) or a body? During movement yes, but in a static fit, the current board might have a tip on a body.
Simplify: track used_body separately; require body ∩ (all cells) = ∅ except its own; tips may overlap tips.
Let me implement: for a placement, require body ∩ (used_body | used_tip) == ∅ and (body|tip) ⊆ occ... plus tips may overlap previously used tips ✓.
Also every occ cell must be covered by something.
Let me redo.

```python
def fit_board(f,V,names=('G','A','C','B','D')):
    occ=occ_set(f)
    variants={k:[(vi,)+cells_of(V,k,vi,(0,0)) for vi in range(len(V[k]))] for k in names}
    sols=[]
    def rec(rem,placed,usedB,usedT):
        if not rem:
            sols.append(dict(placed)); return True
        r0,c0=min(rem)
        for k in names:
            if k in placed: continue
            for vi,b,t in variants[k]:
                for (br,bc) in sorted(b):
                    pos=(r0-br,c0-bc)
                    bb=set((x+pos[0],y+pos[1]) for x,y in b); tt=set((x+pos[0],y+pos[1]) for x,y in t)
                    if not (bb|tt)<=occ: continue
                    if bb&(usedB|usedT): continue
                    placed[k]=(vi,pos)
                    if rec((rem-bb-tt),placed,usedB|bb,usedT|tt): return True

… [167 caracteres más]
```

```text
None
```

**Pensamiento:**

No fit → my model doesn't match the board. Something is off: maybe a piece changed variant unexpectedly (e.g., D's SPACE worked once → st0, and the second SPACE did nothing... or the D piece grew). Or the pieces' cells include a gray weld cell that's counted once ✓ (that's handled).
Let me diagnose: count the total occ cells and compare with the model's expected total. Also, let me fit subsets: try fitting only the pieces I'm confident about (G, A, C) and see what remains.
Let me print the occ count and the board's supergrid to see the shape.

```python
S=supergrid(current_frame)
for R in range(0,20): print(R,''.join(S[R][0:20]))
print('occ',len(occ_set(current_frame)))
V=mkV7()
for k in ['G','A','C','B','D']:
    print(k,[ (vi,len(V[k][vi][1]),len(V[k][vi][2])) for vi in range(len(V[k]))])
```

```text
0 bbbbbbbbbbbbbbbbbbbb
1 bbbbbbbbbbbbbbbbbbbb
2 bbbbbbbbbbbbbbbbbbbb
3 bbbbbbbbbbbbbbbbbbbb
4 bbbbbbbbbbbbbbbbbbbb
5 bbbcccccccbbbbbbbbbb
6 bbbcbbbcbcbbbbbbbbbb
7 bbbcbbccbcbbbbbbbbbb
8 bbbcbbcccccbbbbbbbbb
9 bbbccccbbbccbbbbbbbb
10 bbbcccbbbbcbbbbbbbbb
11 bcbbbcbbbbcbbbbbbbbb
12 bcbbbccccccbbbbbbbb
… [444 caracteres más]
```

## Paso 61 · nivel 6 · acción 274

**Pensamiento:**

Let me carefully read the board from the supergrid (rows 5-17, cols 1-17):
```
row 5:  cols 3-9  'ccccccc'
row 6:  col 3, col 6, col 8
row 7:  col 3, cols 6,7, col 8
row 8:  col 3, cols 6,7, cols 8,9,10,11
row 9:  cols 3,4,5,6, cols 10,11
row 10: cols 3,4,5, col 10
row 11: col 1, col 5, col 10
row 12: col 1, cols 5,6,7,8,9,10
row 13: col 1, col 5, cols 10,11, col 15
row 14: col 1, col 10, col 15
row 15: col 1, cols 9,10, cols 14,15
row 16: cols 1,2, cols 8,9, col 14
row 17: cols 9,10,11,12,13,14,15
```
Total = 7+3+4+7+6+4+2+6+5+3+5+4+7 = let me count: row5:7, row6:3, row7:4, row8:7, row9:6, row10:4, row11:2, row12:6, row13:5, row14:3, row15:5, row16:4, row17:7 → 7+3+4+7+6+4+2+6+5+3+5+4+7 = 63. Hmm, occ=65. Let me recount from the strings:
row5 'bbbcccccccbbbbbbbbbb' → cols 3-9 = 7 ✓
row6 'bbbcbbbcbcbbbbbbbbbb' → col3, col6, col8 = 3
row7 'bbbcbbccbcbbbbbbbbbb' → col3, col6,col7, col8 = 4
row8 'bbbcbbcccccbbbbbbbbb' → col3, col6..10 = 1+5 = 6
row9 'bbbccccbbbccbbbbbbbb' → cols3-6 (4), cols10,11 (2) = 6
row10 'bbbcccbbbbcbbbbbbbbb' → cols3,4,5 (3), col10 (1) = 4
row11 'bcbbbcbbbbcbbbbbbbbb' → col1, col5, col10 = 3
row12 'bcbbbccccccbbbbbbbbb' → col1, cols5-10 (6) = 7
row13 'bcbbbcbbbbccbbbcbbbb' → col1, col5, cols10,11, col15 = 5
row14 'bcbbbbbbbbbcbbbcbbbb' → col1, col10, col15 = 3
row15 'bcbbbbbbbbccbbbccbbb' → col1, cols9,10, cols14,15 = 5
row16 'bccbbbbbbccbbbbbcbbb' → col1,col2, cols8,9, col14 = 5
row17 'bbbbbbbbbbcccccccbbb' → cols9-15 = 7
Total: 7+3+4+6+6+4+3+7+5+3+5+5+7
… [8696 caracteres más]

```python
def place_scores(f,V,names=('G','A','C','B','D')):
    occ=occ_set(f); out={}
    for k in names:
        cands=[]
        for vi in range(len(V[k])):
            b,t=cells_of(V,k,vi,(0,0))
            H=max(r for r,_ in b|t)+1; W=max(c for _,c in b|t)+1
            for r0 in range(-1,21-H+1):
                for c0 in range(-1,21-W+1):
                    bb=set((r+r0,c+c0) for r,c in b); tt=set((r+r0,c+c0) for r,c in t)
                    if min(r0,-0)<0 and min(r for r,_ in tt)<0: pass
                    cells=bb|tt
                    if min(min(r for r,_ in cells),min(c for _,c in cells))<0: continue
                    good=len(cells&occ); bad=len(cells-occ)
                    if bad==0: cands.append((good,vi,(r0,c0)))
        cands.sort(reverse=True)
        out[k]=cands[:14]
   
… [91 caracteres más]
```

```text
G [(14, 0, (5, 3))]
A [(10, 1, (5, 6))]
C [(7, 3, (16, 11)), (7, 3, (11, 5)), (7, 2, (8, 9)), (7, 1, (12, 5)), (7, 1, (5, 3)), (7, 0, (11, 1))]
B [(20, 5, (8, 4)), (17, 4, (8, 4)), (15, 3, (8, 4)), (12, 2, (8, 4)), (10, 1, (8, 4)), (7, 0, (8, 4))]
D [(18, 2, (13, 9))]
```

## Paso 61 · nivel 6 · acción 274

**Pensamiento:**

Excellent! The placements are now clear:
- G: rot 0 at (5,3) — 14 cells, perfect fit ✓
- A: rot 1 at (5,6) — 10 cells ✓
- B: state 5 at (8,4) — 20 cells ✓ (so B moved LEFT 1 and UP 1: from (9,5) → (9,4) → (8,4))
- D: state 2 at (13,9) — 18 cells! (D grew: it was st1, my code pressed SPACE once → st2, then I clicked again and pressed SPACE → that was a no-op... hmm, D is at st2 now. Wait, D's dir was -1 (decreasing), so SPACE should have gone 1→0. But it went to 2! So D's dir was +1 → the first SPACE took it to 2, and the second SPACE (no-op) means... hmm, if dir=+1 and st2 → the next press → st3, not a no-op.
Hmm, maybe D's growth is: 0→1→2→3→2→1→0 and at 3 the white cell disappears (max). D at st2 with 18 cells. Two SPACE presses from st1 → st2 (one press worked, one was a no-op?). The trace: SPACE → effect; then MOUSE → effect; then SPACE → NO-OP. Hmm, if the first SPACE took D from 1→2, the second should take it to 3. Unless the click at (44,35) selected a different piece or deselected...
Whatever: D is at st2 pos (13,9) ✓ (perfect fit, 18 cells).
- C: multiple candidates with 7 cells; the true one is likely rot 0 at (11,1) ✓ (consistent with the UP move from (12,1)).
Total cells: 14+10+20+18+7 = 69; observed occ = 65 → 4 overlaps (welds/tip-on-body).
Let me verify the combination covers all 65 cells exactly.
Then plan the completion from this state.
Current: G(0,(5,3)), A(1,(5,6)), B(5,(8,4)), C(0,(11,1)), D(2,(13,9)).
The target config I want: G(0,(5,3)), A(1,(5,7)), B(5
… [999 caracteres más]

```python
V=mkV7()
st={'G':{'vi':0,'pos':(5,3)},'A':{'vi':1,'pos':(5,6)},'C':{'vi':0,'pos':(11,1)},'B':{'vi':5,'pos':(8,4)},'D':{'vi':2,'pos':(13,9)}}
exp=model_set(V,st); got=occ_set(current_frame)
print('model',len(exp),'board',len(got),'diff',sorted(exp^got))
# welds / overlaps
cnt={}
for k,d in st.items():
    b,t=cells_of(V,k,d['vi'],d['pos'])
    for c in t: cnt.setdefault(c,[]).append(k)
    for c in b: cnt.setdefault(c,[])
ov={c:v for c,v in cnt.items() if len(v)>0 and c in [x for x in cnt if cnt[x]]}
tips={}
for k,d in st.items():
    b,t=cells_of(V,k,d['vi'],d['pos'])
    for c in t: tips.setdefault(c,[]).append(k)
print('tip-tip welds',{c:v for c,v in tips.items() if len(v)>1})
print('tip-on-body',{c:(v,[k for k,d in st.items() if c in cells_of(V,k,d['vi'],d['pos'])[0]]) for c,v in tips.i
… [21 caracteres más]
```

```text
model 65 board 65 diff []
tip-tip welds {}
tip-on-body {(9, 5): (['G'], ['B']), (7, 7): (['G'], []), (10, 3): (['G'], []), (7, 6): (['A'], []), (5, 7): (['A'], ['G']), (11, 1): (['C'], []), (16, 2): (['C'], []), (10, 4): (['B'], []), (13, 10): (['B'], []), (8, 9): (['B'], ['A']), (8, 6): (['B'], ['A
… [116 caracteres más]
```